I've a string like 'intercompany creditors {DEMO[[1]]}'. I want to extract only the numbers from the string, in example just '1'.
How to do this in Invantive SQL?
You should be able to do so with substr (get some piece of text from specific positions in the text) and instr (get the position from a specific piece of text inside some other text):
select substr
( d
, instr(d, '[[') + 2
, instr(d, ']]') - instr(d, '[[') - 2
)
from ( select 'intercompany creditors {DEMO[[1]]}' d
from dual#DataDictionary
) x
Related
Is there a way i could convert an actual string to a number in postgresql
i have record stored in db and below is an example of unique identifier found in each record.
d895774d-7b91-4adc-bfba-f1264e5aae04
I want to store this record in another database but i would want to generate another unique number for each transaction/line
Is there a way i can convert this d895774d-7b91-4adc-bfba-f1264e5aae04 to some number.
like this actual numbers 13693660123082308270370273012321321312321
select 'd895774d-7b91-4adc-bfba-f1264e5aae04' as id
First convert the string into a table of single characters (the from clause);
Then select the digits 'as is', a as 10, b as 11 and so on (the case expression);
Finally aggregate into a string (string_agg)
skipping the - characters (where clause).
select
string_agg(case when c between '0' and '9' then c else (ascii(c) - 87)::text end, '')
from unnest(string_to_array('d895774d-7b91-4adc-bfba-f1264e5aae04', null)) c
where c <> '-';
Result: 13895774137119141013121115111015126414510101404
Edit
select
td.date,
(
select string_agg(case when c between '0' and '9' then c else (ascii(c) - 87)::text end, '')
from unnest(string_to_array(td.id, null)) c
where c <> '-'
) as id
from table_d td;
I have a problem I can't seem to figure out. I am trying to extract capacity from a product description. It is always between two values, "," and "oz." however there could be other commas included in the description that are not part of what I'm trying to extract. Example value is , 15 oz., or , 2 oz.,
I'm trying to find values that have the oz in them and are between two commas and I have been completely unsuccessfully. I've tried many things, but here is the latest that I have tried today and I'm just getting an error.
SELECT SUBSTRING(
FullDescription,
CHARINDEX(',', FullDescription),
CHARINDEX('oz.',FullDescription)
- CHARINDEX(',', FullDescription)
+ Len('oz.')
)
from CatalogManagement.Product
Since the backwards pattern ,.zo is more recognisable, I'd go with the REVERSE function
Sample values:
"something, something more, 18oz., complete"
"shorter, 12oz., remainder"
"there is no capacity, in this, value"
"a bit more, 14oz, and some followups, maybe"
SELECT REVERSE(
SUBSTRING (
REVERSE(FullDescription),
CHARINDEX(',.zo', REVERSE(FullDescription)) + 1,
CHARINDEX(',', REVERSE(FullDescription), CHARINDEX(',.zo', REVERSE(FullDescription)) + 1) - CHARINDEX(',.zo', REVERSE(FullDescription)) - 1
)
)
FROM CatalogManagement.Product
WHERE FullDescription LIKE '%oz.,%'
You might use XML-splitting together with a XQuery predicate:
DECLARE #tbl TABLE(ID INT IDENTITY, YourString VARCHAR(MAX));
INSERT INTO #tbl VALUES('Here is one with an amount, 1 oz., some more text')
,('Here is one with no amount, some more text')
,('a, 10 oz.')
,('b, 20oz., no blank between oz and the number')
,('30oz., starts with the pattern, no leading comma');
SELECT t.*
,A.oz.value('.','nvarchar(max)') oz
FROM #tbl t
CROSS APPLY(SELECT CAST('<x>' + REPLACE((SELECT t.YourString AS [*] FOR XML PATH('')),',','</x><x>') + '</x>' AS XML)
.query('/x[contains(text()[1],"oz.")]')) A(oz);
The idea in short:
We use some string methods to replace commas with XML tags and to cast your string to XML. each fragment is placed within a decent <x> element.
We use a predicate to return just the fragments containing "oz.".
You can filter easily with
WHERE LEN(A.oz.value('.','nvarchar(max)'))>0
I find in my sql database string whit weird whitespace which cannot be replace like REPLACE(string, ' ', '') RTRIM and cant it even find with string = '% %'. This space is even transfered to new table when using SELECT string INTO
If i select this string in managment studio and copy that is seems is normal space and when everything is works but cant do nothing directly from database. What else can i do? Its some kind of error or can i try some special character for this?
First, you must identify the character.
You can do that by using a tally table (or a cte) and the Unicode function:
The following script will return a table with two columns: one contains a char and the other it's unicode value:
DECLARE #Str nvarchar(100) = N'This is a string containing 1 number and some words.';
with Tally(n) as
(
SELECT TOP(LEN(#str)) ROW_NUMBER() OVER(ORDER BY ##SPID)
FROM sys.objects a
--CROSS JOIN sys.objects b -- (unremark if there are not enough rows in the tally cte)
)
SELECT SUBSTRING(#str, n, 1) As TheChar,
UNICODE(SUBSTRING(#str, n, 1)) As TheCode
FROM Tally
WHERE n <= LEN(#str)
You can also add a condition to the where clause to only include "special" chars:
AND SUBSTRING(#str, n, 1) NOT LIKE '[a-zA-Z0-9]'
Then you can replace it using it's unicode value using nchar (I've used 32 in this example since it's unicode "regular" space:
SELECT REPLACE(#str, NCHAR(32), '|')
Result:
This|is|a|string|containing|1|number|and|some|words.
How to return last n words using Postgres.
I have tried using LEFT method.
SELECT DISTINCT LEFT(name, -4) FROM my_table;
but it return last 4 characters ,i want to return last 3 words.
demo:db<>fiddle
You can do this using a the SUBSTRING() function and regular expressions:
SELECT
SUBSTRING(name FROM '((\S+\s+){0,3}\S+$)')
FROM my_table
This has been explained here: How can I match the last two words in a sentence in PostgreSQL?
\S+ is a string of non-whitespace characters
\s+ is a string of whitespace characters (e.g. one space)
(\S+\s+){0,3} Zero to three words separated by a space
\S+$ one word at the end of the text.
-> creates 4 words (or less if there are no more).
One way is to use regexp_split_to_array() to split the string into the words it contains and then put a string back together using the last 3 words in that array.
SELECT coalesce(w.words[array_length(w.words, 1) - 2] || ' ', '')
|| coalesce(w.words[array_length(w.words, 1) - 1] || ' ', '')
|| coalesce(w.words[array_length(w.words, 1)], '')
FROM mytable t
CROSS JOIN LATERAL (SELECT regexp_split_to_array(t."name", ' ') words) w;
db<>fiddle
RIGHT() should do
SELECT RIGHT('MYCOLUMN', 4); -- returns LUMN
UPD
You can convert to array and then back to string
SELECT array_to_string(sentence[(array_length(sentence,1)-3):(array_length(sentence,1))],' ','*')
FROM
(
SELECT regexp_split_to_array('this is the one of the way to get the last four words of the string', E'\\s+') AS sentence
) foo;
DEMO HERE
I Have: AAAA/DATA1/Data2;xyx;pqr
this data
I want only:DATA1 And Data2
If this is for a specific row, maybe use SUBSTR? Something like
SELECT
SUBSTR(column, 6, 5) AS col1
, SUBSTR(column, 13, 5) AS col2
FROM table
Here is something else you can do.. Although it gets pretty complicated, and this isn't the exact answer you are looking for but it will get you started. Hope this helps:
WITH test AS (
SELECT characters
FROM ( VALUES
( 'AAAA/DATA1/Data2;xyx;pqr'
) )
AS testing(characters)
)
SELECT
SUBSTR(characters, 1, LOCATE('/', characters) - 1) AS FIRST_PART
, SUBSTR(characters, LOCATE('/', characters) + 1) AS SECOND_PART
, SUBSTR(characters, LOCATE('/', characters, LOCATE('/', characters) + 1) + 1)
AS THIRD_PART
FROM test
;
DB2 does not have a single function for this, unfortunately. Check out this answer here: How to split a string value based on a delimiter in DB2