Would you be able to advise how can i change the format of the date the functions isbusday and busdate are using ?
The functions use US date format by default, but I need them to be in European format dd/mm/yyyy.
I have attempted to use the code below but it is not working.
isbusday('01-01-2015','dd-mm-yyyy')
busdate('01-01-2015','dd-mm-yyyy',1)
Thank you very much.
You want to convert your string to a datetime object. That is where you can control the format:
d = datetime('01-01-2015','InputFormat','dd-mm-yyyy');
isbusday(d)
busdate(t)
See the documentation: https://www.mathworks.com/help/matlab/ref/datetime.html and https://www.mathworks.com/help/finance/isbusday.html
Related
I am retrieving a date from a database in the following format:
vardate = '01/20/2017 09:20:35' - mm/dd/yyyy hh:mm:ss
I want to convert it to the format dd-mm-yyyy hh:mm:ss
Can I get some guidance on how I could get the format I want?
Date formatting in Lua is pretty simplistic. If you only need to convert it from one format to another, and that format does not change, you could simply use string.match:
function convertDate(vardate)
local d,m,y,h,i,s = string.match(vardate, '(%d+)/(%d+)/(%d+) (%d+):(%d+):(%d+)')
return string.format('%s/%s/%s %s:%s:%s', y,m,d,h,i,s)
end
-- Call it this way
convertDate('01/20/2017 09:20:35')
If you need something more involved, I suggest using an external library.
function ConvertDate(date)
return (date:gsub('(%d+)/(%d+)/(%d+) (%d+:%d+:%d+)','%2-%1-%3 %4'))
end
-- test
print(ConvertDate('01/20/2017 09:20:35'))
I have been looking at the above question and have most of it correct.
I am going to get a datetime in Zulu, and then will want to output that format.
My first go is just as simple as:
DateFormat format = new DateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
My issue I am having is the T and Z. Obviously T is used to separate the date from the time and the Z is representative of Zulu time.
That being said the users will be entering a datetime in Zulu, so it wont need to be converted from Local to Zulu, so i was not sure if 'Z' is an acceptable result. I was not sure if there is a different want to handle this, or if my result was the best answer.
Try this package, Jiffy.
String isoFomart = Jiffy().format(); // This will return ISO format from now
You can also add your DateTime object
String isoFomart = Jiffy(DateTime.now()).format(); // This will also return ISO format from now
Hope this helped
The DateTime object has a method called: toIso8601String which is used to return an ISO formatted string. The 'Z' will be added if isUTC is true, otherwise the result will not have the Z in it.
Make sure that the DateTime object itself is correctly set to UTC as if you look in the constructor for the class will tell you a lot of the defaults are local with the exception of the DateTime.utc() static function.
In that concept, you dont really need a DateFormat use to define an iso string.
I am facing an issue with Talend dates. I have tried several solutions but still an "unparseable date" error persists.
My date format is of the form : "2006-05-27 17:00:00.000"
Can you help me ?
you can use below talendDate function to parse your string into date..
TalendDate.parseDate("yyyy-MM-dd HH:mm:ss.sss","2006-05-27 17:00:00.000")
this would take input as string and return you date.
If you don't handle the conversion yourself in a tMap but just want to use a schema, then: In your mapping configuration in the date field, you can add the following string:
yyyy-MM-dd HH:mm:ss.SSS
to set the correct format mapping for the date string. Otherwise the answer of garpitmzn is the way to go.
you should use this function in talend to fetch date:
TalendDate.parseDate("yyyy-MM-dd HH:mm:ss.SSS","2016-01-12 12:45:00.000")
I have a date string in the format "2013-01-31T10:10:05.000Z". I want to convert this string to a Date object in extjs.
I have tried to use Ext.Date.parse("2013-01-31T10:10:05.000Z","Y-m-dTH:i:s.uZ"). But it is returning undefined.
I also tried with new Date("2013-01-31T10:10:05.000Z"), but it is also returning undefined.
Note: I have tried in IE8 browser.
Could anyone please help me to convert the above date string to Date object?
Thanks a lot sra. Now I am getting the result as ...UTC+5:30... Is there any way to convert this in IST format?
Try Ext.Date.parse("2013-01-31T10:10:05.000Z","c");
The c is the format type for ISO 8601 formatted dates
See the Ext.Date API for more details on this or other available formats
That's because 'T' and 'Z' are special characters in the Date format: http://docs.sencha.com/extjs/4.2.1/#!/api/Ext.Date
You have to escape them like this: Ext.Date.parse("2013-01-31T10:10:05.000Z","Y-m-d\\TH:i:s.u\\Z")
the user enters date in mm-dd-yy format. I have to convert this into ('YYYY-MM-DD"T"HH24:MI:SS) how can i do this in vb.net
Thanks
use DateTime Parse or ParseExact methods (or their Try... variation)
then ToString with your format string the resulting value if it is valid, otherwise tell user to enter a better value.
I don't actually speak VBian so I can't provide sample code.