Calculate the time between these two timestamps in PostgreSQL, create_time='2017-11-02 05:51:13' and update_time='2017-11-02 07:36:18' and display it on HH:MM:SS Format. it should display like this 01:45:04
You can try just subtracting the two timestamps, then using to_char to extract out the time portion:
select
SELECT to_char('2017-11-02 07:36:18'::timestamp -
'2017-11-02 05:51:10'::timestamp, 'HH:MI:SS');
Output:
to_char
01:45:08
Demo
Related
I have a date time column which is of the following format:
2019-11-10-07.10.55.865000
I want my format to be as follows:
2019-11-10 07:10:55.865000
How can I do this in PostgreSQL 9.6.11?
We can try making a full roundtrip from text to timestamp, then back to text again:
SELECT
TO_CHAR(TO_TIMESTAMP('2019-11-10-07.10.55.865000', 'YYYY-MM-DD-HH.MI.SS.US'),
'YYYY-MM-DD HH:MI:SS.US') AS ts_out;
This outputs:
2019-11-10 07:10:00.865000
Demo
As a side note, you should seriously consider not storing your timestamps as text in the first place. Ideally, if you want to view your timestamp column a certain way, e.g. for reporting purposes, you should only have to make a single call to TO_CHAR with the format mask you want to use.
There is the to_char(timestamp, text) function, e.g. to_char(current_timestamp, 'HH12:MI:SS')
https://www.postgresql.org/docs/current/functions-formatting.html
Using PostgreSQL database for my attendance application.
I have a table with IN and out times (hh:mm:ss.us format).
When I subtract the times (OUT -IN) to calculate the working hours, results are not as expected due to precision.
If IN Time is "22:12:56.09"
& OUT TIme is "22:14:06.06" the difference considering only HH:mm should be 00:02 but it actually shows "00:01:09.97" which becomes "00:01" in excel using only HH:mm.
I am trying to do the time conversion from hh:mm:ss.us to hh:mm (time format) so that I can subtract the time and get the desired output.
I have done similar things in SQL Server but I did not find any function in PostgreSQL. Please advise.
First you need to truncate the seconds. Then subtract to get desired result
select
to_char(
(
to_char('22:14:06.06' :: time, 'HH24:MI'):: time -
to_char('22:12:56.09' :: time, 'HH24:MI'):: time
),
'HH24:MI'
)
Result: 00:02
General Solution:
select
to_char(
(
to_char(out, 'HH24:MI'):: time - to_char(in, 'HH24:MI'):: time
),
'HH24:MI'
)
Here the purpose of to_char() is to format result to hours:minutes and not to include seconds.
Postgres includes seconds in interval by default.
You can use the date_trunc function with timestamp.
It would work something like this:
select date_trunc('minute', out) - date_trunc('minute', in)
This would set a minute level precision on the timestamp and convert HH:mm:ss to HH:mm:00
I am using the following code to convert a column of unix time values into dates in pyspark:
transactions3=transactions2.withColumn('date', transactions2['time'].cast('date'))
The column transactions2['time'] contains the unix time values. However the column date which I create here has no values in it (date = None for all rows). Any idea why this would be?
Use from_unixtime. expr("from_unixtime(timeval)")
Is there a way to have the time (HH:mm) between two timestamps in postgresql ?
The difference between two timestamps can be calculated using -, e.g.:
timestamp_one - timestamp_two
However, the result is not a "time", but an "interval".
You can display that in the form HH:mm using to_char():
to_char(timestamp_one - timestamp_two, 'HH:mi')
but what do you expect for differences larger then 24 hours?
I am block-inserting data from Stata (a statistics package) into a Teradata database. I am having trouble converting dates and timestamps from Stata's native format to Teradata's.
Stata stores dates as days since 01/01/1960, so that 01jan1960 is 0 and 02jan1960 is 1. Timestamps are stored as milliseconds since 01jan1960 00:00:00.000, so that 1000 is 01jan1960 00:00:01. Here are some examples:
timestamp Stata's tstamp date Stata's date
2015-04-13 03:07:08 1744513628000 2015-04-13 20191
2015-04-14 19:55:43 1744660543000 2015-04-14 20192
2015-04-08 11:41:39 1744112499000 2015-04-08 20186
2015-04-15 06:53:34 1744700014000 2015-04-15 20193
I tried 2 approaches. The first involves converting the dates/timestamps to strings in Stata before inserting and then doing something like this once the data is inserted:
ALTER TABLE mytable ALTER date_variable DATETIME
However, I cannot figure out how to do the second part from the documentation I have and after searching the various fora.
The second approach is leaving the dates and timestamps as integers, and then doing some of conversion once the integers are inserted. Perhaps I can also pre-convert dates in Stata to TD's internal format with:
gen td_date = ((year(stata_dt)-1900)*10000 + month(stata_dt)*100 + day(stata_dt))
However, I am not sure what the formula for timestamps would be. I am also not sure how to do the second part (making the integers into dates/timestamps).
You can't change the datatype of a column in Teradata from string to date/timestamp.
But when you insert a string into a date/timestamp column there will be an automatic typecast. So simply convert to a string with 'yyyy-mm-dd' or 'yyyy-mm-dd hh:mi:ss' format.
You could also do the conversion during load on Teradata using calculations, but IMHO the 1st solution is preferable:
-- add the number of days to the start date
DATE '1960-01-01' + stata_dt
-- I use a similar approach for Unix Timestamps starting 1970 :-)
-- split into days and seconds
CAST(DATE '1960-01-01' + (stata_ts / 86400000) AS TIMESTAMP(0))
+ ((stata_ts MOD 86400000 / 1000) * INTERVAL '00:00:01' HOUR TO SECOND)