find out min and max in python 3 - find

Question

5.2 Write a program that repeatedly prompts a user for integer numbers until the user enters 'done'. Once 'done' is entered, print out the largest and smallest of the numbers. If the user enters anything other than a valid number catch it with a try/except and put out an appropriate message and ignore the number. Enter 7, 2, bob, 10, and 4 and match the output below.
largest = None
smallest = None
while True:
num = input("Enter a number: ")
if num == "done":
break
print(num)
print("Maximum", largest)
and the output must be like this
Invalid input
Maximum is 10
Minimum is 2
somebody please help me with this????? enter image description here

Answer 1

I think this will do your work,
With simple if conditions
# Defining two variables to None.
largest = None
smallest = None
# starting an infinite loop
while True:
num = input("Enter a number: ")
# try block to capture ValueError
try:
if num == "done":
break
# assign the values of largest and smallest to num if its None ( on first iteration)
if largest is None:
largest = int(num)
if smallest is None:
smallest = int(num)
# changing the values of it greater or smaller
if int(num) > largest:
largest = int(num)
if int(num) < smallest:
smallest = int(num)
# capture the type error and ignores.
except ValueError:
print("ignored.")
continue
print("Maximum: " + str(largest))
print("Minimum: " + str(smallest))
By making use of list and it's methods
# Defining an empty list.
myList = []
# starting an infinite loop
while True:
num = input("Enter a number: ")
# try block to capture ValueError
try:
if num == "done":
break
# append the entered number to list if valid
myList.append(int(num))
# catches value error and ignores it
except ValueError:
print("ignored.")
continue
# prints maximum and min
if len(myList) > 0:
print("Maximum: " + str(max(myList)))
print("Minimum: " + str(min(myList)))
else:
print("List is empty")

Answer 2

largest = None
smallest = None
while True:
try:
num = input("Enter a number: ")
if num == "done":
break
num = int(num)
if largest is None or largest < num:
largest = num
elif smallest is None or smallest > num:
smallest = num
except ValueError:
print("Invalid input")
print ("Maximum is", largest)
print ("Minimum is", smallest)

Answer 3

largest = None
smallest = None
while True:
num = input("Enter a number: ")
if num == "done" :
break
try:
n = int(num)
except:
print ('Invalid input')
continue
if largest is None or n > largest:
largest = n
if smallest is None or n < smallest:
smallest = n
print("Maximum is", largest)
print("Minimum is", smallest)

Answer 4

#Print out largest and smallest number
largest=None
smallest=None
while True:
n = input('Enter a number: ')
if n == "done":
break
try:
num=int(n)
if largest is None:
largest = num
elif num > largest:
largest = num
if smallest is None:
smallest = num
elif num < smallest:
smallest = num
except:
print("Invalid input")
print('maximum:', largest)
print('Minimum:', smallest)