MongoDB get different sum for each list per document - mongodb

I have these documents in my collection
{
id:1,
small:[{k:'A',v:1},{k:'B',v:2},{k:'D',v:3}],
big:[{k:'A',v:2},{k:'B',v:3},{k:'C',v:1},{k:'D',v:4}]
},
{
id:2,
small:[{k:'A',v:1},{k:'B',v:2},{k:'D',v:3}],
big:[{k:'A',v:2},{k:'B',v:3},{k:'C',v:1},{k:'D',v:4}]
},
{
id:3,
small:[{k:'A',v:1},{k:'B',v:2},{k:'D',v:3}],
big:[{k:'A',v:2},{k:'B',v:3},{k:'C',v:1},{k:'D',v:4}]
}
Now, I want to get the sum for each key in both lists. I want my output to look like this:
{k:'A',small:3, big:6},
{k:'B',small:6, big:9},
{k:'D',small:9, big:12}
Notice that the output did not contain the key 'C'. This is because I only want to output the keys that are existing in the 'small' list. What mongodb functions
should I use for this?
Thanks!

Try below aggregation:
db.col.aggregate([
{ $unwind: "$small" },
{ $unwind: "$big" },
{ $redact: {
$cond: {
if: { $eq: [ "$small.k", "$big.k" ] },
then: "$$KEEP",
else: "$$PRUNE"
}
}
},
{
$group: { _id: "$small.k", small: { $sum: "$small.v" }, big: { $sum: "$big.v" } }
},
{
$sort: { "_id": 1 }
}
])
In general we need to have only one small and big in each document (that's why double $unwind). Then we want to keep only documents where keys are equal. That's the moment where C is filtered out - has no pair in small and we're utilizing $redact for that. Aggregation is just a $group with $sum.

Related

Calculating the sum of specific fields from a complex array object

I would like to migrate one of my FireBase projects to Mongo and move the calculations from server side to DB. I already wrote most of the queries but this one is beyond my knowledge.
Player data are saved by week and I need to calculate the sum of donations and points for each players (the rest of the fields should be ignored).
PS: Some of the players are already banned so it would be enough the calculate the fields for a given player set (like: tag in ['playerId1', 'playerId2', ...]). If it's too complex I will do this filtering later on server side.
[
{
"week":"2021-01",
"players":[
{
"donations":20,
"games":3,
"name":"Player1",
"points":258,
"tag":"playerId1"
},
{
"donations":37,
"games":5,
"name":"Player2",
"points":634,
"tag":"playerId2"
},
{ ... }
]
},
{
"week":"2021-02",
"players":[ { ... } ]
}
]
So the result should be something like this:
[
{
"name":"Player1",
"tag":"playerId1",
"donations":90,
"points":980
},
{
"name":"Player2",
"tag":"playerId2",
"donations":80,
"points":1211
}
]
I think the $unwind and the $group operators could be the key but I can't figure out how to use them properly here.
$unwind deconstruct players array
$group by name and get sum of donations and points and get first tag
$project to show required fields
db.collection.aggregate([
{ $unwind: "$players" },
{
$group: {
_id: "$players.name",
donations: { $sum: "$players.donations" },
points: { $sum: "$players.points" },
tag: { $first: "$players.tag" }
}
},
{
$project: {
_id: 0,
name: "$_id",
points: 1,
tag: 1,
donations: 1
}
}
])
Playground
PS: Some of the players are already banned so it would be enough the calculate the fields for a given player set (like: tag in ['playerId1', 'playerId2', ...]).
You can put match condition after $unwind stage,
{ $match: { "players.tag": { $in: ['playerId1', 'playerId2', ..more] } } }
You were right,
play
db.collection.aggregate([
{//Denormalize
"$unwind": "$players"
},
{//Group by name
"$group": {
"_id": "$players.name",
"donations": {
"$sum": "$players.donations"
},
"points": {
"$sum": "$players.points"
},
}
}
])
You can add project stage if you really need name as key than _id

MongoDB aggregation: How to get the index of a document in a collection depending sorted by a document property

Assume I have a collection with millions of documents. Below is a sample of how the documents look like
[
{ _id:"1a1", points:[2,3,5,6] },
{ _id:"1a2", points:[2,6] },
{ _id:"1a3", points:[3,5,6] },
{ _id:"1b1", points:[1,5,6] },
{ _id:"1c1", points:[5,6] },
// ... more documents
]
I want to query a document by _id and return a document that looks like below:
{
_id:"1a1",
totalPoints: 16,
rank: 29
}
I know I can query the whole document, sort by descending order then get the index of the document I want by _id and add one to get its rank. But I have worries about this method.
If the documents are in millions won't this be 'overdoing' it. Querying a whole collection just to get one document? Is there a way to achieve what I want to achieve without querying the whole collection? Or the whole collection has to be involved because of the ranking?
I cannot save them ranked because the points keep on changing. The actual code is more complex but the take away is that I cannot save them ranked.
Total points is the sum of the points in the points array. The rank is calculated by sorting all documents in descending order. The first document becomes rank 1 and so on.
an aggregation pipeline like the following can get the result you want. but how it operates on a collection of millions of documents remains to be seen.
db.collection.aggregate(
[
{
$group: {
_id: null,
docs: {
$push: { _id: '$_id', totalPoints: { $sum: '$points' } }
}
}
},
{
$unwind: '$docs'
},
{
$replaceWith: '$docs'
},
{
$sort: { totalPoints: -1 }
},
{
$group: {
_id: null,
docs: { $push: '$$ROOT' }
}
},
{
$set: {
docs: {
$map: {
input: {
$filter: {
input: '$docs',
as: 'x',
cond: { $eq: ['$$x._id', '1a3'] }
}
},
as: 'xx',
in: {
_id: '$$xx._id',
totalPoints: '$$xx.totalPoints',
rank: {
$add: [{ $indexOfArray: ['$docs._id', '1a3'] }, 1]
}
}
}
}
}
},
{
$unwind: '$docs'
},
{
$replaceWith: '$docs'
}
])

Mongodb comparing using a field with another field in an array of Objects

I have the below structure for my collection:
{
"price":123,
"totalPrices": [
{
"totPrice":123
}
]
}
I am trying to query for all the documents in my collection where price is not equals to totalPrice.totPrice (so above should not be returned).
But it keeps returning the documents which have equal prices as well (such as above sample).
This is the query I'm using:
{
$where : "this.price!== this.totalPrices.totPrice",
totalPrice:{$size:1}
}
What am I doing wrong :(
First, you need to match the size of the array totalPrices is equal to 1. Second, you need to unwind the totalPrices, since it's an array field. Last, you should match the equality of price and totalPrices.totPrice. Try the below code:
db.collection.aggregate([
{
$match: {
$expr: {
$eq: [
{
$size: "$totalPrices"
},
1
]
}
}
},
{
$unwind: "$totalPrices"
},
{
$match: {
$expr: {
$ne: [
"$price",
"$totalPrices.totPrice"
]
}
}
}
])
MongoPlayGroundLink

Mongodb calculation query--cummulative multiplication

I recently started working in Mongodb for POC. I have one json collection below
db.ccpsample.insertMany([
{
"ccp_id":1,
"period":601,
"sales":100.00
},
{
"ccp_id":1,
"period":602,
"growth":2.0,
"sales":"NULL" ##sales=100.00*(1+(2.0/100)) -- 100.00 comes from(ccp_id:1 and period=601)
},
{
"ccp_id":1,
"period":603,
"growth":3.0,
"sales":"NULL" ##sales=100.00*(1+(2.0/100))**(1+(3.0/100))-- 100.00 comes from(ccp_id:1 and period=601) 2.0 comes from (ccp_id:2 and period=602)
},
{
"ccp_id":2,
"period":601,
"sales":200.00
},
{
"ccp_id":2,
"period":602,
"growth":2.0,
"sales":"NULL" ##sales=200.00*(1+(2.0/100))
},
{
"ccp_id":2,
"period":603,
"growth":3.0,
"sales":"NULL" ##same like above
}
])
And i need to calculate sales field which has NULL by using above documents with matching conditions of ccp_id should same and period field should be equal to 601. I have added a line to demonstrate calculation of sales field in collection itself above. I tried with $graphlookup but no luck. Can you people kindly help or suggest some way?
You can use below aggregation:
db.ccpsample.aggregate([
{ $sort: { ccp_id: 1, period: 1 } },
{
$group: {
_id: "$ccp_id",
items: { $push: "$$ROOT" },
baseSale: { $first: "$sales" },
growths: { $push: "$growth" }
}
},
{
$unwind: {
path: "$items",
includeArrayIndex: "index"
}
},
{
$project: {
cpp_id: "$items.cpp_id",
period: "$items.period",
growth: "$items.growth",
sales: {
$cond: {
if: { $ne: [ "$items.sales", "NULL" ] },
then: "$items.sales",
else: {
$reduce: {
input: { $slice: [ "$growths", "$index" ] },
initialValue: "$baseSale",
in: { $multiply: [ "$$value", { $add: [1, { $divide: [ "$$this", 100 ] }] } ] }
}
}
}
}
}
}
])
Basically to calculate the value for n-th element you have to know following things:
sales value of first element ($first in $group)
the array of all growths ($push in $group)
the n which indicates how many multiplications you have to perform
To calculate the index you should $push all elements into one array and then use $unwind with includeArrayIndex option which will insert the index of unwinded array to field index.
Last step calculates the cumulative multiplication. It uses $slice with index field to evaluate how many growths should be processed. So there will be one element for 601, two elements for 602 and so on.
Then it's time for $reduce to process that array and perform the multiplications based on your formula: (1 + (growth/100))

Best usage for MongoDB Aggregate request

I would like to highlight a list of _id documents (with a limit) ranked in descending order (via their timestamp) based on a list of ObjectId.
Corresponding to this:
db.collection.aggregate( [ { $match: { _id: { $in: [ObjectId("X"), ObjectId("Y") ] } } }, { $sort: { timestamp: -1 } }, { $group: { _id: "$_id" } }, { $skip: 0 }, { $limit: 100 } ] )
Knowing that the list from the loop may contain way more than 1000 ObjectId (in $in array), do you think my solution is viable? Is not there a faster and less resource intensive way?
Best Regards.