i need to fetch the table1 content which is not present in the table2 i dont think which is possible by <> or != operator so can any one help me here
select t1._id, t1."categoryName", t1.company_id, t1.active from table1 t1
inner join table2 t2 on t1._id <> t2.category_id
inner join table3 t3 on t2 .department_id <> t3 ._id where t3._id = 1
for example:
a collage can have 10 departments , students enrolled to 5 department which is present 1 collage
table1 is dept
table 3 is col
table 2 looks like this:
col_id| dept_id | student_id
1 | 1 | 1
1 | 2 | 2
1 | 3 | 3
1 | 4 | 4
1 | 5 | 5
i need to fetch rest of the dept_id which is not present in table 2
i need to fetch the table1 content which is not present in the table2
Use a not exists query, something like this:
select *
from table1 t1
where not exists (select *
from table2 t2
where t1._id = t2.category_id)
Note sure how table3 relates to the question "not present in table2"
try not in, or outer join, like here:
select t1._id, t1."categoryName", t1.company_id, t1.active
from table1 t1
left outer join table2 t2 on t1._id = t2.category_id
left outer join table3 t3 on t2 .department_id = t3 ._id
where t3._id = 1
and t2.category_id is null
and t3 ._id is null
yep i got a solution to my question from dbastackexchange this might help others so pasting here
select
cat._id,
cat.cat_name
from
cat
where
not exists(
select
*
from
deptcat
inner join dept on(
dept._id = deptcat.dept_id
)
where
deptcat.cat_id = cat._id
and dept._id = 1
)
Related
how to find number of records in both table using join.
i have two tables table1 and table2 with same structure.
table1
id
item
1
A
1
B
1
C
2
A
2
B
table2
id
item
1
A
1
B
2
A
2
B
2
C
2
D
Output should be like this.
id
table1.itemcount
table2.itemcount
1
3
2
2
2
4
SELECT DISTINCT id, (
SELECT COUNT(*) FROM table1 AS table1_2 WHERE table1_2.id=table1.id
) AS "table1.itemcount", (
SELECT COUNT(*) FROM table2 AS table2_2 WHERE table2_2.id=table1.id
) AS "table2.itemcount"
FROM table1;
Assuming that each id is guaranteed to exist in both tables, the following would work
select
t1.id,
count(distinct t1.item) t1count,
count(distinct t2.item) t2count
from t1
join t2 on t1.id = t2.id
group by 1;
But if that is not guaranteed then we'll have to use full outer join to get unique ids from both tables
select
coalesce(t1.id, t2.id) id,
count(distinct t1.item) t1count,
count(distinct t2.item) t2count
from t1
full outer join t2 on t1.id = t2.id
group by 1;
We're using coalesce here as well for id because if it only exists in t2, t1.id would result in null.
#DeeStark's answer also works if ids are guaranteed to be in both tables but it's quite inefficient because count is essentially run twice for every distinct id in the table. Here's the fiddle where you can test out different approaches. I've prefixed each query with explain which shows the cost
Hope this helps
I have a query which returns next table with name first_table:
Name
ID
First
1
Second
2
And I need to join another table named second_table:
ID
ParentID
22
1
33
323
By the columns first_table."ID" = second_table."ParentID", so if first_table_id exists, I need to add one more row with its first_table."Name" value
So the result should be:
Name
ID
First
1
First
22
Second
2
You can do something like this (result here)
select t1.name,t1.id
from t1 join t2 on t1.id = t2.parent_id
union
select t1.name,t2.id
from t1 join t2 on t1.id = t2.parent_id
union
select t1.name,t1.id
from t1
where t1.id not in (select parent_id from t2)
order by name,id
Below sample query is a part of my main query. I found SORT operator in below query is consuming 30% of the cost.
To avoid SORT, there is need of creation of Indexes. Is there any other way to optimize this code.
SELECT TOP 1 CONVERT( DATE, T_Date) AS T_Date
FROM TableA
WHERE ID = r.ID
AND Status = 3
AND TableA_ID >ISNULL((
SELECT TOP 1 TableA_ID
FROM TableA
WHERE ID = r.ID
AND Status <> 3
ORDER BY T_Date DESC
), 0)
ORDER BY T_Date ASC
Looks like you can use not exists rather than the sorts. I think you'll probably get a better performance boost by use a CTE or derived table instead of the a scalar subquery.
select *
from r ... left outer join
(
select ID, min(t_date) as min_date from TableA t1
where status = 3 and not exists (
select 1 from TableA t2
where t2.ID = t1.ID
and t2.status <> 3 and t2.t_date > t1.t_date
)
group by ID
) as md on md.ID = r.ID ...
or
select *
from r ... left outer join
(
select t1.ID, min(t1.t_date) as min_date
from TableA t1 left outer join TableA t2
on t2.ID = t1.ID and t2.status <> 3
where t1.status = 3 and t1.t_date < t2.t_date
group by t1.ID
having count(t2.ID) = 0
) as md on md.ID = r.ID ...
It also appears that you're relying on an identity column but it's not clear what those values mean. I'm basically ignoring it and using the date column instead.
Try this:
SELECT TOP 1 CONVERT( DATE, T_Date) AS T_Date
FROM TableA a1
LEFT JOIN (
SELECT ID, MAX(TableA_ID) AS MaxAID
FROM TableA
WHERE Status <> 3
GROUP BY ID
) a2 ON a2.ID = a1.ID AND a1.TableA_ID > coalesce(a2.MAXAID,0)
WHERE a1.ID = r.ID AND a1.Status = 3
ORDER BY T_Date ASC
The use of TOP 1 in combination with the unexplained r alias concern me. There's almost certainly a MUCH better way to get this data into your results that doesn't involve doing this in a sub query (unless this is for an APPLY operation).
I have a query
SELECT id_anything FROM table1 JOIN table2 USING (id_tables)
Now, i have a situation which is:
If that join returns two rows from table2 i want to show the id_anything from table1 (1 row only)
and if the join from table2 returns 1 row, i want to show id_anything from table2.
Ps: id_anything from table 2 returns different values
Example data:
table1
id_tables | id_anything
1 | 1
table2
id_tables | id_anything
1 | 10
1 | 100
Return expected: 1
First, get the value you may want to return and the basis for deciding which to return together into one row.
SELECT table1.id_tables, table1.id_anything AS table1_id, MIN(table2.id_anything) AS table2_id, COUNT(*)
FROM table1 JOIN table2 USING (id_tables)
GROUP BY table1.id_tables, table1.id_anything
The aggregate function you use doesn't really matter since you'll only be using the value if there is only one.
You can then pick the relevant value:
WITH join_summary AS (
SELECT table1.id_tables, table1.id_anything AS table1_id, MIN(table2.id_anything) AS table2_id, COUNT(*) AS match_count
FROM table1 JOIN table2 USING (id_tables)
GROUP BY table1.id_tables, table1.id_anything
)
SELECT id_tables, CASE WHEN (match_count > 1) THEN table1_id ELSE table2_id END AS id_anything
FROM join_summary
I need to perform a left join of two tables in netezza during an update. How can i achieve this ? Left join with three tables are working but not with two tables.
UPDATE table_1
SET c2 = t2.c2
FROM
table_1 t1
LEFT JOIN table_2.t1
ON t1.c1=t2.c1
LEFT JOIN table_3 t3
ON t2.c1=t3.c1
this works but
UPDATE table_1
SET c2 = t2.c2
FROM table_1 t1
LEFT JOIN table_2.t1
ON t1.c1=t2.c1
this says like trying to update multiple columns.
Thanks,
Manirathinam.
When performing an UPDATE TABLE with a join in Netezza, it's important to understand that the table being updated is always implicitly INNER JOINed with the FROM list. This behavior is documented here.
Your code is actually joining table_1 to itself (one copy with no alias, and one with t1 as an alias). Since there is no join criteria between those two versions of table_1, you are getting a cross join which is providing multiple rows that are trying to update table_1.
The best way to tackle an UPDATE with an OUTER join is to employ a subselect like this:
TESTDB.ADMIN(ADMIN)=> select * from table_1 order by c1;
C1 | C2
----+----
1 | 1
2 | 2
3 | 3
(3 rows)
TESTDB.ADMIN(ADMIN)=> select * from table_2 order by c1;
C1 | C2
----+----
1 | 10
3 | 30
(2 rows)
TESTDB.ADMIN(ADMIN)=> UPDATE table_1 t1
SET t1.c2 = foo.c2
FROM (
SELECT t1a.c1,
t2.c2
FROM table_1 t1a
LEFT JOIN table_2 t2
ON t1a.c1 = t2.c1
)
foo
WHERE t1.c1 = foo.c1;
UPDATE 3
TESTDB.ADMIN(ADMIN)=> select * from table_1 order by c1;
C1 | C2
----+----
1 | 10
2 |
3 | 30
(3 rows)