How to determine that a Angular form is tried to submit or not to show invalid fields.
When you create a form in angular, then the form object contains a boolian property "submitted". It becomes true when user tries to submit a form.
<form #searchForm="ngForm" [ngClass]="{'FormTried':searchForm.submitted}"
(ngSubmit)="submitData(searchForm)" >
// your form fields
</form>
I used it to add a class for form tried to submit or not.
<form #empForm="ngForm" [ngClass]="{'FormTried':empForm._submitted}"
(ngSubmit)="submitData(empForm)" >
// added code here
</form>
I have used this and this works fine at my end, please try this also.
Related
I'm adding in CSRF token validation and I'm running into a problem where I have two forms on a page and one of them will submit successfully and the other will not. I'm not doing AJAX requests, I'm simply using hidden input fields. If I submit the form when it is the only one on the page, it submits without issue. If I submit it on a page with more than one form, it fails.
Below is the template code for my two forms
{{if .IsAuthenticated}}
<form action='/admin/logout' method='POST'>
<button>Logout</button>
{{.CsrfField}}
</form>
{{end}}
<form action='/admin/stuff/create' method='POST'>
{{with .Form}}
<div>
<label>Title:</label>
<input type='text' name='title' value='{{.Get "title"}}'>
</div>
<div>
<input type='submit' value='Publish stuff'>
</div>
{{end}}
{{.CsrfField}}
</form>
And this is what the generated HTML looks like. Both appear to be valid.
When I click the "Logout" button though, I get the Forbidden - CSRF token invalid error, but clicking the create input value in the second form always works.
The logout button is correctly validated when I attempt to use it on the home page which is "/admin/" but it does not work on any of the other pages "/admin/snippet/:id" or "/admin/snippet/create". The Logout button is part of a base template, so it appears on every page, so there shouldn't be anything different in how it appears on any page.
I've read other SO posts about multiple forms & CSRF tokens on a page and I understand there should be no issue with multiple forms with the same information as long as you have each one in it's own form, it should be fine. So I am not sure where I am going wrong.
I found the issue. Currently the way that gorilla/csrf works, it does not like creating the masked token from one path and then sending that token off to another path. So in my situation, going from /admin/snippet/create to /admin/logout threw an error because it was expecting the path for the token to be /admin/snippet/<something> and so it threw an error.
This issue has been addressed in this PR: https://github.com/gorilla/csrf/pull/147 and essentially the solution is to set the default path yourself to something which all of your routes will contain, so in my case that was /admin
This is what my CSRF declaration looks like now in main.go
var csrfMiddleWare = csrf.Protect(
[]byte("<put your 32 character key here>"),
csrf.Path("/admin"),
csrf.Secure(false),
)
A note, if you had this issue and then apply this fix and it doesn't resolve the problem, trying testing in a separate browser as there may be some caching issues.
In moodle, when you go to Quiz Administration-> User overrides -> Add user override, you get a form (overrideedit.php) to add the details of the user override to be created.
You need to fill that form and submit it. After you submit, the form is processed (in overrideedit.php itself) and then you are redirected to overrides.php page.
Now, I want that form to take post data from my plugin and process it in overrideedit.php and do the redirect.
How do I send post data in this case from my plugin?
You could set a different action for the form you're having in your plugin (this assumes you are using Moodle Form API for your custom form):
// Instantiate your form
// Data will be submitted to /mod/quiz/overrideedit.php
$mform = new custom_form_your_are_having(new moodle_url('/mod/quiz/overrideedit.php'));
Or simply change the action attribute of your custom for to point to /mod/quiz/overrideedit.php:
<form action="/mod/quiz/overrideedit.php" method="post">
...
</form>
I use ngxErrors to display errors for a form control and it works great. Is there any way to get similar functionality for a form or a form group? Currently, I display a form error like this:
<div *ngIf="form.hasError('loginFailed')">
Login Failed
</div>
The bummer is, when I detect that there is a form error (e.g. after the login form is submitted) as opposed to control error, I set it like this:
this.form.setErrors({ loginFailed: true });
this.cdr.detectChanges();
Where this.cdr is an instance of ChangeDetectorRef. This is necessary because I'm using OnPush change detection strategy. So basically it's like calling $scope.$apply() from AngularJS all over again.
What I would really like to do is something more like how ngxErrors does it:
<div ngxErrors="myForm">
<div ngxError="loginFailed" [when]="['dirty', 'touched']">
The login has failed
</div>
But ngxErrors expects myForm to be a control.
This feature is not currently baked into ngxErrors, but I submitted a PR. https://github.com/UltimateAngular/ngxerrors/pull/18
The working syntax is a slight modification of the above:
<div ngxErrors>
<div ngxError="loginFailed" [when]="['dirty', 'touched']">
The login has failed
</div>
</div>
I learned that you do not have to tell child components the form, the FormGroupDirective is available to children automatically.
See this library https://www.npmjs.com/package/ng-error-messages for show error messages based on validation rules:
<input placeholder="Texto:" formControlName="text">
<div errorMessage="text" alias="Super Texto" ></div>
Is it possible to build and validate a simple html form (not a CActiveForm or CHtml widget form) with yii validate() method.If yes, please give suitable and simple example.I can't find anything about this on web,
Thanks in advance
I think yes, try to sent it like Model[field] with the POST method. And disable csrf token.
yes you can use validation without help of CActiveForm and Chtml
use in your html tag name like Model[attribute]
<input type="text" name="User[full_name]">
in your controller function disabled _csrf token
function actionSave() {
$this->enableCsrfValidation = false;
<--here your code
-->
}
Recently i am started tuning our products to IE compatability. Now i am facing a weird problem in IE alone.
My form url is something like this https://x.com/formurl/dynamicvalue
and my form element is
<form action="" method='post'>
...
</form>
some values the dynamicvalue holds are ( Alphanumeric characters )
plan
plan2
1234443
544
Except IE every other browsers sending the actions to https://x.com/formurl/dynamicvalue
IE form action is sending to https://x.com/formurl
I don't know why this is happening, I can replace the document.URL to post the Form back to solve the problem. Still, i want to what's the reason for IE to remove that dynamicvalue
I am testing in IE-9
Kindly someone teach me.
Thanks in advance.
I have also discovered this bug in Internet Explorer 11 when reading the action attribute of a form with action set to the empty string.
<form action="" method="post"></form>
If one reads the form.action attribute in javascript and the current URL does not contain a trailing slash, the last part of the URL will be removed. I.e., if the location is example.com/xxx/yyy, form.action=="example.com/xxx, while if location is example.com/xxx/yyy/, form.action=="example.com/xxx/yyy/.
However, if the form is posted by clicking a submit button, it is posted to the correct URL, i.e., example.com/xxx/yyy or example.com/xxx/yyy/.
I overcame this by using jQuery's attr function to check if action="" in the HTML and then I use location.href instead.
if($(form).attr('action') === '') return location.href else return $(form).attr('action')
(Why would someone do this? I am intercepting the form submit and using ajax to send the data. To do this, I need to know where the form wants to submit)