Passing selector via IBInspectable in Swift 3 - swift

Question

I created a custom control and I want to pass the action in an #IBInspectable property to achieve the same effect of setting up an #IBAction using UIButton. How should I go about doing this?
class MyControl: UIButton {
// Problem with this string approach is
//I have no way to know which instance to perform the selector on.
#IBInspectable var tapAction: String?
// set up tap gesture
...
func labelPressed(_ sender: UIGestureRecognizer) {
if let tapAction = tapAction {
// How should I convert the string in tapAction into a selector here?
//I also want to pass an argument to this selector.
}
}
}

Answer 1

I really don't know why do you want it, but... Here is my solution:
Create a MyActions class, with actions that MyControl can to call:
class MyActions: NSObject {
func foo() {
print("foo")
}
func bar() {
print("bar")
}
func baz() {
print("baz")
}
}
Replace your MyControl class to
class MyControl: UIButton {
#IBInspectable var actionClass: String?
#IBInspectable var tapAction: String?
private var actions: NSObject?
override func awakeFromNib() {
// initialize actions class
let bundleName = Bundle.main.bundleIdentifier!.components(separatedBy: ".").last!
let className = "\(bundleName).\(actionClass!)"
guard let targetClass = NSClassFromString(className) as? NSObject.Type else {
print("Class \(className) not found!")
return
}
self.actions = targetClass.init()
// create tap gesture
let tap = UITapGestureRecognizer(target: self, action: #selector(pressed(_:)))
self.addGestureRecognizer(tap)
}
func pressed(_ sender: UIGestureRecognizer) {
actions!.perform(Selector(tapAction!))
}
}
And, set attributes of your button:
You can change the Tap Action in run time, for example:
#IBAction func buttonChangeAction(_ sender: Any) {
buttonMyControl.tapAction = textField.text!
}
Maybe you can change my code to pass parameters, but... it's you want?