I know this is probably to be a stupid question. I have the following code:
from pyspark.sql import SparkSession
rows = [1,2,3]
df = SparkSession.createDataFrame(rows)
df.printSchema()
df.show()
But I got an error:
createDataFrame() missing 1 required positional argument: 'data'
I don't understand why this happens because I already supplied 'data', which is the variable rows.
Thanks
You have to create SparkSession instance using the build pattern and use it for creating dataframe, check
https://spark.apache.org/docs/2.2.1/api/python/pyspark.sql.html#pyspark.sql.SparkSession
spark= SparkSession.builder.getOrCreate()
Below are the steps to create pyspark dataframe using createDataFrame
Create sparksession
spark = SparkSession.builder.appName('SparkByExamples.com').getOrCreate()
Create data and columns
columns = ["language","users_count"]
data = [("Java", "20000"), ("Python", "100000"), ("Scala", "3000")]
Creating DataFrame from RDD
rdd = spark.sparkContext.parallelize(data)
df= spark.createDataFrame(rdd).toDF(*columns)
the second approach, Directly creating dataframe
df2 = spark.createDataFrame(data).toDF(*columns)
Try
row = [(1,), (2,), (3,)]
?
If I am not wrong createDataFrame() takes 2 lists as input: first list is the data and second list is the column names. The data must be a lists of list of tuples, where each tuple is a row of the dataframe.
Related
I am stuck in a problem where I wanna do PCA on a Pyspark Dataframe column. The name of the column is ‘features’ where each row is a SparseVector.
This is the flow:
Df - name of the pyspark df
Features - name of column
Snippet of the rdd
[Row(features=SparseVector(2,{1:50.0})),
Row(features=SparseVector(2,{0:654.0, 1:20.0}))],
from pyspark.mllib.linalg.distributed import RowMatrix
i = RowMatrix(df.select(‘features’).rdd)
ipc = i.computePrincipalComponents(2)
Error Message
You are getting an RDD[Row] object where your Row is Row(features=SparseVector(2,{1:50.0})).
You need an RDD[SparseVector], so you should change your line:
i = RowMatrix(df.select(‘features’).rdd)
to
i = RowMatrix(df.select(‘features’).rdd.map(lambda x: x[0]))
which will return RDD[SparseVector]
I have a dataframe with headers for example outputDF. I now want to take outputDF.columns and create a new dataframe with just one row which contains column names.
I then want to union both these dataframes with option("head=false") which spark can then write to a HDFS.
How do i do that?
below is an example
Val df = spark.read.csv("path")
val newDf = df.columns.toSeq.toDF
val unoindf= df.union(newDf);
I'm trying to do a count in scala with dataframe. My data has 3 columns and I've already loaded the data and split by tab. So I want to do something like this:
val file = file.map(line=>line.split("\t"))
val x = file1.map(line=>(line(0), line(2).toInt)).reduceByKey(_+_,1)
I want to put the data in dataframe, and having some trouble on the syntax
val file = file.map(line=>line.split("\t")).toDF
val file.groupby(line(0))
.count()
Can someone help check if this is correct?
spark needs to know the schema of the df
there are many ways to specify the schema, here is one option:
val df = file
.map(line=>line.split("\t"))
.map(l => (l(0), l(1).toInt)) //at this point spark knows the number of columns and their types
.toDF("a", "b") //give the columns names for ease of use
df
.groupby('a)
.count()
I am reading 2 different .csv files which has only column as below:
val dF1 = sqlContext.read.csv("some.csv").select($"ID")
val dF2 = sqlContext.read.csv("other.csv").select($"PID")
trying to search if dF2("PID") exists in dF1("ID"):
val getIdUdf = udf((x:String)=>{dF1.collect().map(_(0)).toList.contains(x)})
val dfFinal = dF2.withColumn("hasId", getIdUdf($"PID"))
This gives me null pointer exception.
but if I convert dF1 outside and use list in udf it works:
val dF1 = sqlContext.read.csv("some.csv").select($"ID").collect().map(_(0)).toList
val getIdUdf = udf((x:String)=>{dF1.contains(x)})
val dfFinal = dF2.withColumn("hasId", getIdUdf($"PID"))
I know I can use join to get this done but want to know what is the reason of null pointer exception here.
Thanks.
Please check this question about accessing dataframe inside the transformation of another dataframe. This is exactly what you are doing with your UDF, and this is not possible in spark. Solution is either to use join, or collect outside of transformation and broadcast.
I have an empty dataframe with schema already created.
I'm trying to add the columns to this dataframe from a new dataframe to the existing columns in a for loop.
k schema - |ID|DATE|REPORTID|SUBMITTEDDATE|
for(data <- 0 to range-1){
val c = df2.select(substring(col("value"), str(data)._2, str(data)._3).alias(str(data)._1)).toDF()
//c.show()
k = c.withColumn(str(data)._1, c(str(data)._1))
}
k.show()
But the k dataframe has just one column, but it should have all the 4 columns populated with values.
I think the last line in for loop is replacing exisitng columns in the dataframe.
Can somebody help me with this?
Thanks!!
Add your logic and conditions and create new dataframe
val dataframe2 = dataframe1.select("A","B",C)
Copying few columns of a dataframe to another one is not possible in spark.
Although there are few alternatives to attain the same
1. You need to join both the dataframe based on some join condition.
2. Convert bot the data frame to json and do RDD Union
val rdd = df1.toJSON.union(df2.toJSON)
val dfFinal = spark.read.json(rdd)