I already have a date time column which is updated every time I ingest new data and it works, but I would like to do the same for a new column but just with the date, not the time. Please see the picture attached. What should I write in the Default option? Table column definitions
You could set the default value to CURRENT_DATE ON UPDATE CURRENT_DATE in your EventDate field.
But wouldn't it be better to extract date from the already existing EventDateTime field with DATE_FORMAT(EventDateTime, '%Y-%m-%d') or DATE(EventDateTime) functions?
Related
Every month I download a set of data into a report. That data consists of multiple records and each record has a record specific date as well as having the month end report date on the record's data-row.
I have used Power Query to upload all of these month end reports. I want use Power Query to be able to compare the column of record dates with the earliest date in the column of report dates to see if anybody has fiddled any data entry. The query table has the following headings.
Record ID Record Date Report Date
I've tried adding a custom column using the formula = if Record Date < List.Min(Report Date) then "Old" else "New"
this didn't work and I've spent ages trying to get a solution. I've also tried using Groups to get the minimum value, but I lose all of the other columns, which I want to keep. Any help really appreciated.
You have to refer to the fields in [], so here [Report Date]
To pick a column use Source[Field], so here #"PriorStep"[Report Date]
The List.Min function is not pulling as a number so you cant use <
Insert a Number.From in front of the calculation to convert to number
Same need to add Number.From in front of [Record Date] pulling as a date
Combined code:
#"Added Custom" = Table.AddColumn(#"PriorStep", "Custom", each if Number.From([Record Date])<Number.From(List.Min(#"PriorStep"[Report Date])) then "Old" else "New")
I am trying to create a job to insert all my data from Mysql to MongoDB
and this is my configuration :
how to auto generate date_created and last_updated?
so every data insert will auto fill date_created to new Date() or current date time and every data updated will auto update field last_updated with new Date() or current date.
You are looking for the Get System Info step.
It gives you a number of variables realted to the environement, including the time of the run. I usually use the system date (fixed), so that all the date-created are the same for the run, which ease retrieval.
For the last_update, it is that same technique, if you can setup your Match field for update in the MongoDB output step. If you cannot, have a look at the Merge Row (diff) : it tells you if the record is new, deleted, identical or changed.
Please pardon my ignorance if I have missed any documentation/solution for the same. But I searched the web and could not find an answer.
I have a simple question. In the DB2 table,I have a column of type date and the with data of format 04/25/2013 12:00:00AM . When I query the DB2 database, I want to obtain just the date and not the timestamp i.e to obtain "04/25/2013" and not "04/25/2013 12:00:00AM". I tried DATE(column name) and just gave back the complete value including the time stamp.
This looks like a TIMESTAMP and not a DATE column. If it is indeed a TIMESTAMP column try this:
select varchar_format(current timestamp, 'MM/DD/YYYY') from sysibm.sysdummy1 ;
Just replace the current timestamp in the above example with your column and sysibm.sysdummy1 with your table.
The good thing about varchar_format is that it lets you easily format the timestamp. Just change the 'MM/DD/YYYY' part to 'YYYY.MM.DD' to get a format like '2017.08.18'.
I'm rather new to ASP.NET and SQL, so I'm having a tough time trying to figure out how to compare two time columns. I have a timestamped column and then a Now() column in an .mdb database. I need to have a gridview display records that are "Greater than or equal to 3 hours" from the timestamp. Any idea how I can accomplish this?
The Transact-SQL timestamp data type is a binary data type with no time-related values.
So to answer your question: Is there a way to get DateTime value from timestamp type column?
The answer is: No
You need another column of datetime2 type and use > operator to for comparison. You might want to set default value of getutcdate() to set it when each row is inserted.
UPDATE:
Since the column is of datetime type and not timestamp type (there is a type in SQL Server called timestamp, hence the confusion) you can just do
WHERE [TimeCalled] <= DATEADD(hour, -3, GETDATE())
Make sure your server is running in the same timezone as your code. It may be safer to store all dates in UTC. In that case use GETUTCDATE instead on GETDATE
Timestamps are generally used to track changes to records, and are updated every time the record is changed. If you want to store a specific value you should use a datetime field.
If you're using a DateTime Column and you want the result in TSQL try
DATEDIFF(Hour, 'Your DateTime Column here', 'pass Now() here' )
try to execute this example in TSQL:
select DATEDIFF(Hour, '2012-11-10 00:00:59.900', '2012-11-10 05:01:00.100')
I'm currently trying to do it that way:
// Creating date object
$date = new Zend_Date();
// Adding to it 4 weeks
$date->add('4', Zend_Date::WEEK); // it's expire day
// Getting date in integer(i guess it's unix timestamp yes?)
$date->get();
// Saving it to Mysql in field 'expire' with type Varchar
Then, when needed to get rows, that have date bigger(that haven't yet expired), than current I just add to SQL a simple statement WHERE expire >= $current_date.
Or there is better way to do it? Or how it happens usually?
I would recommend using the native MySQL DATETIME column in your table. This is how you'd retrieve the date for MySQL:
$date->get('yyyy-MM-dd HH:mm:ss');