How to append List[String] to every row of DataFrame? - scala

After a series of validations over a DataFrame,
I obtain a List of String with certain values like this:
List[String]=(lvalue1, lvalue2, lvalue3, ...)
And I have a Dataframe with n values:
dfield 1 | dfield 2 | dfield 3
___________________________
dvalue1 | dvalue2 | dvalue3
dvalue1 | dvalue2 | dvalue3
I want to append the values of the List at the beggining of my Dataframe, in order to get a new DF with something like this:
dfield 1 | dfield 2 | dfield 3 | dfield4 | dfield5 | dfield6
__________________________________________________________
lvalue1 | lvalue2 | lvalue3 | dvalue1 | dvalue2 | dvalue3
lvalue1 | lvalue2 | lvalue3 | dvalue1 | dvalue2 | dvalue3
I have found something using a UDF. Could be this correct for my purpose?
Regards.

TL;DR Use select or withColumn with lit function.
I'd use lit function with select operator (or withColumn).
lit(literal: Any): Column Creates a Column of literal value.
A solution could be as follows.
val values = List("lvalue1", "lvalue2", "lvalue3")
val dfields = values.indices.map(idx => s"dfield ${idx + 1}")
val dataset = Seq(
("dvalue1", "dvalue2", "dvalue3"),
("dvalue1", "dvalue2", "dvalue3")
).toDF("dfield 1", "dfield 2", "dfield 3")
val offsets = dataset.
columns.
indices.
map { idx => idx + colNames.size + 1 }
val offsetDF = offsets.zip(dataset.columns).
foldLeft(dataset) { case (df, (off, col)) => df.withColumnRenamed(col, s"dfield $off") }
val newcols = colNames.zip(dfields).
map { case (v, dfield) => lit(v) as dfield } :+ col("*")
scala> offsetDF.select(newcols: _*).show
+--------+--------+--------+--------+--------+--------+
|dfield 1|dfield 2|dfield 3|dfield 4|dfield 5|dfield 6|
+--------+--------+--------+--------+--------+--------+
| lvalue1| lvalue2| lvalue3| dvalue1| dvalue2| dvalue3|
| lvalue1| lvalue2| lvalue3| dvalue1| dvalue2| dvalue3|
+--------+--------+--------+--------+--------+--------+

Related

How to find similar rows by matching column values spark?

So i have a data set like
{"customer":"customer-1","attributes":{"att-a":"att-a-7","att-b":"att-b-3","att-c":"att-c-10","att-d":"att-d-10","att-e":"att-e-15","att-f":"att-f-11","att-g":"att-g-2","att-h":"att-h-7","att-i":"att-i-5","att-j":"att-j-14"}}
{"customer":"customer-2","attributes":{"att-a":"att-a-9","att-b":"att-b-7","att-c":"att-c-12","att-d":"att-d-4","att-e":"att-e-10","att-f":"att-f-4","att-g":"att-g-13","att-h":"att-h-4","att-i":"att-i-1","att-j":"att-j-13"}}
{"customer":"customer-3","attributes":{"att-a":"att-a-10","att-b":"att-b-6","att-c":"att-c-1","att-d":"att-d-1","att-e":"att-e-13","att-f":"att-f-12","att-g":"att-g-9","att-h":"att-h-6","att-i":"att-i-7","att-j":"att-j-4"}}
{"customer":"customer-4","attributes":{"att-a":"att-a-9","att-b":"att-b-14","att-c":"att-c-7","att-d":"att-d-4","att-e":"att-e-8","att-f":"att-f-7","att-g":"att-g-14","att-h":"att-h-9","att-i":"att-i-13","att-j":"att-j-3"}}
I have flattened the data in the DF like this
+--------+--------+--------+--------+--------+--------+--------+--------+--------+--------+-----------+
| att-a| att-b| att-c| att-d| att-e| att-f| att-g| att-h| att-i| att-j| customer|
+--------+--------+--------+--------+--------+--------+--------+--------+--------+--------+-----------+
| att-a-7| att-b-3|att-c-10|att-d-10|att-e-15|att-f-11| att-g-2| att-h-7| att-i-5|att-j-14| customer-1|
| att-a-9| att-b-7|att-c-12| att-d-4|att-e-10| att-f-4|att-g-13| att-h-4| att-i-1|att-j-13| customer-2|
I want to complete the comapreColumns function.
which compares the columns of the two dataframes(userDF and flattenedDF) and returns a new DF as sample output.
how to do that? Like, compare each row's and column in flattenedDF with userDF and count++ if they match? e.g att-a with att-a att-b with att-b.
def getCustomer(customerID: String)(dataFrame: DataFrame): DataFrame = {
dataFrame.filter($"customer" === customerID).toDF()
}
def compareColumns(customerID: String)(dataFrame: DataFrame): DataFrame = {
val userDF = dataFrame.transform(getCustomer(customerID))
userDF.printSchema()
userDF
}
Sample Output:
+--------------------+-----------+
| customer | similarity_score |
+--------------------+-----------+
|customer-1 | -1 | its the same as the reference customer so to ignore '-1'
|customer-12 | 2 |
|customer-3 | 2 |
|customer-44 | 5 |
|customer-5 | 1 |
|customer-6 | 10 |
Thanks

Spark creating a new column based on a mapped value of an existing column

I am trying to map the values of one column in my dataframe to a new value and put it into a new column using a UDF, but I am unable to get the UDF to accept a parameter that isn't also a column. For example I have a dataframe dfOriginial like this:
+-----------+-----+
|high_scores|count|
+-----------+-----+
| 9| 1|
| 21| 2|
| 23| 3|
| 7| 6|
+-----------+-----+
And I'm trying to get a sense of the bin the numeric value falls into, so I may construct a list of bins like this:
case class Bin(binMax:BigDecimal, binWidth:BigDecimal) {
val binMin = binMax - binWidth
// only one of the two evaluations can include an "or=", otherwise a value could fit in 2 bins
def fitsInBin(value: BigDecimal): Boolean = value > binMin && value <= binMax
def rangeAsString(): String = {
val sb = new StringBuilder()
sb.append(trimDecimal(binMin)).append(" - ").append(trimDecimal(binMax))
sb.toString()
}
}
And then I want to transform my old dataframe like this to make dfBin:
+-----------+-----+---------+
|high_scores|count|bin_range|
+-----------+-----+---------+
| 9| 1| 0 - 10 |
| 21| 2| 20 - 30 |
| 23| 3| 20 - 30 |
| 7| 6| 0 - 10 |
+-----------+-----+---------+
So that I can ultimately get a count of the instances of the bins by calling .groupBy("bin_range").count().
I am trying to generate dfBin by using the withColumn function with an UDF.
Here's the code with the UDF I am attempting to use:
val convertValueToBinRangeUDF = udf((value:String, binList:List[Bin]) => {
val number = BigDecimal(value)
val bin = binList.find( bin => bin.fitsInBin(number)).getOrElse(Bin(BigDecimal(0), BigDecimal(0)))
bin.rangeAsString()
})
val binList = List(Bin(10, 10), Bin(20, 10), Bin(30, 10), Bin(40, 10), Bin(50, 10))
val dfBin = dfOriginal.withColumn("bin_range", convertValueToBinRangeUDF(col("high_scores"), binList))
But it's giving me a type mismatch:
Error:type mismatch;
found : List[Bin]
required: org.apache.spark.sql.Column
val valueCountsWithBin = valuesCounts.withColumn(binRangeCol, convertValueToBinRangeUDF(col(columnName), binList))
Seeing the definition of an UDF makes me think it should handle the conversion fine, but it's clearly not, any ideas?
The problem is that parameters to an UDF should all be of column type. One solution would be to convert binList into a column and pass it to the UDF similar to the current code.
However, it is simpler to adjust the UDF slightly and turn it into a def. In this way you can easily pass other non-column type data:
def convertValueToBinRangeUDF(binList: List[Bin]) = udf((value:String) => {
val number = BigDecimal(value)
val bin = binList.find( bin => bin.fitsInBin(number)).getOrElse(Bin(BigDecimal(0), BigDecimal(0)))
bin.rangeAsString()
})
Usage:
val dfBin = valuesCounts.withColumn("bin_range", convertValueToBinRangeUDF(binList)($"columnName"))
Try this -
scala> case class Bin(binMax:BigDecimal, binWidth:BigDecimal) {
| val binMin = binMax - binWidth
|
| // only one of the two evaluations can include an "or=", otherwise a value could fit in 2 bins
| def fitsInBin(value: BigDecimal): Boolean = value > binMin && value <= binMax
|
| def rangeAsString(): String = {
| val sb = new StringBuilder()
| sb.append(binMin).append(" - ").append(binMax)
| sb.toString()
| }
| }
defined class Bin
scala> val binList = List(Bin(10, 10), Bin(20, 10), Bin(30, 10), Bin(40, 10), Bin(50, 10))
binList: List[Bin] = List(Bin(10,10), Bin(20,10), Bin(30,10), Bin(40,10), Bin(50,10))
scala> spark.udf.register("convertValueToBinRangeUDF", (value: String) => {
| val number = BigDecimal(value)
| val bin = binList.find( bin => bin.fitsInBin(number)).getOrElse(Bin(BigDecimal(0), BigDecimal(0)))
| bin.rangeAsString()
| })
res13: org.apache.spark.sql.expressions.UserDefinedFunction = UserDefinedFunction(<function1>,StringType,Some(List(StringType)))
//-- Testing with one record
scala> val dfOriginal = spark.sql(s""" select "9" as `high_scores`, "1" as count """)
dfOriginal: org.apache.spark.sql.DataFrame = [high_scores: string, count: string]
scala> dfOriginal.createOrReplaceTempView("dfOriginal")
scala> val dfBin = spark.sql(s""" select high_scores, count, convertValueToBinRangeUDF(high_scores) as bin_range from dfOriginal """)
dfBin: org.apache.spark.sql.DataFrame = [high_scores: string, count: string ... 1 more field]
scala> dfBin.show(false)
+-----------+-----+---------+
|high_scores|count|bin_range|
+-----------+-----+---------+
|9 |1 |0 - 10 |
+-----------+-----+---------+
Hope this will help.

Iterate through rows in DataFrame and transform one to many

As an example in scala, I have a list and every item which matches a condition I want to appear twice (may not be the best option for this use case - but idea which counts):
l.flatMap {
case n if n % 2 == 0 => List(n, n)
case n => List(n)
}
I would like to do something similar in Spark - iterate over rows in a DataFrame and if a row matches a certain condition then I need to duplicate the row with some modifications in the copy. How can this be done?
For example, if my input is the table below:
| name | age |
|-------|-----|
| Peter | 50 |
| Paul | 60 |
| Mary | 70 |
I want to iterate through the table and test each row against multiple conditions, and for each condition that matches, an entry should be created with the name of the matched condition.
E.g. condition #1 is "age > 60" and condition #2 is "name.length <=4". This should result in the following output:
| name | age |condition|
|-------|-----|---------|
| Paul | 60 | 2 |
| Mary | 70 | 1 |
| Mary | 70 | 2 |
You can filter matching-conditions dataframes and then finally union all of them.
import org.apache.spark.sql.functions._
val condition1DF = df.filter($"age" > 60).withColumn("condition", lit(1))
val condition2DF = df.filter(length($"name") <= 4).withColumn("condition", lit(2))
val finalDF = condition1DF.union(condition2DF)
you should have your desired output as
+----+---+---------+
|name|age|condition|
+----+---+---------+
|Mary|70 |1 |
|Paul|60 |2 |
|Mary|70 |2 |
+----+---+---------+
I hope the answer is helpful
You can also use a combination of an UDF and explode(), like in the following example:
// set up example data
case class Pers1 (name:String,age:Int)
val d = Seq(Pers1("Peter",50), Pers1("Paul",60), Pers1("Mary",70))
val df = spark.createDataFrame(d)
// conditions logic - complex as you'd like
// probably should use a Set instead of Sequence but I digress..
val conditions:(String,Int)=>Seq[Int] = { (name,age) =>
(if(age > 60) Seq(1) else Seq.empty) ++
(if(name.length <=4) Seq(2) else Seq.empty)
}
// define UDF for spark
import org.apache.spark.sql.functions.udf
val conditionsUdf = udf(conditions)
// explode() works just like flatmap
val result = df.withColumn("condition",
explode(conditionsUdf(col("name"), col("age"))))
result.show
+----+---+---------+
|name|age|condition|
+----+---+---------+
|Paul| 60| 2|
|Mary| 70| 1|
|Mary| 70| 2|
+----+---+---------+
Here is one way to flatten it with rdd.flatMap:
import org.apache.spark.sql.types._
import org.apache.spark.sql.Row
val new_rdd = (df.rdd.flatMap(r => {
val conditions = Seq((1, r.getAs[Int](1) > 60), (2, r.getAs[String](0).length <= 4))
conditions.collect{ case (i, c) if c => Row.fromSeq(r.toSeq :+ i) }
}))
val new_schema = StructType(df.schema :+ StructField("condition", IntegerType, true))
spark.createDataFrame(new_rdd, new_schema).show
+----+---+---------+
|name|age|condition|
+----+---+---------+
|Paul| 60| 2|
|Mary| 70| 1|
|Mary| 70| 2|
+----+---+---------+

How to filter a dataframe based on column values(multiple values through a arraybuffer) in scala

In scala/spark code I have 1 Dataframe which contains some rows:
col1 col2
Abc someValue1
xyz someValue2
lmn someValue3
zmn someValue4
pqr someValue5
cda someValue6
And i have a variable of ArrayBuffer[String] which contains [xyz,pqr,abc];
I want to filter given dataframe based on given values in arraybuffer at col1.
In SQL it would be like:
select * from tableXyz where col1 in("xyz","pqr","abc");
Assuming you have your dataframe:
val df = sc.parallelize(Seq(("abc","someValue1"),
("xyz","someValue2"),
("lmn","someValue3"),
("zmn","someValue4"),
("pqr","someValue5"),
("cda","someValue6")))
.toDF("col1","col2")
+----+----------+
|col1| col2|
+----+----------+
| abc|someValue1|
| xyz|someValue2|
| lmn|someValue3|
| zmn|someValue4|
| pqr|someValue5|
| cda|someValue6|
+----+----------+
Then you can define an UDF to filter the dataframe based on array's values:
val array = ArrayBuffer[String]("xyz","pqr","abc")
val function: (String => Boolean) = (arg: String) => array.contains(arg)
val udfFiltering = udf(function)
val filtered = df.filter(udfFiltering(col("col1")))
filtered.show()
+----+----------+
|col1| col2|
+----+----------+
| abc|someValue1|
| xyz|someValue2|
| pqr|someValue5|
+----+----------+
Alternately you can register your dataframe and sql-query it by SQLContext:
var elements = ""
array.foreach { el => elements += "\"" + el + "\"" + "," }
elements = elements.dropRight(1)
val query = "select * from tableXyz where col1 in(" + elements + ")"
df.registerTempTable("tableXyz")
val filtered = sqlContext.sql(query)
filtered.show()
+----+----------+
|col1| col2|
+----+----------+
| abc|someValue1|
| xyz|someValue2|
| pqr|someValue5|
+----+----------+

How to rank the data set having multiple columns in Scala?

I have data set like this which i am fetching from csv file but how to
store in Scala to do the processing.
+-----------+-----------+----------+
| recent | Freq | Monitor |
+-----------+-----------+----------+
| 1 | 1234| 199090|
| 4 | 2553| 198613|
| 6 | 3232 | 199090|
| 1 | 8823 | 498831|
| 7 | 2902 | 890000|
| 8 | 7991 | 081097|
| 9 | 7391 | 432370|
| 12 | 6138 | 864981|
| 7 | 6812 | 749821|
+-----------+-----------+----------+
Actually I need to sort the data and rank it.
I am new to Scala programming.
Thanks
Answering your question here is the solution, this code reads a csv and order by the third column
object CSVDemo extends App {
println("recent, freq, monitor")
val bufferedSource = io.Source.fromFile("./data.csv")
val list: Array[Array[String]] = (bufferedSource.getLines map { line => line.split(",").map(_.trim) }).toArray
val newList = list.sortBy(_(2))
newList map { line => println(line.mkString(" ")) }
bufferedSource.close
}
you read the file and you parse it to an Array[Array[String]], then you order by the third column, and you print
Here I am using the list and try to normalize each column at a time and then concatenating them. Is there any other way to iterate column wise and normalize them. Sorry my coding is very basic.
val col1 = newList.map(line => line.head)
val mi = newList.map(line => line.head).min
val ma = newList.map(line => line.head).max
println("mininumn value of first column is " +mi)
println("maximum value of first column is : " +ma)
// calculate scale for the first column
val scale = col1.map(x => math.round((x.toInt - mi.toInt) / (ma.toInt - mi.toInt)))
println("Here is the normalized range of first column of the data")
scale.foreach(println)