Querying EXISTS in many to many relations in Criteria API - jpa

Question

Having two entity classes with a many to many relation, I am trying to create query which tests the existence of any relationship for all entities from one table. I am stuck because it seems that there is no way to refer to the JoinTable through the Criteria API.
Example entities:
#Entity
#Table(name="man")
public class Man {
#Id
#GeneratedValue
private Long id;
}
#Entity
#Table(name="woman")
public class Woman {
#Id
#GeneratedValue
private Long id;
#ManyToMany
#JoinTable(
name="man_woman",
joinColumns=
#JoinColumn(name="woman_id", referencedColumnName="id"),
inverseJoinColumns=
#JoinColumn(name="man_id", referencedColumnName="id")
)
private Set<Man> men;
}
I would like to create a query using criteria API which would result in SQL such as:
select m.id,
case when exists(select * from man_woman mw where mw.man_id=m.id) then 1 else 0
from man;
The best I have come up with so far is the following:
CriteriaQuery<Tuple> criteriaQuery = criteriaBuilder.createTupleQuery();
Root<Man> from = criteriaQuery.from(Man.class);
Subquery<Long> subquery = criteriaQuery.subquery(Long.class);
Root<Woman> sub_from = subquery.from(Woman.class);
SetJoin<Woman, Man> setJoin = sub_from.join(Woman_.men);
subquery.select(sub_from.get(Woman_.id));
subquery.where(from.in(setJoin.get(Man_.id)));
criteriaQuery.multiselect(from.alias("man_entity"),
criteriaBuilder.selectCase()
.when(
criteriaBuilder.exists(subquery)
, true)
.otherwise(false)
.alias("knows_any_women")
);
return em.createQuery(criteriaQuery).getResultList()
which results in SQL containing extra joins:
select m.id,
case when exists(select w.id
from woman w
inner join man_woman mw on w.id = mw.woman_id
inner join man m2 on m2.id = mw.man_id
where m.id in (m2.id)
)
then 1 else 0
from man;
I guess this statement would eventually be optimized to look like my desired one - but is there a way to make it simpler from the beginning?