Extracting Object from Some() and Using it - scala

Question

In the below code, encoded is a JSON string. The JSON.parseFull() function is returning an object of the form: Some(Map(...)). I am using .get to extract the Map, but am unable to index it as the compiler sees it as type Any. Is there any to provide the compiler visibility that it is, in fact, a map?
val parsed = JSON.parseFull(encoded)
val mapped = parsed.get

Answer 1

You can utilize the collect with pattern matching to match on the type:
scala> val parsed: Option[Any] = Some(Map("1" -> List("1")))
parsed: Option[Any] = Some(Map(1 -> List(1)))
scala> val mapped = parsed.collect{
case map: Map[String, Any] => map
}
mapped: Option[Map[String,Any]] = Some(Map(1 -> List(1)))
You can do something like the following in the case of a List value to get values from the List:
scala> mapped.get.map{ case(k, List(item1)) => item1}
res0: scala.collection.immutable.Iterable[Any] = List(1)

Answer 2

I was able to use a combination of the get function and pattern matching similar to what was posted in Tanjin's response to get the desired result.
object ReadFHIR {
def fatal(msg: String) = throw new Exception(msg)
def main (args: Array[String]): Unit = {
val fc = new FhirContext()
val client = fc.newRestfulGenericClient("http://test.fhir.org/r2")
val bundle = client.search().forResource("Observation")
.prettyPrint()
.execute()
val jsonParser = fc.newJsonParser()
val encoded = jsonParser.encodeBundleToString(bundle)
val parsed = JSON.parseFull(encoded)
val mapped: Map[String, Any] = parsed.get match{
case map: Map[String, Any] => map
}
println(mapped("resourceType"))
}
}