Is there an equivalent of Pandas Melt function in Apache Spark in PySpark or at least in Scala?
I was running a sample dataset till now in Python and now I want to use Spark for the entire dataset.
Spark >= 3.4
In Spark 3.4 or later you can use built-in melt method
(sdf
.melt(
ids=['A'], values=['B', 'C'],
variableColumnName="variable",
valueColumnName="value")
.show())
+---+--------+-----+
| A|variable|value|
+---+--------+-----+
| a| B| 1|
| a| C| 2|
| b| B| 3|
| b| C| 4|
| c| B| 5|
| c| C| 6|
+---+--------+-----+
This method is available across all APIs so could be used in Scala
sdf.melt(Array($"A"), Array($"B", $"C"), "variable", "value")
or SQL
SELECT * FROM sdf UNPIVOT (val FOR col in (col_1, col_2))
Spark 3.2 (Python only, requires Pandas and pyarrow)
(sdf
.to_koalas()
.melt(id_vars=['A'], value_vars=['B', 'C'])
.to_spark()
.show())
+---+--------+-----+
| A|variable|value|
+---+--------+-----+
| a| B| 1|
| a| C| 2|
| b| B| 3|
| b| C| 4|
| c| B| 5|
| c| C| 6|
+---+--------+-----+
Spark < 3.2
There is no built-in function (if you work with SQL and Hive support enabled you can use stack function, but it is not exposed in Spark and has no native implementation) but it is trivial to roll your own. Required imports:
from pyspark.sql.functions import array, col, explode, lit, struct
from pyspark.sql import DataFrame
from typing import Iterable
Example implementation:
def melt(
df: DataFrame,
id_vars: Iterable[str], value_vars: Iterable[str],
var_name: str="variable", value_name: str="value") -> DataFrame:
"""Convert :class:`DataFrame` from wide to long format."""
# Create array<struct<variable: str, value: ...>>
_vars_and_vals = array(*(
struct(lit(c).alias(var_name), col(c).alias(value_name))
for c in value_vars))
# Add to the DataFrame and explode
_tmp = df.withColumn("_vars_and_vals", explode(_vars_and_vals))
cols = id_vars + [
col("_vars_and_vals")[x].alias(x) for x in [var_name, value_name]]
return _tmp.select(*cols)
And some tests (based on Pandas doctests):
import pandas as pd
pdf = pd.DataFrame({'A': {0: 'a', 1: 'b', 2: 'c'},
'B': {0: 1, 1: 3, 2: 5},
'C': {0: 2, 1: 4, 2: 6}})
pd.melt(pdf, id_vars=['A'], value_vars=['B', 'C'])
A variable value
0 a B 1
1 b B 3
2 c B 5
3 a C 2
4 b C 4
5 c C 6
sdf = spark.createDataFrame(pdf)
melt(sdf, id_vars=['A'], value_vars=['B', 'C']).show()
+---+--------+-----+
| A|variable|value|
+---+--------+-----+
| a| B| 1|
| a| C| 2|
| b| B| 3|
| b| C| 4|
| c| B| 5|
| c| C| 6|
+---+--------+-----+
Note: For use with legacy Python versions remove type annotations.
Related:
R SparkR - equivalent to melt function
Gather in sparklyr
Came across this question in my search for an implementation of melt in Spark for Scala.
Posting my Scala port in case someone also stumbles upon this.
import org.apache.spark.sql.functions._
import org.apache.spark.sql.{DataFrame}
/** Extends the [[org.apache.spark.sql.DataFrame]] class
*
* #param df the data frame to melt
*/
implicit class DataFrameFunctions(df: DataFrame) {
/** Convert [[org.apache.spark.sql.DataFrame]] from wide to long format.
*
* melt is (kind of) the inverse of pivot
* melt is currently (02/2017) not implemented in spark
*
* #see reshape packe in R (https://cran.r-project.org/web/packages/reshape/index.html)
* #see this is a scala adaptation of http://stackoverflow.com/questions/41670103/pandas-melt-function-in-apache-spark
*
* #todo method overloading for simple calling
*
* #param id_vars the columns to preserve
* #param value_vars the columns to melt
* #param var_name the name for the column holding the melted columns names
* #param value_name the name for the column holding the values of the melted columns
*
*/
def melt(
id_vars: Seq[String], value_vars: Seq[String],
var_name: String = "variable", value_name: String = "value") : DataFrame = {
// Create array<struct<variable: str, value: ...>>
val _vars_and_vals = array((for (c <- value_vars) yield { struct(lit(c).alias(var_name), col(c).alias(value_name)) }): _*)
// Add to the DataFrame and explode
val _tmp = df.withColumn("_vars_and_vals", explode(_vars_and_vals))
val cols = id_vars.map(col _) ++ { for (x <- List(var_name, value_name)) yield { col("_vars_and_vals")(x).alias(x) }}
return _tmp.select(cols: _*)
}
}
Since I'm am not that advanced considering Scala, I'm sure there is room for improvement.
Any comments are welcome.
Voted for user6910411's answer. It works as expected, however, it cannot handle None values well. thus I refactored his melt function to the following:
from pyspark.sql.functions import array, col, explode, lit
from pyspark.sql.functions import create_map
from pyspark.sql import DataFrame
from typing import Iterable
from itertools import chain
def melt(
df: DataFrame,
id_vars: Iterable[str], value_vars: Iterable[str],
var_name: str="variable", value_name: str="value") -> DataFrame:
"""Convert :class:`DataFrame` from wide to long format."""
# Create map<key: value>
_vars_and_vals = create_map(
list(chain.from_iterable([
[lit(c), col(c)] for c in value_vars]
))
)
_tmp = df.select(*id_vars, explode(_vars_and_vals)) \
.withColumnRenamed('key', var_name) \
.withColumnRenamed('value', value_name)
return _tmp
Test is with the following dataframe:
import pandas as pd
pdf = pd.DataFrame({'A': {0: 'a', 1: 'b', 2: 'c'},
'B': {0: 1, 1: 3, 2: 5},
'C': {0: 2, 1: 4, 2: 6},
'D': {1: 7, 2: 9}})
pd.melt(pdf, id_vars=['A'], value_vars=['B', 'C', 'D'])
A variable value
0 a B 1.0
1 b B 3.0
2 c B 5.0
3 a C 2.0
4 b C 4.0
5 c C 6.0
6 a D NaN
7 b D 7.0
8 c D 9.0
sdf = spark.createDataFrame(pdf)
melt(sdf, id_vars=['A'], value_vars=['B', 'C', 'D']).show()
+---+--------+-----+
| A|variable|value|
+---+--------+-----+
| a| B| 1.0|
| a| C| 2.0|
| a| D| NaN|
| b| B| 3.0|
| b| C| 4.0|
| b| D| 7.0|
| c| B| 5.0|
| c| C| 6.0|
| c| D| 9.0|
+---+--------+-----+
UPD
Finally i've found most effective implementation for me. It uses all resources for cluster in my yarn configuration.
from pyspark.sql.functions import explode
def melt(df):
sp = df.columns[1:]
return (df
.rdd
.map(lambda x: [str(x[0]), [(str(i[0]),
float(i[1] if i[1] else 0)) for i in zip(sp, x[1:])]],
preservesPartitioning = True)
.toDF()
.withColumn('_2', explode('_2'))
.rdd.map(lambda x: [str(x[0]),
str(x[1][0]),
float(x[1][1] if x[1][1] else 0)],
preservesPartitioning = True)
.toDF()
)
For very wide dataframe I've got performance decreasing at _vars_and_vals generation from user6910411 answer.
It was useful to implement melting via selectExpr
columns=['a', 'b', 'c', 'd', 'e', 'f']
pd_df = pd.DataFrame([[1,2,3,4,5,6], [4,5,6,7,9,8], [7,8,9,1,2,4], [8,3,9,8,7,4]], columns=columns)
df = spark.createDataFrame(pd_df)
+---+---+---+---+---+---+
| a| b| c| d| e| f|
+---+---+---+---+---+---+
| 1| 2| 3| 4| 5| 6|
| 4| 5| 6| 7| 9| 8|
| 7| 8| 9| 1| 2| 4|
| 8| 3| 9| 8| 7| 4|
+---+---+---+---+---+---+
cols = df.columns[1:]
df.selectExpr('a', "stack({}, {})".format(len(cols), ', '.join(("'{}', {}".format(i, i) for i in cols))))
+---+----+----+
| a|col0|col1|
+---+----+----+
| 1| b| 2|
| 1| c| 3|
| 1| d| 4|
| 1| e| 5|
| 1| f| 6|
| 4| b| 5|
| 4| c| 6|
| 4| d| 7|
| 4| e| 9|
| 4| f| 8|
| 7| b| 8|
| 7| c| 9|
...
Use list comprehension to create struct column of column names and col values and explode the new column using the magic inline. Code below;
melted_df=(df.withColumn(
#Create struct of column names and corresponding values
'tab',F.array(*[F.struct(lit(x).alias('var'),F.col(x).alias('val'))for x in df.columns if x!='A'] ))
#Explode the column
.selectExpr('A',"inline(tab)")
)
melted_df.show()
+---+---+---+
| A|var|val|
+---+---+---+
| a| B| 1|
| a| C| 2|
| b| B| 3|
| b| C| 4|
| c| B| 5|
| c| C| 6|
+---+---+---+
1) Copy & paste
2) Change the first 2 variables
to_melt = {'latin', 'greek', 'chinese'}
new_names = ['lang', 'letter']
melt_str = ','.join([f"'{c}', `{c}`" for c in to_melt])
df = df.select(
*(set(df.columns) - to_melt),
F.expr(f"stack({len(to_melt)}, {melt_str}) ({','.join(new_names)})")
)
null is created if some values contain null. To remove it, add this:
.filter(f"!{new_names[1]} is null")
Full test:
from pyspark.sql import functions as F
df = spark.createDataFrame([(101, "A", "Σ", "西"), (102, "B", "Ω", "诶")], ['ID', 'latin', 'greek', 'chinese'])
df.show()
# +---+-----+-----+-------+
# | ID|latin|greek|chinese|
# +---+-----+-----+-------+
# |101| A| Σ| 西|
# |102| B| Ω| 诶|
# +---+-----+-----+-------+
to_melt = {'latin', 'greek', 'chinese'}
new_names = ['lang', 'letter']
melt_str = ','.join([f"'{c}', `{c}`" for c in to_melt])
df = df.select(
*(set(df.columns) - to_melt),
F.expr(f"stack({len(to_melt)}, {melt_str}) ({','.join(new_names)})")
)
df.show()
# +---+-------+------+
# | ID| lang|letter|
# +---+-------+------+
# |101| latin| A|
# |101| greek| Σ|
# |101|chinese| 西|
# |102| latin| B|
# |102| greek| Ω|
# |102|chinese| 诶|
# +---+-------+------+
I have a following sample pyspark dataframe and after groupby I want to calculate mean, and first of multiple columns, In real case I have 100s of columns, so I cant do it individually
sp = spark.createDataFrame([['a',2,4,'cc','anc'], ['a',4,7,'cd','abc'], ['b',6,0,'as','asd'], ['b', 2, 4, 'ad','acb'],
['c', 4, 4, 'sd','acc']], ['id', 'col1', 'col2','col3', 'col4'])
+---+----+----+----+----+
| id|col1|col2|col3|col4|
+---+----+----+----+----+
| a| 2| 4| cc| anc|
| a| 4| 7| cd| abc|
| b| 6| 0| as| asd|
| b| 2| 4| ad| acb|
| c| 4| 4| sd| acc|
+---+----+----+----+----+
This is what I am trying
mean_cols = ['col1', 'col2']
first_cols = ['col3', 'col4']
sc.groupby('id').agg(*[ f.mean for col in mean_cols], *[f.first for col in first_cols])
but it's not working. How can I do it like this with pyspark
The best way for multiple functions on multiple columns is to use the .agg(*expr) format.
import pyspark.sql.functions as F
from pyspark.sql.functions import udf
from pyspark.sql.types import *
import numpy as np
#Test data
tst = sqlContext.createDataFrame([(1,2,3,4),(3,4,5,1),(5,6,7,8),(7,8,9,2)],schema=['col1','col2','col3','col4'])
fn_l = [F.min,F.max,F.mean,F.first]
col_l=['col1','col2','col3']
expr = [fn(coln).alias(str(fn.__name__)+'_'+str(coln)) for fn in fn_l for coln in col_l]
tst_r = tst.groupby('col4').agg(*expr)
The result will be
tst_r.show()
+----+--------+--------+--------+--------+--------+--------+---------+---------+---------+----------+----------+----------+
|col4|min_col1|min_col2|min_col3|max_col1|max_col2|max_col3|mean_col1|mean_col2|mean_col3|first_col1|first_col2|first_col3|
+----+--------+--------+--------+--------+--------+--------+---------+---------+---------+----------+----------+----------+
| 5| 5| 6| 7| 7| 8| 9| 6.0| 7.0| 8.0| 5| 6| 7|
| 4| 1| 2| 3| 3| 4| 5| 2.0| 3.0| 4.0| 1| 2| 3|
+----+--------+--------+--------+--------+--------+--------+---------+---------+---------+----------+----------+----------+
For selectively applying functions on columns, you can have multiple expression arrays and concatenate them in aggregation.
fn_l = [F.min,F.max]
fn_2=[F.mean,F.first]
col_l=['col1','col2']
col_2=['col1','col3','col4']
expr1 = [fn(coln).alias(str(fn.__name__)+'_'+str(coln)) for fn in fn_l for coln in col_l]
expr2 = [fn(coln).alias(str(fn.__name__)+'_'+str(coln)) for fn in fn_2 for coln in col_2]
tst_r = tst.groupby('col4').agg(*(expr1+expr2))
A simpler way to do:
import pyspark.sql.functions as F
tst_r = ( tst.groupby('col4')
.agg(*[F.mean(col).alias(f"{col}_mean") for col in means_col],
*[F.first(col).alias(f"{col}_first") for col in firsts_col]) )
I am trying to create a sum column by taking the sum of the row values of a set of columns in a dataframe. So I followed the following method to do it.
val temp_data = spark.createDataFrame(Seq(
(1, 5),
(2, 4),
(3, 7),
(4, 6)
)).toDF("A", "B")
val cols = List(col("A"), col("B"))
temp_data.withColumn("sum", cols.reduce(_ + _)).show
+---+---+---+
| A| B|sum|
+---+---+---+
| 1| 5| 6|
| 2| 4| 6|
| 3| 7| 10|
| 4| 6| 10|
+---+---+---+
So this methods works fine and produce the expected output. However, I want to create the cols variable without specifying the column names explicitly. Therefore I've used typedLit as follows.
val cols2 = temp_data.columns.map(x=>typedLit(x)).toList
when I look at cols and cols2 they look identical.
cols: List[org.apache.spark.sql.Column] = List(A, B)
cols2: List[org.apache.spark.sql.Column] = List(A, B)
However, when I use cols2 to create my sum column, it doesn't work the way I expect it to work.
temp_data.withColumn("sum", cols2.reduce(_ + _)).show
+---+---+----+
| A| B| sum|
+---+---+----+
| 1| 5|null|
| 2| 4|null|
| 3| 7|null|
| 4| 6|null|
+---+---+----+
Does anyone have any idea what I'm doing wrong here? Why doesn't the second method work like the first method?
lit or typedLit is not a replacement for Column. What your code does it creates a list of string literals - "A" and "B"
temp_data.select(cols2: _*).show
+---+---+
| A| B|
+---+---+
| A| B|
| A| B|
| A| B|
| A| B|
+---+---+
and asks for their sums - hence the result is undefined.
You might use TypedColumn here:
import org.apache.spark.sql.TypedColumn
val typedSum: TypedColumn[Any, Int] = cols.map(_.as[Int]).reduce{
(x, y) => (x + y).as[Int]
}
temp_data.withColumn("sum", typedSum).show
but it doesn't provide any practical advantage over standard Column here.
You are trying with typedLit which is not right and like other answer mentioned you don't have to use a function with TypedColumn. You can simply use map transformation on columns of dataframe to convert it to List(Col)
Change your cols2 statement to below and try.
val cols = temp_data.columns.map(f=> col(f))
temp_data.withColumn("sum", cols.reduce(_ + _)).show
You will get below output.
+---+---+---+
| A| B|sum|
+---+---+---+
| 1| 5| 6|
| 2| 4| 6|
| 3| 7| 10|
| 4| 6| 10|
+---+---+---+
Thanks
I have a PySpark Dataframe with two columns:
+---+----+
| Id|Rank|
+---+----+
| a| 5|
| b| 7|
| c| 8|
| d| 1|
+---+----+
For each row, I'm looking to replace Id column with "other" if Rank column is larger than 5.
If I use pseudocode to explain:
For row in df:
if row.Rank > 5:
then replace(row.Id, "other")
The result should look like this:
+-----+----+
| Id|Rank|
+-----+----+
| a| 5|
|other| 7|
|other| 8|
| d| 1|
+-----+----+
Any clue how to achieve this? Thanks!!!
To create this Dataframe:
df = spark.createDataFrame([('a', 5), ('b', 7), ('c', 8), ('d', 1)], ['Id', 'Rank'])
You can use when and otherwise like -
from pyspark.sql.functions import *
df\
.withColumn('Id_New',when(df.Rank <= 5,df.Id).otherwise('other'))\
.drop(df.Id)\
.select(col('Id_New').alias('Id'),col('Rank'))\
.show()
this gives output as -
+-----+----+
| Id|Rank|
+-----+----+
| a| 5|
|other| 7|
|other| 8|
| d| 1|
+-----+----+
Starting with #Pushkr solution couldn't you just use the following ?
from pyspark.sql.functions import *
df.withColumn('Id',when(df.Rank <= 5,df.Id).otherwise('other')).show()
I am trying to apply different aggregation functions to different columns in a pyspark dataframe. Following some suggestions on stackoverflow, I tried this:
the_columns = ["product1","product2"]
the_columns2 = ["customer1","customer2"]
exprs = [mean(col(d)) for d in the_columns1, count(col(c)) for c in the_columns2]
followed by
df.groupby(*group).agg(*exprs)
where "group" is a column not present in either the_columns or the_columns2. This does not work. How to do different aggregation functions on different columns?
You are very close already, instead of put the expressions in a list, add them so you have a flat list of expressions:
exprs = [mean(col(d)) for d in the_columns1] + [count(col(c)) for c in the_columns2]
Here is a demo:
import pyspark.sql.functions as F
df.show()
+---+---+---+---+
| a| b| c| d|
+---+---+---+---+
| 1| 1| 2| 1|
| 1| 2| 2| 2|
| 2| 3| 3| 3|
| 2| 4| 3| 4|
+---+---+---+---+
cols = ['b']
cols2 = ['c', 'd']
exprs = [F.mean(F.col(x)) for x in cols] + [F.count(F.col(x)) for x in cols2]
df.groupBy('a').agg(*exprs).show()
+---+------+--------+--------+
| a|avg(b)|count(c)|count(d)|
+---+------+--------+--------+
| 1| 1.5| 2| 2|
| 2| 3.5| 2| 2|
+---+------+--------+--------+