How to explain the following sentences about private[this] and variance? - scala

In Chapter 19 ,"Programming in scala 2nd edition",how to explain the bold sentences ?
object private members can be accessed only from within the object in
which they are defined. It turns out that accesses to variables from
the same object in which they are defined do not cause problems with
variance. The intuitive explanation is that, in order to construct a
case where variance would lead to type errors, you need to have a
reference to a containing object that has a statically weaker type
than the type the object was defined with. For accesses to object
private values, however,this is impossible.

I think the most intuitive way to explain what Martin is trying to say is to look at arrays in Java. Arrays in Java are covariant but don't type check according to covariance rules. This means they explode at runtime instead of compile time:
abstract class Animal {}
class Girafee extends Animal {}
class Lion extends Animal {}
public class Foo {
public static void main(String[] args) {
Animal[] animals = new Girafee[10];
animals[0] = new Lion();
}
}
The fact that I can do this is because:
Java doesn't restrict this at compile time (due to a design decision)
I have a reference to the underlying array which allows me to manipulate it's internal values
This doesn't hold when talking about private fields of a class from the outside.
For example, assume the following class:
class Holder[+T](initialValue: Option[T]) {
private[this] var value: Option[T] = initialValue
}
When creating an instance of Holder, I am not visible to it's internal fields, thus I cannot manipulate them directly like I did with the Java array. This way, the compiler makes sure they are protected, and each manipulation to the field will have to be through a method, where the type checker is strict and doesn't allow funky business.

Related

Singleton Object vs Companion Object in Class

I have written the following code:
class a {
object c {
var a = "STATIC"
def m() = print("STATIC METHOD")
var f = () => print("STATIC FUNCTION")
}
}
object m {
def main(args: Array[String]) = {
var o = new a()
o.c.m()
}
}
Can I say that the variables, functions and methods that are declared in object c can be static?
If I change name of object c with a then will the object becomes a companion object?
Scala has no true meaning of 'static' that Java does.
The fact that objects have a backing on the JVM that uses static methods / fields is a leaking implementation detail that you only need to deal with if using Java/JVM interop.
Unless you explicitly need that interop, you need to stop thinking of declared objects as 'static' and instead think of them as singletons within their given scope.
An inner object nested under a class, means that there is only ever going to be 1 instance of that object, for each class instance, unlike inner classes which could have multiple instances.
This applies at the top level as well, except that Scala can do additional compatibility with other JVM languages, and mark some of the methods/members as static.
Fields and methods in an object are how Scala declares things that you would have used static for in Java. I guess you can, for intuition sake, say that those fields are usually static (as in only one of those in a JVM at once).
However, in your example, you put an object inside a class, making it no longer static. You can easily check this with a few lines of code (that you can find here on Scastie).
class MyClass {
object Embedded {
val a = "field"
def m = println("method")
}
}
val a = new MyClass().Embedded
val b = new MyClass().Embedded
// prints "a and b are different objects"
if (a eq b)
println("a and b are the same object")
else
println("a and b are different objects")
Regarding your second question: no, class and object must be in the same scope in order for it to be a companion object. You can find more details on the Scala Language Specification.
I quote from there:
Generally, a companion module of a class is an object which has the same name as the class and is defined in the same scope and compilation unit. Conversely, the class is called the companion class of the module.
To answer you questions:
The methods and fields in a.c are not globally static because they need an instance of a to exist. If a were an object, a.c would be static too.
If you want to have a companion object with static fields and methods for your class a it has to be defined outside of a's code block, like this:
class a {
/* non-static stuff goes here */
}
object a {
/* static stuff goes there */
def m() = print("STATIC METHOD")
}
You must keep both in the same file, defining the object or the
class first doesn't matter, so it generally depend on a convention or what makes most sense depending on use case.
If you want to call the static method a.m inside the class a, you will still need to call it a.m and not just m. But the class a will be able to use private fields and methods of object a, because they are companions.
As others already said, static doesn't really exist in Scala, but the concept transpires from Java since Scala is in most cases compiled into java bytecode.
Last advice, the convention is usually the same in Scala and in Java for classes and object: the first-letter of their name should be uppercase (except in some advanced Scala cases)

Why does the ArrayBuilder base class not provide method interfaces?

ArrayBuilder has no method definitions:
abstract class ArrayBuilder[T] extends ReusableBuilder[T, Array[T]] with Serializable
Yet, implementations of it will commonly share methods with same interface, up to the generic type argument T (taking mkArray as an example):
final class ofFloat extends ArrayBuilder[Float] {
//...
private def mkArray(size: Int): Array[Float] = {
val newelems = new Array[Float](size)
if (this.size > 0) Array.copy(elems, 0, newelems, 0, this.size)
newelems
}
Methods creating new arrays couldn't be abstracted "up to the generic type argument T" before ClassTags were introduced; afterwards they could, but it would lose performance (probably very slightly in most circumstances, but this code is called quite often...).
Type erasure interacts weirdly with arrays. Any Array[T] you have in ArrayBuilder[T] will end up being Array[AnyRef]. So if you just have abstract methods there, classes like ofFloat will end up with a lot of hidden casts which JIT may or may not optimize.

companion object to a private class: why isn't it valid?

i needed two instances that has access to each other privates. i naturaly thought of a companion object that grants access to a one and only instance of it's companion class. the class itself i made private, so users cannot just create instances using new.
object A {
def apply = dual
lazy val dual = new A
}
private class A {
//some irrelevant logic...
}
this code does not compile. i get: class A escapes its defining scope as part of type A error, which i don't really understand. my current workaround was to define a trait with every method declaration the class should have and make class A extend that trait, while dual is of the trait type, and not class A type.
what's the theoretic problem i'm missing here? why is this forbiden?
Paolo's solution is good (+1), but he didn't explain the error message, so let me try that. The problem stems from the fact that every method needs a return type. Your original definition of apply and dual returned an object of class A, thus the implicit return type of both was A. That implies that A must be visible to clients - how else could they call the function or access the val? Moreover, as both - and their parent object too - are public, they are globally visible. However, you declared A private which means it must not be visible outside its package. So there is a conflict which can't be resolved by the compiler.
The general rule is that all parameter and return type of functions / members must have (at least) the same scope of visibility as the referring member itself*. Thus one trivial way to solve this problem would be to reduce the visibility of apply and dual to private. This would satisfy the compiler, but not you :-)
Your solution gets around the problem by changing the static return type to a public trait, which thus has the same visibility as the members referring to it. The dynamic type of the returned object is still class A, however, this need not be visible to clients. This is a classic example of the principle "program to interfaces, not implementations".
Note that to apply this principle to the full extent, one could turn class A into a private inner class of object A, thus making it innaccessible even for other classes within the same package:
trait A {
//...
}
object A {
def apply: A = dual
lazy val dual: A = new AImpl
private class AImpl extends A {
//some irrelevant logic...
}
}
* To be pedantic, the enclosing class / object may reduce the visibility of its members, like here:
private class Holder {
def member = new Hidden
}
private class Hidden
where member is public but its enclosing class is private, effectively hiding its members from the external world. So the compiler emits no complaints here.
I think you don't want a private class, but a class with a private constructor.
class A private()
object A {
def apply = dual
lazy val dual = new A
}
Now your class is "visible" to outside code, but only your companion object can create instances of it.

Is there any advantage to definining a val over a def in a trait?

In Scala, a val can override a def, but a def cannot override a val.
So, is there an advantage to declaring a trait e.g. like this:
trait Resource {
val id: String
}
rather than this?
trait Resource {
def id: String
}
The follow-up question is: how does the compiler treat calling vals and defs differently in practice and what kind of optimizations does it actually do with vals? The compiler insists on the fact that vals are stable — what does in mean in practice for the compiler? Suppose the subclass is actually implementing id with a val. Is there a penalty for having it specified as a def in the trait?
If my code itself does not require stability of the id member, can it be considered good practice to always use defs in these cases and to switch to vals only when a performance bottleneck has been identified here — however unlikely this may be?
Short answer:
As far as I can tell, the values are always accessed through the accessor method. Using def defines a simple method, which returns the value. Using val defines a private [*] final field, with an accessor method. So in terms of access, there is very little difference between the two. The difference is conceptual, def gets reevaluated each time, and val is only evaluated once. This can obviously have an impact on performance.
[*] Java private
Long answer:
Let's take the following example:
trait ResourceDef {
def id: String = "5"
}
trait ResourceVal {
val id: String = "5"
}
The ResourceDef & ResourceVal produce the same code, ignoring initializers:
public interface ResourceVal extends ScalaObject {
volatile void foo$ResourceVal$_setter_$id_$eq(String s);
String id();
}
public interface ResourceDef extends ScalaObject {
String id();
}
For the subsidiary classes produced (which contain the implementation of the methods), the ResourceDef produces is as you would expect, noting that the method is static:
public abstract class ResourceDef$class {
public static String id(ResourceDef $this) {
return "5";
}
public static void $init$(ResourceDef resourcedef) {}
}
and for the val, we simply call the initialiser in the containing class
public abstract class ResourceVal$class {
public static void $init$(ResourceVal $this) {
$this.foo$ResourceVal$_setter_$id_$eq("5");
}
}
When we start extending:
class ResourceDefClass extends ResourceDef {
override def id: String = "6"
}
class ResourceValClass extends ResourceVal {
override val id: String = "6"
def foobar() = id
}
class ResourceNoneClass extends ResourceDef
Where we override, we get a method in the class which just does what you expect. The def is simple method:
public class ResourceDefClass implements ResourceDef, ScalaObject {
public String id() {
return "6";
}
}
and the val defines a private field and accessor method:
public class ResourceValClass implements ResourceVal, ScalaObject {
public String id() {
return id;
}
private final String id = "6";
public String foobar() {
return id();
}
}
Note that even foobar() doesn't use the field id, but uses the accessor method.
And finally, if we don't override, then we get a method which calls the static method in the trait auxiliary class:
public class ResourceNoneClass implements ResourceDef, ScalaObject {
public volatile String id() {
return ResourceDef$class.id(this);
}
}
I've cut out the constructors in these examples.
So, the accessor method is always used. I assume this is to avoid complications when extending multiple traits which could implement the same methods. It gets complicated really quickly.
Even longer answer:
Josh Suereth did a very interesting talk on Binary Resilience at Scala Days 2012, which covers the background to this question. The abstract for this is:
This talk focuses on binary compatibility on the JVM and what it means
to be binary compatible. An outline of the machinations of binary
incompatibility in Scala are described in depth, followed by a set of rules and guidelines that will help developers ensure their own
library releases are both binary compatible and binary resilient.
In particular, this talk looks at:
Traits and binary compatibility
Java Serialization and anonymous classes
The hidden creations of lazy vals
Developing code that is binary resilient
The difference is mainly that you can implement/override a def with a val but not the other way around. Moreover val are evaluated only once and def are evaluated every time they are used, using def in the abstract definition will give the code who mixes the trait more freedom about how to handle and/or optimize the implementation. So my point is use defs whenever there isn't a clear good reason to force a val.
A val expression is evaluated once on variable declaration, it is strict and immutable.
A def is re-evaluated each time you call it
def is evaluated by name and val by value. This means more or less that val must always return an actual value, while def is more like a promess that you can get a value when evaluating it. For example, if you have a function
def trace(s: => String ) { if (level == "trace") println s } // note the => in parameter definition
that logs an event only if the log level is set to trace and you want to log an objects toString. If you have overriden toString with a value, then you need to pass that value to the trace function. If toString however is a def, it will only be evaluated once it's sure that the log level is trace, which could save you some overhead.
def gives you more flexibility, while val is potentially faster
Compilerwise, traits are compiled to java interfaces so when defining a member on a trait, it makes no difference if its a var or def. The difference in performance would depend on how you choose to implement it.

Difference between object and class in Scala

I'm just going over some Scala tutorials on the Internet and have noticed in some examples an object is declared at the start of the example.
What is the difference between class and object in Scala?
tl;dr
class C defines a class, just as in Java or C++.
object O creates a singleton object O as instance of some anonymous class; it can be used to hold static members that are not associated with instances of some class.
object O extends T makes the object O an instance of trait T; you can then pass O anywhere, a T is expected.
if there is a class C, then object C is the companion object of class C; note that the companion object is not automatically an instance of C.
Also see Scala documentation for object and class.
object as host of static members
Most often, you need an object to hold methods and values/variables that shall be available without having to first instantiate an instance of some class.
This use is closely related to static members in Java.
object A {
def twice(i: Int): Int = 2*i
}
You can then call above method using A.twice(2).
If twice were a member of some class A, then you would need to make an instance first:
class A() {
def twice(i: Int): Int = 2 * i
}
val a = new A()
a.twice(2)
You can see how redundant this is, as twice does not require any instance-specific data.
object as a special named instance
You can also use the object itself as some special instance of a class or trait.
When you do this, your object needs to extend some trait in order to become an instance of a subclass of it.
Consider the following code:
object A extends B with C {
...
}
This declaration first declares an anonymous (inaccessible) class that extends both B and C, and instantiates a single instance of this class named A.
This means A can be passed to functions expecting objects of type B or C, or B with C.
Additional Features of object
There also exist some special features of objects in Scala.
I recommend to read the official documentation.
def apply(...) enables the usual method name-less syntax of A(...)
def unapply(...) allows to create custom pattern matching extractors
if accompanying a class of the same name, the object assumes a special role when resolving implicit parameters
A class is a definition, a description. It defines a type in terms of methods and composition of other types.
An object is a singleton -- an instance of a class which is guaranteed to be unique. For every object in the code, an anonymous class is created, which inherits from whatever classes you declared object to implement. This class cannot be seen from Scala source code -- though you can get at it through reflection.
There is a relationship between object and class. An object is said to be the companion-object of a class if they share the same name. When this happens, each has access to methods of private visibility in the other. These methods are not automatically imported, though. You either have to import them explicitly, or prefix them with the class/object name.
For example:
class X {
// class X can see private members of object X
// Prefix to call
def m(x: Int) = X.f(x)
// Import and use
import X._
def n(x: Int) = f(x)
private def o = 2
}
object X {
private def f(x: Int) = x * x
// object X can see private members of class X
def g(x: X) = {
import x._
x.o * o // fully specified and imported
}
}
An object has exactly one instance (you can not call new MyObject). You can have multiple instances of a class.
Object serves the same (and some additional) purposes as the static methods and fields in Java.
As has been explained by many, object defines a singleton instance. The one thing in the answers here that I believe is left out is that object serves several purposes.
It can be the companion object to a class/trait, containing what might be considered static methods or convenience methods.
It can act much like a module, containing related/subsidiary types and definitions, etc.
It can implement an interface by extending a class or one or more traits.
It can represent a case of a sealed trait that contains no data. In this respect, it's often considered more correct than a case class with no parameters. The special case of a sealed trait with only case object implementors is more or less the Scala version of an enum.
It can act as evidence for implicit-driven logic.
It introduces a singleton type.
It's a very powerful and general construct. What can be very confusing to Scala beginners is that the same construct can have vastly different uses. And an object can serve many of these different uses all at once, which can be even more confusing.
Defining an object in Scala is like defining a class in Java that has only static methods. However, in Scala an object can extend another superclass, implement interfaces, and be passed around as though it were an instance of a class. (So it's like the static methods on a class but better).
The formal difference -
you can not provide constructor parameters for Objects
Object is not a type - you may not create an instance with new operator. But it can have fields, methods, extend a superclass and mix in traits.
The difference in usage:
Scala doesn't have static methods or fields. Instead you should use object. You can use it with or without related class. In 1st case it's called a companion object. You have to:
use the same name for both class and object
put them in the same source file.
To create a program you should use main method in object, not in class.
object Hello {
def main(args: Array[String]) {
println("Hello, World!")
}
}
You also may use it as you use singleton object in java.
  
    
  
In scala, there is no static concept. So scala creates a singleton object to provide entry point for your program execution.
If you don't create singleton object, your code will compile successfully but will not produce any output. Methods declared inside Singleton Object are accessible globally. A singleton object can extend classes and traits.
Scala Singleton Object Example
object Singleton{
def main(args:Array[String]){
SingletonObject.hello() // No need to create object.
}
}
object SingletonObject{
def hello(){
println("Hello, This is Singleton Object")
}
}
Output:
Hello, This is Singleton Object
In scala, when you have a class with same name as singleton object, it is called companion class and the singleton object is called companion object.
The companion class and its companion object both must be defined in the same source file.
Scala Companion Object Example
class ComapanionClass{
def hello(){
println("Hello, this is Companion Class.")
}
}
object CompanoinObject{
def main(args:Array[String]){
new ComapanionClass().hello()
println("And this is Companion Object.")
}
}
Output:
Hello, this is Companion Class.
And this is Companion Object.
In scala, a class can contain:
1. Data member
2. Member method
3. Constructor Block
4. Nested class
5. Super class information etc.
You must initialize all instance variables in the class. There is no default scope. If you don't specify access scope, it is public. There must be an object in which main method is defined. It provides starting point for your program. Here, we have created an example of class.
Scala Sample Example of Class
class Student{
var id:Int = 0; // All fields must be initialized
var name:String = null;
}
object MainObject{
def main(args:Array[String]){
var s = new Student() // Creating an object
println(s.id+" "+s.name);
}
}
I am sorry, I am too late but I hope it will help you.
The object keyword creates a new singleton type, which is like a class that only has a single named instance. If you’re familiar with Java, declaring an object in Scala is a lot like creating a new instance of an anonymous class.
Scala has no equivalent to Java’s static keyword, and an object is often used in Scala where you might use a class with static members in Java.
Object is a class but it already has(is) an instance, so you can not call new ObjectName. On the other hand, Class is just type and it can be an instance by calling new ClassName().
A class is just like any other class in other languages. You define class just like any other language with some syntax difference.
class Person(val name: String)
val me = new Person("My name")
However, object is a class with single object only. This makes it interesting as it can be used to create static members of a class using companion object. This companion object has access to private members of the class definition and it has the same name as the class you're defining.
class Person(var name: String) {
import Person._
def hi(): String = sayHello(name)
}
object Person {
private def sayHello(name: String): String = "Hello " + name
}
val me = new Person("My name")
me.hi()
Also, noteworthy point is that object class is lazily created which is another important point. So, these are not instantiated unless they are needed in our code.
If you're defining connection creation for JDBC, you can create them inside object to avoid duplication just like we do in Java with singleton objects.
Scala class same as Java Class but scala not gives you any entry method in class, like main method in java. The main method associated with object keyword. You can think of the object keyword as creating a singleton object of a class that is defined implicitly.
more information check this article
class and object keyword in scala programming
The object is similar to the static class in Java to some extend, the static characteristic means the static class need not to create an object when putting to the JVM, it can be used by it's class name directly and the same instance(same data state) is shared wherever it is used.
If you are coming from java background the concept of class in scala is kind of similar to Java, but class in scala cant contain static members.
Objects in scala are singleton type you call methods inside it using object name, in scala object is a keyword and in java object is a instance of class