I'd like to setup a countif function that counts the cells in a range based on the cell string length.
I've tried inserting the formula as an argument to the countif function, but I can't get it to work.
I wanted to compare the length for each cell in the range with a specific lenght defined somewhere else, but I don't know how to reference back the cell in the range.
One of my failed attempts was =COUNTIF($'Delovni list1'.$D$3:$D$102;">2")
given that the cells in the range are formatted as text. But the above doesn't even work if there are numbers in the cells.
My use case is this: I need to count the cells with 1 specific letter and cells which have many characters.
Thank you.
seba
I found this to work:
=COUNTIF($'Delovni list1'.$D$3:$D$102;"[:alnum:]..*")
regards,
seba
Related
I have a large google spreadsheet that predicts events based on dates of other events based on simple formula e.g.
=ArrayFormula(K2:K)+5
I simply want the cell to which the formula applies to stay blank if there is no input in the reference cell
I have tried
=If((ArrayFormula(K2:K)+5)> 4/1/1900, ArrayFormula(K2:K)+5, " ")
but I still get 04/01/1900 displayed in the cells. I try to edit the formula to add the "0" in the month of the date in the formula, but it deletes it and the formula then does not work.
Any help greatly appreciated.
Clear the entire column L in which you want to apply the ARRAYFORMULA, then enter in cell L2:
=ARRAYFORMULA(IF(ISBLANK(K2:K),"",K2:K+5))
If the values come up numbers, then format column L as dates.
Sample:
use:
=ARRAYFORMULA(IF((K2:K+5)>"4/1/1900", (K2:K+5), ))
I am very new to MATLAB. I am sorry if my question is basic. I am using "printmat" function to show some matrices in the command console. For example, printmat(A) and printmat(B), where A = 2.79 and B = 0.45e-7 is a scalar (for the sake of simplicity).
How do I increase the precision arbitrarily to seven decimals? For example: my output looks like 2.7943234 and B = 0.00000004563432.
How do I add a currency (say dollar) figure to the output of printmat?
How do I add a percentage figure (%) to the output of printmat?
Note: The reason I use printmat is that I can name my rows and columns. If you know a better function that can do all above, I would be glad to know.
Regards Mariam. From what I understand, you would like to display the numbers and show their full precision. I am also newbie, If I may contribute, you could convert the number data to string data (for display purposes) by using the sprintf function.
I am using the variable A=2.7943234 as example. This value will not display the full precision, instead it will display 2.7943. To show all the decimal tails, you could first convert this to string by
a = sprintf('%0.8f',A);
It will set the value a to a string '2.79432340'. The %0.8f means you want it to display 8 decimal tails. For this example,%0.7f is sufficient of course.
Another example: A=0.00000004563432, use %0.14f.
A=0.00000004563432;
a=sprintf('%0.14f $ or %%',A);
the output should be : '0.00000004563432 $ or %'.
You could analyze further in https://www.mathworks.com/help/matlab/ref/sprintf.html
You could try this first. If this does not help to reach your objective, I appreciate some inputs. Thanks.
The printmat function is very obsolete now. I think table objects are its intended successor (and functions such as array2table to convert a matrix to a table of data). Tables allow you to add row and column names and format the columns in different ways. I don't think there's a way to add $ or % to each number, but you can specify the units of each column.
In general, you can also format the display precision using format. Something like this may be what you want:
format long
I am trying to add two zero place holders in front of a field without changing the actual values involved. The field is an order number that is being pulled from MOMs. So right now that fields' formula is {cms.ORDERNO}.
When I try '00'+{cms.ORDERNO} the field displays 001,254.00. How can I remove the decimals and comma so it displays 001254?
The usual trick is to pad with plenty of extra digits on the left and then only take the six you really want from the right. This would handle any order number ranging from 1 to 999999.
right("000000" + totext({cms.ORDERNO}, "0"), 6)
When you don't specify a format string, as you tried, it uses default settings which usually come from Windows. By the way, if I recall correctly cstr() and totext() are equivalent for the most part but totext() has more options.
You should also be able to specify "000000" as the format string to produce the left-padded zeroes. Sadly I don't have Crystal Reports installed or I'd check it out for you to be sure. If this is the case then you probably don't need a formula if you just want to use the formatting options for the field on the canvas. If you do use a formula it's still simple.
totext({cms.ORDERNO}, "000000")
You definitely want to use the Replace formula a few times for this. The formula below converts ORDERNO into string, removes any commas and trailing decimal places, then adds the two zeroes at the beginning:
`00` + REPLACE(REPLACE(CSTR({cms.ORDERNO}),".00",""),",","")
So for example, if cms.ORDERNO is 1,254.00 the output from this formula would be 001254
I know this is older, but better solutions exists and I ran across this same issue. ToText has what you need built right in.
"00" + ToText({cms.ORDERNO}, 0, "")
From the Crystal Documentation:
ToText (x, y, z)
x is a Number or Currency value to be converted into a text string; it
can be a whole or fractional value.
y is a whole number indicating the number of decimal places to carry
the value in x to (This argument is optional.).
z is a single character text string indicating the character to be
used to separate thousands in x. Default is the character specified in
your International or Regional settings control panel. (This argument
is optional.)
I have followed many posts about format of numbers in Matlab. Now I have set up Matlab uitable in such a way that one can fill the table cell by cell. I want the first column to maintain numbers up to say 12 digits, so I set the format to longG. Matlab uitable is refusing to accept my format and the frustrating part is, in the command window all digits are shown even up to 15 digits with format longG option. This is the sample;
colNam={'W','X','Y','Z'};
t=uitable('ColumnName',colNam,'Data',zeros(4),'ColumnEditable',...
[true true true true],'ColumnWidth',{150,'auto'},...
'ColumnFormat',{'numeric'});
set(t,'ColumnFormat',{'longG'});
I know of sprintf and fprintf as has been explained elsewhere. But please what we are refusing to realize is that, these change the class of the number from double to char. What if you want to set up the table so that it increases by 1 dynamically (credits to thewaywewalk)? We can't add double to char for this purpose. Please this is frustrating. Any suggestions? Thank you.
There is no such ColumnFormat property called "longG", where dis you see that ?
You have the possibility of manipulating the Java part of the Uitable in order to really display numeric values... but I think the best (and easiest) way is to use char.
If you want to increase the values, just convert it first to numeric, increase, then convert it back.
Based on John's suggestion, I put up this code and I could set the table to accept any number of digits.
f=figure;
dat=[101100220001;101100220002;101100220003;101100220004;101100220005];
colNam={'W'};
t=uitable('ColumnName',colNam,'Data',dat,'ColumnEditable',...
[true],'ColumnWidth',{150},'pos',[5 250 200 120]);
newdat=get(t,'Data');
newdat=strtrim(cellstr(num2str(newdat))); %Convert data to cell array of strings
tt=uitable('ColumnName',colNam,'Data',newdat,'pos',[300 250 200 120]);
i've got a cell array full of numbers, with 44 rows and different column length in each row
how could i calculate the number of columns in each row?(the columns which their contents are not empty)
i've used 2 different ways which both of them where wrong
the 1st one:
%a is the cell array
s=length(a)
it gives 44 which is the number of rows
the 2nd one
[row, columms]=size(a)
but it doesn't work either cause the number of columns is different in each row.
at least i mean the number of columns which are not empty
for example i need the number of columns in row one which it is 43(a{1 1:43}) but it gives the number of columns for each elements like a{1,1} which is 384 or a{1,2},a{1,3} and so on
You need to access each member of the cell array separately, you are looking for the size of the data contained in the cell - the cell is the container. Two methods
for loop:
cell_content_lengths=zeros(1,length(a));
for v=1:length(a)
cell_content_lengths(v)=length(a{v});
end
cellfun:
cell_content_lengths=cellfun(#length,a);
Any empty cells will just have length 0. To extend the for-loop to matrices is trivial, and you can extend the cellfun part to cells containing matrix by using something like this, if you are interested:
cell_content_sizes=cell2mat(cellfun(#length,a,'uniformoutput',false));
(Note for the above, each element of a needs to have the same dimension, otherwise it will give errors about concatenating different size matrices)
EDIT
Based on your comment I think I understand what you are looking for:
non_empty_cols = sum(~cellfun(#isempty,a),2);
With thanks to #MZimmerman6 who understood it before me.
So what you're really asking, is "How many non-empty elements are in each row of my cell array?"
filledCells = ~cellfun(#isempty,a);
columns = sum(filledCells,2);