I use kartik/GridView. In my database, I have following record using widget of \dosamigos\ckeditor\CKEditor in _form.php:
<p>ist gewöhnungsbedürftig aber halt auch kompetent</p>
Any ideas how to outline this record in GridView without HTML-tags, just plain text like this:
ist gewöhnungsbedürftig aber halt auch kompetent
Here is my DetailView:
<?php
use yii\helpers\Html;
use yii\widgets\DetailView;
?>
<div class="bewerber-view">
<div class="row">
<div class="col-sm-9">
<h2><?= Html::encode($model->id) ?></h2>
</div>
</div>
<div class="col-lg-1">
<?php
$gridColumn = [
.
.
'beurteilung_persoenlich:ntext', //contains upper record
.
.
];
echo DetailView::widget([
'model' => $model,
'attributes' => $gridColumn
]);
?>
</div>
got solution by my own:
<?php
use yii\helpers\Html;
use yii\widgets\DetailView;
?>
<div class="bewerber-view">
<div class="row">
<div class="col-sm-9">
<h2><?= Html::encode($model->id) ?></h2>
</div>
</div>
<div class="col-lg-1">
<?php
$gridColumn = [
.
.
'beurteilung_persoenlich:html', //contains upper record
.
.
];
echo DetailView::widget([
'model' => $model,
'attributes' => $gridColumn
]);
?>
</div>
will solve my problem as described.
Happy Coding
this worked for me
'your_attritube_name:html'
Related
I am struggling with this problem, I am writing a code for a dashboard but It's not coming together. This is the code currently have:
<?= $this->Html->link('Edit', array('#' => 'container edit', $server->id)) ?>
This is the link to the div right down here, it's working when i don't give the server-id to the specific row. With the ID it doesn't redirect correctly.
<div class="container admin-section admin-sub edit" id="admin-edit">
<nav class="col col-xs-12 col-md-4 columns" id="actions-sidebar">
<ul class="side-nav">
<li class="heading"><?= __('Actions') ?></li>
<li data-target="admin-overview">Server List</li>
<li><?= $this->Form->postLink(
__('Delete'),
['action' => 'delete', $servers->id],
['confirm' => __('Are you sure you want to delete # {0}?', $servers->id)]
)
?></li>
</ul>
</nav>
<div class="servers form col col-xs-12 col-md-8 columns content">
<?= $this->Form->create($servers) ?>
<fieldset>
<legend><?= __('Edit Server') ?></legend>
<?php
echo $this->Form->input('url', ['class'=> 'form-control']);
echo $this->Form->input('description', ['class'=> 'form-control']);
?>
</fieldset>
<?= $this->Form->button(__('Submit'), ['class'=> 'btn btn-primary']) ?>
<?= $this->Form->end() ?>
</div>
</div>
Instead it'll go to http://dashboard/pages/1#container%20add which it shouldn't be doing. How can I make sure it'll only go to the div and not a different page?
You can do this with Url->Build
exemple:
toto
You can do it by using controller and action name.
Example :
echo $this->Html->link('Title', array(
'controller'=>'pages',
'action'=>'index',
$server->id,
'container edit'
)
);
Above code will produce -
pages/{serverId}#container%20add
pages/index/{serverId}#container%20add
I am generating list within a form like the following code. But for updating view how can select the particular option according to the user. Suppose for this user's role is Customer. Then how can select this(Customer) option in CakePHP 3.
<?= $this->Form->create($user) ?>
<?php
echo $this->Form->input('fullname');
echo $this->Form->input('contact_no');
?>
<div class="form-group">
<?php echo $this->Form->select(
'role',
['Customer', 'Staff', 'User'],
['title' => 'Select user type']
); ?>
</div>
<?= $this->Form->end() ?>
Here is what I did : (According that I have 2 tables : Users which belongsTo Roles)
In my UsersController, i added this following line :
$this->set('roles', $this->Users->Roles->find('list')->order('name'));
Then, you'll need to edit your view from
<div class="form-group">
<?php echo $this->Form->select(
'role',
['Customer', 'Staff', 'User'],
['title' => 'Select user type']
); ?>
</div>
to
<div class="form-group">
<?= $this->Form->select(
'role_id',
$roles,
['id' => 'role-id', 'required' => true]
);
?>
</div>
I'm having some trouble with short code's breaking a featured image I have set on my home page in Wordpress (4.0). For some reason, when I paste in my shortcode in the wp-admin > page > edit > content for the home page, suddenly my featured image stops working. It's working until I paste in the shortcode and update the page, but then the image disappears and the_post_thumbnail() returns false. I've also tried get_the_post_thumbnail() without success.
Here's my code excerpt from "front-page.php":
<div class="small-12 medium-6 columns">
<?php while ( have_posts() ) : the_post(); ?>
<h1><?php the_title(); ?></h1>
<?php the_content(); ?>
<?php endwhile; ?>
</div>
<div class="small-12 medium-6 columns">
<?php if (has_post_thumbnail()) {the_post_thumbnail();} ?>
</div>
And here's the shortcode function from "functions.php":
// [random_testimonial]
function short_code_get_random_testimonial(){
$args = array( 'post_type' => 'testimonial', 'posts_per_page' => 1, 'orderby' => 'rand' );
$query = new WP_Query( $args );
while ( $query->have_posts() ) : $query->the_post();
$random_testimonial = get_the_content();
$author = get_the_title();
$rt = '<p class="quote">' . $random_testimonial;
$rt .= '</p><p class="right">– ' . $author . '</p>';
endwhile;
return $rt;
}
// Register the shortcodes.
add_shortcode( 'random_testimonial', 'short_code_get_random_testimonial' );
// Allow text widgets to contain shortcodes.
add_filter('widget_text', 'do_shortcode');
add_filter('the_content', 'do_shortcode');
Any ideas would be greatly appreciated.
I think I may have solved this one. It seems to have something to do with the fact that I was calling a custom post type with the shortcode, so by the time the_post_thumbnail() was called, the query had changed to refer to the custom post type included in the shortcode ("testimonial") rather than the parent post (in this case the home page). I revised my code as follows to catch the image before the shortcode is called, and all is working again:
<div class="small-12 medium-6 columns">
<?php while ( have_posts() ) : the_post(); ?>
<?php
// go ahead and get the post image in case [random_testimonial]
// shortcode is used in page content which will break the query.
if (has_post_thumbnail()) {$image = get_the_post_thumbnail();} ?>
<h1><?php the_title(); ?></h1>
<?php the_content(); ?>
<?php endwhile; ?>
</div>
<div class="small-12 medium-6 columns">
<?php
// Echo post image from above.
if(isset($image)){echo $image;}
?>
</div>
I'm using an example of bootstrap-datetimepicker in my codeigniter project.
I create a form with only the datetimepicker input.
view:
<?php // Change the css classes to suit your needs
$attributes = array('class' => '', 'id' => '');
echo form_open('/calendario/nadevent/', $attributes); ?>
<div class="form-group">
<label for="reservationtime">Fecha:</label>
<div class="input-group">
<span class="input-group-addon">
<i class="fa fa-calendar"></i>
</span>
<input type="text" name="reservationtime" id="reservationtime" class="form-control" value="<?php echo set_value('reservationtime') ?>" />
</div>
</div>
<?php echo form_submit( 'submit', 'Submit','class="btn btn-default"'); ?>
<?php echo form_close(); ?>
JS:
$('#reservationtime').daterangepicker({timePicker: true, timePickerIncrement: 30, format: 'DD-MM-YYYY hh:mm:ss', timePicker12Hour: false, separator: '/'});
The datepicker works fine but when i submit the form, I want to format the data and split into an array:
Controller:
$this->form_validation->set_rules('reservationtime', 'reservationtime', '');
$array = explode('/',set_value('reservationtime'));
Then I try to insert the values:
form_data = array(
'start' => $array[0],
'end' => $array[1]
;
But if I print the array, its empty:
Array ( [start] => [end] => )
Wha'ts wrong with the code?
Thanks for the help :)
You really not getting data from your form, can you dump the $_POST?
I'm trying to submit a form from inside a modal window using the modal buttons in the modal-footer.
The form itself is loaded through ajax from a link (controller/action).
Just to be clearer I attached this picture:
This is the code for the modal:
<?php $this->beginWidget('bootstrap.widgets.TbModal', array('id'=>'modal')); ?>
<div class="modal-header">
<a class="close" data-dismiss="modal">×</a>
<h4>Client Ticket Status Update</h4>
</div>
<div class="modal-body">
</div>
<div class="modal-footer">
<?php $this->widget('bootstrap.widgets.TbButton', array(
'buttonType'=>'ajaxSubmit',
'type'=>'primary',
'label'=>'Save changes',
'url'=>'#',
'htmlOptions'=>array('data-dismiss'=>'modal'),
)); ?>
<?php $this->widget('bootstrap.widgets.TbButton', array(
'label'=>'Close',
'url'=>'#',
'htmlOptions'=>array('data-dismiss'=>'modal'),
)); ?>
</div>
<?php $this->endWidget(); ?>
This is the javascript that loads the form inside the modal:
$("a[data-toggle=modal]").click(function(){
var target = $(this).attr('data-target');
var url = $(this).attr('href');
if(url){
$(target).find(".modal-body").load(url);
}
});
This is the form view:
<div class="form">
<?php $form=$this->beginWidget('CActiveForm', array(
'id'=>'client-ticket-form',
'enableAjaxValidation'=>false,
)); ?>
<p class="note">Fields with <span class="required">*</span> are required. </p>
<?php echo $form->errorSummary($ticket); ?>
<div>
<?php echo $form->labelEx($ticket,'sent_to'); ?>
<?php echo $form->textField($ticket,'sent_to'); ?>
<?php echo $form->error($ticket,'sent_to'); ?>
</div>
<div>
<?php echo $form->labelEx($ticket,'courier'); ?>
<?php echo $form->textField($ticket,'courier'); ?>
<?php echo $form->error($ticket,'courier'); ?>
</div>
<div>
<?php echo $form->labelEx($ticket,'awb'); ?>
<?php echo $form->textField($ticket,'awb'); ?>
<?php echo $form->error($ticket,'awb'); ?>
</div>
<div>
<?php echo $form->labelEx($ticket,'awb_date'); ?>
<?php echo $form->textField($ticket,'awb_date'); ?>
<?php echo $form->error($ticket,'awb_date'); ?>
</div>
<div class="buttons">
<?php echo CHtml::submitButton($ticket->isNewRecord ? 'Create' : 'Save'); ?>
</div>
<?php $this->endWidget(); ?>
</div><!-- form -->
Any help is very appreciated. If you require more information, please ask.
Change code at model-footer as below:
<div class="modal-footer">
<?php $this->widget('bootstrap.widgets.TbButton', array(
'type'=>'primary',
'label'=>'Save changes',
'url'=>'#',
'htmlOptions'=>array('onclick' => '$("#formID").submit()'),
)); ?>
<?php $this->widget('bootstrap.widgets.TbButton', array(
'label'=>'Close',
'url'=>'#',
'htmlOptions'=>array('data-dismiss'=>'modal'),
)); ?>
This first response didn't resolve my problem of a modal form closing on submit. For anyone else that is having issues, I had to enable client Validation in the CActiveForm.
It ended up looking like this:
$form = $this->beginWidget(
'CActiveForm',
array(
'id' => 'feature-form',
'enableAjaxValidation' => true,
'enableClientValidation' => true,
'clientOptions' => array(
'validateOnSubmit' => true,
'validateOnChange' => true,
'validateOnType' => true
)
)
);
Hopefully this helps some coming after me.
just trigger the click event on the other one that you don't want to show, an also hide it first!