%% File Names reading and label generation
dataFolder= 'allcontent';
fileNames = dir([dataFolder 'c*.*']);
lbl = sscanf(cat(1,'fileNames.name'),'co2%c%d.rd.%d');
status = lbl(1:3:end);
id = lbl(2:3:end);
ids = unique(id);
trial = lbl(3:3:end);
I want to concatenate the names of all the files in the folder titled all content , at the moment, matlab doesn't understand what allcontent is. Can someone help me get the contents of the folder ' all content' which are of the form 'c*.*' and then concatenate them?
You can use fullfile to concatenate paths in Matlab, i.e.
fileNames = dir(fullfile(dataFolder, 'c*.*'));
Also, I don't think fileNames.name should be in quotes. As #Wolfie mentioned, you can concatenate the filenames into a cell array using {fileNames.name}
filenames_array = {fileNames.name}
Then you can iterate over filenames_array using for or cellfun
Related
this question about matlab:
i'm running a loop and each iteration a new set of data is produced, and I want it to be saved in a new file each time. I also overwrite old files by changing the name. Looks like this:
name_each_iter = strrep(some_source,'.string.mat','string_new.(j).mat')
and what I#m struggling here is the iteration so that I obtain files:
...string_new.1.mat
...string_new.2.mat
etc.
I was trying with various combination of () [] {} as well as 'string_new.'j'.mat' (which gave syntax error)
How can it be done?
Strings are just vectors of characters. So if you want to iteratively create filenames here's an example of how you would do it:
for j = 1:10,
filename = ['string_new.' num2str(j) '.mat'];
disp(filename)
end
The above code will create the following output:
string_new.1.mat
string_new.2.mat
string_new.3.mat
string_new.4.mat
string_new.5.mat
string_new.6.mat
string_new.7.mat
string_new.8.mat
string_new.9.mat
string_new.10.mat
You could also generate all file names in advance using NUM2STR:
>> filenames = cellstr(num2str((1:10)','string_new.%02d.mat'))
filenames =
'string_new.01.mat'
'string_new.02.mat'
'string_new.03.mat'
'string_new.04.mat'
'string_new.05.mat'
'string_new.06.mat'
'string_new.07.mat'
'string_new.08.mat'
'string_new.09.mat'
'string_new.10.mat'
Now access the cell array contents as filenames{i} in each iteration
sprintf is very useful for this:
for ii=5:12
filename = sprintf('data_%02d.mat',ii)
end
this assigns the following strings to filename:
data_05.mat
data_06.mat
data_07.mat
data_08.mat
data_09.mat
data_10.mat
data_11.mat
data_12.mat
notice the zero padding. sprintf in general is useful if you want parameterized formatted strings.
For creating a name based of an already existing file, you can use regexp to detect the '_new.(number).mat' and change the string depending on what regexp finds:
original_filename = 'data.string.mat';
im = regexp(original_filename,'_new.\d+.mat')
if isempty(im) % original file, no _new.(j) detected
newname = [original_filename(1:end-4) '_new.1.mat'];
else
num = str2double(original_filename(im(end)+5:end-4));
newname = sprintf('%s_new.%d.mat',original_filename(1:im(end)-1),num+1);
end
This does exactly that, and produces:
data.string_new.1.mat
data.string_new.2.mat
data.string_new.3.mat
...
data.string_new.9.mat
data.string_new.10.mat
data.string_new.11.mat
when iterating the above function, starting with 'data.string.mat'
I have a folder containing a series of data with file names like this:
abc1
abc2
abc3
bca1
bca2
bca3
bca4
bca5
cba1
... etc
My goal is to load all the relevant files for each file name, so all the "abc" files, and plot them in one graph. Then move on to the next file name, and do the same, and so forth. Is there a way to do this?
This is what I currently have to load and run through all the files, grab the data in them and get their name (without the .mat extension) to be able to save the graph with the same filename.
dirName = 'C:\DataDirectory';
files = dir( fullfile(dirName,'*.mat') );
files = {files.name}';
data = cell(numel(files),1);
for i=1:numel(files)
fname = fullfile(dirName,files{i});
disp(fname);
files{i} = files{i}(1:length(files{i})-4);
disp(files{i});
[Rest of script]
end
You already found out about the cool features of dir, and have a cell array files, which contains all file names, e.g.
files =
'37abc1.mat'
'37abc2.mat'
'50bca1.mat'
'50bca2.mat'
'1cba1.mat'
'1cba2.mat'
The main task now is to find all prefixes, 37abc, 50bca, 1cba, ... which are present in files. This can be done using a regular expression (regexp). The Regexp Pattern can look like this:
'([\d]*[\D]*)[\d]*.mat'
i.e. take any number of numbers ([\d]*), then any number of non-numeric characters ([\D]*) and keep those (by putting that in brackets). Next, there will be any number of numeric characters ([\d]*), followed by the text .mat.
We call the regexp function with that pattern:
pre = regexp(files,'([\d]*[\D]*)[\d]*.mat','tokens');
resulting in a cell array (one cell for each entry in files), where each cell contains another cell array with the prefix of that file. To convert this to a simple not-nested cell array, we call
pre = [pre{:}];
pre = [pre{:}];
resulting in
pre =
'37abc' '37abc' '50bca' '50bca' '1cba' '1cba'
To remove duplicate entries, we use the unique function:
pre = unique(pre);
pre =
'37abc' '50bca' '1cba'
which leaves us with all prefixes, that are present. Now you can loop through each of these prefixes and apply your stuff. Everything put together is:
% Find all files
dirName = 'C:\DataDirectory';
files = dir( fullfile(dirName,'*.mat') );
files = {files.name}';
% Find unique prefixes
pre = regexp(files,'([\d]*[\D]*)[\d]*.mat','tokens');
pre = [pre{:}]; pre = [pre{:}];
pre = unique(pre);
% Loop through prefixes
for ii=1:numel(pre)
% Get files with this prefix
curFiles = dir(fullfile(dirName,[pre{ii},'*.mat']));
curFiles = {curFiles.name}';
% Loop through all files with this prefix
for jj=1:numel(curFiles)
% Here the magic happens
end
end
Sorry, I misunderstood your question, I found this solution:
file = dir('*.mat')
matching = regexp({file.name}, '^[a-zA-Z_]+[0-9]+\.mat$', 'match', 'once'); %// Match once on file name, must be a series of A-Z a-z chars followed by numbers.
matching = matching(~cellfun('isempty', matching));
str = unique(regexp(matching, '^[a-zA-Z_]*', 'match', 'once'));
str = str(~cellfun('isempty', str));
group = cell(size(str));
for is = 1:length(str)
ismatch = strncmp(str{is}, matching, length(str{is}));
group{is} = matching(ismatch);
end
Answer came from this source: Matlab Central
I am trying to append filenames in a directory to a list for later processing. The code below does not work.
files = dir( fullfile(home,'*.csv') );
files = {files.name}'; %'# file names
symbolsList = [];
filedata = cell(numel(files),1); %# store file contents
for i=1:numel(files)
[pathstr,name,ext] = fileparts(files{i});
symbolsList(end + 1) = name; % THIS GIVES ERROR
end
In your code, symbolsList will be interpreted as an array of characters. The statement where the error is appearing is interpreted as appending a single character to symbolsList. You are probably getting a subscript alignment mismatch because a name will most likely have more than one character, yet you are trying to fit many characters into a single spot in that array of characters. That's probably not what you want.
You want each "space" to have a name. Because each name will most likely not have the same amount of characters, you should probably use a cell array instead:
files = dir( fullfile(home,'*.csv') );
files = {files.name}'; %'# file names
symbolsList = cell(numel(files),1); %// Change
filedata = cell(numel(files),1); %# store file contents
for i=1:numel(files)
[pathstr,name,ext] = fileparts(files{i});
symbolsList{i} = name; %// Change
end
Take note that I've pre-allocated the cell array and for each file you want to look at, I've indexed into the right cell and placed the name there. This is preferred over concatenation primarily due to efficiency. To access the ith name, simply do:
name_to_choose = symbolsList{i};
Minor Note
filedata in your code isn't being used anywhere at all. Are you sure you put all of your code up?
I am new to matlab and image analysis. I would really appreciate some insight/help into the following problem. I am trying to rename images (jpg) in a folder that have a random name into specific (new) names. I made the an excel file with two columns the first column contains the old names and the second column the new names. I found the next code on stack overflow (Rename image file name in matlab):
dirData = dir('*.jpg'); %# Get the selected file data
fileNames = {dirData.name}; %# Create a cell array of file names
for iFile = 1:numel(fileNames) %# Loop over the file names
newName = sprintf('image%05d.jpg',iFile); %# Make the new name
movefile(fileNames{iFile},newName); %# Rename the file
end
The code gives all the photos a new name based on the old one but that is not what I want, the new names I use are not linked to the old ones. I tried the following code :
g= xlsread('names.xlsx') % names.xlsx the excel file with old and new names
for i=1:nrows(g)
image=open(g(i,1));
save(g(i,2),image);
end
It doesn't work. I get the error message :using open (line 68)
NAME must contain a single string. I don't think open is the right function to use.
Thank you !
How about this:
% Get the jpeg names
dir_data = dir('*.jpg');
jpg_names = {dir_data.name};
% Rename the files according to the .xlsx file
[~,g,~] = xlsread('names.xlsx'); % Thanks to the post of Sean
old_names = g(:,1);
new_names = g(:,2);
for k = 1:numel(old_names)
% check if the file exists
ix_file = strcmpi(old_names{k}, jpg_names);
if any(ix_file)
movefile(old_names{k}, new_names{k});
end;
end;
It seems like g = xlsread(file) reads only numeric data from file (see here). The third output argument of xlsread returns raw data including strings; does the following work? (i don't have excel and can't test it)
[~, ~, g] = xlsread('names.xlsx')
for i = 1:nrows(g)
movefile(g{i,1}, g{i,2})
end
how I can read the following files using the for loop: (can the loop ignore the characters in filenames?)
abc-1.TXT
cde-2.TXT
ser-3.TXT
wsz-4.TXT
aqz-5.TXT
iop-6.TXT
What do I have to add at the beginning of this loop ??
for i = 1:1:6
nom_fichier = strcat(['MyFile\.......' num2str(i) '.TXT']);
You can avoid constructing the filenames by using the DIR command. For instance:
myfiles = dir('*.txt');
for i = 1:length(myfiles)
nom_fichier = myfiles(i).name;
...do processing here...
end
First of all, why would you use strcat here? This is, by itself, a SINGLE string. All concatenation has already been done by the brackets [].
['MyFile\.......' num2str(i) '.TXT']
Next, I'm not certain what is your question here. Is it how to load in the data? If the files are simply delimited numbers, with the same number of them on each line, then load will suffice to load them in, or perhaps you may need textread.
My guess is you do not know how to build the main part of of the file name. You might do it this way:
Names = {'abc' 'cde 'ser' 'wsz' 'aqz' 'iop'};
for i = 1:6
fn = ['MyFile',filesep,Names{i},'-',num2str(i),'.TXT'];
data = load(fn);
% do other stuff ...
end
If you don't want to create a variable with the names by typing them in, then use dir, perhaps like this to create a list of text file names:
Names = dir('MyFile\*.TXT');