I have rows like so:
roll_no
---------
0690543
0005331
0760745
0005271
And I want string like this :
"0690543.pdf" "0005331.pdf" "0760745.pdf" "0005271.pdf"
I have tried concat but unable to do so
You can use an aggregate function like string_agg, after first mangling the quotes and the .pdf extension to your column data. Use a space as your delimiter:
SELECT string_agg('"'||roll_no||'.pdf "', ' ') from myTable
SqlFiddle here
Related
Say I have a varchar column let's say religions that looks like this: ["Christianity", "Buddhism", "Judaism"] (yes it has a bracket in the string) and I want the string (not array) split into multiple rows like "Christianity", "Buddhism", "Judaism" so it can be used in a WHERE clause.
Eventually I want to use the results of the query in a where clause like this:
SELECT ...
FROM religions
WHERE name in
(
<this subquery>
)
How can one do this?
You can use the function JSON_PARSE to convert the varchar string into an array. Then you can use the strategy described in Convert varchar array to rows in redshift - Stack Overflow to convert the array to separate rows.
You can do the following.
Create a temporary table with sequence of numbers
Using the sequence and split_part function available in redshift, you can split the values based on the numbers generated in the temporary table by doing a cross join.
To replace the double quote and square brackets, you can use the regexp_replace function in Redshift.
create temp table seq as
with recursive numbers(NUMBER) as
(
select 1 UNION ALL
select NUMBER + 1 from numbers where NUMBER < 28
)
select * from numbers;
select regexp_replace(split_part(val,',',seq.number),'[]["]','') as value
from
(select '["christianity","Buddhism","Judaism"]' as val) -- You can select the actual column from the table here.
cross join
seq
where seq.number <= regexp_count(val,'[,]')+1;
I have a VIEW like this:
SELECT * FROM test --will show:
path
------------------------
/downloads/abc-dbc-abcd
/downloads/dfg-gfd-hjkl
/downloads/tyu-iti-titk
How do I use TRIM to only select the trailing part of the strings in column path?
In PostgreSQL, I've tried:
SELECT TRIM('/downloads/' FROM (SELECT * FROM test);
SELECT TRIM('/downloads/' FROM (SELECT path FROM test);
I expect to receive the output strings as just 'abc-dbc-abcd', etc.; the same as input but with '/downloads/' removed. I have been getting an error...
ERROR: more than one row returned by a subquery used as an expression
Your error are because you are using SubQuery in your TRIM() function and it returned more than 1 row so the error show.
And I prefer you use REPLACE() rather than TRIM() function here. From Documentation REPLACE :
Replace all occurrences in string of substring from with substring to
For the query :
SELECT REPLACE(path, '/downloads/', '') from test;
You can see here for Demo
Try this.
SELECT LTRIM(RTRIM(REPLACE(path,'/downloads/','')))
I want to convert a column of type "character varying" that has integers with commas to a regular integer column.
I want to support numbers from '1' to '10,000,000'.
I've tried to use: to_number(fieldname, '999G999G999'), but it only works if the format matches the exact length of the string.
Is there a way to do this that supports from '1' to '10,000,000'?
select replace(fieldname,',','')::numeric ;
To do it the way you originally attempted, which is not advised:
select to_number( fieldname,
regexp_replace( replace(fieldname,',','G') , '[0-9]' ,'9','g')
);
The inner replace changes commas to G. The outer replace changes numbers to 9. This does not factor in decimal or negative numbers.
You can just strip out the commas with the REPLACE() function:
CREATE TABLE Foo
(
Test NUMERIC
);
insert into Foo VALUES (REPLACE('1,234,567', ',', '')::numeric);
select * from Foo; -- Will show 1234567
You can replace the commas by an empty string as suggested, or you could use to_number with the FM prefix, so the query would look like this:
SELECT to_number(my_column, 'FM99G999G999')
There are things to take note:
When using function REPLACE("fieldName", ',', '') on a table, if there are VIEW using the TABLE, that function will not work properly. You must drop the view to use it.
I am trying to combine rows and concatenate two columns (name, vorname) in a Postgres query.
This works good like this:
SELECT nummer,
array_to_string(array_agg(name|| ', ' ||vorname), '\n') as name
FROM (
SELECT DISTINCT
nummer, name, vorname
FROM myTable
) AS m
GROUP BY nummer
ORDER BY nummer;
Unfortunately, if "vorname" is empty I get no results although name has a value.
Is it possible get this working:
array_to_string(array_agg(name|| ', ' ||vorname), '\n') as name
also if one column is empty?
Use coalesce to convert NULL values to something that you can concatenate:
array_to_string(array_agg(name|| ', ' ||coalesce(vorname, '<missing>')), '\n')
Also, you can concatenate strings directly without collecting them to an array by using the string_agg function.
If you have 9.1, then you can use third parameter for array_to_string - null string
array_to_string(array_agg(name), ',', '<missing>') from bbb
I have a string value in a varchar column. It is a string that has two parts. Splitting it before it hits the database is not an option.
The column's values look like this:
one_column:
'part1 part2'
'part1 part2'
So what I want is a a result set that looks like:
col1,col2:
part1,part2
part1,part2
How can I do this in a SELECT statement? I found a pgsql function to split the string into an array but I do not know how to get it into two columns.
select split_part(one_column, ' ', 1) AS part1,
split_part(one_column, ' ', 2) AS part2 ...