7-zip extracted files not showing up when called from command line - command-line

I am attempting to write a command that calls 7-zip from the command line. My command is:
7z x z:\dev\archive.7z
Anytime I run this command in the command prompt, it acts like it's working, but when I navigate to the folder after the fact, the extracted files aren't there, although they are there if I run 7-zip from the contextual menu. Is there something I'm missing here?

If you don't specify a destination directory, 7z will extract files in your current directory.
As per the doc, to specify a target:
7z x archive.zip -oC:\path\to\target
Or use cd C:\path\to\target and then invoke your initial command.
In your case (from comments), what you want is:
7z x z:\dev\archive.7z -oz:\dev
This nice answer might help if you're confused with the options.

Try using the -spf switch
7z x z:\dev\archive.7z -spf

Related

How to create mask in winrar to archive folders by name?

I have folders C:\testA01, C:\testA02 and C:\testB01, C:\testB02.
How to create a command to archive only folders with testA in their name?
"C:\Program Files\WinRAR\WinRAR.exe" a -r -u -rr8 -y C:\BACKUP\backup.rar C:\testA ?? \*.*
Windows command line interpreter does not support wildcards in folder paths. It is only possible to search for folders matching a pattern with DIR or FOR.
But take a look on text file WhatsNew.txt in program files directory of WinRAR version 5.30 or any later version. There can be read:
Folder wildcards are allowed in RAR command line in file names to
archive. For example:
rar a backup c:\backup\2015*\*
will archive all '2015*' folders in c:\backup. Use -r switch to search
for '2015*' also in c:\backup subfolders.
WinRAR v5.30 can be used on Windows XP and later Windows.
A command line for your backup task is for example:
"%ProgramFiles%\WinRAR\Rar.exe" u -cfg- -ep1 -idq -r -rr8 -y C:\BACKUP\backup.rar C:\testA*\*
For details on the used command u which is like command a with switch -u and the used switches see text file Rar.txt being the manual for the console version Rar.exe of WinRAR.
Of course you can also run from command line the GUI version, but one switch must be changed:
"%ProgramFiles%\WinRAR\WinRAR.exe" u -cfg- -ep1 -ibck -r -rr8 -y C:\BACKUP\backup.rar C:\testA*\*
The switch -ibck for running GUI version in background (minimized to system tray) is used instead of -idq which means for console version to run in quiet mode with only error messages printed into console window.
The commands and switches for the GUI version with some differences to console version are explained in help of WinRAR. Start WinRAR, click in menu Help on menu item Help topics, select tab Contents, open item Command line mode and read the pages listed below this list item.

7zip / winrar command to extract a folder with path intact to specific folder but excluding parent source path

example
There is a file "sample.rar".
Folder structure is: "rising\dawn\ and here there are many (folders1, folders2 and file1, file2)" in this archive.
i have used following command
7z.exe x "sample.rar" "rising\dawn\*" -oi:\delete
The result is:
all files and folders in "rising\dawn\" are extracted to "i:\delete" folder but the empty parent folders "rising\dawn\" are also created in destination folder.
e.g. destination looks:
i:\delete\rising\dawn\folder1\file1.bmp
i:\delete\rising\dawn\folder2\subfolder
i:\delete\rising\dawn\file1.txt
i:\delete\rising\dawn\file2.txt
i don't want "rising\dawn\" empty folders to be created but the folder structure there onwards must be as is in the archive.
i want the result:
i:\delete\folder1\file1.bmp
i:\delete\folder2\subfolder
i:\delete\file1.txt
i:\delete\file2.txt
at last i found a way out solution. thanks to the winrar support. i have accepted it as an answer below.
if you find the question useful don't forget to click the up-vote button.
Finally this gave me the result.
Thanks to winrar support.
rar x -ep1 sample.rar rising\dawn\* d:\e\delete\
i have tried other answers given here, this is the only correct answer.
don't forget to upvote.
You can extract the archive normally and
1) move the lower level folder/files to where you would like it, then
2) remove the extra top level archive folders.
Code to do so will depend on the exact task.
Using e command instead of x and add -r option works well.
Like this:
7z.exe e -r "sample.rar" "rising\dawn\*" -oi:\delete
My executable version is "7-Zip [64] 9.20 2010-11-18",
And the platform is Windows 8.1.
This command line eliminates unnecessary parent folders and preserves the hierarchy of folders.
You need to use the e command rather than the x command:
7z.exe e "sample.rar" "scholar\update\*" -oi:\delete
Using e instead of x means 7zip will extract all matching files into the same folder (as specified via the -so switch, or the current directory if this isn't specified) rather than preserving the folder structure from inside the archive.

How do I silently install a 7-zip self-extracting archive to a specific directory?

The Ruby Devkit is a 7-zip based self-extracting archive.
I would like to invoke it silently without having to install 7-Zip to extract the files to a folder of my choosing, so that I can script the installation. I imagine it to be something like:
cmd> DevKit-tdm-32-4.5.2-20111229-1559-sfx.exe /silent /dir="C:\DevKit"
But that, of course, doesn't work. What command line flags must I use to silently extract this archive into a folder of my choice?
try this:
C:\> DevKit-tdm-32-4.5.2-20111229-1559-sfx.exe -o"C:\DevKit" -y
Update 2017: The tool from 7zsfx.info is now dead and gone.
Original, old post from 08-2015:
If you are trying to extract an 7zip SFX (http://7zsfx.info/) archive:
sfx.exe -y -gm2 -InstallPath="C:\\your\\target\\path"
Switches Docu
-y hide some prompts
-gm2 hides the extraction dialog completely (silent mode)
-InstallPath sets the target path (you need double backslashes)
7z SFX Guide
The official way to create a SFX package is to use -sfx[{name}] : Create SFX archive.
And that means the created SFX packages uses two kinds of CLI options:
official CLI options from 7zSFX, and
the passed through options you configured in your config, before creating the package.
You can think of it as parameter forwarding to the packaged executable. This parameter forwarding depends on the SetEnvironment and RunProgramm configuration!
The full process:
Create archive Package.7z:
containing Installer.msi and additional crap.cab file.
Create config file config.txt:
;!#Install#!UTF-8!
Title="Installation"
SetEnvironment="strInstall=hidcon:Installer.msi /qn"
RunProgram="%strInstall%"
;!#InstallEnd#!
Now we generate Test.exe by combining sfx+config+archive into an executable.
copy /b 7zS.sfx + config.txt + Package.7z SfxInstaller.exe
Note: 7zS.sfx is from the official 7zip extra package.
Now, when you run SfxInstaller.exe you can pass for instance /lv InstallerLog.txt to create a install log, e.g.
SfxInstaller.exe /lv InstallerLog.txt
Since 7-zip is used, simply create a self-extracting archive in .exe. and run it with switches -o and -y.
I use it to save space on USB drive. For instance, I run VDiskAir application infrequently. I create a self-extracting archive of the VDiskAir program folder (about 15MB):
7z a -SFX -mx9 VDiskAir.exe [VDiskAir folder path]
NB: -mx9 is used here to maximise compression.
I create a DOS BAT to run the self-extracting VDiskAir.exe (about 5MB) created, save it as VDiskAir.bat containing:
VDiskAir.exe -o%TMP% -y
%TMP%\VDiskAir\VDisk_Air.exe
I'm not worried that the VDiskAir folder (in %TMP% extracted with VDiskAir program files) is undeleted after running VDiskAir this way, since I have a BAT script to clear %TMP% on shutting down/starting up.
Below is what I use for Autodesk product:
Start /W %~dp0AutoCAD_2018_French_LP_Win_64bit_dlm.sfx.exe -suppresslaunch -d C:\Autodesk

Matlab function call directory

So i had this issue that occurred when I ran a Matlab script. Here is an a simple example that illustrates it:
So its important to outline the file structure:
MainFolder
script.m
SubFolder
a1.csv
a2.csv
a3.csv
now say i have a script like this:
-> script.m
dir
it would simply print out the files in the folder.
Now the wierd thing, if i run the script in the Subfolder like this:
>>script
it will do this:
>> a1.csv a2.csv a3.csv
but if i do this in the folder:
>>run('C:\Users\....\MainFolder\script.m')
it will only print out
>> script.m
So obviously it is acting as if i ran it form MainFolder rather than SubFolder.
What is the point of this functionality?
The dir command shows the directory contents of Matlab's current directory, not that of where the script is located. So the script showed you the directory contents of wherever you happened to be in the Matlab command prompt when you called that script.
To get what you want, use this in the script:
dir(fileparts(mfilename('fullpath')))
Use pwd to see current dir
Use cd to change directory
Use path to see if your project folders are included in the path
Use which to see you are calling the right *.m file (in case there is multiple .m files with same name on the path)

Compressing only files using 7z without preserving the path

I am using 7z command line executable to zip files, but I see that while adding to an archive the path of the files is preserved in the archive.
So if I do
7z a -tzip myzip.zip dir1\dir2\*
the archive myzip.zip will contain the path dir1\dir2. I do not want this, rather I want only the files to be added to the zip file without the paths being preserved.
I searched quite a bit but do not seem to find any way of doing this, maybe I am missing something obvious?
Thanks
Just add a dot before the path, i.e.
7z a -tzip -r myzip.zip .\Relative\Dir\*
Give the full path. That should work. Not the relative path from the current location.
For example, I give the below, where I want the files in the man5 folder to be archived.
$ 7z a -tzip myzip.zip /home/pradeeban/Desktop/man4/man5/*
The zip contained only the files, without the directories.
Then I gave only the relative path. It had the directories, inside the zip.
$ 7z a -tzip myzip.zip Desktop/man4/man5/*
Tried with Linux (Ubuntu 12.04). Not sure whether that differs from Windows.
I discovered a way to do this by using a relative path:
7z a -tzip myzip.zip %CD%\dir1\dir2\*
%CD% is how you get the current path in a Windows batch file, but it also works from the command line. More info about Capturing the current directory from a batch file.
As explained in related question in 7-zip user FAQ, 7z stores paths relative to working directory, so you will need to first cd to desired top-level directory for archive and run 7-zip from here.
cd dir1\dir2\
7z a -tzip myzip.zip *
If you run it from script and don't want to affect it with changed directory, use directory push/pop facilities available in your shell of choice or run cd+7-zip in spawned process to avoid affecting your entire script with changed directory. For example, using Windows' start that would be:
start /D dir1\dir2\ /wait 7z a -tzip myzip.zip *
This worked for me
Consider folder structure like C:\Parent\SubFolders..... And you want to create parent.zip which will contain all files and folders C:\Parent without parent folder [i.e it will start from SubFolders.....]
cd /D "C:\Parent"
"7z.exe" a Parent.zip "*.*" -r
This will create Parent.zip in C:\Parent