Powershell get-acl from childitems that not equals foldername - powershell

Question

At work we have a folder with lots of subfolders named like "MeyerS". (Lastname and the first letter of surname)
When I take a look at Get-ChildItem $path | Get-Acl the username equals the subfolder-name. But there is also a "SCHUELER\" in front of "MeyerS". This is what the output looks like a.e.: SCHUELER\MeyerS Allow Write, ReadAndExecute, Synchronize
Some subfolders don't have this kind of username. Now I want to output all these subfolders without this username- "combination".
With my first codesnippet I get all of them, but I really just want these specific ones.
I checked some similar questions, and found something. I modified it, but it shows all subfolders just without SCHUELER\MeyerS. I think I just need a small push to the right way.
The code so far:
$path = "R:\HOME"
$folders = Get-ChildItem $path | where {$_.psiscontainer}
foreach ($folder in $folders){
$domain = "domname"
$aclname = "ACLname"
$aclfullname ="$domain\$aclname"
Get-Acl | select -ExpandProperty Access | where {$_.identityreference -notcontains $aclfullname}
Write-Host $folder.FullName}
Short note: I tried a lot of variations with -noteq or -notlike.
What do I have to change?
If there is already an answer I really didn't know.
Sometimes it's really hard to enunciate yourself in another language. I hope you get my point.
Thanks.

Answer 1

$path = "R:\HOME"
$folders = Get-ChildItem $path | where {$_.psiscontainer}
foreach ($folder in $folders)
{
$domain = "domname"
$aclname = "ACLname"
$aclfullname ="$domain\$aclname"
$FoldersWithAclFullName = $null
$FoldersWithAclFullName = Get-Acl -Path $Folder `
| Select-Object -ExpandProperty Access `
| Where-Object -Property IdentityReference -ne -Value $aclfullname
if ( -not $FoldersWithAclFullName )
{
Write-Host $folder.FullName
}
}