I am unable to figure out how to convert tabular data to JSON format and store it in another table in Redshift. For example, I have a "DEMO" table with four columns: pid,stid,item_id,trans_id.
For each combination of pid,stid,item_id there exist many trans_ids.
pid stid item_id trans_id :
1 , AB , P1 , T1
1 , AB , P1 , T2
1 , AB , P1 , T3
1 , AB , P1 , T4
2 , ABC , P2 , T5
2 , ABC , P2 , T6
2 , ABC , P2 , T7
2 , ABC , P2 , T8
I want to store this data in another table called "SAMPLE" as:
pid stid item_id trans_id
1 , AB , P1 , {"key1":T1, "key2":"T2" "key2":"T3" "key2":"T4"}
2 , ABC , P2 , {"key1":T5, "key2":"T6" "key2":"T7" "key2":"T8"}
I am unable to figure out how to load the data from "DEMO" to "SAMPLE" in JSON format only for column "trans_id" using a SQL query in Redshift. I don't want to use any intermediate files.
There is LISTAGG aggregate function that allows you to concatenate text values within groups. It allows the effective construction of JSON objects:
SELECT
pid
,stid
,item_id
,'{'||listagg(
'"key'||row_number::varchar||'":'||trans_id::varchar
,',') within group (order by row_number)
||'}'
FROM (
SELECT *, row_number() over (partition by pid,stid,item_id order by trans_id)
FROM "DEMO"
)
GROUP BY 1,2,3;
As a side note, in this particular case an array of transaction IDs might work better, you'll be able to request the element of a specific order easily without using keyN key:
WITH tran_arrays as (
SELECT
pid
,stid
,item_id
,listagg(trans_id::varchar,',') within group (order by trans_id) as tran_array
FROM "DEMO"
GROUP BY 1,2,3
)
SELECT *
,split_part(tran_array,',',1) as first_element
FROM tran_arrays;
Very similar to the existing Answer however slightly different. This example is also run out of an Oracle Database. I put the work into it and felt like sharing in case it may help someone else out.
/* Oracle Example */
WITH demo_data AS
(
SELECT 1 AS pid, 'AB' AS stid, 'P1' AS item_id, 'T1' AS trans_id FROM dual UNION ALL
SELECT 1 AS pid, 'AB' AS stid, 'P1' AS item_id, 'T2' AS trans_id FROM dual UNION ALL
SELECT 1 AS pid, 'AB' AS stid, 'P1' AS item_id, 'T3' AS trans_id FROM dual UNION ALL
SELECT 1 AS pid, 'AB' AS stid, 'P1' AS item_id, 'T4' AS trans_id FROM dual UNION ALL
SELECT 2 AS pid, 'ABC' AS stid, 'P2' AS item_id, 'T5' AS trans_id FROM dual UNION ALL
SELECT 2 AS pid, 'ABC' AS stid, 'P2' AS item_id, 'T6' AS trans_id FROM dual UNION ALL
SELECT 2 AS pid, 'ABC' AS stid, 'P2' AS item_id, 'T7' AS trans_id FROM dual UNION ALL
SELECT 2 AS pid, 'ABC' AS stid, 'P2' AS item_id, 'T8' AS trans_id FROM dual
)
, transformData AS
(
SELECT pid, stid, item_id, trans_id, rownum AS keyNum FROM demo_data
)
SELECT pid, stid, item_id
, '{'||
LISTAGG(CHR(34)||'key'||keynum||CHR(34)||':'||CHR(34)||trans_id||CHR(34), ' ')
WITHIN GROUP (ORDER BY pid)
||'}' AS trans_id
FROM transformData
GROUP BY pid, stid, item_id
;
Output will look like this:
Related
We want to group our members' enrollments into "continuous enrollments," allowing for a gap of up to 45 days. I know how to use LEAD to determine if an enrollment should be grouped with the next, but I don't know how to group them. Would it be more appropriate to add 45 to the term date and subtract 45 from the effective date, then check for overlapping date periods? My goal is to have a SQL view that returns the results similar to the final query below. Thank you for your help.
SELECT '101' AS MemID, '2021-01-01' AS EffDate, '2021-01-31' AS TermDate INTO #T1 UNION
SELECT '101', '2021-02-01', '2021-02-28' UNION
SELECT '101', '2021-03-01', '2021-03-31' UNION
SELECT '101', '2021-06-01', '2021-06-30' UNION
SELECT '999', '2021-01-01', '2021-01-15' UNION
SELECT '999', '2021-09-01', '2021-09-28' UNION
SELECT '999', '2021-10-01', '2021-10-31'
SELECT *
, LEAD(EffDate) OVER (PARTITION BY MemID ORDER BY EffDate) AS LeadEffDate
, DATEDIFF(DAY, TermDate, (LEAD(EffDate) OVER (PARTITION BY MemID ORDER BY EffDate))) AS DaysToNextEnrollment
, CASE WHEN (DATEDIFF(DAY, TermDate, (LEAD(EffDate) OVER (PARTITION BY MemID ORDER BY EffDate)))) <= 45 THEN 1 ELSE 0 END AS CombineWithNextRecord
FROM #T1
-- result objective
SELECT 101 AS MemID, '2021-01-01' AS EffDate, '2021-03-31' AS TermDate UNION
SELECT 101, '2021-06-01', '2021-06-30' UNION
SELECT 999, '2021-01-01', '2021-01-15' UNION
SELECT 999, '2021-09-01', '2021-10-31'
I think you are really close. Your question is very similar to
TSQL - creating from-to date table while ignoring in-between steps with conditions with a logic difference on what you want to consider to be the same group.
My basic approach is to use the LAG() function to figure out the previous values for MemID and TermDate and combine that with your 45 day rule to define a group. And finally get the first and last values of each group.
Here is my response to that question modified to your situation.
SELECT
a4.MemID
, CONVERT (DATE, a4.First_EffDate) AS [EffDate]
, CONVERT (DATE, a4.TermDate) AS [TermDate]
FROM (
SELECT
a3.MemID
, a3.EffDate
, a3.TermDate
, a3.MemID_group
, FIRST_VALUE (a3.EffDate) OVER (PARTITION BY a3.MemID_group ORDER BY a3.EffDate) AS [First_EffDate]
, ROW_NUMBER () OVER (PARTITION BY a3.MemID_group ORDER BY a3.EffDate DESC) AS [Row_number]
FROM (
SELECT
a2.MemID
, a2.EffDate
, a2.TermDate
, a2.Previous_MemID
, a2.Previous_TermDate
, a2.New_group
, SUM (a2.New_group) OVER (ORDER BY a2.MemID, a2.EffDate) AS [MemID_group]
FROM (
SELECT
a1.MemID
, a1.EffDate
, a1.TermDate
, a1.Previous_MemID
, a1.Previous_TermDate
---------------------------------------------------------------------------------
-- new group if the MemID is different from the previous row OR
-- if the MemID is the same as the previous row AND it has been more than 45 days
-- between the TermDate of the previous row and the EffDate of the current row
,
IIF((a1.MemID <> a1.Previous_MemID)
OR (
a1.MemID = a1.Previous_MemID
AND DATEDIFF (DAY, a1.Previous_TermDate, a1.EffDate) > 45
)
, 1
, 0) AS [New_group]
---------------------------------------------------------------------------------
FROM (
SELECT
MemID
, EffDate
, TermDate
, LAG (MemID) OVER (ORDER BY MemID) AS [Previous_MemID]
, LAG (TermDate) OVER (PARTITION BY MemID ORDER BY EffDate) AS [Previous_TermDate]
FROM #T1
) a1
) a2
) a3
) a4
WHERE a4.[Row_number] = 1;
Here is the dbfiddle.
I have a table that looks like this:
A slowly changing dimension type 2, according to Kimball.
Key is just a surrogate key, a key to make rows unique.
As you can see there are three rows for product A.
Timelines for this product are ok. During time the description of the product changes.
From 1-1-2020 up until 4-1-2020 the description of this product was ProdA1.
From 5-1-2020 up until 12-2-2020 the description of this product was ProdA2 etc.
If you look at product B, you see there are gaps in the timeline.
We use DB2 V12 z/Os. How can I check if there are gaps in the timelines for each and every product?
Tried this, but doesn't work
with selectie (key, tel) as
(select product, count(*)
from PROD_TAB
group by product
having count(*) > 1)
Select * from
PROD_TAB A
inner join selectie B
on A.product = B.product
Where not exists
(SELECT 1 from PROD_TAB C
WHERE A.product = C.product
AND A.END_DATE + 1 DAY = C.START_DATE
)
Does anyone know the answer?
The following query returns all gaps for all products.
The idea is to enumerate (RN column) all periods inside each product by START_DATE and join each record with its next period record.
WITH
/*
MYTAB (PRODUCT, DESCRIPTION, START_DATE, END_DATE) AS
(
SELECT 'A', 'ProdA1', DATE('2020-01-01'), DATE('2020-01-04') FROM SYSIBM.SYSDUMMY1
UNION ALL SELECT 'A', 'ProdA2', DATE('2020-01-05'), DATE('2020-02-12') FROM SYSIBM.SYSDUMMY1
UNION ALL SELECT 'A', 'ProdA3', DATE('2020-02-13'), DATE('2020-12-31') FROM SYSIBM.SYSDUMMY1
UNION ALL SELECT 'B', 'ProdB1', DATE('2020-01-05'), DATE('2020-01-09') FROM SYSIBM.SYSDUMMY1
UNION ALL SELECT 'B', 'ProdB2', DATE('2020-01-12'), DATE('2020-03-14') FROM SYSIBM.SYSDUMMY1
UNION ALL SELECT 'B', 'ProdB3', DATE('2020-03-15'), DATE('2020-04-18') FROM SYSIBM.SYSDUMMY1
UNION ALL SELECT 'B', 'ProdB4', DATE('2020-04-16'), DATE('2020-05-03') FROM SYSIBM.SYSDUMMY1
)
,
*/
MYTAB_ENUM AS
(
SELECT
T.*
, ROWNUMBER() OVER (PARTITION BY PRODUCT ORDER BY START_DATE) RN
FROM MYTAB T
)
SELECT A.PRODUCT, A.END_DATE + 1 START_DT, B.START_DATE - 1 END_DT
FROM MYTAB_ENUM A
JOIN MYTAB_ENUM B ON B.PRODUCT = A.PRODUCT AND B.RN = A.RN + 1
WHERE A.END_DATE + 1 <> B.START_DATE
AND A.END_DATE < B.START_DATE;
The result is:
|PRODUCT|START_DT |END_DT |
|-------|----------|----------|
|B |2020-01-10|2020-01-11|
May be more efficient way:
WITH MYTAB2 AS
(
SELECT
T.*
, LAG(END_DATE) OVER (PARTITION BY PRODUCT ORDER BY START_DATE) END_DATE_PREV
FROM MYTAB T
)
SELECT PRODUCT, END_DATE_PREV + 1 START_DATE, START_DATE - 1 END_DATE
FROM MYTAB2
WHERE END_DATE_PREV + 1 <> START_DATE
AND END_DATE_PREV < START_DATE;
Thnx Mark, will try this one of these days.
Never heard of LAG in DB2 V12 for z/Os
Will read about it
Thnx
I would like group the columns of a table with by a column value as well as when another condition is met. For example, with the following table:
Events:
id session_id flags created_at ...
--------------------------------------------
1 100 OTHER ...
2 101 OTHER ...
3 101 NEW_SESSION ...
4 101 OTHER ...
5 101 NEW_SESSION ...
6 100 OTHER ...
7 102 OTHER ...
I want the following result:
session_id events_count first_event_id last_event_id
-------------------------------------------------------
100-0 2 1 6
101-0 1 2 2
101-1 2 3 4
101-2 1 5 5
102-0 1 7 7
The basic idea is that I want to extract sessions from events. They are grouped by session_id. I also want a new session whenever I have the flag NEW_SESSION.
The query is something like this:
SELECT ? as session_id
, count(id) as events_count
, MIN(id) as first_event_id
, MAX(id) last_event_id
GROUP BY session_id
-- , and whenever flags is NEW_SESSION
ORDER BY id
But I dont know how to express the group by condition properly. Any idea ?
Update 2
In the comments I've noticed that you want them unique. Then we can use a variable:
SET #inc := 0;
(
SELECT CONCAT(session_id, '-', !ABS(STRCMP(flags, 'NEW_SESSION'))) AS session_id
, COUNT(id) AS events_count
, MIN(id) AS first_event_id
, MAX(id) last_event_id
FROM events
WHERE flags != 'NEW_SESSION'
GROUP BY events.session_id, events.flags
ORDER BY events.id
) UNION (
SELECT CONCAT(session_id, '-', #inc := #inc + 1) AS session_id
, COUNT(id) AS events_count
, MIN(id) AS first_event_id
, MAX(id) last_event_id
FROM events
WHERE flags = 'NEW_SESSION'
GROUP by events.id
ORDER BY events.id
);
Update
The following prevents grouping for the NEW_SESSION rows:
(
SELECT CONCAT(session_id, '-', !ABS(STRCMP(flags, 'NEW_SESSION'))) AS session_id
, COUNT(id) AS events_count
, MIN(id) AS first_event_id
, MAX(id) last_event_id
FROM events
WHERE flags != 'NEW_SESSION'
GROUP BY events.session_id, events.flags
ORDER BY events.id
) UNION (
SELECT CONCAT(session_id, '-1') AS session_id
, COUNT(id) AS events_count
, MIN(id) AS first_event_id
, MAX(id) last_event_id
FROM events
WHERE flags = 'NEW_SESSION'
GROUP BY id
ORDER BY events.id
);
Original answer
As far as I understand, you are trying to group events by the session IDs and
"whether it's a NEW_SESSION" flag. If it's so, then I'd express it as follows:
SELECT CONCAT(session_id, '-', !ABS(STRCMP(flags, 'NEW_SESSION'))) AS session_id
, COUNT(id) AS events_count
, MIN(id) AS first_event_id
, MAX(id) last_event_id
FROM events
GROUP BY events.session_id, events.flags
ORDER BY events.id;
I have following table
ID | Group | Type | Product
1 Dairy Milk Fresh Milk
2 Dairy Butter Butter Cream
3 Beverage Coke Coca cola
4 Beverage Diet Dew
5 Beverage Juice Fresh Juice
I need following output/query result:
ID | Group | Type | Product
1 Dairy
1 Milk Fresh Milk
2 Butter Butter Cream
2 Beverage
1 Coke Coca cola
2 Diet Dew
3 Juice Fresh Juice
For above sample a hard coded script can do the job but I look for a dynamic script for any number of groups. I do not have any idea how it can be done so, I do not have a sample query yet. I need ideas, examples that at least give me an idea. PIVOT looks a close option but does not looks to be fully fit for this case.
Here's a possible way. It basically unions the "Group-Headers" and the "Group-Items". The difficulty was to order them correctly.
WITH CTE AS
(
SELECT ID,[Group],Type,Product,
ROW_NUMBER() OVER (PARTITION BY [Group] Order By ID)AS RN
FROM Drink
)
SELECT ID,[Group],Type,Product
FROM(
SELECT RN AS ID,[Group],[Id]AS OriginalId,'' As Type,'' As Product, 0 AS RN, 'Group' As RowType
FROM CTE WHERE RN = 1
UNION ALL
SELECT RN AS ID,'' AS [Group],[Id]AS OriginalId,Type,Product, RN, 'Item' As RowType
FROM CTE
)X
ORDER BY OriginalId ASC
, CASE WHEN RowType='Group' THEN 0 ELSE 1 END ASC
, RN ASC
Here's a demo-fiddle: http://sqlfiddle.com/#!6/ed6ca/2/0
A slightly simplified approach:
With Groups As
(
Select Distinct Min(Id) As Id, [Group], '' As [Type], '' As Product
From dbo.Source
Group By [Group]
)
Select Coalesce(Cast(Z.Id As varchar(10)),'') As Id
, Coalesce(Z.[Group],'') As [Group]
, Z.[Type], Z.Product
From (
Select Id As Sort, Id, [Group], [Type], Product
From Groups
Union All
Select G.Id, Null, Null, S.[Type], S.Product
From dbo.Source As S
Join Groups As G
On G.[Group] = S.[Group]
) As Z
Order By Sort
It should be noted that the use of Coalesce is purely for aesthetic reasons. You could simply return null in these cases.
SQL Fiddle
And an approach with ROW_NUMBER:
IF OBJECT_ID('dbo.grouprows') IS NOT NULL DROP TABLE dbo.grouprows;
CREATE TABLE dbo.grouprows(
ID INT,
Grp NVARCHAR(MAX),
Type NVARCHAR(MAX),
Product NVARCHAR(MAX)
);
INSERT INTO dbo.grouprows VALUES
(1,'Dairy','Milk','Fresh Milk'),
(2,'Dairy','Butter','Butter Cream'),
(3,'Beverage','Coke','Coca cola'),
(4,'Beverage','Diet','Dew'),
(5,'Beverage','Juice','Fresh Juice');
SELECT
CASE WHEN gg = 0 THEN dr1 END GrpId,
CASE WHEN gg = 1 THEN rn1 END TypeId,
ISNULL(Grp,'')Grp,
CASE WHEN gg = 1 THEN Type ELSE '' END Type,
CASE WHEN gg = 1 THEN Product ELSE '' END Product
FROM(
SELECT *,
DENSE_RANK()OVER(ORDER BY Grp DESC) dr1
FROM(
SELECT *,
ROW_NUMBER()OVER(PARTITION BY Grp ORDER BY type,gg) rn1,
ROW_NUMBER()OVER(ORDER BY type,gg) rn0
FROM(
SELECT Grp,Type,Product, GROUPING(Grp) gg, GROUPING(type) tg FROM dbo.grouprows
GROUP BY Product, Type, Grp
WITH ROLLUP
)X1
WHERE tg = 0
)X2
WHERE gg=1 OR rn1 = 1
)X3
ORDER BY rn0
I have been trying all afternoon to try and achieve this with no success.
I have a db in with info on customers and the date that they purchase products from the store. It is grouped by a batch ID which I have converted into a date format.
So in my table I now have:
CustomerID|Date
1234 |2011-10-18
1234 |2011-10-22
1235 |2011-11-16
1235 |2011-11-17
What I want to achieve is to see the number of days between the most recent purchase and the last purchase and so on.
For example:
CustomerID|Date |Outcome
1234 |2011-10-18 |
1234 |2011-10-22 | 4
1235 |2011-11-16 |
1235 |2011-11-17 | 1
I have tried joining the table to itself but the problem I have is that I end up joining in the same format. I then tried with my join statement to return where it did <> match date.
Hope this makes sense, any help appreciated. I have searched all the relevant topics on here.
Will there be multiple groups of CustomerID? Or only and always grouped together?
DECLARE #myTable TABLE
(
CustomerID INT,
Date DATETIME
)
INSERT INTO #myTable
SELECT 1234, '2011-10-14' UNION ALL
SELECT 1234, '2011-10-18' UNION ALL
SELECT 1234, '2011-10-22' UNION ALL
SELECT 1234, '2011-10-26' UNION ALL
SELECT 1235, '2011-11-16' UNION ALL
SELECT 1235, '2011-11-17' UNION ALL
SELECT 1235, '2011-11-18' UNION ALL
SELECT 1235, '2011-11-19'
SELECT CustomerID,
MIN(date),
MAX(date),
DATEDIFF(day,MIN(date),MAX(date)) Outcome
FROM #myTable
GROUP BY CustomerID
SELECT a.CustomerID,
a.[Date],
ISNULL(DATEDIFF(DAY, b.[Date], a.[Date]),0) Outcome
FROM
(
SELECT ROW_NUMBER() OVER(PARTITION BY [CustomerID] ORDER BY date) Row,
CustomerID,
Date
FROM #myTable
) A
LEFT JOIN
(
SELECT ROW_NUMBER() OVER(PARTITION BY [CustomerID] ORDER BY date) Row,
CustomerID,
Date
FROM #myTable
) B ON a.CustomerID = b.CustomerID AND A.Row = B.Row + 1