I use Laravel 5.4 and want to upload image.
But in controllrt $request->hasFile('pic') returns false.
This is my blade.php :
.
.
.
<form action="{{ route('my-url') }}" method="post">
<input type="file" name="pic">
</form>
.
.
.
And this is my controller :
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
class myclass extends Controller {
public function myfunc(Request $request) {
if($request->hasFile('pic')){
// never get this
}
}
}
Should i add another field to form or input in blade.php or controller?
You should try this:
The form data being encoded as “multipart/form-data”, which is required when files will be included as form data.
<form action="{{ route('my-url') }}" method="post" enctype="multipart/form-data">
<input type="file" name="pic">
</form>
just addd in your form
<form action="{{ route('my-url') }}" method="post" enctype="multipart/form-data">
<input type="file" name="pic">
</form>
//enctype="multipart/form-data" add this, this will your
Related
On a Typo3 website a form is integrated. The action should be routed to a typoscript user function.
This is what I tried so far:
The fluid form code (excerpt):
<form action="{f:cObject(typoscriptObjectPath: 'lib.mynlreg')}" method="post">
<input type="text" name="email" placeholder="Ihre E-Mail-Adresse">
<input type="submit" name="send" value="Jetzt registrieren" class="submit" />
</form>
The typoscript lib:
lib.mynlreg = USER_INT
lib.mynlreg {
userFunc = Vendor\Extension\myClass->myFunction
}
And the class:
class myClass {
public function myFunction($content, $conf) {
$arguments = $this->request->getArguments();
$formEmail = $arguments['email'];
return '<div>' . $formEmail . '</div>';
}
}
I expect to get the content of the form field "email", but after submitting the page throws an error. The question is, how do I get the post vars into the user function? Thank you for any help!
$this->request is not available in a userFunc. As gautamsinh mori says, you should use \TYPO3\CMS\Core\Utility\GeneralUtility::_GP('email');, however I'm not sure you understand what the f:cObject ViewHelper does.
With this code, your HTML before submitting the form will be:
<form action="<div></div>" method="post">
<input type="text" name="email" placeholder="Ihre E-Mail-Adresse">
<input type="submit" name="send" value="Jetzt registrieren" class="submit" />
</form>
Your HTML after submitting will be:
<form action="<div>filledInEmail</div>" method="post">
<input type="text" name="email" placeholder="Ihre E-Mail-Adresse">
<input type="submit" name="send" value="Jetzt registrieren" class="submit" />
</form>
I'd recommend making an extension for this, but if you really want/need to do it like this, I think what you're looking for is something like:
<f:cObject typoscriptObjectPath="lib.mynlreg" />
<form action="{uri.page(addQueryString: 1)}" method="post">
<input type="text" name="email" placeholder="Ihre E-Mail-Adresse">
<input type="submit" name="send" value="Jetzt registrieren" class="submit" />
</form>
This will create the form with action to the current page (including any query string). You then have to change the userFunc to return an empty string if the form hasn't been submitted. Something like:
class myClass {
public function myFunction($content, $conf) {
$formEmail = \TYPO3\CMS\Core\Utility\GeneralUtility::_GP('email');
if (empty($formEmail)) {
return '';
}
return '<div>' . $formEmail . '</div>';
}
}
I have a model with a field called map_zips and inside that field, I would like to store up to 5 zip codes, comma separated.
I would like to have five different form fields that before getting stored in the database model, I concatenate the values together and store them in the DB in the single column.
How can I create multiple form fields in a view, validate said form fields, perform what needs to be done on said form fields, store them? Beyond that, I think I will also need to split them up when loading up the edit/update page as well.
I guess the simplest way would be to create 5 different columns, one for each zip, but I'd like to learn how to do this to help extend my limited knowledge of Laravel.
In my ReportsController.php my current store method looks like this:
public function store(Request $request) {
$this->validate($request, $this->rules);
$user = Auth::user();
$report = $request->all();
$report['user_id'] = $user->id;
Report::create($report);
return redirect('/reports')->with('status', 'Report created');
}
I don't know if i undertand you question but you can try this:
if you want 5 input fields in your view you can try this, you will see error messages from you validation and a returned message to confirm that the value was stored propperly
#if (count($errors) > 0)
<div class="alert alert-danger">
#foreach ($errors->all() as $error)
<div>{{ $error }}</div>
#endforeach
</div>
#endif
#if(session()->has('message'))
<div class="alert alert-success">
{{ session()->get('message') }}
</div>
#endif
<form action="{{ route("route_to_store_function") }}" method="post">
<input type="text" name="zip1">
<input type="text" name="zip2">
<input type="text" name="zip3">
<input type="text" name="zip4">
<input type="text" name="zip5">
<button type="submit"></button>
</form>
then in your store function, concatenate the fields, save the report and return with a message to the previous page:
public function store(Request $request) {
$this->validate($request, [
'zip1' => 'required',// you can add more validations here
'zip2' => 'required',
'zip3' => 'required',
'zip4' => 'required',
'zip5' => 'required',
]);
$report = new Report();
$report->map_zips = $request->zip1.",".$request->zip2.",".$request->zip3.",".$request->zip4.",".$request->zip5;
$report->save();
return redirect()->back()->with('message', 'The report has been stored succesfully');
}
Then when you want to edit the report you can try this:
public function edit($id) {
$report = Report::find($id)
$zipCodes = explode(",", $report->map_zips);
return view('edit_report_view', compact("report", "zipCodes"));
}
And in you edit view:
<form action="{{ route("route_to_update") }}" method="post">
<input type="hidden" name="id" value="{{ $report->id }}">
<input type="text" name="zip1" value="{{ $zipCodes[0] }}">
<input type="text" name="zip2" value="{{ $zipCodes[1] }}">
<input type="text" name="zip3" value="{{ $zipCodes[2] }}">
<input type="text" name="zip4" value="{{ $zipCodes[3] }}">
<input type="text" name="zip5" value="{{ $zipCodes[4] }}">
<button type="submit"></button>
</form>
I am facing problems with yii2 form get method. Here is my form:
<form class="search-form" method="get" action="<?php echo Yii::$app->urlManager->createAbsoluteUrl(['search/index']); ?>" id="search-form">
<div class="row search-box">
<div class="12u search-box-inner">
<input class="search-input" type="text" id="search-query" placeholder="Search" name="search_key" autocomplete="off" >
</div>
</div>
</form>
Here is my SearchController with actionIndex():
public function actionIndex()
{
$request = Yii::$app->request;
$search_key = $request->get('search_key');
return $this->render('index', ['search_key'=>$search_key]);
}
I want to submit to web/index?r=search/index&&search_key='something', but when I submit this form always returns web/index?searchkey='something'.
What need I do?
If you want use a parameter in your SearchController/Index
return $this->render('index', ['search_key'=>$search_key]);
You should declare in function declaration
public function actionIndex($search_key)
in this way you can use the value of $search_key passsed in render call
by your form submit action
<form class="search-form" method="get" action="
<?php echo Yii::$app->urlManager->createAbsoluteUrl(['search/index']); ?>"
id="search-form">
the resulting target is should be
web/index.php?r=search&id=search-form
and for use this get submit in your SearchController/Index
Your actionIndex function should be
public function actionIndex($id)
{
// $id contain the value you assigne in form action
// in you case you should obtain the value 'search-form'
.......
}
First of all, you need to configuring-web-servers correctly.
The url should not include 'web/index'.
Then change your form with ActiveForm
<?php
use yii\widgets\ActiveForm;
?>
<?php $form = ActiveForm::begin(); ?>
Your form content here.
<?php ActiveForm::end(); ?>
OR
Just change url.
<?php echo Url::to(['search/index']); ?>
I wana create a front-end joomla component and this is my first experience.
here is important things:
1-component/controller.php
class TestController extends JControllerLegacy
{
public function display($cachable = false, $urlparams = false)
{
$view= JFactory::getApplication()->input->getCmd('view','items');
JFactory::getApplication()->input->set('view', $view);
parent::display($cachable, $urlparams);
}
}
2: com_test/model/items.php
<?php
defined('_JEXEC') or die();
jimport( 'joomla.application.component.modellist' );
class TestModelItems extends JModelList
{
public function __construct($config = array())
{
if (empty($config['filter_fields']))
$config['filter_fields'] = array('id', 'title', 'catid');
parent::__construct($config);
}
function getListQuery()
{
$db = JFactory::getDBO();
$query = $db->getQuery(true);
$query->select(...)
return $query;
}
}
I can print the query result on default.php on view folder!
but I wana another thing.
I have a form like this in the front page of my site in a custom module:
<form action="" method="post">
<input type="text" name="wordsearch" value="search">
.
.
<input type="submit" />
</form>
Now!
I do not know how can I send this form (with post method) to getListQuery() function in model folder...how can do it?
i wana when sb click submit form, the component filter query sql according to values of form and then show new result to user!
i googled for hourse but no chance to solve. thanks for your help.
You can submit Form from module to component as follows.
Suppose your component name is com_helloworld The in your module form should have the following things.
<form action="" method="post">
<input type="text" name="wordsearch" value="search">
.
.
<input type="hidden" name="option" value="com_helloworld" />
<input type="hidden" name="view" value="yourview" />
<input type="hidden" name="task" value="my_controller_fun" />
<input type="hidden" value="your_controller_file_name" name="controller">
<input type="submit" />
</form>
In this example your controller file should have my_controller_fun method from controller to model you can use regular method. This methods will get all the form data in your controller , then you can pass that to model.
Detailed :
In your controller file.
function my_controller_fun(){
$post_array = $_POST;
$model = $this->getModel('Profile', 'UsersModel');//example for including profile model you can specify your model file name
$model->function_inyourmodel($post_array);//this function should be in model
}
Hope its help..
I am used to get the echo message of the php script using the jquery ajax success function now I use a plugin but I dont know how to use it
my approach is this but definitely do not work how should the right way? It just go directly to my php script
$(function() {
$('form').ajaxForm(function() {
success: function(data){
$('.new-profile-pic').html(data);
}
});
});
HTML:
<p class="new-profile-pic">
<!--Image should be here-->
</p>
<form enctype="multipart/form-data" action="upload-image.php" method="post">
<input type="hidden" name="MAX_FILE_SIZE" value="100000">
<input class="profile-pic-name" name="uploadedfile" type="file">
<input type="submit">
</form>
PHP:
<?php
$target_path = "uploads/";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo '<img alt="" src="'.$target_path.'">';
} else{
echo "There was an error uploading the file, please try again!";
}
?>
You need to prevent the default action from occuring.
I believe this post has the answer you are looking for:
How do I submit a form using jquery (ajaxForm plugin) to an external site but not reload to a different page?
You need to use .preventDefault() on the submit event, or get it to return false on the form submit, e.g.:
<form enctype="multipart/form-data" action="upload-image.php" method="post" onsubmit="return false;">