Remove everything in a line before comma - sed

Question

I have multiple files with lines like:
foo, 123456
bar, 654321
baz, 098765
I would like to remove everything on each line before (and including) the comma.
The output would be:
123456
654321
098765
I attempted to use the following after seeing something similar on another question, but the user didn't leave an explanation, so I'm not sure how the wildcard would be handled:
find . -name "*.csv" -type f | xargs sed -i -e '/*,/d'
Thank you for any help you can offer.

Answer 1

METHOD 1:
If it's always the 2nd column you want, you can do this with awk -- this command is actually splitting the rows on the whitespace rather than the comma, so it gets your second column -- the numbers, but without the leading space:
awk '{print $2}' < whatever.csv
METHOD 2:
Or to get everything after the comma (including the space):
sed -e 's/^.*,//g' < whatever.csv
METHOD 3:
If you want to find all of the .csv files and get the output of all of them together, you can do:
sed -e 's/^.*,//g' `find . -name '*.csv' -print`
METHOD 4:
Or the same way you were starting to -- with find and xargs:
find . -name '*.csv' -type f -print | xargs sed -e 's/^.*,//'
METHOD 5:
Making all of the .csv files into .txt files, processed in the way described above, you can make a brief shell script. Like this:
Create a script "bla.sh":
#!/bin/sh
for infile in `find . -name '*.csv' -print` ; do
outfile=`echo $infile | sed -e 's/.csv/.txt/'`
echo "$infile --> $outfile"
sed -e 's/^.*,//g' < $infile > $outfile
done
Make it executable by typing this:
chmod 755 bla.sh
Then run it:
./bla.sh
This will create a .txt output file with everything after the comma for each .csv input file.
ALTERNATE METHOD 5:
Or if you need them to be named .csv, the script could be updated like this -- this just makes an output file named "file-new.csv" for each input file named "file.csv":
#!/bin/sh
for infile in `find . -name '*.csv' -print` ; do
outfile=`echo $infile | sed -e 's/.csv/-new.csv/'`
echo "$infile --> $outfile"
sed -e 's/^.*,//g' < $infile > $outfile
done

Answer 2

Something like this should work for a single file. Let's say the
input is 'yourfile' and you want the output to go to 'outfile'.
sed 's/^.*,//' < yourfile > outfile
The syntax to do a search-and-replace is s/input_pattern/replacement/
The ^ anchors the input pattern to the beginning of the line.
A dot . matches any single character; .* matches a string of zero or more of any character.
The , matches the comma.
The replacement pattern is empty, so whatever matched the input_pattern
will be removed.