Create table with stored function postgresql - postgresql

Question

I have a query for create table like below
DROP TABLE IF EXISTS BAJUL;
CREATE TABLE BAJUL AS (
SELECT dt_trx, row_number() OVER (ORDER BY dt_trx DESC) AS row_number
FROM stock_trx_idx
WHERE dt_trx BETWEEN '2017-01-01' AND '2017-02-28'
GROUP BY 1
ORDER BY 1 DESC);
How able to create above table with stored function in Postgresql?
I tried with below script
CREATE OR REPLACE FUNCTION my_function (dt1 DATE, dt2 DATE)
RETURNS VOID AS
$func$
BEGIN
EXECUTE format('
DROP TABLE IF EXISTS tblq;
CREATE TABLE IF NOT EXISTS tblq AS(
SELECT dt_trx, row_number() OVER (ORDER BY dt_trx DESC) AS row_number
FROM stock_trx
WHERE dt_trx BETWEEN dt1 AND dt2
GROUP BY 1
ORDER BY 1 DESC
)' );
END
$func$ LANGUAGE plpgsql;
but when I try to execute SF like below
SELECT my_function ('2017-01-01', '2017-02-28');
I got error --> ERROR: column "dt1" does not exist
Would like to seek your help.
Thanks & rgds,
Bayu

Answer 1

Use
format('CREATE ... WHERE dt_trx BETWEEN %L AND %L ...', dt1, dt2)

Answer 2

You error is obvious. In the SELECT statement,
SELECT dt_trx, row_number() OVER (ORDER BY dt_trx DESC) AS row_number
FROM stock_trx
WHERE dt_trx BETWEEN dt1 AND dt2
GROUP BY 1
ORDER BY 1 DESC
The dt1 column doesn't exist. You didn't tell him you wanted to use your variable. Try concatenate your string with your variables.
By the way, you can drop your ORDER BY if your creating a table with that statement.