Group and count in Mongo DB - mongodb

I have many tweets object like this:
{
"_id" : ObjectId("5a2f4a381cb29b482553e2c9"),
"user_id" : 21898942,
"created_at" : ISODate("2009-03-09T19:48:50Z"),
"id" : 1301923516,
"place" : "",
"retweet_count" : 0,
"tweet" : "Save the Date! March 28th Vietnamese Cooking Class! Call to Reserve 312.255.0088",
"favorite_count" : 0
"type": A
}
I'm using this code to qroup the tweets by date and by type:
pipeline = [
{
"$group": {
"_id": {
"date": {
"$dateToString": {
"format": "%Y-%m-%d",
"date": "$created_at"
}
},
"type": "$type"
},
"count": {
"$sum": 1
}
}
}
]
results = mongo.db.tweets.aggregate(pipeline)
Here is the result I get:
{
"_id": {
"date": "2009-03-17",
"type": A
},
"count": 4
,
{
"_id": {
"date": "2009-03-17",
"type": B
},
"count": 6
}
But now I want to have the result in this format:
{date: "2009-03-17", A: 4, B: 6, C: 9}
Is there anyway I can achieve this through aggregate directly?
Note: I'm using MongoDB and PyMongo

You can try the below aggregation query in 3.6 version.
Added the second group to create array of type and count value pairs followed by $mergeObjects to merge date key value with $arrayToObject, which produces create a type value key and count value pairs, to generate the expected response.
$replaceRoot to promote the document to the top level.
pipeline = [
{
"$group": {
"_id": {
"date": {
"$dateToString": {
"format": "%Y-%m-%d",
"date": "$created_at"
}
},
"type": "$type"
},
"count": {
"$sum": 1
}
}
},
{
"$group": {
"_id": "$_id.date",
"typeandcount": {
"$push": {
"k": "$_id.type",
"v": "$count"
}
}
}
},
{
"$replaceRoot": {
"newRoot": {
"$mergeObjects": [
{
"date": "$_id"
},
{
"$arrayToObject": "$typeandcount"
}
]
}
}
}
]
Mongo 3.4 version:
Replace the last stage with below
{
"$replaceRoot": {
"newRoot": {
"$arrayToObject": {
"$concatArrays": [
[
{
"k": "date",
"v": "$_id"
}
],
"$typeandcount"
]
}
}
}
}

Related

need to convert the data in another format

We have Data:
[
{
"_id": ObjectId("5f87e152219aaf1f9404ef3f"),
"parameterId": "5f914ca2679bae721d38410b",
"average": 574998.153846154,
"count": 26.0,
"date": ISODate("2020-09-08T18:30:00.000Z"),
"_class": "org.nec.iotplatform.entities.RawData"
},
{
"_id": ObjectId("5f87e1e2219aaf1f9404eff5"),
"parameterId": "5f914ca2679bae721d38410b",
"average": 494217.606225681,
"count": 1285.0,
"date": ISODate("2020-09-09T18:30:00.000Z"),
"_class": "org.nec.iotplatform.entities.RawData"
}
]
I have query which I am executing on above data and then getting the result as below the query
db.collection.aggregate([
{
"$project": {
"year": {
"$year": "$date"
},
"month": {
"$month": "$date"
},
"dayOfMonth": {
"$dayOfMonth": "$date"
},
"average": "$average",
"count": "$count",
"Symbol": 1
}
},
{
"$group": {
"_id": {
year: "$year",
month: "$month",
dayOfMonth: "$dayOfMonth"
},
"data": {
"$push": "$$ROOT"
}
}
},
{
"$project": {
"average": {
"$divide": [
{
"$reduce": {
"input": "$data",
"initialValue": 0,
"in": {
"$add": [
"$$value",
{
"$multiply": [
"$$this.count",
"$$this.average"
]
}
]
}
}
},
{
$reduce: {
input: "$data",
initialValue: 0,
in: {
"$add": [
"$$value",
"$$this.count"
]
}
}
}
]
}
}
}
])
I am getting output :
[{
"_id" : {
"year" : 2020,
"month" : 9,
"dayOfMonth" : 8
},
"average" : 574998.153846154
},
{
"_id" : {
"year" : 2020,
"month" : 9,
"dayOfMonth" : 9
},
"average" : 494217.606225681
}]
But I need to format the result data like this. by adding the date like this:
{
2020-09-08T18:30:00.000Z : 574998.153846154,
2020-09-09T18:30:00.000Z : 494217.606225681
}
Thanks in advance.
You can use $dateFromString to create the date you want.
Also, you need $concat and $toString to parse the numbers to string and concat into a single string.
After that, using $group you can get the all values you need in the same array. And how you want set the date as KEY, is neccesary create fields k and v and parse again to string.
With the values together, using $arrayToObject you can cerate the schema you want date: average and use $replaceRoot to get only the values at top level.
To do this you need to add this query at the end of your aggregation.
{
"$set": {
"date": { "$dateFromString": { "dateString": {
"$concat": [
{ "$toString": "$_id.dayOfMonth" }, "-",
{ "$toString": "$_id.month" }, "-",
{ "$toString": "$_id.year" }
] },
"format": "%d-%m-%Y", "timezone": "Europe/Madrid"
} } }
},
{
"$group": {
"_id": null,
"date": { "$push": { "k": { "$toString": "$date" }, "v": "$average" } }
}
},
{
"$replaceRoot": { "newRoot": { "$arrayToObject": "$date" } }
}
This query add a new field called date like this:
"date": ISODate("2020-09-08T04:00:00Z")
I've used Europe/Madrid as timezone but you can choose you want to get your desired date.
Example here.
The output is:
{
"2020-09-07T22:00:00.000Z": 574998.153846154,
"2020-09-08T22:00:00.000Z": 494217.606225681
}
Using America/New_York as timezone:
{
"2020-09-08T04:00:00.000Z": 574998.153846154,
"2020-09-09T04:00:00.000Z": 494217.606225681
}

Group by date in mongoDB while counting other fields

I've been using MongoDB for just a week and I have problems achieving this result: I want to group my documents by date while also keeping track of the number of entries that have a certain field set to a certain value.
So, my documents look like this:
{
"_id" : ObjectId("5f3f79fc266a891167ca8f65"),
"recipe" : "A",
"timestamp" : ISODate("2020-08-22T09:38:36.306Z")
}
where recipe is either "A", "B" or "C". Right now I'm grouping the documents by date using this pymongo query:
mongo.db.aggregate(
# Pipeline
[
# Stage 1
{
"$project": {
"createdAt": {
"$dateToString": {
"format": "%Y-%m-%d",
"date": "$timestamp"
}
},
"progressivo": 1,
"temperatura_fusione": 1
}
},
# Stage 2
{
"$group": {
"_id": {
"createdAt": "$createdAt"
},
"products": {
"$sum": 1
}
}
},
# Stage 3
{
"$project": {
"label": "$_id.createdAt",
"value": "$products",
"_id": 0
}
}])
Which gives me results like this:
[{"label": "2020-08-22", "value": 1}, {"label": "2020-08-15", "value": 2}, {"label": "2020-08-11", "value": 1}, {"label": "2020-08-21", "value": 5}]
What I'd like to have is also the counting of how many times each recipe appears on every date. So, if for example on August 21 I have 2 entries with the "A" recipe, 3 with the "B" recipe and 0 with the "C" recipe, the desired output would be
{"label": "2020-08-21", "value": 5, "A": 2, "B":3, "C":0}
Do you have any tips?
Thank you!
You can do like following, what have you done is excellent. After that,
In second grouping, We just get total value and value of each recipe.
$map is used to go through/modify each objects
$arrayToObject is used to covert the array what we have done via map (key : value pair) to object
$ifNull is used for, sometimes your data might not have "A" or "B" or "C". But you need the value should be 0 if there is no name as expected output.
Here is the code
[
{
"$project": {
"createdAt": {
"$dateToString": {
"format": "%Y-%m-%d",
"date": "$timestamp"
}
},
recipe: 1,
"progressivo": 1,
"temperatura_fusione": 1
}
},
{
"$group": {
"_id": {
"createdAt": "$createdAt",
"recipeName": "$recipe",
},
"products": {
$sum: 1
}
}
},
{
"$group": {
"_id": "$_id.createdAt",
value: {
$sum: "$products"
},
recipes: {
$push: {
name: "$_id.recipeName",
val: "$products"
}
}
}
},
{
$project: {
"content": {
"$arrayToObject": {
"$map": {
"input": "$recipes",
"as": "el",
"in": {
"k": "$$el.name",
"v": "$$el.val"
}
}
}
},
value: 1
}
},
{
$project: {
_id: 1,
value: 1,
A: {
$ifNull: [
"$content.A",
0
]
},
B: {
$ifNull: [
"$content.B",
0
]
},
C: {
$ifNull: [
"$content.C",
0
]
}
}
}
]
Working Mongo playground

mongodb aggregation with multiple sub groups

I have a collection with documents that look similar to this:
[
{
"_id": ObjectId("..."),
"date": ISODate("..."),
"type": "TypeA",
"color": "ColorA",
"soldFor": 12.15
},
{
"_id": ObjectId("..."),
"date": ISODate("..."),
"type": "TypeA",
"color": "ColorB",
"soldFor": 13.15
},
{
"_id": ObjectId("..."),
"date": ISODate("..."),
"type": "TypeB",
"color": "ColorA",
"soldFor": 12.15
},
{
"_id": ObjectId("..."),
"date": ISODate("..."),
"type": "TypeB",
"color": "ColorB",
"soldFor": 12.15
}
]
I know that this is not a good way to store such information, but unfortunately I have no influence in that.
What I need to get out of the collection is something like this:
[
2017: {
typeA: {
colorA: {
sum: 125.00
},
colorB: {
sum: 110.00
}
},
typeB: {
colorA: {
sum: 125.000
}
}
},
2016: {
typeA: {
colorB: {
sum: 125.000
}
}
}
]
At the moment I have two group stages that give me everything grouped by year, but I have no clue how to get the two other sub-groups. Building the sum would be a nice to have, but I am certain that I can figure out how that would be done in a group.
So far my pipeline looks like this:
[
{
$group: {
_id: { type: '$type', color: '$color', year: { $year: '$date' } },
docs: {
$push: '$$ROOT'
}
}
},
{
$group: {
_id: { year: '$_id.year' },
docs: {
$push: '$$ROOT'
}
}
}
]
which results in something like this:
[
{
"_id": {
"year": 2006
},
"docs": {
"_id": {
"type": "typeA",
"color": "colorA",
"year": 2006
},
"docs": [
{
... root document
}
]
}
},
{
"_id": {
"year": 2016
},
"docs": [
{
"_id": {
"type": "typeA",
"color": "colorB",
"year": 2016
},
"docs": [
{
... root document
}
]
}
... more docs with three keys in id
]
}
]
Help is much appreciated!
Using a cohort of operators found in MongoDB 3.4.4 and newer, i.e. $addFields, $arrayToObject and $replaceRoot, you can compose a pipeline like the following to get the desired result:
[
{ "$group": {
"_id": {
"year": { "$year": "$date" },
"type": "$type",
"color": "$color"
},
"count": { "$sum": "$soldFor" }
} },
{ "$group": {
"_id": {
"year": "$_id.year",
"type": "$_id.type"
},
"counts": {
"$push": {
"k": "$_id.color",
"v": { "sum": "$count" }
}
}
} },
{ "$addFields": {
"counts": { "$arrayToObject": "$counts" }
} },
{ "$group": {
"_id": "$_id.year",
"counts": {
"$push": {
"k": "$_id.type",
"v": "$counts"
}
}
} },
{ "$addFields": {
"counts": { "$arrayToObject": "$counts" }
} },
{ "$group": {
"_id": null,
"counts": {
"$push": {
"k": { "$substr": ["$_id", 0, -1 ]},
"v": "$counts"
}
}
} },
{ "$replaceRoot": {
"newRoot": {
"$mergeObjects": [
{ "$arrayToObject": "$counts" },
"$$ROOT"
]
}
} },
{ "$project": { "counts": 0 } }
]

Grouping different amounts together in MongoDB

If I have a set of objects each with the same description, but with different amounts.
{
{
"_id": "101",
"description": "DD from my employer1",
"amount": 1000.33
},
{
"_id": "102",
"description": "DD from my employer1",
"amount": 1000.34
},
{
"_id": "103",
"description": "DD from my employer1",
"amount": 1000.35
},
{
"_id": "104",
"description": "DD from employer1",
"amount": 5000.00
},
{
"_id": "105",
"description": "DD from my employer2",
"amount": 2000.33
},
{
"_id": "106",
"description": "DD from my employer2",
"amount": 2000.33
},
{
"_id": "107",
"description": "DD from my employer2",
"amount": 2000.33
}
}
Below, I am able to group them using the description:
{
{
"$group": {
"_id": {
"description": "$description"
},
"count": {
"$sum": 1
},
"_id": {
"$addToSet": "$_id"
}
}
},
{
"$match": {
"count": {
"$gte": 3
}
}
}
}
Is there a way to include all the amounts in the group (_ids: 101, 102, and 103 plus 105,106,107) even if they have a small difference, but exclude the bonus amount, which in the sample above is _id 104?
I don't believe it could be done in a group stage, but is there something that could be done at a later stage that could group _ids 101, 102 and 103 together and exclude _id 104. Basically, I want MongoDB to ignore the small differences in 101, 102, 103 and group them together since the are paychecks coming from the same employer.
I have been working with $stdDevPop, but can't get a solid formula down.
I am looking for a simple array output of just the _ids.
{
"result": [
"101",
"102",
"103",
"105",
"106",
"107"
]
}
You can do this by doing some math on the "amount" to round it down to the nearest 1000 and use that as the grouping _id:
db.collection.aggregate([
{ "$group": {
"_id": {
"$subtract": [
{ "$trunc": "$amount" },
{ "$mod": [
{ "$trunc": "$amount" },
1000
]}
]
},
"results": { "$push": "$_id" }
}},
{ "$redact": {
"$cond": {
"if": { "$gt": [ { "$size": "$results" }, 1 ] },
"then": "$$KEEP",
"else": "$$PRUNE"
}
}},
{ "$unwind": "$results" },
{ "$group": {
"_id": null,
"results": { "$push": "$results" }
}}
])
If your MongoDB is older than 3.2 then you would just need to use a long form with $mod of what $trunc is doing. And if your MongoDB is older than 2.6 then rather than $redact you would $match. So in the longer form this is:
db.collection.aggregate([
{ "$group": {
"_id": {
"$subtract": [
{ "$subtract": [
"$amount",
{ "$mod": [ "$amount", 1 ] }
]},
{ "$mod": [
{ "$subtract": [
"$amount",
{ "$mod": [ "$amount", 1 ] }
]},
1000
]}
]
},
"results": { "$push": "$_id" },
"count": { "$sum": 1 }
}},
{ "$match": { "count": { "$gt": 1 } } },
{ "$unwind": "$results" },
{ "$group": {
"_id": null,
"results": { "$push": "$results" }
}}
])
Either way the output is just the _id values whose amounts grouped to the boundaries with a count more than once.
{ "_id" : null, "results" : [ "105", "106", "107", "101", "102", "103" ] }
You could either add a $sort in there or live with sorting the result array in client code.
db.yourDBNameHere.aggregate( [
{ $match: { "amount" : { $lt : 5000 } } },
{ $project: { _id: 1 } },
])
that will grab the ID only of every transaction less than 5000$.

Mongo Aggregation : $group and $project array to object for counts

I have documents like:
{
"platform":"android",
"install_date":20151029
}
platform - can have one value from [android|ios|kindle|facebook ] .
install_date - there are many install_dates
There are also many fields.
Aim : I am calculating installs per platform on particular date.
So I am using group by in aggregation framework and make counts by platform. Document should look like like:
{
"install_date":20151029,
"platform" : {
"android":1000,
"ios": 2000,
"facebook":1500
}
}
I have done like:
db.collection.aggregate([
{
$group: {
_id: { platform: "$platform",install_date:"$install_date"},
count: { "$sum": 1 }
}
},
{
$group: {
_id: { install_date:"$_id.install_date"},
platform: { $push : {platform :"$_id.platform", count:"$count" } }
}
},
{
$project : { _id: 0, install_date: "$_id.install_date", platform: 1 }
}
])
which Gives document like:
{
"platform": [
{
"platform": "facebook",
"count": 1500
},
{
"platform": "ios",
"count": 2000
},
{
"platform": "android",
"count": 1000
}
],
"install_date": 20151027
}
Problem:
Projecting array to single object as "platform"
With MongoDb 3.4 and newer, you can leverage the use of $arrayToObject operator to get the desired result. You would need to run the following aggregate pipeline:
db.collection.aggregate([
{ "$group": {
"_id": {
"date": "$install_date",
"platform": { "$toLower": "$platform" }
},
"count": { "$sum": 1 }
} },
{ "$group": {
"_id": "$_id.date",
"counts": {
"$push": {
"k": "$_id.platform",
"v": "$count"
}
}
} },
{ "$addFields": {
"install_date": "$_id",
"platform": { "$arrayToObject": "$counts" }
} },
{ "$project": { "counts": 0, "_id": 0 } }
])
For older versions, take advantage of the $cond operator in the $group pipeline step to evaluate the counts based on the platform field value, something like the following:
db.collection.aggregate([
{ "$group": {
"_id": "$install_date",
"android_count": {
"$sum": {
"$cond": [ { "$eq": [ "$platform", "android" ] }, 1, 0 ]
}
},
"ios_count": {
"$sum": {
"$cond": [ { "$eq": [ "$platform", "ios" ] }, 1, 0 ]
}
},
"facebook_count": {
"$sum": {
"$cond": [ { "$eq": [ "$platform", "facebook" ] }, 1, 0 ]
}
},
"kindle_count": {
"$sum": {
"$cond": [ { "$eq": [ "$platform", "kindle" ] }, 1, 0 ]
}
}
} },
{ "$project": {
"_id": 0, "install_date": "$_id",
"platform": {
"android": "$android_count",
"ios": "$ios_count",
"facebook": "$facebook_count",
"kindle": "$kindle_count"
}
} }
])
In the above, $cond takes a logical condition as it's first argument (if) and then returns the second argument where the evaluation is true (then) or the third argument where false (else). This makes true/false returns into 1 and 0 to feed to $sum respectively.
So for example, if { "$eq": [ "$platform", "facebook" ] }, is true then the expression will evaluate to { $sum: 1 } else it will be { $sum: 0 }