Subtract dates By Mongo query by Pikking from Array - mongodb

Question

I want to subtract checkin date from checkout date in MongoDB
How Can I do that ??
Data from MongoDB :-
"timeLogs" : [
{
"type" : "chekin",
"date" : ISODate("2017-05-02T05:10:00.000Z"),
"_id" : ObjectId("590822c66216cf3864740e3d")
},
{
"type" : "checkout",
"date" : ISODate("2017-05-02T14:10:00.000Z"),
"_id" : ObjectId("59088037feb56c0fcd60a090")
}
]
Any help will be appriciated ..

Answer 1

I am not quite sure how do you want the format, bu you can try those options as a date or an hour.
db.getCollection('Date').aggregate([
{
$project: {
_id: "$_id",
startDate: {
$arrayElemAt: ["$timeLogs", 0]
},
endDate: {
$arrayElemAt: ["$timeLogs", 1]
}
}
}, {
$project: {
timeDiff: {
$divide: [{
$subtract: ["$endDate.date", "$startDate.date"]
}, 1000 * 60 * 60]
}
}
}
])
or as a date
db.getCollection('sample date').aggregate([
{
$project: {
_id: "$_id",
startDate: {
$arrayElemAt: ["$timeLogs", 0]
},
endDate: {
$arrayElemAt: ["$timeLogs", 1]
}
}
}, {
$project: {
timeDiff: {
$add: [new Date(0), {
$subtract: ["$endDate.date", "$startDate.date"]
}]
}
}
}
])
For mongo <3.2
db.getCollection('Date').aggregate([
{
$unwind: "$timeLogs"
},
{
$group: {
_id: "$_id",
startDate: {
$first: "$timeLogs"
},
endDate: {
$last: "$timeLogs"
}
}
}, {
$project: {
timeDiff: {
$add: [new Date(0), {
$subtract: ["$endDate.date", "$startDate.date"]
}]
}
}
}
])