I am writing a Mac OS app in Swift and want to repeat a task every 0.5s (more or less, high precision is not required). This app should run in the background while I use other applications.
I'm currently using a Timer:
Timer.scheduledTimer(withTimeInterval: 0.5, repeats: true)
It starts fine with updates roughly every 0.5s but after some time in the background, the Timer slows down considerably to intervals of roughly 1s or 2s (it's very close to these values to it seems that the timer skips ticks or has a slowdown of a factor 2 or 4).
I suspect it's because the app is given a low priority after a few seconds in the background. Is there a way to avoid this? It can be either in the app settings in XCode by asking to stay active all the time, or possibly from the system when the app is run (or even but doing things differently without Timer but I'd rather keep it simple if possible).
Here is a minimal working example: the app only has a ViewController with this code
import Cocoa
class ViewController: NSViewController {
var lastUpdate = Date().timeIntervalSince1970
override func viewDidLoad() {
super.viewDidLoad()
let timer = Timer.scheduledTimer(withTimeInterval: 0.5, repeats: true) {
timer in
let now = Date().timeIntervalSince1970
print(now - self.lastUpdate)
self.lastUpdate = now
}
RunLoop.current.add(timer, forMode: .common)
}
}
Output at start is
0.5277011394500732
0.5008649826049805
0.5000109672546387
0.49898695945739746
0.5005381107330322
0.5005340576171875
0.5000457763671875
...
But after a few seconds in the background it becomes
0.49993896484375
0.49997520446777344
0.5000619888305664
1.5194149017333984
1.0009620189666748
0.9984869956970215
2.0002501010894775
2.001321792602539
1.9989290237426758
...
If I bring the app back to the foreground, the timer goes back to 0.5s increments.
Note: I'm running Mac OSX 10.15.5 (Catalina) on an iMac
This is because of the App Nap. You can disable App Nap but it is not recommended.
var activity: NSObjectProtocol?
activity = ProcessInfo().beginActivity(options: .userInitiatedAllowingIdleSystemSleep, reason: "Timer delay")
The default tolerance value of timer is zero but The system reserves the right to apply a small amount of tolerance to certain timers regardless of the value of tolerance property.
As I stated in my comment below, if you want granularities lower than 1.0 s, you should not use Timer objects, but rather GCD. I wrote a class MilliTimer you can use where you have improved granularity down to a few milliseconds. Please try this in a Playground and then in your app. In this example, I set the granularity of the timer based on GCD to 50 milliseconds. To adjust the delay pass the delay you want in milliseconds in the respective parameter of the initializer. In your case, you might be interested in 500 ms = 0.5 s.
import Cocoa
public class MilliTimer
{
static let µseconds = 1000000.0
static var lastUpdate = DispatchTime.now()
var delay = 0
var doStop = false
var runs = 0
let maxRuns = 50
private class func timer(_ milliseconds:Int, closure:#escaping ()->())
{
let when = DispatchTime.now() + DispatchTimeInterval.milliseconds(milliseconds)
DispatchQueue.main.asyncAfter(deadline: when, execute: closure)
}
init(delay:Int) {
self.delay = delay
}
func delta() -> Double {
let now = DispatchTime.now()
let nowInMilliseconds = Double(now.uptimeNanoseconds) / MilliTimer.µseconds
let lastUpdateInMilliseconds = Double(MilliTimer.lastUpdate.uptimeNanoseconds) / MilliTimer.µseconds
let delta = nowInMilliseconds - lastUpdateInMilliseconds
MilliTimer.lastUpdate = now
return delta
}
func scheduleTimer()
{
MilliTimer.timer(delay) {
print(self.delta())
if self.doStop == false {
self.scheduleTimer()
self.runs += 1
if self.runs > self.maxRuns {
self.stop()
}
}
}
}
func stop() {
doStop = true
}
}
MilliTimer(delay: 50).scheduleTimer()
CFRunLoopRun()
I am writing a Mac OS app in Swift and want to repeat a task every 0.5s (more or less, high precision is not required). This app should run in the background while I use other applications.
I'm currently using a Timer:
Timer.scheduledTimer(withTimeInterval: 0.5, repeats: true)
It starts fine with updates roughly every 0.5s but after some time in the background, the Timer slows down considerably to intervals of roughly 1s or 2s (it's very close to these values to it seems that the timer skips ticks or has a slowdown of a factor 2 or 4).
I suspect it's because the app is given a low priority after a few seconds in the background. Is there a way to avoid this? It can be either in the app settings in XCode by asking to stay active all the time, or possibly from the system when the app is run (or even but doing things differently without Timer but I'd rather keep it simple if possible).
Here is a minimal working example: the app only has a ViewController with this code
import Cocoa
class ViewController: NSViewController {
var lastUpdate = Date().timeIntervalSince1970
override func viewDidLoad() {
super.viewDidLoad()
let timer = Timer.scheduledTimer(withTimeInterval: 0.5, repeats: true) {
timer in
let now = Date().timeIntervalSince1970
print(now - self.lastUpdate)
self.lastUpdate = now
}
RunLoop.current.add(timer, forMode: .common)
}
}
Output at start is
0.5277011394500732
0.5008649826049805
0.5000109672546387
0.49898695945739746
0.5005381107330322
0.5005340576171875
0.5000457763671875
...
But after a few seconds in the background it becomes
0.49993896484375
0.49997520446777344
0.5000619888305664
1.5194149017333984
1.0009620189666748
0.9984869956970215
2.0002501010894775
2.001321792602539
1.9989290237426758
...
If I bring the app back to the foreground, the timer goes back to 0.5s increments.
Note: I'm running Mac OSX 10.15.5 (Catalina) on an iMac
This is because of the App Nap. You can disable App Nap but it is not recommended.
var activity: NSObjectProtocol?
activity = ProcessInfo().beginActivity(options: .userInitiatedAllowingIdleSystemSleep, reason: "Timer delay")
The default tolerance value of timer is zero but The system reserves the right to apply a small amount of tolerance to certain timers regardless of the value of tolerance property.
As I stated in my comment below, if you want granularities lower than 1.0 s, you should not use Timer objects, but rather GCD. I wrote a class MilliTimer you can use where you have improved granularity down to a few milliseconds. Please try this in a Playground and then in your app. In this example, I set the granularity of the timer based on GCD to 50 milliseconds. To adjust the delay pass the delay you want in milliseconds in the respective parameter of the initializer. In your case, you might be interested in 500 ms = 0.5 s.
import Cocoa
public class MilliTimer
{
static let µseconds = 1000000.0
static var lastUpdate = DispatchTime.now()
var delay = 0
var doStop = false
var runs = 0
let maxRuns = 50
private class func timer(_ milliseconds:Int, closure:#escaping ()->())
{
let when = DispatchTime.now() + DispatchTimeInterval.milliseconds(milliseconds)
DispatchQueue.main.asyncAfter(deadline: when, execute: closure)
}
init(delay:Int) {
self.delay = delay
}
func delta() -> Double {
let now = DispatchTime.now()
let nowInMilliseconds = Double(now.uptimeNanoseconds) / MilliTimer.µseconds
let lastUpdateInMilliseconds = Double(MilliTimer.lastUpdate.uptimeNanoseconds) / MilliTimer.µseconds
let delta = nowInMilliseconds - lastUpdateInMilliseconds
MilliTimer.lastUpdate = now
return delta
}
func scheduleTimer()
{
MilliTimer.timer(delay) {
print(self.delta())
if self.doStop == false {
self.scheduleTimer()
self.runs += 1
if self.runs > self.maxRuns {
self.stop()
}
}
}
}
func stop() {
doStop = true
}
}
MilliTimer(delay: 50).scheduleTimer()
CFRunLoopRun()
I can't find a way to implement a wait function, I'm using swiftforwindows and no examples online have been able to solve it so far. It's Swift 4.2
The class is basically an array that when a function is called each index on the array gets a constant value deducted. the tick function is what is being called. I'm new to Swift.
class resProj {
var list = [1,1,1,1]
var projReq = [100,200,300,50]
var completed = false
func tick(){
for count in 0..<projReq.count{
if projReq[count] <= list[count]{
projReq[count] = 0
}
else if projReq[count] > list[count]{
projReq[count] -= list[count]
}
}
print(projReq)
}
init(
mathsP mathsIn: Int,
scienceP sciecnceIn: Int,
enginerP enginerIn: Int,
businessP businessIn: Int) {
self.list [0] = mathsIn
self.list [1] = sciecnceIn
self.list [2] = enginerIn
self.list [3] = businessIn
}
}
var spaceElev = resProj(
mathsP: 10,
scienceP: 20,
enginerP: 30,
businessP: 5)
var x = false
while x == false{
//wait function here pls//
print("tick", terminator:"?")
let y = readLine()
if y == "y"{
spaceElev.tick()
}
else{
print("gotta put y")
}
var templist = spaceElev.projReq
var templistcount = 0
templistcount = templist.count
for loop in 0..<templistcount{
if templist[loop] == 0{
templistcount -= 1
}
}
if templistcount == 0 {
x = true
print("project completed")
}
}
}
Where it says //wait function here pls// I would like to make the program wait for 1 second.
There are a lot of way to do this but most common way is create a completion function. For example:
func doSth(_ someParameter: String, _ completion: ()->()) {
print(someParameter)
// After your code is finish call completion
completion()
}
And when you call (there is two way to call):
doSth("Done") {
print("You can be sure that this block will work after your func finish")
}
or you can simply create another func and send it as a parameter.
You can also use DispatchQueue:
DispatchQueue.main.asyncAfter(deadline: .now()+1) {
// put your func here...
}
You can simple use the UNIX-Functin func sleep(_: UInt32) -> UInt32.
In your case use sleep(1) to wait one second.
You could use Grand Central Dispatch or perform.
GCD solution:
let delayInSeconds = 1
DispatchQueue.main.asyncAfter(deadline: .now() + delayInSeconds) {
print("tick", terminator:"?")
}
If you want to learn more about Grand Central Dispatch (GCD) I suggest you read through this:
Grand Central Dispatch - Wikipedia
Grand Central Dispatch Tutorial - Ray Wenderlich
Perform solution:
Create a function like this:
#objc func delayedFunc() {
//write the code here that you want to execute with a one second delay
}
Then call this where you want the delayed function to execute:
let delayInSeconds = 1
perform(#selector(delayedFunc), with: nil, afterDelay: delayInSeconds)
You can use the RunLoop class:
func wait(for interval: TimeInterval) {
RunLoop.current.run(until: Date() + interval)
}
I have two objects where I need to update their UI at the same time. I have a for loop for one, and after that another for loop. Each iteration in the for loop I have a short delay so that for elements in the object I am making a UI change... one after the other - not seemingly all at once.
func update(value: Int){
var delay: Double = 0.05
// first loop
for i in 0...value {
delayWithSeconds(delay) {
//do something with object 1
}
delay = delay + 0.05
}
var delay2: Double = 0.05
// second loop
for i in 0...value {
delayWithSeconds(delay2) {
//do something with object 2
}
delay2 = delay2 + 0.05
}
}
// Utility
func delayWithSeconds(_ seconds: Double, completion: #escaping () -> ()) {
DispatchQueue.main.asyncAfter(deadline: .now() + seconds) {
completion()
}
}
I have tried wrapping each for loop with DispatchQueue.main.async and it didn't make a difference. In short - I would like to run both for loops at the same time (or perceived as such). These are on the UI thread.
I tried this and it seemed to work out quite well. It does exactly what I want it to do (at least visually they seem to run at the same time).
let concurrentQueue = DispatchQueue(label: "net.ericd.hello", attributes: .concurrent)
concurrentQueue.async {
//my loop with delay here for object 1.
}
concurrentQueue.async {
//my separate loop with delay here for object 2.
}
We can use it when we want execute different arrays at the same time:
using this Generic Function
zip(_:_:)
Here i took 2 array:
var arrOfInt = ["1","2","3"]
var arrOfIntString = ["one","two","three"]
for (intNum, intString) in zip(arrOfInt, arrOfIntString) {
print("Int:\(intNum), String:\(intString)")
}
How can we measure the time elapsed for running a function in Swift? I am trying to display the elapsed time like this: "Elapsed time is .05 seconds". Saw that in Java, we can use System.nanoTime(), are there any equivalent methods available in Swift to accomplish this?
Please have a look at the sample program:
func isPrime(_ number: Int) -> Bool {
var i = 0;
for i=2; i<number; i++ {
if number % i == 0, i != 0 {
return false
}
}
return true
}
var number = 5915587277
if isPrime(number) {
print("Prime number")
} else {
print("NOT a prime number")
}
Update
With Swift 5.7, everything below becomes obsolete. Swift 5.7 introduces the concept of a Clock which has a function designed to do exactly what is required here.
There are two concrete examples of a Clock provided: ContinuousClock and SuspendingClock. The former keeps ticking when the system is suspending and the latter does not.
The following is an example of what to do in Swift 5.7
func doSomething()
{
for i in 0 ..< 1000000
{
if (i % 10000 == 0)
{
print(i)
}
}
}
let clock = ContinuousClock()
let result = clock.measure(doSomething)
print(result) // On my laptop, prints "0.552065882 seconds"
It also allows you to measure closures directly, of course
let clock = ContinuousClock()
let result = clock.measure {
for i in 0 ..< 1000000
{
if (i % 10000 == 0)
{
print(i)
}
}
}
print(result) // "0.534663798 seconds"
Pre Swift 5.7
Here's a Swift function I wrote to measure Project Euler problems in Swift
As of Swift 3, there is now a version of Grand Central Dispatch that is "swiftified". So the correct answer is probably to use the DispatchTime API.
My function would look something like:
// Swift 3
func evaluateProblem(problemNumber: Int, problemBlock: () -> Int) -> Answer
{
print("Evaluating problem \(problemNumber)")
let start = DispatchTime.now() // <<<<<<<<<< Start time
let myGuess = problemBlock()
let end = DispatchTime.now() // <<<<<<<<<< end time
let theAnswer = self.checkAnswer(answerNum: "\(problemNumber)", guess: myGuess)
let nanoTime = end.uptimeNanoseconds - start.uptimeNanoseconds // <<<<< Difference in nano seconds (UInt64)
let timeInterval = Double(nanoTime) / 1_000_000_000 // Technically could overflow for long running tests
print("Time to evaluate problem \(problemNumber): \(timeInterval) seconds")
return theAnswer
}
Old answer
For Swift 1 and 2, my function uses NSDate:
// Swift 1
func evaluateProblem(problemNumber: Int, problemBlock: () -> Int) -> Answer
{
println("Evaluating problem \(problemNumber)")
let start = NSDate() // <<<<<<<<<< Start time
let myGuess = problemBlock()
let end = NSDate() // <<<<<<<<<< end time
let theAnswer = self.checkAnswer(answerNum: "\(problemNumber)", guess: myGuess)
let timeInterval: Double = end.timeIntervalSinceDate(start) // <<<<< Difference in seconds (double)
println("Time to evaluate problem \(problemNumber): \(timeInterval) seconds")
return theAnswer
}
Note that using NSdate for timing functions is discouraged: "The system time may decrease due to synchronization with external time references or due to an explicit user change of the clock.".
This is a handy timer class based on CoreFoundations CFAbsoluteTime:
import CoreFoundation
class ParkBenchTimer {
let startTime: CFAbsoluteTime
var endTime: CFAbsoluteTime?
init() {
startTime = CFAbsoluteTimeGetCurrent()
}
func stop() -> CFAbsoluteTime {
endTime = CFAbsoluteTimeGetCurrent()
return duration!
}
var duration: CFAbsoluteTime? {
if let endTime = endTime {
return endTime - startTime
} else {
return nil
}
}
}
You can use it like this:
let timer = ParkBenchTimer()
// ... a long runnig task ...
print("The task took \(timer.stop()) seconds.")
Use clock, ProcessInfo.systemUptime, or DispatchTime for simple start-up time.
There are, as far as I know, at least ten ways to measure elapsed time:
Monotonic Clock based:
ProcessInfo.systemUptime.
mach_absolute_time with mach_timebase_info as mentioned in this
answer.
clock() in POSIX standard.
times() in POSIX standard. (Too complicated since we need
to consider user-time v.s. system-time, and child processes are
involved.)
DispatchTime (a wrapper around Mach time API) as mentioned by JeremyP in accepted answer.
CACurrentMediaTime().
Wall Clock based:
(never use those for metrics: see below why)
NSDate/Date as mentioned by others.
CFAbsoluteTime as mentioned by others.
DispatchWallTime.
gettimeofday() in POSIX standard.
Option 1, 2 and 3 are elaborated below.
Option 1: Process Info API in Foundation
do {
let info = ProcessInfo.processInfo
let begin = info.systemUptime
// do something
let diff = (info.systemUptime - begin)
}
where diff:NSTimeInterval is the elapsed time by seconds.
Option 2: Mach C API
do {
var info = mach_timebase_info(numer: 0, denom: 0)
mach_timebase_info(&info)
let begin = mach_absolute_time()
// do something
let diff = Double(mach_absolute_time() - begin) * Double(info.numer) / Double(info.denom)
}
where diff:Double is the elapsed time by nano-seconds.
Option 3: POSIX clock API
do {
let begin = clock()
// do something
let diff = Double(clock() - begin) / Double(CLOCKS_PER_SEC)
}
where diff:Double is the elapsed time by seconds.
Why Not Wall-Clock Time for Elapsed Time?
In documentation of CFAbsoluteTimeGetCurrent:
Repeated calls to this function do not guarantee monotonically
increasing results.
Reason is similar to currentTimeMillis vs nanoTime in Java:
You can't use the one for the other purpose. The reason is that no
computer's clock is perfect; it always drifts and occasionally
needs to be corrected. This correction might either happen
manually, or in the case of most machines, there's a process that
runs and continually issues small corrections to the system clock
("wall clock"). These tend to happen often. Another such correction
happens whenever there is a leap second.
Here CFAbsoluteTime provides wall clock time instead of start-up
time. NSDate is wall clock time as well.
Swift 4 shortest answer:
let startingPoint = Date()
// ... intensive task
print("\(startingPoint.timeIntervalSinceNow * -1) seconds elapsed")
It will print you something like 1.02107906341553 seconds elapsed (time of course will vary depending on the task, I'm just showing this for you guys to see the decimal precision level for this measurement).
Hope it helps someone in Swift 4 from now on!
Update
If you want to have a generic way of testing portions of code, I'd suggest the next snippet:
func measureTime(for closure: #autoclosure () -> Any) {
let start = CFAbsoluteTimeGetCurrent()
closure()
let diff = CFAbsoluteTimeGetCurrent() - start
print("Took \(diff) seconds")
}
Usage
measureTime(for: <insert method signature here>)
Console log
Took xx.xxxxx seconds
Just Copy and Paste this function. Written in swift 5.
Copying JeremyP here.
func calculateTime(block : (() -> Void)) {
let start = DispatchTime.now()
block()
let end = DispatchTime.now()
let nanoTime = end.uptimeNanoseconds - start.uptimeNanoseconds
let timeInterval = Double(nanoTime) / 1_000_000_000
print("Time: \(timeInterval) seconds")
}
Use it like
calculateTime {
exampleFunc()// function whose execution time to be calculated
}
let start = NSDate()
for index in 1...10000 {
// do nothing
}
let elapsed = start.timeIntervalSinceNow
// elapsed is a negative value.
You could create a time function for measuring you calls.
I am inspired by Klaas' answer.
func time <A> (f: #autoclosure () -> A) -> (result:A, duration: String) {
let startTime = CFAbsoluteTimeGetCurrent()
let result = f()
let endTime = CFAbsoluteTimeGetCurrent()
return (result, "Elapsed time is \(endTime - startTime) seconds.")
}
This function would allow you to call it like this time (isPrime(7)) which would return a tuple containing the result and a string description of the elapsed time.
If you only wish the elapsed time you can do this time (isPrime(7)).duration
It looks like iOS 13 introduced a new API to use with DispatchTime that removes a need to calculate the difference between two timestamps manually.
distance(to:)
let start: DispatchTime = .now()
heavyTaskToMeasure()
let duration = start.distance(to: .now())
print(duration)
// prints: nanoseconds(NUMBER_OF_NANOSECONDS_BETWEEN_TWO_TIMESTAMPS)
Sadly the documentation is not provided, but after doing some tests it looks like the .nanoseconds case is always returned.
With a simple extension you could convert the DispatchTimeInterval to TimeInterval. credit
extension TimeInterval {
init?(dispatchTimeInterval: DispatchTimeInterval) {
switch dispatchTimeInterval {
case .seconds(let value):
self = Double(value)
case .milliseconds(let value):
self = Double(value) / 1_000
case .microseconds(let value):
self = Double(value) / 1_000_000
case .nanoseconds(let value):
self = Double(value) / 1_000_000_000
case .never:
return nil
}
}
}
Simple helper function for measuring execution time with closure.
func printExecutionTime(withTag tag: String, of closure: () -> ()) {
let start = CACurrentMediaTime()
closure()
print("#\(tag) - execution took \(CACurrentMediaTime() - start) seconds")
}
Usage:
printExecutionTime(withTag: "Init") {
// Do your work here
}
Result:
#Init - execution took 1.00104497105349 seconds
you can measure the nanoseconds like e.g. this:
let startDate: NSDate = NSDate()
// your long procedure
let endDate: NSDate = NSDate()
let dateComponents: NSDateComponents = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian).components(NSCalendarUnit.CalendarUnitNanosecond, fromDate: startDate, toDate: endDate, options: NSCalendarOptions(0))
println("runtime is nanosecs : \(dateComponents.nanosecond)")
I use this:
public class Stopwatch {
public init() { }
private var start_: NSTimeInterval = 0.0;
private var end_: NSTimeInterval = 0.0;
public func start() {
start_ = NSDate().timeIntervalSince1970;
}
public func stop() {
end_ = NSDate().timeIntervalSince1970;
}
public func durationSeconds() -> NSTimeInterval {
return end_ - start_;
}
}
I don't know if it's more or less accurate than previously posted. But the seconds have a lot of decimals and seem to catch small code changes in algorithms like QuickSort using swap() vs. implementing swap urself etc.
Remember to crank up your build optimizations when testing performance:
Here is my try for the simplest answer:
let startTime = Date().timeIntervalSince1970 // 1512538946.5705 seconds
// time passes (about 10 seconds)
let endTime = Date().timeIntervalSince1970 // 1512538956.57195 seconds
let elapsedTime = endTime - startTime // 10.0014500617981 seconds
Notes
startTime and endTime are of the type TimeInterval, which is just a typealias for Double, so it is easy to convert it to an Int or whatever. Time is measured in seconds with sub-millisecond precision.
See also DateInterval, which includes an actual start and end time.
Using the time since 1970 is similar to Java timestamps.
The recommend way to check elapsed time/performance is using the measure function that is available in XCTests.
It isn't reliable to write your own measure blocks, since the performance (and therefore execution/elapsed time) of a block of code is influenced by e.g. CPU caches.
The second time a function is invoked, would likely be quicker than the first time it is invoked, although it can vary a few %. Therefore 'benchmarking' by using your own closures (given all over the place here) by executing it once, can give different results than your code being executed in production by real users.
The measure function invokes your block of code several times, mimicking the performance/elapsed time of your code like it is used in production (at least gives more accurate results).
I have borrowed the idea from Klaas to create a lightweight struct to measure running and interval time:
Code Usage:
var timer = RunningTimer.init()
// Code to be timed
print("Running: \(timer) ") // Gives time interval
// Second code to be timed
print("Running: \(timer) ") // Gives final time
The stop function does not have to be called, as the print function will give the time lapsed. It may be called repeatedly to get the time lapsed.
But to stop the timer at certain point in the code use timer.stop() it may also be used to return the time in seconds: let seconds = timer.stop()
After the timer is stopped the interval timer will not, so the print("Running: \(timer) ") will give the correct time even after a few lines of code.
Following is the code for RunningTimer. It is tested for Swift 2.1:
import CoreFoundation
// Usage: var timer = RunningTimer.init()
// Start: timer.start() to restart the timer
// Stop: timer.stop() returns the time and stops the timer
// Duration: timer.duration returns the time
// May also be used with print(" \(timer) ")
struct RunningTimer: CustomStringConvertible {
var begin:CFAbsoluteTime
var end:CFAbsoluteTime
init() {
begin = CFAbsoluteTimeGetCurrent()
end = 0
}
mutating func start() {
begin = CFAbsoluteTimeGetCurrent()
end = 0
}
mutating func stop() -> Double {
if (end == 0) { end = CFAbsoluteTimeGetCurrent() }
return Double(end - begin)
}
var duration:CFAbsoluteTime {
get {
if (end == 0) { return CFAbsoluteTimeGetCurrent() - begin }
else { return end - begin }
}
}
var description:String {
let time = duration
if (time > 100) {return " \(time/60) min"}
else if (time < 1e-6) {return " \(time*1e9) ns"}
else if (time < 1e-3) {return " \(time*1e6) µs"}
else if (time < 1) {return " \(time*1000) ms"}
else {return " \(time) s"}
}
}
Wrap it up in a completion block for easy use.
public class func secElapsed(completion: () -> Void) {
let startDate: NSDate = NSDate()
completion()
let endDate: NSDate = NSDate()
let timeInterval: Double = endDate.timeIntervalSinceDate(startDate)
println("seconds: \(timeInterval)")
}
Static Swift3 class for basic function timing. It will keep track of each timer by name. Call it like this at the point you want to start measuring:
Stopwatch.start(name: "PhotoCapture")
Call this to capture and print the time elapsed:
Stopwatch.timeElapsed(name: "PhotoCapture")
This is the output: *** PhotoCapture elapsed ms: 1402.415125
There is a "useNanos" parameter if you want to use nanos.
Please feel free to change as needed.
class Stopwatch: NSObject {
private static var watches = [String:TimeInterval]()
private static func intervalFromMachTime(time: TimeInterval, useNanos: Bool) -> TimeInterval {
var info = mach_timebase_info()
guard mach_timebase_info(&info) == KERN_SUCCESS else { return -1 }
let currentTime = mach_absolute_time()
let nanos = currentTime * UInt64(info.numer) / UInt64(info.denom)
if useNanos {
return (TimeInterval(nanos) - time)
}
else {
return (TimeInterval(nanos) - time) / TimeInterval(NSEC_PER_MSEC)
}
}
static func start(name: String) {
var info = mach_timebase_info()
guard mach_timebase_info(&info) == KERN_SUCCESS else { return }
let currentTime = mach_absolute_time()
let nanos = currentTime * UInt64(info.numer) / UInt64(info.denom)
watches[name] = TimeInterval(nanos)
}
static func timeElapsed(name: String) {
return timeElapsed(name: name, useNanos: false)
}
static func timeElapsed(name: String, useNanos: Bool) {
if let start = watches[name] {
let unit = useNanos ? "nanos" : "ms"
print("*** \(name) elapsed \(unit): \(intervalFromMachTime(time: start, useNanos: useNanos))")
}
}
}
This is the snippet I came up with and it seems to work for me on my Macbook with Swift 4.
Never tested on other systems, but I thought it's worth sharing anyway.
typealias MonotonicTS = UInt64
let monotonic_now: () -> MonotonicTS = mach_absolute_time
let time_numer: UInt64
let time_denom: UInt64
do {
var time_info = mach_timebase_info(numer: 0, denom: 0)
mach_timebase_info(&time_info)
time_numer = UInt64(time_info.numer)
time_denom = UInt64(time_info.denom)
}
// returns time interval in seconds
func monotonic_diff(from: MonotonicTS, to: MonotonicTS) -> TimeInterval {
let diff = (to - from)
let nanos = Double(diff * time_numer / time_denom)
return nanos / 1_000_000_000
}
func seconds_elapsed(since: MonotonicTS) -> TimeInterval {
return monotonic_diff(from: since, to:monotonic_now())
}
Here's an example of how to use it:
let t1 = monotonic_now()
// .. some code to run ..
let elapsed = seconds_elapsed(since: t1)
print("Time elapsed: \(elapsed*1000)ms")
Another way is to do it more explicitly:
let t1 = monotonic_now()
// .. some code to run ..
let t2 = monotonic_now()
let elapsed = monotonic_diff(from: t1, to: t2)
print("Time elapsed: \(elapsed*1000)ms")
This is how I wrote it.
func measure<T>(task: () -> T) -> Double {
let startTime = CFAbsoluteTimeGetCurrent()
task()
let endTime = CFAbsoluteTimeGetCurrent()
let result = endTime - startTime
return result
}
To measure a algorithm use it like that.
let time = measure {
var array = [2,4,5,2,5,7,3,123,213,12]
array.sorted()
}
print("Block is running \(time) seconds.")
Based on Franklin Yu answer and Cœur comments
Details
Xcode 10.1 (10B61)
Swift 4.2
Solution 1
measure(_:)
Solution 2
import Foundation
class Measurer<T: Numeric> {
private let startClosure: ()->(T)
private let endClosure: (_ beginningTime: T)->(T)
init (startClosure: #escaping ()->(T), endClosure: #escaping (_ beginningTime: T)->(T)) {
self.startClosure = startClosure
self.endClosure = endClosure
}
init (getCurrentTimeClosure: #escaping ()->(T)) {
startClosure = getCurrentTimeClosure
endClosure = { beginningTime in
return getCurrentTimeClosure() - beginningTime
}
}
func measure(closure: ()->()) -> T {
let value = startClosure()
closure()
return endClosure(value)
}
}
Usage of solution 2
// Sample with ProcessInfo class
m = Measurer { ProcessInfo.processInfo.systemUptime }
time = m.measure {
_ = (1...1000).map{_ in Int(arc4random()%100)}
}
print("ProcessInfo: \(time)")
// Sample with Posix clock API
m = Measurer(startClosure: {Double(clock())}) { (Double(clock()) - $0 ) / Double(CLOCKS_PER_SEC) }
time = m.measure {
_ = (1...1000).map{_ in Int(arc4random()%100)}
}
print("POSIX: \(time)")
From Swift 5.7 (macOS 13.0, iOS 16.0, watchOS 9.0, tvOS 16.0), you can use ContinuousClock and the measure block, which returns a Duration object. It has components that contain the measured time in seconds or attoseconds, which is 1×10−18 of a second.
let clock = ContinuousClock()
let duration = clock.measure {
// put here what you want to measure
}
print("Duration: \(duration.components.seconds) seconds")
print("Duration: \(duration.components.attoseconds) attoseconds")