I have a MongoDB collection containing documents like this:
"_id" : "d0888171-473d-46c7-a9c2-e18dfa141998",
"NUMBER" : 111111,
"SECURITIES" : [
{
"FK_GROUPS_ID" : ObjectId("59d4e02540b8f85428c827f9"),
"ACCESS_LEVEL" : "r"
},
{
"FK_GROUPS_ID" : ObjectId("59d24bce184fcd62968a21a3"),
"ACCESS_LEVEL" : "rw"
}
]
}
How to find all documents with a specific FK_GROUPS_ID in SECURITIES array?
Thanks
db.collection.find({'SECURITIES.FK_GROUPS_ID' : ObjectId("GroupsIdString")});
Related
Hi I'm trying to remove multiple objects from an array that looks like this.
{
"_id" : ObjectId("5a7da1bda21d5f3e8cf005b3"),
"owner" : "1",
"group_name" : "PAASCU Board",
"group_members" : [
{
"faculty_name" : "Cheska Dela Rosa",
"faculty_number" : 2,
"_id" : ObjectId("5a7da1bda21d5f3e8cf005b5")
},
{
"faculty_name" : "Earl Sempio",
"faculty_number" : 7323,
"_id" : ObjectId("5a7da1bda21d5f3e8cf005b4")
},
{
"faculty_number" : 203,
"faculty_name" : "Sample",
"_id" : ObjectId("5a7dbf7952bd150a94d83958")
},
{
"faculty_number" : 8025,
"faculty_name" : "Sample Postman",
"_id" : ObjectId("5a7dc64a1cf5dd3d50167d53")
}
],
"__v" : 0 }
It works when I remove a single object using the $pull with this code.
db.getCollection('groups').update({_id: ObjectId("5a7da1bda21d5f3e8cf005b3")}, {$pull: {"group_members": {"faculty_number":8025}}})
But what if I want to remove multiple objects with different faculty_number? I tried using the $each method just like how I add multiple objects in the array but it doesn't work well.
Use $in operator to pass the list of faculty values to remove documents from embedded array. More here
Try
db.groups.update(
{"_id": ObjectId("5a7da1bda21d5f3e8cf005b3")},
{"$pull":{"group_members":{"faculty_number":{$in:[8025,7323]}}}}
)
How do I update a subelement data in nested field
{
"_id" : ObjectId("5efc287809c3635ae4977df0"),
"deviceid" : "f7dd4c1b-d7b1-4d1b-9ab0-b0fa52b1f7e7",
"solution" : []
}
I need to update same as below.
{
"_id" : ObjectId("5efc287809c3635ae4977df0"),
"deviceid" : "f7dd4c1b-d7b1-4d1b-9ab0-b0fa52b1f7e7",
"solution" : [
{
"solutionid" :1.0
}
]
}
Please use below query.
db.collection.updateOne({"deviceid" : "f7dd4c1b-d7b1-4d1b-9ab0-b0fa52b1f7e7"},{"$set":{"solution":[{"solutionid" :1.0}]}})
Have records in my db with such structure:
{
"_id" : "YA14163134",
"discount" : "",
"retail" : "115.0000",
"cost" : "",
"description" : "Caterpillar Mens Big Twist Analog Watch",
"stock_update" : "05",
"brand" : "Kronos",
"img_url" : "image2342000.jpg",
"UPC" : "4895053708012",
"stock" : [ [ "1611292138", "5" ], [ "1612032232", "4" ], [ "1612050918", "0" ] ]
}
and looking for query to get all records that have in "stock" "1612050918" value. That is update id.
Trying something like:
db.vlc.find({stock: {$elemMatch:{$all:["1612050918"]}}})
or
db.vlc.find({stock: { $in : ['1611292138']}})
or
db.vlc.find({stock: { $all : [[1611292138]]}})
with no result. It works only if I include in request second array element like here
db.vlc.find({stock: { $all : [['1611292138', '7']]}})
but that limit my request to all items from update with qnty 7 when I need with any qnty. Thank you in advance!
use this query:
{
"stock" : {
"$elemMatch" : {
"$elemMatch" : {
"$eq" : "1611292138"
}
}
}
}
Explanation:
The first $elemMatch allows you to scan all three arrays under stock
The nex $elemMatch allows you to scan the two elements in the sub-arrays
since $elemMatch requires a query object, the $eq notation is used for a literal match.
If you know that "1611292138" will always be the first element of the sub-array, your query becomes simpler:
{ "stock" : { "$elemMatch" : { "0" : "1611292138" } } }
Explanation:
Scan all arrays under stock
Look for "1611292138" in the first slot of each sub-array
Use nested $elemMatch as below :
db.vlc.find({stock: { "$elemMatch":{"$elemMatch":{"$all":["1612050918"]}}}})
Or
db.vlc.find({stock: {"$elemMatch":{ "$elemMatch":{"$in" : ["1612050918"]}}}})
In a find query projection, fields I specify after the positional operator are ignored and the whole document is always returned.
'myArray.$.myField' : 1 behave exactly like 'myArray.$' : 1
the positional operator selects the right document. But this document is quite big. I would like to project only 1 field from it.
Exemple:
db.getCollection('match').find({"participantsData.id" : 0001}, { 'participantsData.$.id': 1, })
here the response I have
{
"_id" : "myid",
"matchCreation" : 1463916465614,
"participantsData" : [
{
"id" : 0001,
"plenty" : "of",
"other" : "fields",
"and" : "subdocuments..."
}
]
}
This is what I want
{
"_id" : "myid",
"matchCreation" : 1463916465614,
"participantsData" : [
{
"id" : 0001
}
]
}
Is it possible with mongo?
Yes it can be done in mongo
Please try the below query
db.getCollection('match').find(
{"participantsData.id" : 0001},
{"participantsData.id": 1, "matchCreation": 1 })
This will give you the below result
{
"_id" : "myid",
"matchCreation" : 1463916465614,
"participantsData" : [
{
"id" : 1
}
]
}
I need get a specific object in array of array in MongoDB.
I need get only the task object = [_id = ObjectId("543429a2cb38b1d83c3ff2c2")].
My document (projects):
{
"_id" : ObjectId("543428c2cb38b1d83c3ff2bd"),
"name" : "new project",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b"),
"members" : [
ObjectId("5424ac37eb0ea85d4c921f8b")
],
"US" : [
{
"_id" : ObjectId("5434297fcb38b1d83c3ff2c0"),
"name" : "Test Story",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b"),
"tasks" : [
{
"_id" : ObjectId("54342987cb38b1d83c3ff2c1"),
"name" : "teste3",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b")
},
{
"_id" : ObjectId("543429a2cb38b1d83c3ff2c2"),
"name" : "jklasdfa_XXX",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b")
}
]
}
]
}
Result expected:
{
"_id" : ObjectId("543429a2cb38b1d83c3ff2c2"),
"name" : "jklasdfa_XXX",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b")
}
But i not getting it.
I still testing with no success:
db.projects.find({
"US.tasks._id" : ObjectId("543429a2cb38b1d83c3ff2c2")
}, { "US.tasks.$" : 1 })
I tryed with $elemMatch too, but return nothing.
db.projects.find({
"US" : {
"tasks" : {
$elemMatch : {
"_id" : ObjectId("543429a2cb38b1d83c3ff2c2")
}
}
}
})
Can i get ONLY my result expected using find()? If not, what and how use?
Thanks!
You will need an aggregation for that:
db.projects.aggregate([{$unwind:"$US"},
{$unwind:"$US.tasks"},
{$match:{"US.tasks._id":ObjectId("543429a2cb38b1d83c3ff2c2")}},
{$project:{_id:0,"task":"$US.tasks"}}])
should return
{ task : {
"_id" : ObjectId("543429a2cb38b1d83c3ff2c2"),
"name" : "jklasdfa_XXX",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b")
}
Explanation:
$unwind creates a new (virtual) document for each array element
$match is the query part of your find
$project is similar as to project part in find i.e. it specifies the fields you want to get in the results
You might want to add a second $match before the $unwind if you know the document you are searching (look at performance metrics).
Edit: added a second $unwind since US is an array.
Don't know what you are doing (so realy can't tell and just sugesting) but you might want to examine if your schema (and mongodb) is ideal for your task because the document looks just like denormalized relational data probably a relational database would be better for you.