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I want to know what this line of code does.
ind_x = [1,3:5:size(paths,2)]
What would ind_x contain after this line? I already know that size(paths,2) means the size of second dimension of paths matrix.
3:5:size(path,2) returns a vector which starts from 3 to size(path,2) with steps 5. For example, if size(path,2) is equal to 20, the result would be:
ind_x
[1 3 8 13 18]
As you can see it counts from 3 to size(path,2) with step size 5 (3, 8, 13, ...).
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I have tried to create vector matrix array, to add integer elements after their arrival.
a={[1 1 1 1 1]; [3 3 3 3 3 3 3 3 3]; [4 4]; [5]};
print(a);
That code gives me this error:
You should take a look at the documentation for print. It is used to:
Print figure or save to specific file format
What you want is either disp which is used to
Display value of variable
Or fprintf which is used to:
Write data to text file (which can be the console)
Or even simpler: Just write
a % Note the absence of ';'
Upon encountering an operation without semicolon, MATLAB aromatically displays the result in the console. So this is enough to print you variable.
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I understand how the program works but I have a little bit of confusion. If anybody can explain, that will be great. The output is 21, 12. Does it work like 7*3=21 and 4*3=12?
mat=[7 11 3; 3:5];
[r,c]=size(mat);
for i=1:r
fprintf ('The sum is %d\n',sum(mat(i,:)))
end
mat(i,:) will give you all values in the first row of mat. In your example, this first row is [7 11 3], and the second row is [3 4 5]. The outputs you're seeing are the sums of all values in each row (7+11+3=21).
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I got a few Matlab code to play. But the answer is not correct:
x = linspace(-pi, pi, 10)
sinc = #(x) sin(x) ./ x
sinc(x) // wrong result occurs at here.
The expected result as below:
ans =
Columns 1 through 6:
3.8982e-17 2.6306e-01 5.6425e-01 8.2699e-01 9.7982e-01 9.7982e-01
Columns 7 through 10:
8.2699e-01 5.6425e-01 2.6306e-01 3.8982e-17
real result:
ans =
Columns 1 through 3
0.000000000000000 0.263064408273866 0.564253278793615
Columns 4 through 6
0.826993343132688 0.979815536051016 0.979815536051016
Columns 7 through 9
0.826993343132688 0.564253278793615 0.263064408273866
Column 10
0.000000000000000
details: My OS is arch linux,
Matlab is downloaded through official website.
matlab version is 2015b
The expected result and the real results you present are identical as far as I can see.
The only difference is the notation: normal vs scientific.
With format short you can switch to scientific notation and get identical results with identical formatting.
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In MATLAB, how can I fetch all the element in A but not in B?
If
A = [1 2 3 4 5 6 7 8];
B = [1 2 3];
I hope the answer to be [4 5 6 7 8].
It sounds like you need setdiff().
As Oli stated you can use setdiff, however a little faster way to perform the same operation is
C = A(~ismember(A, B));
setdiff also sorts the resulting array, if you need this you have to sort C in the above statement
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I have the following data: ET = [1 3 5 7 6 4], and below is my code:
for i=1:3
meanET(i)=ET(:,1+(2*i-2)); %//for i=1,extract ET column 1 data
stdET(i)=ET(:,2+(2*i-2));
totalET(i)=meanET(i)+stdET(i)
end
However, MATLAB display's an error that says that in the assignment A(I)=B, the number of elements in B and I must be the same, and therefore I modified my code to this:
for i=1:3
meanET=ET(:,1+(2*i-2));%for i=1,extract ET column 1 data
stdET=ET(:,2+(2*i-2));
totalET=meanET+stdET
end
After running the latter code, it showed meanET=6, stdET=4, and totalET=10, which means that it only stored the data for i=3 in the workspace. I want to get the result like
totalET=[4 12 10] in the workspace, corresponding to i = 1, 2, 3. How do I do that?
OR you could just go with a simple vectorized solution:
>> totalET = ET(1:2:5) + ET(2:2:6)
totalET =
4 12 10
you should just declare your target array at the beginning of your code:
meanET=zeros(size(ET,1),3);
stdET=zeros(size(ET,1),3);
for i=1:3
meanET(:,i)=ET(:,1+(2*i-2));
stdET(:,i)=ET(:,2+(2*i-2));
end
totalET=meanET+stdET