This question already has answers here:
Split a String into an array in Swift?
(40 answers)
Closed 5 years ago.
I'm writing a app where I need to present the second name of a person on the screen.
The names are always "firstname space lastname" as in:
let str = "Fred Bloggs"
let secondStr = "William Wright"
Can you tell me how to get "Bloggs" out of that first string and "Wright" out of the second string, not knowing the index of Bloggs. All the examples I've seen seem to assume you know the index of the position you want to get a substring from.
Thanks.
import Foundation
let fullName = "First Last"
let fullNameArr = fullName.components(separatedBy: " ")
let name = fullNameArr[0]
let lastName = fullNameArr[1]
Related
This question already has answers here:
How to get the first character of each word in a string?
(11 answers)
Closed 1 year ago.
I have quick question about Swift algorithm, assuming I have a string “New Message” which option I need to use to get just initials NM ?
I would use map to get the first character of each word in the string, then use reduce to combine them.
let string = "New Message"
let individualWords = string.components(separatedBy: " ")
let firstCharacters = individualWords.map { $0.prefix(1) }.reduce("", +)
print("firstCharacters is \(firstCharacters)")
Result:
firstCharacters is NM
Edit: Per #LeoDabus' comment, joined is more concise than reduce("", +), and does the same thing.
let firstCharacters = individualWords.map { $0.prefix(1) }.joined()
This question already has answers here:
Any way to replace characters on Swift String?
(23 answers)
Closed 2 years ago.
my code is like the following:
let fileName = "/users/lezi/downloads/Zootopia.srt"
var srtFile = try? String(contentsOfFile: fileName)
let range = srtFile?.range(of: "00:00:59,825")
print(srtFile?[range!])
srtFile?.replaceSubrange(range!, with: "00:00:59,826")
print(srtFile?[range!])
I hope the "00:00:59,825" is replaced to "00:00:59,826", but the print is "Optional("\r\n\r\n2")\n", some characters just before "00:00:59,825"
Regardless of use case. The common syntax to replace the substring is:
str.replacingOccurrences(of: "replace_this", with: "with_this")
where replace_thisis the text string you want to replace and ```with_this`` is the new sub-string to insert.
You can try using replacingOccurrences(of:with:).
Returns a new string in which all occurrences of a target string in the receiver are replaced by another given string
sample example :
let str = "Swift 4.0 is the best version of Swift to learn, so if you're starting fresh you should definitely learn Swift 4.0."
let replaced = str.replacingOccurrences(of: "4.0", with: "5.0")
This question already has answers here:
How should I remove all the leading spaces from a string? - swift
(31 answers)
Closed 4 years ago.
i'm getting my contacts number locally from my mobile. There are some number in which there are white spaces between numbers. I'm trying to remove the white spaces from the number but it isn't working,this is how i'm removing the white spaces,
let number = contact.phoneNumbers.first?.value.stringValue
let formattedString = number?.replacingOccurrences(of: " ", with: "")
print(formattedString)
But when i print this is what i got in the console,
+92 324 4544783
The white sapces are still coming how can i remove that?
Here you go: source
For trimming white spaces from both ends, you can use:
let number = contact.phoneNumbers.first?.value.stringValue
let formattedString = number.trimmingCharacters(in: .whitespacesAndNewlines)
print(formattedString)
For removing whitespaces that might be inside the string, use:
let x = "+92 300 7681277"
let result = x.replacingOccurrences(of: " ", with: "")
You should get:
result = +923007681277
EDIT: I updated my answer.
let number = contact.phoneNumbers.first?.value.stringValue
let number_without_space = number.components(separatedBy: .whitespaces).joined()
print(number_without_space) //use this variable wherever you want to use
joined() is a function it will join your string after removing spaces like this
let str = "String Name"
str.components(separatedBy: .whitespaces).joined()
extension to remove spaces
extension String
{
func removeSpaces() -> String {
return components(separatedBy: .whitespaces).joined()
}
}
This question already has answers here:
Reversing the order of a string value
(13 answers)
Closed 5 years ago.
Needed to reverse a swift string, managed to do so with this.
var str = "Hello, playground"
let reactedText = str.characters.reversed()
let nowBackwards = Array(reactedText)
let answer = String(nowBackwards)
And since I find nothing on SO in the subject I post it for some positive votes :) or indeed a better [shorter, as in different] solution.
Assuming you are using Swift 4 :
let string = "Hello, playground"
let reversedString = String(string.reversed())
Since in Swift 4, Strings are Character arrays again, you can call reversed on the String itself and the result will be of type [Character], from which you can initialize a String.
let stringToBeReversed = "Hello, playground"
let reversedString = String(stringToBeReversed.reversed()) //"dnuorgyalp ,olleH"
reversed method is available in String library
let str = "Hello, world!"
let reversed = String(str.reversed())
print(reversed)
This question already has answers here:
Split a String into an array in Swift?
(40 answers)
Closed 6 years ago.
I want get value before symbol # or number in swift. I have email which is john#gmail.com. I want get john only. Another example is peter34#gmail.com. I want get peter only.
Use components(separatedBy:) passing it a CharacterSet composed of # and the digits, and then use first to get the first part of the symbol:
let emails = ["john#gmail.com", "peter34#gmail.com"]
for email in emails {
if let name = email.components(separatedBy: CharacterSet(charactersIn: ("#0123456789"))).first {
print(name)
}
}
Output:
john
peter
try this
let EMAIL= "peter34#gmail.com"
let EMAILARR= EMAIL.characters.split{$0 == "#"}.map(String.init)
EMAILARR[0] // to get peter34
EMAILARR[1] // to get gmail.com