This question already has answers here:
How to store more than 4 decimal places in an array in MATLAB
(2 answers)
Closed 5 years ago.
is it possible to get this in an array with 16 decimals after the comma?
Poorly it gets cut in my Workspace as you can see in the link below.
Kind regards!
format long;
startYCoordinateNorthEast=([50.93952193697642, 6.99745722361763]);
here you can see the array, cut to 4 decimals but I need 16
In your Matlab workspace, you are right that format long will show you the long output:
>> startYCoordinateNorthEast
startYCoordinateNorthEast =
50.939521936976419 6.997457223617630
In the Workspace Viewer, to see all the decimals, you must click on the tab called "View". From there, under "Number Display Format" choose "Long Fixed Decimal"
Related
This question already has answers here:
Is floating point math broken?
(31 answers)
Closed 4 years ago.
I have a easy problem but I can't fix it. In my program There are lines where I have a for loop with custom array. This array has got 3 value each of them string(array created by the JSON object from web). Whenever I tried the reach these string variables in double form I can't as pictures show.
As you can see in the pictures my aim is get he latitude and longitude values turn into double and use in CLLocationCoordinate2D init. but the conversion of string value is for latitude = 35.32041000000002 how can I convert it into presicion 6 digit. Thanks all. Have a nice day.
Read this to understand floating point numbers. In summary: Not all numbers can be exactly represented in the 64-bits of a Double. So you'll end up with something that extremely close, but with extra digit(s), or for example with a long tail of 9999999999.
The conversion succeeded. The value that the extra digit (0.000000000000002) won't hurt as they are rather insignificant.
This question already has an answer here:
Why did MATLAB delete my decimals?
(1 answer)
Closed 4 years ago.
I am calculating the area of objects in my image using bwarea like so:
i=imread('Z:\Azhagu project work\MRI\input.jpg');
imshow(i);
bwarea(i)
This gives the following output:
ans = 1.0428e+05
Why is the area in an exponential format?
It's not in exponential output; it's in scientific notation.
ans = 1.0428e+05 == 104280
You can force MATLAB to show all decimals using format long or format longG. This is just a display quirk of MATLAB, internally your number is stored as a double anyway, so for further calculations this is of no concern.
This area value is not in exponential format. For your given image, area is represented in Floating-Point numbers format. Hence the value 1.0428e+05 is actually 104280.
This question already has answers here:
How to store more than 4 decimal places in an array in MATLAB
(2 answers)
Closed 5 years ago.
i have code below in matlab:
converted = ncread(this_file, 'U');
disp(converted(50,10,20));
and the result is:
-0.1561
actually the number is -0.15617890 but this code changes the the number of floating numbers. why?
MATLAB displays only 4 digits after the decimal point by default. You can use format to display more digits:
format long
converted = ncread(this_file, 'U');
disp(converted(50,10,20));
This question already has answers here:
Convert output from symbolic math (sym) to float
(2 answers)
Closed 8 years ago.
I did following:
clc
clear all
I0=1.2e12;
FWHM=10e-12;
c=FWHM./2.35482;
t=0:1e-12:50e-12;
syms t
int(I0.*exp(-1.*(t-5e-12).^2./(2.*c.^2)),t,0,40e-12)
but it does not give me a simple number (just a number)
The reason why matlab does not automatically give you a number is that precision could be lost.
Suppose you have a symbolic variable with value 1/3. That has infinite accuracy at this point. Yet if you evaluate it, you would lose this precision, so that is why it is not evaluated directly.
If you want to evaluate it, you could do that of course. Try doc double,doc vpa, doc eval or doc subs. I think the first one is what you need.
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Binary representation of a number in Matlab
I am using matlab and would like to convert a number such as 7546.456124865 to single precision.
I've used the single() command, but I would like to get the binary for the single precision floating point. How do I go about doing this?
>> num2hex(single(7546.456124865))
ans =
45ebd3a6