MongoDB: How to get add filter main collection by second collection using $lookup [duplicate] - mongodb

Question

How can I add a filter after an $lookup or is there any other method to do this?
My data collection test is:
{ "_id" : ObjectId("570557d4094a4514fc1291d6"), "id" : 100, "value" : "0", "contain" : [ ] }
{ "_id" : ObjectId("570557d4094a4514fc1291d7"), "id" : 110, "value" : "1", "contain" : [ 100 ] }
{ "_id" : ObjectId("570557d4094a4514fc1291d8"), "id" : 120, "value" : "1", "contain" : [ 100 ] }
{ "_id" : ObjectId("570557d4094a4514fc1291d9"), "id" : 121, "value" : "2", "contain" : [ 100, 120 ] }
I select id 100 and aggregate the childs:
db.test.aggregate([ {
$match : {
id: 100
}
}, {
$lookup : {
from : "test",
localField : "id",
foreignField : "contain",
as : "childs"
}
}]);
I get back:
{
"_id":ObjectId("570557d4094a4514fc1291d6"),
"id":100,
"value":"0",
"contain":[ ],
"childs":[ {
"_id":ObjectId("570557d4094a4514fc1291d7"),
"id":110,
"value":"1",
"contain":[ 100 ]
},
{
"_id":ObjectId("570557d4094a4514fc1291d8"),
"id":120,
"value":"1",
"contain":[ 100 ]
},
{
"_id":ObjectId("570557d4094a4514fc1291d9"),
"id":121,
"value":"2",
"contain":[ 100, 120 ]
}
]
}
But I want only childs that match with "value: 1"
At the end I expect this result:
{
"_id":ObjectId("570557d4094a4514fc1291d6"),
"id":100,
"value":"0",
"contain":[ ],
"childs":[ {
"_id":ObjectId("570557d4094a4514fc1291d7"),
"id":110,
"value":"1",
"contain":[ 100 ]
},
{
"_id":ObjectId("570557d4094a4514fc1291d8"),
"id":120,
"value":"1",
"contain":[ 100 ]
}
]
}

Answer 1

The question here is actually about something different and does not need $lookup at all. But for anyone arriving here purely from the title of "filtering after $lookup" then these are the techniques for you:
MongoDB 3.6 - Sub-pipeline
db.test.aggregate([
{ "$match": { "id": 100 } },
{ "$lookup": {
"from": "test",
"let": { "id": "$id" },
"pipeline": [
{ "$match": {
"value": "1",
"$expr": { "$in": [ "$$id", "$contain" ] }
}}
],
"as": "childs"
}}
])
Earlier - $lookup + $unwind + $match coalescence
db.test.aggregate([
{ "$match": { "id": 100 } },
{ "$lookup": {
"from": "test",
"localField": "id",
"foreignField": "contain",
"as": "childs"
}},
{ "$unwind": "$childs" },
{ "$match": { "childs.value": "1" } },
{ "$group": {
"_id": "$_id",
"id": { "$first": "$id" },
"value": { "$first": "$value" },
"contain": { "$first": "$contain" },
"childs": { "$push": "$childs" }
}}
])
If you question why would you $unwind as opposed to using $filter on the array, then read Aggregate $lookup Total size of documents in matching pipeline exceeds maximum document size for all the detail on why this is generally necessary and far more optimal.
For releases of MongoDB 3.6 and onwards, then the more expressive "sub-pipeline" is generally what you want to "filter" the results of the foreign collection before anything gets returned into the array at all.
Back to the answer though which actually describes why the question asked needs "no join" at all....
Original
Using $lookup like this is not the most "efficient" way to do what you want here. But more on this later.
As a basic concept, just use $filter on the resulting array:
db.test.aggregate([
{ "$match": { "id": 100 } },
{ "$lookup": {
"from": "test",
"localField": "id",
"foreignField": "contain",
"as": "childs"
}},
{ "$project": {
"id": 1,
"value": 1,
"contain": 1,
"childs": {
"$filter": {
"input": "$childs",
"as": "child",
"cond": { "$eq": [ "$$child.value", "1" ] }
}
}
}}
]);
Or use $redact instead:
db.test.aggregate([
{ "$match": { "id": 100 } },
{ "$lookup": {
"from": "test",
"localField": "id",
"foreignField": "contain",
"as": "childs"
}},
{ "$redact": {
"$cond": {
"if": {
"$or": [
{ "$eq": [ "$value", "0" ] },
{ "$eq": [ "$value", "1" ] }
]
},
"then": "$$DESCEND",
"else": "$$PRUNE"
}
}}
]);
Both get the same result:
{
"_id":ObjectId("570557d4094a4514fc1291d6"),
"id":100,
"value":"0",
"contain":[ ],
"childs":[ {
"_id":ObjectId("570557d4094a4514fc1291d7"),
"id":110,
"value":"1",
"contain":[ 100 ]
},
{
"_id":ObjectId("570557d4094a4514fc1291d8"),
"id":120,
"value":"1",
"contain":[ 100 ]
}
]
}
Bottom line is that $lookup itself cannot "yet" query to only select certain data. So all "filtering" needs to happen after the $lookup
But really for this type of "self join" you are better off not using $lookup at all and avoiding the overhead of an additional read and "hash-merge" entirely. Just fetch the related items and $group instead:
db.test.aggregate([
{ "$match": {
"$or": [
{ "id": 100 },
{ "contain.0": 100, "value": "1" }
]
}},
{ "$group": {
"_id": {
"$cond": {
"if": { "$eq": [ "$value", "0" ] },
"then": "$id",
"else": { "$arrayElemAt": [ "$contain", 0 ] }
}
},
"value": { "$first": { "$literal": "0"} },
"childs": {
"$push": {
"$cond": {
"if": { "$ne": [ "$value", "0" ] },
"then": "$$ROOT",
"else": null
}
}
}
}},
{ "$project": {
"value": 1,
"childs": {
"$filter": {
"input": "$childs",
"as": "child",
"cond": { "$ne": [ "$$child", null ] }
}
}
}}
])
Which only comes out a little different because I deliberately removed the extraneous fields. Add them in yourself if you really want to:
{
"_id" : 100,
"value" : "0",
"childs" : [
{
"_id" : ObjectId("570557d4094a4514fc1291d7"),
"id" : 110,
"value" : "1",
"contain" : [ 100 ]
},
{
"_id" : ObjectId("570557d4094a4514fc1291d8"),
"id" : 120,
"value" : "1",
"contain" : [ 100 ]
}
]
}
So the only real issue here is "filtering" any null result from the array, created when the current document was the parent in processing items to $push.
What you also seem to be missing here is that the result you are looking for does not need aggregation or "sub-queries" at all. The structure that you have concluded or possibly found elsewhere is "designed" so that you can get a "node" and all of it's "children" in a single query request.
That means just the "query" is all that is really needed, and the data collection ( which is all that is happening since no content is really being "reduced" ) is just a function of iterating the cursor result:
var result = {};
db.test.find({
"$or": [
{ "id": 100 },
{ "contain.0": 100, "value": "1" }
]
}).sort({ "contain.0": 1 }).forEach(function(doc) {
if ( doc.id == 100 ) {
result = doc;
result.childs = []
} else {
result.childs.push(doc)
}
})
printjson(result);
This does exactly the same thing:
{
"_id" : ObjectId("570557d4094a4514fc1291d6"),
"id" : 100,
"value" : "0",
"contain" : [ ],
"childs" : [
{
"_id" : ObjectId("570557d4094a4514fc1291d7"),
"id" : 110,
"value" : "1",
"contain" : [
100
]
},
{
"_id" : ObjectId("570557d4094a4514fc1291d8"),
"id" : 120,
"value" : "1",
"contain" : [
100
]
}
]
}
And serves as proof that all you really need to do here is issue the "single" query to select both the parent and children. The returned data is just the same, and all you are doing on either server or client is "massaging" into another collected format.
This is one of those cases where you can get "caught up" in thinking of how you did things in a "relational" database, and not realize that since the way the data is stored has "changed", you no longer need to use the same approach.
That is exactly what the point of the documentation example "Model Tree Structures with Child References" in it's structure, where it makes it easy to select parents and children within one query.