I have the following Postres code:
SELECT
a.assessmentid,
b.groupid
FROM wo_assessment a
LEFT JOIN wo_group_info b ON a.assessmentid = b.assessmentid
WHERE a.workorderid=2
ORDER BY a.assessmentid
Which returns the following results:
|-------------------|------------|
| assessmentid | groupid |
|-------------------|------------|
| 5 | 5 |
|-------------------|------------|
| 6 | 4 |
|-------------------|------------|
| 7 | 0 |
|-------------------|------------|
| 8 | 5 |
|-------------------|------------|
| 9 | 0 |
|-------------------|------------|
| 10 | 0 |
|-------------------|------------|
I would like to populate the 0 values in the groupid field with the next number above in that column, that isn't 0.
So for example I want my table to look like this:
|-------------------|------------|
| assessmentid | groupid |
|-------------------|------------|
| 5 | 5 |
|-------------------|------------|
| 6 | 4 |
|-------------------|------------|
| 7 | 4 |
|-------------------|------------|
| 8 | 5 |
|-------------------|------------|
| 9 | 5 |
|-------------------|------------|
| 10 | 5 |
|-------------------|------------|
Here is what worked for me:
SELECT q.assessmentid,
first_value(b.groupid ) over (partition by value_partition order by q.assessmentid) FROM (
SELECT a.assessmentid,
b.groupid ,
sum(case when b.groupid is null then 0 else 1 end) over (order by a.assessmentid) as value_partition
FROM wo_assessment as a
LEFT JOIN wo_group_info b ON a.assessmentid = b.assessmentid
ORDER BY a.assessmentid ) as q
LEFT JOIN wo_group_info b ON q.assessmentid = b.assessmentid
Related
Having two tables (table1, table2) with the same column names (generation, parent), the desired output would be the combination of all columns of both tables. Thereby the rows of table2 should join table1 so that the rows of table2 are matching those of table1 on generation column. The parent number should be ordered ascending for the entries in table1 as well as in table2. The number of rows of the query results should be equal of those of table1.
Given the following tables
table1:
| generation | parent |
|:----------:|:------:|
| 0 | 1 |
| 0 | 2 |
| 0 | 3 |
| 1 | 3 |
| 1 | 2 |
| 1 | 1 |
| 2 | 2 |
| 2 | 1 |
| 2 | 3 |
table2:
| generation | parent |
|:----------:|:------:|
| 1 | 3 |
| 1 | 1 |
| 1 | 3 |
| 2 | 1 |
| 2 | 2 |
| 2 | 3 |
The following queries are thought for creating and populating two sample tables as shown above:
create table table1(generation integer, parent integer);
insert into table1 (generation, parent) values(0,1),(0,2),(0,3),(1,3),(1,2),(1,1),(2,2),(2,1),(2,3);
create table table2(generation integer, parent integer);
insert into table2 (generation, parent) values(1,3),(1,1),(1,3),(2,1),(2,2),(2,3);
the imagined query should lead to the following desired result:
| table1_generation | table1_parent | table2_generation | table2_parent |
|:-----------------:|:-------------:|:-----------------:|:-------------:|
| 0 | 1 | | |
| 0 | 2 | | |
| 0 | 3 | | |
| 1 | 1 | 1 | 1 |
| 1 | 2 | 1 | 3 |
| 1 | 3 | 1 | 3 |
| 2 | 1 | 2 | 1 |
| 2 | 2 | 2 | 2 |
| 2 | 3 | 2 | 3 |
Current query looks as follows:
with
p as (
select
generation,
parent
from
table1
order by
generation,
parent
), o as(
select
generation,
parent
from
table2
order by
generation,
parent
)
select
p.generation as table1_generation,
p.parent as table1_parent,
o.generation as table2_generation,
o.parent as table2_parent
from
p
left join o on
o.generation=p.generation;
Which leads to the following result:
| table1_generation | table1_parent | table2_generation | table2_parent |
|:-----------------:|:-------------:|:-----------------:|:-------------:|
| 0 | 1 | | |
| 0 | 2 | | |
| 0 | 3 | | |
| 1 | 1 | 1 | 1 |
| 1 | 1 | 1 | 3 |
| 1 | 1 | 1 | 3 |
| 1 | 2 | 1 | 1 |
| 1 | 2 | 1 | 3 |
| 1 | 2 | 1 | 3 |
| 1 | 3 | 1 | 1 |
| 1 | 3 | 1 | 3 |
| 1 | 3 | 1 | 3 |
| 2 | 1 | 2 | 1 |
| 2 | 1 | 2 | 2 |
| 2 | 1 | 2 | 3 |
| 2 | 2 | 2 | 1 |
| 2 | 2 | 2 | 2 |
| 2 | 2 | 2 | 3 |
| 2 | 3 | 2 | 1 |
| 2 | 3 | 2 | 2 |
| 2 | 3 | 2 | 3 |
This link led to the conclusion, that any join command might not what is necessary here ... But union does only append rows... so for me it is absolutely unclear, how the desired result can be achieved o.O
Any help is highly appreciated. Thanks in advance!
The main misunderstanding on this question arose from the fact that you mentioned join, which is a very precisely mathematically defined concept based on the Cartesian product and can be applied to any two sets. So the current output is clear.
But as you wrote in the title, you want to put two tables side by side. You take advantage of the fact that they have the same number of rows (triples).
This select returns the output you want.
I made artificial join columns, row_number() OVER (order by generation, parent) as rnum, and moved the second table using the addition of three. I hope this helps you:
with
p as (
select
row_number() OVER (order by generation, parent) as rnum,
generation,
parent
from
table1
order by
generation,
parent
), o as(
select
row_number() OVER (order by generation, parent) as rnum,
generation,
parent
from
table2
order by
generation,
parent
)
select
p.generation as table1_generation,
p.parent as table1_parent,
o.generation as table2_generation,
o.parent as table2_parent
from
p
left join o on
o.rnum+3=p.rnum
order by 1,2,3,4;
Output:
table1_generation
table1_parent
table2_generation
table2_parent
0
1
(null)
(null)
0
2
(null)
(null)
0
3
(null)
(null)
1
1
1
1
1
2
1
3
1
3
1
3
2
1
2
1
2
2
2
2
2
3
2
3
I have table AnalysisForm
a_id| a_description | medical_card_id
-------------------------
1 | Analysis1 | 5
2 | Analysis2 | 3
3 | Analysis3 | 2
4 | Analysis4 | 1
and table DicomForm
d_id| d_description | medical_card_id
-------------------------
1 | DicomForm1 | 5
2 | DicomForm2 | 3
3 | DicomForm3 | 2
4 | DicomForm4 | 1
Now I want to get info by medical_card_id = 5 like this
form_id| form_description | medical_card_id
-------------------------
1 | DicomForm1 | 5
1 | Analysis1 | 5
How can I make it in Postgres?
I actually think that you want a union query here, rather than a join:
SELECT a_id AS form_id, a_description AS form_description, medical_card_id
FROM AnalysisForm
WHERE medical_card_id = 5
UNION ALL
SELECT d_id, d_description, medical_card_id
FROM DicomForm
WHERE medical_card_id = 5;
I need to select first 2 lines where the store_name is different than one given for a given product
id | store_name | prod_name
----+------------+------
1 | 1 | A
2 | 1 | B
3 | 1 | C
4 | 1 | A
5 | 2 | E
6 | 2 | A
7 | 3 | G
8 | 2 | A
9 | 1 | A
10 | 3 | A
(10 rows)
result should be store_name <> 3 AND prod_name ='A'
id | store_name | prod_name
----+------------+------
1 | 1 | A
4 | 1 | A
6 | 2 | A
8 | 2 | A
Use the row_number() window function to accomplish this.
Query #1
with first_two as (
select *,
row_number() over (partition by store_name
order by id) as rn
from store_product
where store_name <> 3
and prod_name = 'A'
)
select id, store_name, prod_name
from first_two
where rn <= 2;
| id | store_name | prod_name |
| --- | ---------- | --------- |
| 1 | 1 | A |
| 4 | 1 | A |
| 6 | 2 | A |
| 8 | 2 | A |
View on DB Fiddle
I have two table table:
I. Table 1 like this:
------------------------------------------
codeid | pos | neg | category
-----------------------------------------
1 | 10 | 3 | begin2016
1 | 3 | 5 | justhere
3 | 7 | 7 | justthere
4 | 1 | 1 | else
4 | 12 | 0 | begin2015
4 | 5 | 12 | begin2013
1 | 2 | 50 | now
2 | 5 | 33 | now
5 | 33 | 0 | Begin2011
5 | 11 | 7 | begin2000
II. Table 2 like this:
------------------------------------------
codeid | codedesc | codegroupid
-----------------------------------------
1 | road runner | 1
2 | bike warrior | 2
3 | lazy driver | 4
4 | clever runner | 1
5 | worker | 3
6 | smarty | 1
7 | sweety | 3
8 | sweeper | 1
I want to have one result like this having two (or more) conditions:
sum pos and neg where codegroupid IN('1', '2', '3')
BUt do not sum pos and neg if category like 'begin%'
So the result will like this:
------------------------------------------
codeid | codedesc | sumpos | sumneg
-----------------------------------------
1 | roadrunner | 5 | 55 => (sumpos = 3+2, because 10 have category like 'begin%' so doesn't sum)
2 | bike warrior | 5 | 33
4 | clever runner | 1 | 1
5 | worker | 0 | 0 => (sumpos=sumneg=0) becase codeid 5 category ilike 'begin%'
Group by codeid, codedesc;
Sumpos is sum(pos) where category NOT ILIKE 'begin%', BUT IF category ILKIE 'begin%' make all pos values become zero (0);
Sumpos is sum(neg) where category NOT ILIKE 'begin%', BUT IF category ILKIE 'begin%' make all neg values become zero;
Any ideas how to do it?
Try:
SELECT
b.codeid,
b.codedesc,
sum(CASE WHEN category LIKE 'begin%' THEN 0 ELSE a.pos END) AS sumpos,
sum(CASE WHEN category LIKE 'begin%' THEN 0 ELSE a.neg END) AS sumneg
FROM
table1 AS a
JOIN
table2 AS b ON a.codeid = b.codeid
WHERE b.codegroupid IN (1, 2, 3)
GROUP BY
b.codeid,
b.codedesc;
I'm using SQL server 2008R2 and I have a view which returns the following:
+----+-------+-------+-------+-------+-------+-------+
| ID | col1A | col1B | col2A | col2B | col3A | col3B |
+----+-------+-------+-------+-------+-------+-------+
| 1 | 1 | 1 | 3 | 5 | 4 | 4 |
| 2 | 1 | 1 | 5 | 5 | 5 | 4 |
| 3 | 3 | 4 | 5 | 5 | 4 | 4 |
| 4 | 1 | 2 | 5 | 5 | 4 | 3 |
| 5 | 1 | 1 | 2 | 2 | 3 | 3 |
+----+-------+-------+-------+-------+-------+-------+
As you can see this view contains column pairs (col1A and col1B), (col2A and col2B), (col3A and col3B).
I need to query this view and find rows where the column pairs contain different values.
So I would be looking to return:
+----+------------+---+-----+
| ID | ColumnType | A | B |
+----+------------+---+-----+
| 1 | Col2 | 3 | 5 |
| 2 | Col3 | 5 | 4 |
| 3 | Col1 | 3 | 4 |
| 4 | Col1 | 1 | 2 |
| 4 | Col3 | 4 | 3 |
+----+------------+---+-----+
I think I need to use UNPIVOT but not sure how – appreciate any suggestions?
Since you are using SQL Server 2008+ you can use CROSS APPLY to unpivot the pair of columns and then you can easily compare the values in the A and B to return the rows that don't match:
select t.ID,
c.ColumnType,
c.A,
c.B
from [dbo].[yourview] t
cross apply
(
values
('Col1', Col1A, Col1B),
('Col2', Col2A, Col2B),
('Col3', Col3A, Col3B)
) c (ColumnType, A, B)
where c.A <> c.B;
If you have different datatypes in your columns, then you'll need to convert the data to the same type. You can do this conversion within the VALUES clause:
select t.ID,
c.ColumnType,
c.A,
c.B
from [dbo].[yourview] t
cross apply
(
values
('Col1', cast(Col1A as varchar(50)), Col1B),
('Col2', cast(Col2A as varchar(50)), Col2B),
('Col3', cast(Col3A as varchar(50)), Col3B)
) c (ColumnType, A, B)
where c.A <> c.B