cakephp3- unable to post form data to controller function - forms

I have a contact us form and user enter data and submits it. This data needs to accessed in controller function so I can send a mail to admin informing about the user request recently received.
But when I press submit button, nothing happens. Form just reloads and the contactus form (view page) is shown to the users. I don't know why the data is not getting passed to the controller function.
I'mm new to CakePHP framework and I'm using CakePHP3 for development purposes.
Here is my form:
<?php echo $this->Form->create(null, ['url' => ['controller' => 'Pages', 'action' => 'contactus']]); ?>
<div class="col-md-6">
<?php echo $this->Form->input('fname', ['placeholder' => 'Your name.' , 'id' => 'fname', 'required' => 'required']); ?>
</div>
<div class="col-md-6">
<?php echo $this->Form->input('mail', ['placeholder' => 'Your email.' , 'id' => 'mail', 'required' => 'required']); ?>
</div>
<div class="col-md-6">
<?php echo $this->Form->input('subject', ['placeholder' => 'Write something.', 'id' => 'subject']); ?>
</div>
<div class="col-md-9">
<?php echo $this->Form->button(__('Submit')); ?>
</div>
<?php echo $this->Form->end(); ?>
And my controller function is:
public function contactus()
{
$pages ='';
if ($this->request->is('post'))
{
$pages = $this->request->data('Contact');
}
$this->set(compact('pages'));
$this->set('_serialize', ['pages']);
}
Can anyone tell me the mistakes I made?

I think your form is submitting but not through the post method. So I would like to say you that, please make the bellow changes before submitting the form.
$pages ='';
if ($this->request->is('post'))
{
echo "Request is post";die;
$pages = $this->request->data('Contact');
}else{
echo "request is not post";die;
}
$this->set(compact('pages'));
$this->set('_serialize', ['pages']);
Now check, which is printing in the display. Then I can help you further.
Remember: - fill the form, then after change the controller method, then press submit method.

Related

Yii2 use form tags

When I submit my form i got some errors,
This is my form script which contains posted fields.
<?php $form = ActiveForm::begin([
'action'=>'userpermission/create',
]); ?>
<form method="post" action="<?php echo Yii::$app->getUrlManager()->createUrl('admin/userpermission/create')?>">
<ul class="list-unstyled">
<li>
<?= $form->field($model, 'idPermission')->checkboxList(ArrayHelper::map(Permission::find()->all(),"idPermission", "libelle", [
'onclick' => "$(this).val( $('input:checkbox:checked').val());",
'item' => function($index, $label, $name, $checked, $value) {
return "<label class='ckbox ckbox-primary col-md-4'><input type='checkbox' {$checked} name='{$name}' value='{$value}' tabindex='3'>{$label}</label>";
}
])) ?>
</li><br>
</ul>
<div class="form-group">
<?php Html::submitButton($model->isNewRecord ? 'Valider' : 'Create' ,['class' => $model->isNewRecord ? 'btn btn-primary','value'=>'Create', 'name'=>'submit']) ?>
</div>
<?php ActiveForm::end(); ?>
and my create function looks like but i got the error undefined variable model!
public function actionCreate()
{
$model = new Userpermission();
if ($model->load(Yii::$app->request->post()) && $model->save()) {
print_r(Yii::$app->request->post());
exit;
return $this->redirect(['index', 'id' => $model->id]);
} else {
return $this->render('create', [
'model' => $model,
]);
}
}
1st off, you dont need that <form> tag.
<?php $form = ActiveForm::begin([
'action'=>'userpermission/create',
]); ?>
creates and initializes the form for you with corresponding client-validations.
the possible issue is due to unclosed </form> which anyways is unnecessary.
suggesting to remove the <form> tag entirely. and try again and if any issue please let me know the error.
also bring the print_r(Yii::$app->request->post()); before if condition.
enable error reporting in your function
error_reporting(E_ALL);
please give the filename to code block. it would be easier to understand that way.

Can't validate form CakePHP 3

I'm new on CakePHP and I can't validate a login form. I'm getting the following error: Notice (8): Undefined variable: user [APP/Template\Users\login.ctp, line 5]
I already tried to use this code: <?= $this->Form->create('User'); ?> The error is removed but the validation doesn't works.
Can someone help me?
login.ctp:
<br>
<div class="index large-4 medium-5 large-offset-4 medium-offset-4 columns">
<div class="panel">
<h2 class="text-center">Login</h2>
<?= $this->Form->create($user); ?>
<?php
echo $this->Form->input('email');
echo $this->Form->input('password');
?>
<?= $this->Form->submit('Login', array('class' => 'button')); ?>
<?= $this->Form->end(); ?>
</div>
</div>
login function - UsersController.php:
// Login
public function login()
{
if($this->request->is('post'))
{
$user = $this->Auth->identify();
if($user)
{
$this->Auth->setUser($user);
return $this->redirect(['controller' => 'comentario']);
}
// Erro no Login
$this->Flash->error('Erro de autenticaĆ§Ć£o');
}
}
First of all, change this line
<?= $this->Form->create($user); ?>
to this
<?= $this->Flash->render('auth') ?>
<?= $this->Form->create() ?>
Then, you can simplify your submit like this
<?= $this->Form->button(__('Login')); ?>
Make sure you create UsersTable.php in you src/Model/Table and put this code
// src/Model/Table/UsersTable.php
namespace App\Model\Table;
use Cake\ORM\Table;
use Cake\Validation\Validator;
class UsersTable extends Table
{
public function validationDefault(Validator $validator)
{
return $validator
->notEmpty('username', 'A username is required')
->notEmpty('password', 'A password is required')
}
}
It's not good using redirect the specific controller inside login method. Change it:
return $this->redirect($this->Auth->redirectUrl());
Then tell your Auth Component where user should be redirect after login
$this->loadComponent('Auth', [
'loginRedirect' => [
'controller' => 'Articles',
'action' => 'index'
],
'logoutRedirect' => [
'controller' => 'Pages',
'action' => 'display',
'home'
]
]);
And the most important. Read Authentication and Authorization Tutorial

CakePHP 2.0 Determine which submit button has been clicked

In CakePHP 1.3 you can create a form with multiple submit buttons:
echo $this->Form->submit('Submit 1', array('name'=>'submit');
echo $this->Form->submit('Submit 2', array('name'=>'submit');
and detect which submit button was pressed in the controller with:
if (isset($this->params['form']['submit']) && $this->params['form']['submit'] == "Submit 1") {
// first button clicked
}
In CakePHP, $this->params['form'] isn't set and the clicked button value doesn't appear anywhere in $this->request, $this->request->data, $this->params, $this->data or $_POST.
How do I determine which button has been clicked in CakePHP 2.0?
Thanks in advance.
Edit:
As requested, here's the code for the form:
<?php echo $this->Form->create('History', array('action'=>'add')); ?>
<div class='submit'>
<?php
echo $this->Form->submit('Yes', array('div'=>false, 'name'=>'submit'));
echo $this->Form->submit('No', array('div'=>false, 'name'=>'submit'));
?>
</div>
<?php echo $this->Form->end()?>
And the output of the form:
<form action="/projects/kings_recruit/trunk/www/histories/add" id="HistoryAddForm" method="post" accept-charset="utf-8">
<div style="display:none;">
<input name="_method" value="POST" type="hidden">
</div>
<div class="submit">
<input name="submit" value="Yes" type="submit">
<input name="submit" value="No" type="submit">
</div>
</form>
Generally it is a bad practise to use the same name for both submit buttons.
There should be a "submit" key in the $_POST and $this->request->data
I tested this in CakePHP 2.1.1 as shown below:
The view code:
<?php echo $this->Form->create('Message', array('action'=>'test'));
// Extra test input field
echo $this->Form->input('test');
?>
<div class='submit'>
<?php
echo $this->Form->submit('Yes', array('div'=>false, 'name'=>'submit'));
echo $this->Form->submit('No', array('div'=>false, 'name'=>'submit'));
?>
</div>
<?php echo $this->Form->end()?>
The in the controller in $this->request->data:
array(
'submit' => 'Yes',
'Message' => array(
'test' => 'TestFieldTest'
)
)
And in $_POST:
array(
'_method' => 'POST',
'data' => array(
'Message' => array(
'test' => 'TestFieldTest'
)
),
'submit' => 'Yes'
)
You can also give the two submits different names:
echo $this->Form->submit('Yes', array('div'=>false, 'name'=>'submitY'));
echo $this->Form->submit('No', array('div'=>false, 'name'=>'submitN'));
This way you can differ them in the $_POST or $this->request->data, because the keys will be the submits' names:
array(
'submitY' => 'Yes',
'Message' => array(
'test' => 'foo'
)
)
array(
'_method' => 'POST',
'data' => array(
'Message' => array(
'test' => 'Bar'
)
),
'submitY' => 'Yes'
)
Then to determine which button is pressed you can use a simple isset($_POST['']) or over $this->request->data ?
Don't use the same name for both submit buttons. Consider this example:
<?php echo $this->Form->create(false); ?>
<?php echo $this->Form->text('input'); ?>
<?php echo $this->Form->submit('Yes', array('name' => 'submit1')); ?>
<?php echo $this->Form->submit('No', array('name' => 'submit2')); ?>
<?php echo $this->Form->end(); ?>
debug($this->request->data) will produce the following when the "Yes" button is clicked:
array(
'submit1' => 'Yes',
'input' => 'test'
)
And here it is when the "No" button is clicked:
array(
'submit2' => 'No',
'input' => 'test'
)
To check which button was clicked:
if (isset($this->request->data['submit1'])) {
// yes button was clicked
} else if (isset($this->request->data['submit2'])) {
// no button was clicked
}
in 2.0 there is no $this->params['form'] anymore
all form helper posted fields end up in $this->data (which makes more sense anyway)
so
if (!empty($this->data['submit']) && $this->data['submit'] == "Submit 1") {}
note that !empty() is better here as well.
PS: you can use my enhanced upgrade shell to replace it in your code: https://github.com/dereuromark/upgrade
its the command
cake Upgrade.Upgrade request
(https://github.com/dereuromark/upgrade/blob/master/Console/Command/UpgradeShell.php#L833)
if (!empty($this->request->data['submit']) && $this->request->data['submit'] == "Yes") {
// do your stuff
}

Zend Framework Custom Forms with viewScript

I am having some problems working out how to use custom forms in Zend Framework.
I have followed various guides but none seem to work. Nothing at all gets rendered.
Here is the bits of code that I am trying to use (All code below is in the default module). I have simplified the code to a single input for the test.
applications/forms/One/Nametest.php
class Application_Form_One_Nametest extends Zend_Form {
public function init() {
$this->setMethod('post');
$name = new Zend_Form_Element_Text('name');
$name->setLabel('Box Name')
->setRequired(true)
->addFilter('StripTags')
->addFilter('StringTrim')
->addValidator('NotEmpty');
$submit = new Zend_Form_Element_Submit('submit');
$submit->setLabel('Submit Message');
$submit->setAttrib('id', 'submitbutton');
$submit->setAttrib('class', 'bluebutton');
$this->addElements(array($name, $submit));
}
}
application/views/scripts/one/formlayout.phtml
<form action="<?= $this->escape($this->form->getAction()) ?>" method="<?= $this->escape($this->form->getMethod()) ?>">
<p>
Please provide us the following information so we can know more about
you.
</p>
<? echo $this->element->name ?>
<? echo $this->element->submit ?>
</form>
application/controllers/IndexController.php
public function formtestAction() {
$form = new Application_Form_One_Nametest();
$form->setDecorators(array(array('ViewScript', array('viewScript' => 'one/formlayout.phtml'))));
$this->view->form = $form;
}
application/views/scripts/index/formtest.phtml
<h1>Formtest</h1>
<?
echo $this->form;
?>
The above code does not throw any errors or render any part of formlayout.phtml including the form tags or text between the p tags.
Can anybody tell me what I might be doing wrong?
I think the problem is your form element's decorator. You should set the decorator to ViewHelper and Error only. It works for me at least.
Here is the code I used and it should work
applications/forms/Form.php
class Application_Form_Form extends Zend_Form {
public function loadDefaultDecorators() {
$this->setDecorators(
array(
array(
'ViewScript',
array(
'viewScript' => 'index/formlayout.phtml',
)
)
)
);
}
public function init() {
$this->setAction('/action');
$this->setMethod('post');
$this->addElement('text', 'name', array(
'decorators' => array('ViewHelper', 'Errors')
));
}
}
application/views/scripts/index/formlayout.phtml
<form action="<?php echo $this->element->getAction(); ?>" method="<?php echo $this->element->getMethod(); ?>">
<div>
<label for="name">Box Name</label>
<?php echo $this->element->name; ?>
</div>
<input type="submit" value="Submit Message" id="submitbutton" class="bluebutton">
</form>
application/views/scripts/index/index.phtml
<!-- application/views/scripts/index/index.phtml -->
<?php echo $this -> form; ?>
application/controllers/IndexController.php
public function indexAction() {
$form = new Application_Form_Form();
$this -> view -> form = $form;
}
Here is a very simple example to get you going adapted from this article.
The form:-
class Application_Form_Test extends Zend_Form
{
public function init()
{
$this->setMethod('POST');
$this->setAction('/');
$text = new Zend_Form_Element_Text('testText');
$submit = new Zend_Form_Element_Submit('submit');
$this->setDecorators(
array(
array('ViewScript', array('viewScript' => '_form_test.phtml'))
)
);
$this->addElements(array($text, $submit));
$this->setElementDecorators(array('ViewHelper'));
}
}
The order in which setDecorators(), addElements() and setElementDecorators() are called is very important here.
The view script _form_test.phtml can be called anything you like, but it needs to be in /views/scripts so that it can be found by the renderer.
/views/scripts/_form_test.phtml would look something like this:-
<form id="contact" action="<?php echo $this->element->getAction(); ?>"
method="<?php echo $this->element->getMethod(); ?>">
<p>
Text<br />
<?php echo $this->element->testText; ?>
</p>
<p>
<?php echo $this->element->submit ?>
</p>
</form>
You instantiate the form, pass it to the view and render it as usual. The output from this example looks like this:-
<form id='contact' action='/' method='post'>
<p>
Text<br />
<input type="text" name="testText" id="testText" value=""></p>
<p>
<input type="submit" name="submit" id="submit" value="submit"></p>
</form>
That should be enough to get you started creating your own forms.
Usually, if you don't see anything on the screen it means that some sort of error happened.
Maybe you have errors turned off or something, maybe not. I'm just trying to give you ideas.
The only things I could spot where the following.
In the below code, you have to still specify the form when trying to print out the elements.
<form>
action="<?php $this->escape($this->element->getAction()) ?>"
method="<?php $this->escape($this->element->getMethod()) ?>" >
<p>
Please provide us the following information so we can know more about
you.
</p>
<?php echo $this->element->getElement( 'name' ); ?>
<?php echo $this->element->getElement( 'submit' ) ?>
</form>
As vascowhite's code shows, once you are inside the viewscript, the variable with the form is called element. The viewscript decorator uses a partial to do the rendering and thus it creates its own scope within the viewscript with different variable names.
So, although in your original view it was called $form, in the viewscript you'll have to call it element.
Also, maybe it was copy/paste haste, but you used <? ?> tags instead of <?= ?> or <?php ?> tags. Maybe that caused some error that is beyond parsing and that's why you got no output.

select menu default values not rendering in symfony

I am using Symfony 1.4, and am using embedded forms to place multiple similar forms into one form for a configuration page. I am having success showing the form, but the default values of the sfWidgetFormChoice widgets are not being rendered, i.e. the selected="selected" attribute is gone from the HTML.
Incidentally, the default values show up if I don't use embedded forms. The problem with avoiding embedded forms is that each form has identical inputs and therefore overwrites itself.
The action code is as such, some code omitted for brevity:
$serviceFormArray = array();
$this->fullForm = new ConfigForm();
foreach($this->serviceArray as $net => $service)
{
$this->partialForm = new ConfigForm();
foreach($service as $typeId => $val)
{
$typeObj = Doctrine::getTable('Type')->find($typeId);
$typeField = new sfWidgetFormChoice(array(
'default' => $val,
'choices' => array('1' => 'on', '0' => 'off'),
'label' => $typeObj->name)
);
$typeField->setDefault($val);
$serviceFormArray[$typeObj->name] = $typeField;
}
$netObj = Doctrine::getTable('Network')->find($net);
$this->partialForm->setWidgets($serviceFormArray);
$this->fullForm->embedForm($netObj->name,$this->partialForm);
}
and the template looks like this, some code omitted for brevity:
<div class="sectionBox">
<?php echo $fullForm->renderFormTag('/configure/submitconfig') ?>
<?php foreach ($fullForm->getVisibleFields() as $part => $field): ?>
<div class="settingsField">
<?php echo $field->renderLabel() ?>
<?php echo $field->render() ?>
<input type="hidden" name="plug" value="<?php echo $plugName; ?>"/>
</div>
<?php endforeach; ?>
<div id="submitConfig"><input type="submit" value="Save"/></div>
</form>
</div>
Try setting default value via $form->setDefault($name, $default).
$this->partialForm->setDefault($typeObj->name, $val);