Found something weird with the find command on AIX 7.1. I executed find command to list files of specific permissions. It works when I execute as below
find . -type f -perm 600 -exec ls -la {} \;
But fails to pull the files when I execute as below
find /user -type f -perm 600 -exec ls -la {} \;
Is anyone familiar with this kind of error?
Thanks,
Related
Is there a way to change perms only on files/folders not on those perms already?
Say, if executing find . -type f -exec chmod 0640 {} \; on a file that is already in 0640, skip it and don't overwrite.
I'm syncing (trough lsyncd) files from one to many hosts and when executing that command, ALL files are modified and so, all files are also synced. Thanks.
The correct and fastest way is
find . -type f ! -perm 644 -exec chmod 644 {} \;
I am trying to copy a folder containing a subfolder structure, while excluding a specified subfolder by using the find -exec cp command. I have managed to use multiple working excluding options when I am using the find command alone, but once I add the '-exec cp' command, the excluding terms work no longer.
Imagine the directory of interest containing multiple files and subfolders, with one subfolder named "exclusion_string"
This find command works properly when used alone:
find ~/directory/of/interest/ -maxdepth 2 ! -name "*exclusion_string*"
... while this command negates the exclusion criterium:
find ~/directory/of/interest/ -maxdepth 2 ! -name "*exclusion_string*" -exec cp -r '{}' . \;
Likewise, when using other criteria or arguments, the exclusion of a subdirectory is lost, E.g:
find ~/directory/of/interest/ -maxdepth 2 -name "*" -size -100k -exec cp -r '{}' . \;
find ~/directory/of/interest/ -maxdepth 2 -name "*exclusion_string*" | xargs cp -rt .
What am I missing here?
Kind of new to Perl, still navigating my way through.
Is there another way to write the bash command below in "Perl"?
find $INPUT_DIR -ctime -$DAYS_NUM -type f -exec grep -hs EDI_DC {} \; |
grep -i -v xml >> $OUTPUT_DIR/$OUTPUT_FILENAME
where INPUT_DIR, DAYS_NUM, OUTPUT_DIR and OUTPUT_FILENAME are arguments passed during runtime.
When you try to convert find command to perl, consider using find2perl script.
It generate the perl code.
find2perl 'INPUT_DIR' -ctime -'DAYS_NUM' -type f -exec grep -hs EDI_DC {} \;
So I have a find command as below which finds the libclntsh.so.* files in a directory instantclient.
find instantclient -type f -name "*libclntsh\.so\.[0-9]*\.[0-9]*"
This results in for e.g.,
instantclient/libclntsh.so.11.1
How do I now ln within instantclient directory, ln -s libclntsh.so.11.1 libclntsh.so all with a find command in combination with exec
I should mention here that I DO NOT want to cd into instantclient.
And this is for Alpine Linux.
Use the -execdir option. As per manual:
-execdir command {} ;
Like -exec, but the specified command is run from the subdirectory containing the matched file, which is not normally the directory in which you started find. This a much more secure method for invoking commands, as it avoids race conditions during resolution of the paths to the matched files.
So your command will be:
find instantclient -type f -name "*libclntsh\.so\.[0-9]*\.[0-9]*" -execdir ln -s {} libclntsh.so \;
EDIT:
Another solution
find instantclient -type f -name "*libclntsh\.so\.[0-9]*\.[0-9]*" | xargs -I {} sh -c 'ln -s $(basename {}) instantclient/libclntsh.so'
As specified in title I am looking for a way how to create links to all subfolders containing specified text in their names, so for example for all subfolders of root directory containing ".app" in their names an link will be created to "/AppLinks" directory. I would like to use it in bash script (open source, free).
Does anyone know how to do that?
I searched it by google with no luck.
find yourdir -type d -name '*.app' -exec ln -s {} /AppLinks \;
Find all directories named something.app in yourdir, and create a symlink to them in /AppLinks.
single line bash-fu
function FUNCsymlink() { echo "$1"; fileName=`basename "$1"`; ln -s "$1" "/AppLinks/$fileName"; }; export -f FUNCsymlink; find `pwd`/ -maxdepth 1 -type d -iname "*.app" -exec bash -c "FUNCsymlink '{}'" \;
to easy reading:
function FUNCsymlink() {
echo "$1";
fileName=`basename "$1"`;
ln -s "$1" "/AppLinks/$fileName";
};
export -f FUNCsymlink;
find `pwd`/ -maxdepth 1 -type d -iname "*.app" -exec bash -c "FUNCsymlink '{}'" \;
you may have to adjust it a bit for your specific solution.
wherever you run it, it will create the symlinks to /AppLinks
it will only look for direct subfolders, not subfolders of subfolders, thats what I believe you need..