In Sencha in a child window I obtain an id of an image, how can I then pass the image id to a text field in a parent window. I go to the child window with a button click, and would like to display the id of the chosen image in a text field above the button.
Thanks.
You would pass a textfield reference to the window during window creation, and when the button is clicked, you use that reference:
xtype: 'textfield',
},{
xtype:'button',
text: 'Get Image'
handler: function(btn) {
Ext.create('Ext.window.Window',{
textfieldReference: btn.previousSibling('textfield'),
buttons:[{
text: 'OK',
handler: function(okBtn) {
okBtn.up('window').textfieldReference.setValue(imageId);
}
}]
})
}
Related
I am trying to manipulate the html content of text that is selected in the editor. tinymce.activeEditor.getContent({format: 'html'}); grabs all of the html content in the editor which is great but I want the html of selected/highlighted text. I was under the impression that using tinymce.activeEditor.selection.getContent({format: 'html'}); would achieve this but it only returns html if all of the text in the editor is selected.
Here is my code:
setup: function (ed) {
ed.addButton('customFormatSelect', {
type: 'menubutton',
text: 'Formats',
icon: false,
menu: [{
text: 'Get HTML',
icon: false,
onselect: function() {
alert(tinymce.activeEditor.selection.getContent({format: 'html'}));
}
}]
});
}
I have tried using onclick instead of onselect and still get the same result.
Here are some screenshots of the issue:
Here is me selecting the text I want the HTML from and clicking my 'Get HTML' button:
Image 1
Here is the alert that I get:
Image 2
How can i make (Text Field + three buttons) as default child controls for my custom ui5 control.Whenever my custom control loads, it should render (text field + three buttons) inside my custom control by default.
Regards,
Karthik S
in events: onholdevent": {},
in agrredation:
"button": {
type: "sap.m.Button",
multiple: false
},
in onIt:
this.setAggregation("button", new sap.m.Button({
text: "On Press",
press: function() {
that.fireOnholdevent(this);
}
}));
in render : oControl.getAggregation("button");
main thing is the this refrence , through 'this' you can get in controller which button is clicked .In the view just give the event name and refrence it in controller.
I created an action sheet containing some options
when I select an option I want it to be highlighted.
I took the code from here
https://ionicframework.com/docs/components/#action-sheets
can someone help me please
You can use some (S)CSS to style it with a pseudo-class like :active or :hover. To include your own CSS classes to the action sheet you could use its cssClass property when creating it. Like so:
let actionSheet = this.actionSheetCtrl.create({
title: 'Ionic Action Sheet',
cssClass: 'your-custom-class',
buttons: [
{
text: 'Button 1',
cssClass: 'custom-button-1-class',
handler: () => {
console.log("Button 1 picked!");
}
}
]
});
By doing that, you can use custom CSS classes to style each button (option) of your action sheet, as well as the action sheet itself. If you wanted to, say, make Button 1 have a black background whenever a user "activated" it, you could write:
.custom-button-1-class:active {
background-color: black;
}
I have an extjs menu, in which, upon clicking a button, a colorPicker is opened.
When a color is selected, onColorPickerSelect: function(colorpicker, color, eOpts) springs into action. How do I select the button element in this function, taking the value of the colorpicker variable as my start point?
items: [
{
xtype: 'button',
itemId: 'color1',
style: 'background-color:#fc0;',
text: '1. Farbe',
menu: {
xtype: 'colormenu',
listeners: {
select: {
fn: me.onColorPickerSelect,
scope: me
}
}
}
}
]
As I answer in your previous question, use var button = colorpicker.up('button');
onColorPickerSelect: function(colorpicker, color, e0pts) {
var button = colorpicker.up('button');
button.getEl().setStyle('background-color', '#' + color);
}
When moving between panels I get the following error
[WARN][Ext.Component#constructor] Registering a component with a id (`logOutButton`) which has already been used. Please ensure the existing component has been destroyed (`Ext.Component#destroy()`.
I can go back to the previous screen but the cannot go forward again without getting the above error.
To combat this I have tried using the code below, but it does not work. Can anyone help me out?
var loginView = Ext.getCmp('login');
if(!loginView){
Ext.getCmp('loginTest2').destroy();
loginView = Ext.create('com.view.Login');
}
Ext.Viewport.setActiveItem('login');
I also tried:
if(Ext.getCmp('login')){
Ext.Viewport.setActiveItem('Login');
}else{
Ext.Viewport.setActiveItem(Ext.create('com.view.Login'));
}
Neither of these work and result in the same error and a blank screen. I am using Sencha Touch 2.
we can simply use following line to navigate from one panel to another..
Ext.Viewport.animateActiveItem({ xtype: "cat" }, { type: "slide", direction: "up" });
here, xtype is that we can define for the panel we want to display, like this...,
Ext.define('BeLocal.view.LeftCurveList', {
extend: 'Ext.Panel',
**xtype: 'cat',**
config: {
items: [
{
xtype: 'toolbar',
docked: 'top',
width: '100%',
padding:0,
title: 'BeLocal Places',
items:[{
xtype: 'button',
ui: 'back',
text: 'Back',
]
},
]
}
});
To avoid this error do not use id for button or any other item instead of id use action config for button or use item id .to destroy a component using itemId simply use this`
Ext.ComponentQuery.query('list[action=diaryselectlist]')[0].destroy();
above it just destroying a list to whom i gave action not id you can give itemId instead of action in this ..
hope you will enjoy this