I am having a trouble in showing a plot which runs from 0-10K.
Currently I have calculation running from 0-100 and it looks great.
Currently:
Now I want to add one X points which is 10K
And it looks this way:
How do I keep it from 0-100 and show only then the jumps to 10K ?
Is it even possible ?
The problem is that 0-100 is very small portion in 10K so it looks bad.
You could plot your one outlier point at a closer x coordinate, then adjust the XTick and XTickLabel properties to make it appear as though there is a break in the plot range. For example:
plot([1:20 25], 1./[1:20 10000]);
set(gca, 'XTick', [2:2:20 25], ...
'XTickLabel', strtrim(cellstr(int2str([2:2:20 10000].'))));
And here's the plot this creates:
Maybe you can try to sample the x points (for the second plot) in different gaps. You can combine two arrays of x sample points (each array with a fixed gap but the first gap is much smaller than the second gap). then you plot the combined points.
Here's a code example:
clear;
close all;
clc;
gap1 = 0.2;
x_left = 1:gap1:3;
gap2 = 0.5;
x_right = 3+gap2:gap2:6;
x_ticks_for_plot = [x_left x_right];
x=x_ticks_for_plot;
y = sin(x);
plot(x,y);
xticks(x_ticks_for_plot);
And the plot:
In your case the second gap should be much bigger than the first but it's the same idea.
Related
I need ideas to resize my axes to have a much more airy graph to better visualize and calculate the gain between the different curves.
I used the code : axis([0 6 1e-3 1e0]) or xlim([0 6]); ylim([1e-3 1e0])
I would like to have for example my curve with: xlim([0:0.2:6]) (just the idea, otherwise it's wrong on matlab).
Thank you!
If I understand what you want, you need more XTicks in the x limits mentioned. After you plot just:
set(gca,'XTick',0:0.2:6)
another way is to write:
h=plot(.... whatever you plot...
h.XTick=0:0.2:6
Logarithmic Plot:
To create the axes the function xticks() and yticks() can be used to set the intervals, start and endpoints. xticks() and yticks() essentially take vectors that define all the ticks on the scales/axes. Just in case you'd like to also edit the interval along the y-axis. This vector can be created by raising each element in the vector (-3,1:0) to be an exponent with a base of 10. Finally, setting gca (the current axis) to logarithmic will allow the vertical spacing between the ticks to be evenly distributed.
axis([0 6 1e-3 1e0]);
Start = 0; Interval = 0.2; End = 6;
X_Vector = (Start: Interval: End);
xticks(X_Vector);
Y_Vector = 10.^(-3: 1: 0);
yticks(Y_Vector);
set(gca, 'YScale', 'log');
title("Logarithmic Plot");
grid;
Ran using MATLAB R2019b
I have the following graph:
x-axis represents time and both x and y axis data are discrete. I want to find the time spent by the graph during the time it exits the bin marked by yellow and red lines and when it comes back. The problem is that x axis data is discrete and and I want the duration x(t') - x(t).
Suppose the graph cuts yellow line at say n= 3.2 and goes outside the bin and then again cuts the yellow line at say n = 5.1, then I want the duration (5.1-3.2). SImilarly for the red line as well. Any idea on how can I do that?
The MATLAB code to generate the data set is:
mu =4;
x(1)=0.2; % x_{0}
nn=1:1001;
for n=1:1000
x(n+1) = mu*x(n)*(1-x(n));
end
figure;
plot(nn,x);
hold on;
plot([1 1010],[0.49 0.49]);
xlabel('n');
ylabel('x_{n}');
title('Plot of the equation: x_{n+1} = 4x_{n}(1-x_{n}) for x_{0} = 0.2 with
a bin of width 0.01 from x_{n} = 0.49 to x_{n+1}= 0.50');
hold on;
plot([1 1010],[0.50 0.50]);
I hope i interpreted this correctly when answering. So you're looking for values of n where they are x_n are 0.5 and 0.49. this will take two matrices and a while or for loop that will go for the 1000 iterations. Inside that put two if statements one for 0.5 and one for 0.49. Inside each one set a matrix to store the n value
I am trying to adjust the scale of the x-axis so that the values are closer together, but I am not able to do so.
I need the output to be like this photo:
However, what I actually get is the photo below:
Here's the code I have written to reproduce this error:
x = [0.1 1 10 100 1000 10000];
y = [1.9904 19.8120 82.6122 93.0256 98.4086 99.4016];
figure;
bar(x,y);
ylabel('Y values');
xlabel('X values');
set(gca,'XTick', [0.1 1 10 100 1000 10000])
How can I adjust the x-axis so that it looks like the first photo?
Because your data has such huge dynamic range, and because of the linear behaviour of the x axis, your graph is naturally going to appear like that. One compromise that I can suggest is that you transform your x data so that it gets mapped to a smaller scale, then remap your x data so that it falls onto a small exponential scale. After, simply plot the data using this remapped scale, then rename the x ticks so that they have the same values as your x data. To do this, I would take the log10 of your data first, then apply an exponential to this data. In this way, you are scaling the x co-ordinates down to a smaller dynamic range. When you apply the exponential to this smaller range, the x co-ordinates will then spread out in a gradual way where higher values of x will certainly make the value go farther along the x-axis, but not too far away like you saw in your original plot.
As such, try something like this:
x = [0.1 1 10 100 1000 10000]; %// Define data
y = [1.9904 19.8120 82.6122 93.0256 98.4086 99.4016];
xplot = (1.25).^(log10(x)); %// Define modified x values
figure;
bar(xplot,y); %// Plot the bar graph on the modified scale
set(gca,'XTick', xplot); %// Define ticks only where the bars are located
set(gca,'XTickLabel', x); %// Rename these ticks to our actual x data
This is what I get:
Note that you'll have to play around with the base of the exponential, which is 1.25 in what I did, to suit your data. Obviously, the bigger the dynamic range of your x data, the smaller this exponent will have to be in order for your data to be closer to each other.
Edit from your comments
From your comments, you want the bars to be equidistant in between neighbouring bars. As such, you simply have to make the x axis linear in a small range, from... say... 1 to the total number of x values. You'd then apply the same logic where we rename the ticks on the x axis so that they are from the true x values instead. As such, you only have to change one line, which is xplot. The other lines should stay the same. Therefore:
x = [0.1 1 10 100 1000 10000]; %// Define data
y = [1.9904 19.8120 82.6122 93.0256 98.4086 99.4016];
xplot = 1:numel(x); %// Define modified x values
figure;
bar(xplot,y); %// Plot the bar graph on the modified scale
set(gca,'XTick', xplot); %// Define ticks only where the bars are located
set(gca,'XTickLabel', x); %// Rename these ticks to our actual x data
This is what I get:
I'd like to create a quasi boxplot graph as shown on pages 15/16 of the attached report.
comisef.eu/files/wps031.pdf
Ideally I only want to show the median, the maximum and minimum values as in the report.
I would also like to have similar spacing to that shown in the report.
Currently I have two matrices with the all the necessary values stored in them but have no idea how to do this in matlab.
The boxplot function gives too much data (outliers etc) which makes the resulting graph look confused especially when I try to plot 200 on one page as in the original report.
Is there another function that can so the same thing as in the report in matlab?
Baz
OK here is some test data each row represents 10 sets of estimations of a data set, and each column represents the test number for a given observation.
As boxplot works on the columns of the input matrix you will need to transpose the matrix.
Is it possible to turn outliers and the inter-quartile ranges off? Ideally I just want to see the maximum, minimum and median values?
You can repeat the data below to get up to 200. Or I can send more data if necessary.
0.00160329732202511 0.000859407819412016 0.000859407819411159 0.0659939338995606 0.000859407819416322 0.000859407819416519 2.56395024851142e-15 2.05410662537078e-14 0.000859407819416209
1.67023155116586e-06 8.88178419700125e-16 1.67023155115637e-06 0.000730536218639616 1.67023155105582e-06 3.28746017489609e-15 4.41416632660789e-15 1.67023155094400e-06 1.67023155097567e-06
1.42410590843629e-06 1.42410590840224e-06 1.76149166727218e-15 5.97790925044131e-15 1.42410590843863e-06 2.87802701599909e-15 9.31529385335274e-16 9.17306727455842e-16 0.000820358763518906
8.26849110292527e-16 3.23505095414772e-15 4.38139485761850e-07 4.38139485938112e-07 4.38139485981887e-07 0.000884647755317917 3.72611754134110e-15 4.38139485974329e-07 4.38139485923219e-07
0.000160661751819407 0.000870787937135265 0.000870787937136209 1.16934122581182e-15 9.02860049358913e-16 1.18053134896556e-15 1.40433338743068e-15 0.000870787937135929 1.13510916297112e-15
1.16934122581182e-15 3.80292342262841e-05 3.80292342263200e-05 0.00284904319356532 1.74649997619656e-15 3.80292342264024e-05 0.00284904319356537 1.01267920724547e-15 0.00284904319356540
0.100091800399985 0.100091773169254 0.100091803903140 0.000770464183529358 0.100091812455930 3.49996706323281e-05 3.49996706323553e-05 1.05090687851466e-15 0.100091846333800
0.00100555294602561 0.00100555294601056 0.105365907420183 0.000121078082591672 9.02860049358913e-16 0.000121078082591805 4.49679158258033e-15 7.77684615168284e-16 0.000121078082591693
0.122539456858702 0.000363547764643498 0.000363547764643509 0.122516928568610 0.0101487499394213 0.122408366511784 0.000363547764643519 1.13510916297112e-15 0.122521393586646
0.000460749357561036 0.000460749357560646 3.27600489447913e-13 1.18053134896556e-15 0.000460749357561239 1.54689304063675e-15 0.000460749357560827 0.000460749357561205 1.16934122581182e-15
Instead of using boxplot, I suggest just drawing lines from the min to the max and making a mark at the median. Boxplot draws boxes from the 25 to 75 percentile, which doesn't sound like what you want. Something like this:
% fake data
nPoints = 100;
data = 10*rand(10, nPoints);
% find statistics
minData = min(data, [], 1);
maxData = max(data, [], 1);
medData = median(data);
% x coordinates of each line. Change this to change the spacing.
x = 1:nPoints;
figure
hold on
%plot lines
line([x; x], [minData; maxData])
% plot cross at median
plot(x, medData, '+')
EDIT: To have horizontal lines and a second axis you can do something like this:
figure
h1 = subplot(1,2,1);
h2 = subplot(1,2,2);
% left subplot
axes(h1)
hold on
%plot lines
line([minData; maxData], [x; x])
% plot cross at median
plot(medData, x, '+')
% link the axes so they will have the same limits
linkaxes([h1,h2],'y')
% turn off ticks on y axis.
set(h2, 'YTick', [])
I think it's a question of playing with the settings. You can try:
boxplot(X, 'plotstyle', 'compact', 'colors', 'k', 'medianstyle', 'line', 'outliersize', 0);
Explanation:
'plotstyle', 'compact': makes the boxes filled and the lines undashed
'colors', 'k': color is black
'medianstyle', 'line': the median is marked by a line
'outliersize', 0: if outlier size is zero, you don't see them
Other you can try:
'orientation', 'vertical': this flips the orientation, depends on your data
'whisker', 10 (or higher): this sets the maximum whisker length as a function of the interquartile limits (if you crank it up, it will eventually default to max and min values), I wasn't sure if this is what you wanted. Right now, it goes to the 25th and 75th percentile values.
The spacing is going to depend on how much data you have. If you edit with some data, I can try it out for you.
I have the following code.
% Generate message signal
t1 = -1:0.1:1;
message_sig = rectpuls(t1);
L = length(message_sig);
figure(2)
stairs(0:L-1:L, 'linewidth',1.5);
axis([0 L -1 2]);
title('Message Signal');
When i run this, the length of my x axis is from 0 to 20.
How can i reduce it to say 0 to 8, while plotting the same bit pattern. Because when i try modulating and add noise, the whole plot (noise modulated signal) is blue and needs to be zoomed alot to see accurately.
So can someone help me with a code that could solve this.
simply use xlim([0,8]), that will restrict the x-axis from going beyond 8, or edit your axis call to be axis([0,8,-1,2])
UPDATE
Assuming you have the image processing toolbox, it is really simple
in = [0,1,0];
imresize(in,[1,8],'nearest');
This will take that pattern and expand it to whatever dimension you want.