I just started using Primsa 2 so I am still a noob at this but all I am trying to do is create a flat array of strings(Array<number>) based on the values I get from a specific field. Right now when I target that field it gives me an array of objects like this: userIds: [{ issueId: 1, userId: 1 }]
All I want is the value I get from the userId key and the array to return like this userIds: [ 1 ]. I was able to fix this with some formatting code after the query which was done like so:
const issues = project.issues.map(issue => ({ ...issue, userIds: [...issue.userIds.map((id) => id.userId)] }))
const _project = { ...project, issues }
However, this doesn't seem like the most optimal solution. If this is the only way that is fine but I assume with the power that Prisma has for querying, this is something I can do just in the query alone?
For reference, my query currently looks like this:
const project = await prisma.project.findFirst({
where: { id: req.currentUser.projectId },
include: { users: true, issues: { include: { userIds: true } } },
})
Thanks in advance!
Can you show your schema? Perhaps you can model the relation differently. However, unless if you provide a field, userIds, that is a flat array and not a field of a an other relation it will be returned as a list of objects as you have already.
From the docs:
You can also chain multiple where() methods to create more specific queries (logical AND).
How can I perform an OR query?
Example:
Give me all documents where the field status is open OR upcoming
Give me all documents where the field status == open OR createdAt <= <somedatetime>
OR isn't supported as it's hard for the server to scale it (requires keeping state to dedup). The work around is to issue 2 queries, one for each condition, and dedup on the client.
Edit (Nov 2019):
Cloud Firestore now supports IN queries which are a limited type of OR query.
For the example above you could do:
// Get all documents in 'foo' where status is open or upcmoming
db.collection('foo').where('status','in',['open','upcoming']).get()
However it's still not possible to do a general OR condition involving multiple fields.
With the recent addition of IN queries, Firestore supports "up to 10 equality clauses on the same field with a logical OR"
A possible solution to (1) would be:
documents.where('status', 'in', ['open', 'upcoming']);
See Firebase Guides: Query Operators | in and array-contains-any
suggest to give value for status as well.
ex.
{ name: "a", statusValue = 10, status = 'open' }
{ name: "b", statusValue = 20, status = 'upcoming'}
{ name: "c", statusValue = 30, status = 'close'}
you can query by ref.where('statusValue', '<=', 20) then both 'a' and 'b' will found.
this can save your query cost and performance.
btw, it is not fix all case.
I would have no "status" field, but status related fields, updating them to true or false based on request, like
{ name: "a", status_open: true, status_upcoming: false, status_closed: false}
However, check Firebase Cloud Functions. You could have a function listening status changes, updating status related properties like
{ name: "a", status: "open", status_open: true, status_upcoming: false, status_closed: false}
one or the other, your query could be just
...where('status_open','==',true)...
Hope it helps.
This doesn't solve all cases, but for "enum" fields, you can emulate an "OR" query by making a separate boolean field for each enum-value, then adding a where("enum_<value>", "==", false) for every value that isn't part of the "OR" clause you want.
For example, consider your first desired query:
Give me all documents where the field status is open OR upcoming
You can accomplish this by splitting the status: string field into multiple boolean fields, one for each enum-value:
status_open: bool
status_upcoming: bool
status_suspended: bool
status_closed: bool
To perform your "where status is open or upcoming" query, you then do this:
where("status_suspended", "==", false).where("status_closed", "==", false)
How does this work? Well, because it's an enum, you know one of the values must have true assigned. So if you can determine that all of the other values don't match for a given entry, then by deduction it must match one of the values you originally were looking for.
See also
in/not-in/array-contains-in: https://firebase.google.com/docs/firestore/query-data/queries#in_and_array-contains-any
!=: https://firebase.googleblog.com/2020/09/cloud-firestore-not-equal-queries.html
I don't like everyone saying it's not possible.
it is if you create another "hacky" field in the model to build a composite...
for instance, create an array for each document that has all logical or elements
then query for .where("field", arrayContains: [...]
you can bind two Observables using the rxjs merge operator.
Here you have an example.
import { Observable } from 'rxjs/Observable';
import 'rxjs/add/observable/merge';
...
getCombinatedStatus(): Observable<any> {
return Observable.merge(this.db.collection('foo', ref => ref.where('status','==','open')).valueChanges(),
this.db.collection('foo', ref => ref.where('status','==','upcoming')).valueChanges());
}
Then you can subscribe to the new Observable updates using the above method:
getCombinatedStatus.subscribe(results => console.log(results);
I hope this can help you, greetings from Chile!!
We have the same problem just now, luckily the only possible values for ours are A,B,C,D (4) so we have to query for things like A||B, A||C, A||B||C, D, etc
As of like a few months ago firebase supports a new query array-contains so what we do is make an array and we pre-process the OR values to the array
if (a) {
array addObject:#"a"
}
if (b) {
array addObject:#"b"
}
if (a||b) {
array addObject:#"a||b"
}
etc
And we do this for all 4! values or however many combos there are.
THEN we can simply check the query [document arrayContains:#"a||c"] or whatever type of condition we need.
So if something only qualified for conditional A of our 4 conditionals (A,B,C,D) then its array would contain the following literal strings: #["A", "A||B", "A||C", "A||D", "A||B||C", "A||B||D", "A||C||D", "A||B||C||D"]
Then for any of those OR combinations we can just search array-contains on whatever we may want (e.g. "A||C")
Note: This is only a reasonable approach if you have a few number of possible values to compare OR with.
More info on Array-contains here, since it's newish to firebase docs
If you have a limited number of fields, definitely create new fields with true and false like in the example above. However, if you don't know what the fields are until runtime, you have to just combine queries.
Here is a tags OR example...
// the ids of students in class
const students = [studentID1, studentID2,...];
// get all docs where student.studentID1 = true
const results = this.afs.collection('classes',
ref => ref.where(`students.${students[0]}`, '==', true)
).valueChanges({ idField: 'id' }).pipe(
switchMap((r: any) => {
// get all docs where student.studentID2...studentIDX = true
const docs = students.slice(1).map(
(student: any) => this.afs.collection('classes',
ref => ref.where(`students.${student}`, '==', true)
).valueChanges({ idField: 'id' })
);
return combineLatest(docs).pipe(
// combine results by reducing array
map((a: any[]) => {
const g: [] = a.reduce(
(acc: any[], cur: any) => acc.concat(cur)
).concat(r);
// filter out duplicates by 'id' field
return g.filter(
(b: any, n: number, a: any[]) => a.findIndex(
(v: any) => v.id === b.id) === n
);
}),
);
})
);
Unfortunately there is no other way to combine more than 10 items (use array-contains-any if < 10 items).
There is also no other way to avoid duplicate reads, as you don't know the ID fields that will be matched by the search. Luckily, Firebase has good caching.
For those of you that like promises...
const p = await results.pipe(take(1)).toPromise();
For more info on this, see this article I wrote.
J
OR isn't supported
But if you need that you can do It in your code
Ex : if i want query products where (Size Equal Xl OR XXL : AND Gender is Male)
productsCollectionRef
//1* first get query where can firestore handle it
.whereEqualTo("gender", "Male")
.addSnapshotListener((queryDocumentSnapshots, e) -> {
if (queryDocumentSnapshots == null)
return;
List<Product> productList = new ArrayList<>();
for (DocumentSnapshot snapshot : queryDocumentSnapshots.getDocuments()) {
Product product = snapshot.toObject(Product.class);
//2* then check your query OR Condition because firestore just support AND Condition
if (product.getSize().equals("XL") || product.getSize().equals("XXL"))
productList.add(product);
}
liveData.setValue(productList);
});
For Flutter dart language use this:
db.collection("projects").where("status", whereIn: ["public", "unlisted", "secret"]);
actually I found #Dan McGrath answer working here is a rewriting of his answer:
private void query() {
FirebaseFirestore db = FirebaseFirestore.getInstance();
db.collection("STATUS")
.whereIn("status", Arrays.asList("open", "upcoming")) // you can add up to 10 different values like : Arrays.asList("open", "upcoming", "Pending", "In Progress", ...)
.addSnapshotListener(new EventListener<QuerySnapshot>() {
#Override
public void onEvent(#Nullable QuerySnapshot queryDocumentSnapshots, #Nullable FirebaseFirestoreException e) {
for (DocumentSnapshot documentSnapshot : queryDocumentSnapshots) {
// I assume you have a model class called MyStatus
MyStatus status= documentSnapshot.toObject(MyStatus.class);
if (status!= null) {
//do somthing...!
}
}
}
});
}
I Am building an express JS application with graphql, and mongodb (mongoose). I am using facebooks Dataloader to batch and cache requests.
Its working perfectly fine except for this use case.
I have a database filled with users posts. Each post contains the users ID for reference. When i make a call to return all the posts in the database. The posts are returned fine but if i try to get the user in each post. Users with multiple posts will only return a single user because the key for the second user is cached. So 2 posts(keys) from user "x" will only return 1 user object "x".
However Dataloader has to return the same amount of promises as keys that it recieves.
It has a option to specify cache as false so each key will make a request. But this doesnt seem to work for my use case.
Sorry if i havn't explained this very well.
this is my graphql request
query {
getAllPosts {
_id // This is returned fine
user {
_id
}
}
}
Returned error:
DataLoader must be constructed with a function which accepts Array<key> and returns Promise<Array<value>>, but the function did not return a Promise of an Array of the same length as the Array of keys.
are you trying to batch post keys [1, 2, 3] and expecting to get user results [{ user1 }, {user2}, { user1 }]?
or are you trying to batch user keys [1, 2] and expecting to get post results [{ post1}, {post3}] and [{ post2 }]?
seems like only in the second case will you run into a situation where you have length of keys differing from length of results array.
to solve the second, you could do something like this in sql:
const loader = new Dataloader(userIDs => {
const promises = userIDs.map(id => {
return db('user_posts')
.where('user_id', id);
});
return Promise.all(promises);
})
loader.load(1)
loader.load(2)
so you return [[{ post1}, {post3}], [{ post2 }]] which dataloader can unwrap.
if you had done this instead:
const loader = new Dataloader(userIDs => {
return db('user_posts')
.where('user_id', [userIDs]);
})
loader.load(1)
loader.load(2)
you will instead get [{ post1}, {post3}, { post2 }] and hence the error: the function did not return a Promise of an Array of the same length as the Array of keys
not sure if the above is relevant / helpful. i can revise if you can provide a snippet of your batch load function
You need to map the data returned from the database to the Array of keys.
Dataloader: The Array of values must be the same length as the Array of keys
This issue is well explained in this YouTube Video - Dataloader - Highly recommended
I'm trying to return all groups that the current user is a part of. Each user has a groups field that's simply an array of id's for the groups the user belongs to. Here's what my code looks like:
My server method for returning the correct groups
userGroups: function(){
var currentUser = Meteor.users.find({_id: Meteor.userId()});
return Groups.find({_id: { $in: currentUser.groups}});
}
Then the call to that method in my helper:
groups: function(){
return Meteor.call('userGroups');
}
I've tried debugging this in the console but I'm just getting more confused. I can call var user = Meteor.users.find(_id: Meteor.userId()) and it correctly assigns the current user to the variable, but then when I call user.groups (which is the array of group id's) it says it's undefined. If I check the document in the meteor mongo command line interface, the current user has a groups field with group id's in it.
find query in Meteor returns a cursor which is not an array, but an object.
You should add .fetch() or use findOne().
userGroups: function(){
var currentUser = Meteor.users.findOne({_id: Meteor.userId()});
// or use var currentUser = Meteor.users.find({_id: Meteor.userId()}).fetch();
return Groups.find({_id: { $in: currentUser.groups}});
}
This should work!
Update on publishing groups form Meteor.users collection
To add groups from Meteor.users collection to your Meteor.user() auto-publish which acccounts-password package does, you need to include that into a null publication.
Something like this:
Meteor.publish(null, function () {
if (!this.userId) return this.ready();
return Meteor.users.find({_id: this.userId}, {
fields: {
profile : 1,
emails : 1,
groups : 1
}
});
});