I hope you're having a great day,
I want to remove two patterns, I want to remove the parts that contains the word images from a text that I have:
in the files test1 I have this:
APP:Server1:files APP:Server2:images APP:Server3:misc APP:Server4:xml APP:Server5:json APP:Server6:stats APP:Server7:graphs APP:Server8:images-v2
I need to remove APP:Server2:image and APP:Server8:images-v2 ... I want this output:
APP:Server1:files APP:Server3:misc APP:Server4:xml APP:Server5:json APP:Server6:stats APP:Server7:graphs
I'm trying this:
cat test1 | sed 's/ .*images.* / /g'
You need to make sure that your wildcards do not allow spaces:
cat data | sed 's/ [^ ]*image[^ ]* / /g'
This should work for you
sed 's/\w{1,}:Server[2|8]:\w{1,} //g'
\w matches word characters (letters, numbers, _)
{1,} matches one or more of the preceeding item (\w)
[2|8] matches either the number 2 or 8
cat test.file
APP:Server1:files APP:Server2:images APP:Server3:misc APP:Server4:xml APP:Server5:json APP:Server6:stats APP:Server7:graphs APP:Server8:images-v2
The below command removes the matching lines and leaves blanks in their place
tr ' ' '\n' < test.file |sed 's/\w\{1,\}:Server[2|8]:\w\{1,\}.*$//'
APP:Server1:files
APP:Server3:misc
APP:Server4:xml
APP:Server5:json
APP:Server6:stats
APP:Server7:graphs
To remove the blank lines, just add a second option to the sed command, and paste the contents back together
tr ' ' '\n' < test.file |sed 's/\w\{1,\}:Server[2|8]:\w\{1,\}.*$//;/^$/d'|paste -sd ' ' -
APP:Server1:files APP:Server3:misc APP:Server4:xml APP:Server5:json APP:Server6:stats APP:Server7:graphs
GNU aWk alternative:
awk 'BEGIN { RS="APP:" } $0=="" { next } { split($0,map,":");if (map[2] ~ /images/ ) { next } OFS=RS;printf " %s%s",OFS,$0 }'
Set the record separator to "APP:" and then process the text in between as separate records. If the record is blank, skip to the next record. Split the record into array map based on ":" as the delimiter, then check if there is image in the any of the text in the second index. If there is, skip to the next record, otherwise print along with the record separator.
I need to remove any data between , and ( and the "," along with it.
I'm currently using the below command.
sed -i '/,/,/(/{//!d;s/ ,$//}' test1.txt
cat test1.txt
CREATE SET TABLE EDW_EXTRC_TAB.AVER_MED_CLM_HDR_EXTRC
,NO FALLBACK ,
NO BEFORE JOURNAL,
NO AFTER JOURNAL,
CHECKSUM = DEFAULT,
DEFAULT MERGEBLOCKRATIO
(
EXTRC_RUN_ID INTEGER NOT NULL,
Current Output
CREATE SET TABLE EDW_EXTRC_TAB.AVER_MED_CLM_HDR_EXTRC
,NO FALLBACK (
EXTRC_RUN_ID INTEGER NOT NULL,
Expected Output:
CREATE SET TABLE EDW_EXTRC_TAB.AVER_MED_CLM_HDR_EXTRC
(
EXTRC_RUN_ID INTEGER NOT NULL,
What is wrong here ?
Any suggestions?
Thanks in advance.
Two approaches:
-- GNU sed approach:
sed -z 's/,[^(]*//' test1.txt
-- GNU awk approach:
awk -v RS= '{ sub(/,[^(]+/,"",$0) }1' test1.txt
The output:
CREATE SET TABLE EDW_EXTRC_TAB.AVER_MED_CLM_HDR_EXTRC
( EXTRC_RUN_ID INTEGER NOT NULL,
I have a bunch of php files, which have many insert commands.
In each query, I want to insert a column variable admin_id = '$admin_id',
i.e., if the query is
insert into users (ch_id, num_value) values ('2', '100')
the query should be converted to
insert into users (admin_id, ch_id, num_value) values ($admin_id, '2', '100')
To do this, I have executed the following command
sed -i 's/\(insert.*into.*\) (\(.*values\)/\1 (admin_id, \2/' *.php
and
sed -i "s/\(insert.*into.*\) values (/\1 values ('\$admin_id', /" *.php
The above has worked successfully, but am still facing problem with SQL queries where there is no where in the query, i.e.,
insert into abctable (id,no)
to
insert into tablename (admin_id, id, no)
and
insert into abctable select $column from $tableperiod
to
insert into abctable select $column from $tableperiod where admin_id='$admin_id'
and
insert into abctable select $column from $tableperiod where abc != 'xyz'
to
insert into abctable select $column from $tableperiod where admin_id = '$admin_id' and abc != 'xyz'
How can I insert admin_id in these queries as well?
The queries in php files are executed by passing the query to the function in the following way:
execute_query("insert * from $table order by username");
I can find the queries still which are left to be modified by
executing
grep 'execute_query' *| grep insert| grep -v admin_id > stillleft.txt
I have solved it by using the following command
sed -e "s/\(query.*insert.*select.*where\)/& admin_id='\$admin_id' and /g" -e t \
-e "s/\(query.*insert.*select.*\)\")/\1 where admin_id='\$admin_id\")'/g" -e t \
-e "s/\(query.*insert.*\)(\(.*\)values (/\1(admin_id, \2values ('\$admin_id', /g" -e t \
-e "s/\(query.*insert.*(\)/& admin_id, /g" \
-i *.php
I'm not sure my testcases are right, but I think this could help you:
I changed the first statement, because I think it's easier and it matches the first and the second command of YOUR sed
sed -i 's/\(insert into .* (\)\(.*) values (\)\(.*\)) /\1admin_id, \2\$admin_id, \3/' *.php
The second (the first you are looking for) should work with the following
sed -i 's/\(insert into .* (\)\(.*) \)/\1admin_id, \2/' *.php
And the last two should work with this:
sed -i "s/\(insert into \w* select \$column from \$tableperiod\)/\1 where admin_id='\$admin_id'/" *.php
I hope this works for you, if not, please send a little bit more test data, if tested the commands with the text of your question as input
I you use multiple sed commands, you'll traverse the complete file each time. You can do it in a single pass. Assuming an input file infile that looks like this:
insert into users (ch_id, num_value) values ('2', '100')
insert into abctable (id, no)
insert into abctable select $column from $tableperiod
insert into abctable select $column from $tableperiod where abc != 'xyz'
we can use the following sed script sedscr
/^insert into/ {
s/\(([^)]*)\)(.*)\(([^)]*)\)/(admin_id, \1)\2($admin_id, \3)/
s/^([^(]+)\(([^)]*)\)$/\1(admin_id, \2)/
/\(.*\)/! {
/where/s/$/ and admin_id ='$admin_id'/
/where/!s/$/ where admin_id='$admin_id'/
}
}
It does the following:
if a line starts with insert into, then
for all lines with two pairs of parentheses, insert admin_id in the the first one and $admin_id in the second one
for lines with one pair of parentheses at the end, insert admin_id
if there are no parentheses, then
if there is a "where" clause, append and admin_id = '$admin_id'
else append where admin_id='$admin_id'
This can be called as follows:
$ sed -rf sedscr infile
insert into users (admin_id, ch_id, num_value) values ($admin_id, '2', '100')
insert into abctable (admin_id, id, no)
insert into abctable select $column from $tableperiod where admin_id='$admin_id'
insert into abctable select $column from $tableperiod where abc != 'xyz' and admin_id ='$admin_id'
If you can't use extened regular expressions (-r), the quoting of parentheses has to be inverted (all \( become ( etc.) and the + has to be replaced by \{1,\}.
The cumbersome regexes such as \(([^)]*)\) stand for "between literal parentheses, capture zero or more characters that are not a closing parenthesis" – this enables non-greedy capturing.
I need to generate a file.sql file from a file.csv, so I use this command :
cat file.csv |sed "s/\(.*\),\(.*\)/insert into table(value1, value2)
values\('\1','\2'\);/g" > file.sql
It works perfectly, but when the values exceed 9 (for example for \10, \11 etc...) it takes consideration of only the first number (which is \1 in this case) and ignores the rest.
I want to know if I missed something or if there is another way to do it.
Thank you !
EDIT :
The not working example :
My file.csv looks like
2013-04-01 04:00:52,2,37,74,40233964,3860,0,0,4878,174,3,0,0,3598,27.00,27
What I get
insert into table
val1,val2,val3,val4,val5,val6,val7,val8,val9,val10,val11,val12,val13,val14,val15,val16
values
('2013-04-01 07:39:43',
2,37,74,36526530,3877,0,0,6080,
2013-04-01 07:39:430,2013-04-01 07:39:431,
2013-04-01 07:39:432,2013-04-01 07:39:433,
2013-04-01 07:39:434,2013-04-01 07:39:435,
2013-04-01 07:39:436);
After the ninth element I get the first one instead of the 10th,11th etc...
As far I know sed has a limitation of supporting 9 back references. It might have been removed in the newer versions (though not sure). You are better off using perl or awk for this.
Here is how you'd do in awk:
$ cat csv
2013-04-01 04:00:52,2,37,74,40233964,3860,0,0,4878,174,3,0,0,3598,27.00,27
$ awk 'BEGIN{FS=OFS=","}{print "insert into table values (\x27"$1"\x27",$2,$3,$4,$5,$6,$7,$8,$9,$10,$11,$12,$13,$14,$15,$16 ");"}' csv
insert into table values ('2013-04-01 04:00:52',2,37,74,40233964,3860,0,0,4878,174,3,0,0,3598,27.00,27);
This is how you can do in perl:
$ perl -ple 's/([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+),([^,]+)/insert into table values (\x27$1\x27,$2,$3,$4,$5,$6,$7,$8,$9,$10,$11,$12,$13,$14,$15,$16);/' csv
insert into table values ('2013-04-01 04:00:52',2,37,74,40233964,3860,0,0,4878,174,3,0,0,3598,27.00,27);
Try an awk script (based on #JS웃 solution):
script.awk
#!/usr/bin/env awk
# before looping the file
BEGIN{
FS="," # input separator
OFS=FS # output separator
q="\047" # single quote as a variable
}
# on each line (no pattern)
{
printf "insert into table values ("
print q $1 q ", "
print $2,$3,$4,$5,$6,$7,$8,$9,$10,$11,$12,$13,$14,$15,$16
print ");"
}
Run with
awk -f script.awk file.csv
One-liner
awk 'BEGIN{OFS=FS=","; q="\047" } { printf "insert into table values (" q $1 q ", " $2","$3","$4","$5","$6","$7","$8","$9","$10","$11","$12","$13","$14","$15","$16 ");" }' file.csv
I have a file in stanza format. Example of the file are as below.
id_1:
id=241
pgrp=staff
groups=staff
home=/home/id_1
shell=/usr/bin/ks
id_2:
id=242
pgrp=staff
groups=staff
home=/home/id_2
shell=/usr/bin/ks
How do I use sed or awk to process it and return only the id name, id and groups in a single line and tab delimited format? e.g.:
id_1 241 staff
id_2 242 staff
with awk:
BEGIN { FS="="}
$1 ~ /id_/ { printf("%s", $1) }
$1 ~ /id/ && $1 !~ /_/ { printf("\t%s", $2) }
$1 ~ /groups/ { printf("\t%s\n", $2) }
Here is an awk solution:
translate.awk
#!/usr/bin/awk -f
{
if(match($1, /[^=]:[ ]*$/)){
id_=$1
sub(/:/,"",id_)
}
if(match($1,/id=/)){
split($1,p,"=")
id=p[2]
}
if(match($1,/groups=/)){
split($1,p,"=")
print id_," ",id," ",p[2]
}
}
Execute it either by:
chmod +x translated.awk
./translated.awk data.txt
or
awk -f translated.awk data.txt
For completeness, here comes a shortened version:
#!/usr/bin/awk -f
$1 ~ /[^=]:[ ]*$/ {sub(/:/,"",$1);printf $1" ";FS="="}
$1 ~ /id/ {printf $2" "}
$1 ~ /groups/ {print $2}
sed 'N;N;N;N;N;y/=\n/ /' data.txt | awk '{print $1,$3,$7}'
Here is the one-liner approach by setting RS:
awk 'NR>1{print "id_"++i,$3,$7}' RS='id_[0-9]+:' FS='[=\n]' OFS='\t' file
id_1 241 staff
id_2 242 staff
Requires GNU awk and assumes the IDs are in increasing order starting at 1.
If the ordering of the ID's is arbitrary:
awk '!/shell/&&NR>1{gsub(/:/,"",$1);print "id_"$1,$3,$5}' RS='id_' FS='[=\n]' OFS='\t' file
id_1 241 staff
id_2 242 staff
awk -F"=" '/id_/{split($0,a,":");}/id=/{i=$2}/groups/{printf a[1]"\t"i"\t"$2"\n"}' your_file
tested below:
> cat temp
id_1:
id=241
pgrp=staff
groups=staff
home=/home/id_1
shell=/usr/bin/ks
id_2:
id=242
pgrp=staff
groups=staff
home=/home/id_2
shell=/usr/bin/ks
> awk -F"=" '/id_/{split($0,a,":");}/id=/{i=$2}/groups/{printf a[1]"\t"i"\t"$2"\n"}' temp
id_1 241 staff
id_2 242 staff
This might work for you (GNU sed):
sed -rn '/^[^ :]+:/{N;N;N;s/:.*id=(\S+).*groups=(\S+).*/\t\1\t\2/p}' file
Look for a line holding an id then get the next 3 lines and re-arrange the output.