MongoDB aggregate query $match - mongodb

Question

I create a query that returns the farmland details and all events that is connected with it (see below)
Now I want to filter and return only events that have the status field not equal to delete. I tried with $match operator but it doesn't work... Is there someone who can help me with?
Here are the collections of the database:
Farmland collections
{
"_id" : ObjectId("5909d9bc19383e2a16378271"),
"SUID" : "IT0001",
"id" : "A",
"UUID" : "CAL123",
"name" : "Pratosaiano (Maza)",
"status" : "close"
}
Events collections
...
{
"_id" : ObjectId("5909e3387786e52c90f158da"),
"SUID" : "IT0001",
"farmland" : "B",
"opening" : "00:00",
"closing" : "00:00",
"type" : "scheduled",
"days" : [
0,
0,
0,
0,
0,
0,
0
],
"active" : true,
"status" : "add",
"id" : 204
},
{
"_id" : ObjectId("590b4ec6cdddea05130fbc3b"),
"SUID" : "IT0001",
"farmland" : "B",
"opening" : "00:00",
"closing" : "01:00",
"type" : "semiautomatic",
"active" : true,
"status" : "add",
"id" : 16
}
...
The query:
db.farmlands.aggregate([
{
$match: {
"SUID": "IT0001",
"id": "B",
}
},
{
$lookup: {
localField: "id",
from: "events",
foreignField: "farmland",
as: "events"
}
},
{
$project: {
"_id": 0,
"SUID": 1,
"id": 1,
"name": 1,
"events.id": 1,
"events.type": 1,
"events.opening": 1,
"events.closing": 1,
"events.days": 1,
"events.active": 1,
"events.status": 1
}
}]);
The output of this query
{
"_id" : ObjectId("5909d9bc19383e2a16378272"),
"SUID" : "IT0001",
"id" : "B",
"UUID" : "CAL123",
"name" : "Pratosaiano (Maza)",
"status" : "close",
"events" : [
{
"_id" : ObjectId("5909da8312452a289bbb62c1"),
"SUID" : "IT0001",
"farmland" : "B",
"opening" : "07:00",
"closing" : "08:00",
"type" : "scheduled",
"days" : [
0,
0,
0,
0,
0,
0,
0
],
"active" : true,
"status" : "update",
"id" : 237
}, ...
]
}