I'm trying to use a regular expression with the command sed to substitute any 8 consecutive digits with a specific 8 digits in a whole file. I'm not sure if this is the correct way to do it but I keep getting an error saying the command is unterminated. Any idea why ?
sed -i 's/d\{8\}/20170526' ./somefolder/somefile.xml
the error says char17 which corresponds to the / before 20170526
You need 3 separators (a slash in your case) for a sed switch statement.
sed -eE 's/[0-9]{8}/20170526/' ./somefolder/somefile.xml
Related
This question already has answers here:
How to pass a variable containing slashes to sed
(7 answers)
Closed 1 year ago.
I have this as variable
set var=1920 x 1080p / 23.976 fps /16:9 / High Profile 4.1
and i will replace with sed
sed -e "s/1920/%var%/" movie.txt > movie2.txt.nfo
error output is
ed: -e expression #1, char 30: unknown option to `s'
I do not understand what's wrong
Regards
The problem is with slashes. Your final command will have many slashes coming from the variable itself, which will be confused with the / delimiter you provided in the sed command itself.
Luckily, sed can have any char as the delimiter. Change to something like:
sed -e "s-1920-%var%-"
Now, - won't be confused with / (from the variable).
This sed works, to replace the value for Java home in a shell script:
sed -i 's#^JAVA_HOME=.*$#JAVA_HOME="/usr/lib/jvm/java-1.7.0-oracle.x86_64"#' /apps/tempbsu.sh
but now I am trying to use/invoke that sed from inside a Perl app, using qx():
qx(sed -i 's#^JAVA_HOME=.*$#JAVA_HOME="/usr/lib/jvm/java-1.7.0-oracle.x86_64"#' /apps/tempbsu.sh);
and when I do that, I am getting an error:
sed: -e expression #1, char 58: unterminated `s' command
From checking, I gather that error is happening because the sed is missing the last delimiter, but it seems like it is correct, i.e.:
sed -i 's#.....#.......#' /apps/tempbssu.sh
Can someone tell me why this sed is failing with I use in a qx() in Perl?
$#JAVA_HOME is treated as a Perl variable (the number of the last element of the array variable). Escape it: \$#JAVA_HOME
I'm running the following in my provisioner
sed -i 's/DocumentRoot \/var\/www\/DocumentRoot \/var\/www\/app\/web-root\/\g' /etc/apache2/sites-available/000-default.conf
however I'm getting the error: sed: -e expression #1, char 69: unterminated 's' command - which is a hyphen (-) at that position. I've tried escaping it (\-) to no avail.
Any ideas?
your line:
sed -i 's/DocumentRoot \/var\/www\/DocumentRoot \/var\/www\/app\/web-root\/\g ...
^
sed needs s/.../.../g you have escaped the last / before g flag, more than that, you escaped g flag too. At least this mistake won't let your sed command go.
what better is, you pick another delimiter, if your pattern/replacement containing /(slash) too. It can save those dozens back slashes:
sed -i 's#foo/bar/blah#foo1/bar1/blah1#g` file
I have a config file I need to change (again) and the line is
set wrapper_code=C:\windows\drivers\cache
I need to change it to
set wrapper_code=/home/harry/solo/run
I wrote
cat Proxy.bat | sed -i.bk -e 's/\(^set wrapper_home\=\).*/\/home/'1${dbuser}'/gateway/service\' Proxy.bat
I get an error message
sed: -e expression #1, char 37: unknown option to `s'
What is wrong with my code string
If you are using / as the pattern separator is sed, you have to escape the slashes in the strings (paths). To avoid it, use a different separator:
sed -i.bk -e 's%\^set wrapper_code=C:\\windows\\drivers\\cache%set wrapper_code=/home/harry/solo/run%' Proxy.bat
You also have to escape backslashes, as they have a special meaning in sed.
The cat part is useless.
I'd like to replace all the \r\n with < br/ >in a document, and I'm trying this see script below
# sed -i 's/\r\n/<br/>' ~/xxd/*
however i got this error back
sed: -e expression #1, char 12: unknown option to `s'
How do i solve this problem?
Thanks!
Your problem is that you have the / separator in your replacement string so sed is assuming that's the end of your replacement, and that the > following it is a flag.
If your sed is modern enough, just use a different separator character, one that's not in the replacement string:
pax$ echo hello | sed -e 's/e/<br />/'
sed: -e expression #1, char 9: unknown option to `s'
pax$ echo hello | sed -e 's?e?<br />?'
h<br />llo
Alternatively, you can escape the offending character but I try to avoid that since it tends to lead to overly sawtooth sed commands like /\/\/\/\/\/\.
The other thing you may want to watch out for is trying to use \n in your regex since sed operates on lines anyway. If your intent is to just strip carriage returns and insert HTML line breaks, then the following sed command may be better:
s?\r$?<br />?