Perl reference not printing the expected value - perl

Question

This is my program but why not it is printing my array values instead.
use strict;
use warnings;
use Data::Dumper;
my (#arr1,#arr2) = ([1,1,1,2,3,4],[5,5,5,6,9,87]);
my #arr3 = [\#arr1,\#arr2];
foreach (#arr3){
foreach (#$_){
print $_;
}
}
Output:
ARRAY(0x556414c6b908)ARRAY(0x556414c6b7e8)
but why not it is printing my array values instead.

Answer 1

Because the values are array references. To print the inner values, use dereference:
print #{ $array_ref };
For complex structures (arrays of arrays), you can use Data::Dumper:
use Data::Dumper;
print Dumper($array_ref);
But it still wouldn't work. You can't assign to several arrays at once. The first array gets all the values, the remaining arrays stay empty.
Documented in perlsub:
Do not, however, be tempted to do this:
(#a, #b) = upcase(#list1, #list2);
Like the flattened incoming parameter list, the return list is also
flattened on return. So all you have managed to do here is stored
everything in #a and made #b empty.

Answer 2

First of all, you weren't assigning anything to #arr2. You used something like the following to try to assign to #arr2:
(#arr1, #arr2) = ...;
However, Perl has no way to know how many scalars to assign to #arr1 and how many to assign to #arr2, so it assigns them all to #arr1. Use two different assignments instead.
Secondly, [ ] creates an array and returns a reference to it, so
my #arr1 = [1,1,1,2,3,4];
assigns a single scalar (a reference) to #arr1. This is what you are printing. You want
my #arr1 = (1,1,1,2,3,4);
Same goes for #arr2 and #arr3.
Therefore, your code should be
use strict;
use warnings;
use feature qw( say );
my #arr1 = (1,1,1,2,3,4);
my #arr2 = (5,5,5,6,9,87);
my #arr3 = (\#arr1,\#arr2);
for (#arr3) {
say join ", ", #$_;
}
or
use strict;
use warnings;
use feature qw( say );
my #arr3 = ([1,1,1,2,3,4],[5,5,5,6,9,87]);
for (#arr3) {
say join ", ", #$_;
}