Matlab circle packing on a sphere - matlab

I am trying to pack same-radi circles on a sphere using matlab. I have figured out how to pack circles and spheres in a box or a cube but just can't figure out where to start when packing it on the surface of a sphere. I would love any hints or ideas in doing this.
Wish you all the best of luck

This is a really hard problem, not sure if there exists a generic solution.
To obtain perfectly regular distribution of circles, take any regular polyhedron, and put a circle at each vertex. The largest regular polyhedron, the dodecahedron has 20 vertices, so you would be able to fit 20 circles on a sphere with this method. If you are willing to have a tiling that is not perfectly regular, you can use shapes such as that of a buckyball (same as soccer ball).
Other ways to distribute points evenly around a sphere have been proposed.
A friend of mine proposed a way that allowed him to easily index each point. It was based on the icosahedron (dual of the dodecahedron, it has 20 faces), and tiled each triangular face. See his paper for more details.
That paper has references to some other methods known at that time. I think the most useful one would be the one where the sphere is cut vertically into slices of equal width (the surface of the sphere section has equal height, the cuts themselves are not spaced evenly), and each section is then a strip that can be tiled by circles evenly. This leads to one circle on the top and one on the bottom, and in between rows of circles. The distribution is not even, and the spacing depends on the ratio of the circle size and sphere size.

Related

Is it possible to find the depth of an internal point of an object using stereo images (or any other method)?

I have image of robot with yellow markers as shown
The yellow points shown are the markers. There are two cameras used to view placed at an offset of 90 degrees. The robot bends in between the cameras. The crude schematic of the setup can be referred.
https://i.stack.imgur.com/aVyDq.png
Using the two cameras I am able to get its 3d co-ordinates of the yellow markers. But, I need to find the 3d-co-oridnates of the central point of the robot as shown.
I need to find the 3d position of the red marker points which is inside the cylindrical robot. Firstly, is it even feasible? If yes, what is the method I can use to achieve this?
As a bonus, is there any literature where they find the 3d location of such internal points which I can refer to (I searched, but could not find anything similar to my ask).
I am welcome to a theoretical solution as well(as long as it assures to find the central point within a reasonable error), which I can later translate to code.
If you know the actual dimensions, or at least, shape (e.g. perfect circle) of the white bands, then yes, it is feasible and possible.
You need to do the following steps, which are quite non trivial to do, and I won't do them here:
Optional but extremely suggested: calibrate your camera, and
undistort it.
find the equation of the projection of a 3D circle into a 2D camera, for any given rotation. You can simplify this by assuming the white line will be completely horizontal. You want some function that takes the parameters that make a circle and a rotation.
Find all white bands in the image, segment them, and make them horizontal (rotate them)
Fit points in the corrected white circle to the equation in (1). That should give you the parameters of the circle in 3d (radious, angle), if you wrote the equation right.
Now that you have an analytic equation of the actual circle (equation from 1 with parameters from 3), you can map any point from this circle (e.g. its center) to the image location. Remember to uncorrect for the rotations in step 2.
This requires understanding of curve fitting, some geometric analytical maths, and decent code skills. Not trivial, but this will provide a solution that is highly accurate.
For an inaccurate solution:
Find end points of white circles
Make line connecting endpoints
Chose center as mid point of this line.
This will be inaccurate because: choosing end points will have more error than fitting an equation with all points, ignores cone shape of view of the camera, ignores geometry.
But it may be good enough for what you want.
I have been able to extract the midpoint by fitting an ellipse to the arc visible to the camera. The centroid of the ellipse is the required midpoint.
There will be wrong ellipses as well, which can be ignored. The steps to extract the ellipse were:
Extract the markers
Binarise and skeletonise
Fit ellipse to the arc (found a matlab function for this)
Get the centroid of the ellipse
hsv_img=rgb2hsv(im);
bin=new_hsv_img(:,:,3)>marker_th; %was chosen 0.35
%skeletonise
skel=bwskel(bin);
%use regionprops to get the pixelID list
stats=regionprops(skel,'all');
for i=1:numel(stats)
el = fit_ellipse(stats(i).PixelList(:,1),stats(i).PixelList(:,2));
ellipse_draw(el.a, el.b, -el.phi, el.X0_in, el.Y0_in, 'g');
The link for fit_ellipse function
Link for ellipse_draw function

Smoothing algorithm, 2.5D

The picture below shows a triangular surface mesh. Its vertices are exactly on the surface of the original 3D object but the straight edges and faces have of course some geometric error where the original surface bends and I need some algorithm to estimate the smooth original surface.
Details: I have a height field of (a projectable part of) this surface (a 2.5D triangulation where each x,y pair has a unique height z) and I need to compute the height z of arbitrary x,y pairs. For example the z-value of the point in the image where the cursor points to.
If it was a 2D problem, I would use cubic splines but for surfaces I'm not sure what is the best solution.
As commented by #Darren what you need are patches.
It can be bi-linear patches or bi-quadratic or Coon's patches or other.
I have found no much reference doing a quick search but this links:
provide an overview: http://www.cs.cornell.edu/Courses/cs4620/2013fa/lectures/17surfaces.pdf
while this is more technical: https://www.doc.ic.ac.uk/~dfg/graphics/graphics2010/GraphicsHandout05.pdf
The concept is that you calculate splines along the edges (height function with respect to the straight edge segment itself) and then make a blending inside the surface delimited by the edges.
The patch os responsible for the blending meaning that inside any face you have an height which is a function of the point position coordinates inside the face and the values of the spline ssegments which are defined on the edges of the same face.
As per my knowledge it is quite easy to use this approach on a quadrilateral mesh (because it becomes easy to define on which edges sequence to do the splines) while I am not sure how to apply if you are forced to go for an actual triangulation.

Selecting volume chunk by rotation around axis

I have a 3D volume and I need to set some parts of it to zero.
The problem is that I don't know how to refer to the parts I want. I know the shape of the area I want to crop, but I need that area revolved around the Z axis.
A picture's worth a thousand words:
The image shows the cross section of a 3D matrix in the XZ plane, in the middle is the Z axis. The area I want to select (or set to zero) in the volume is the red area, revolved around the green axis, the Z axis.
I'd rather have a solution that doesn't have a very big memory dependency (such as using meshgrid would) as these matrices can get quite big. Else, a meshgrid solution with cylindrical coordinates wouldn't be too difficult to make, as #Luis suggests.
How can I select this area?

Draws the intersecting volume of two spheres in MATLAB?

I have the equations of two spheres in MATLAB, like
(x-x0)^2+(y-y0)^2+(z-z0)^2=R0^2
(x-x1)^2+(y-y1)^2+(z-z1)^2=R1^2
They have an intersecting part (I find a similar picture which could explain my meaning on the web like below)
Now I would like to only draw the spatial intersecting volume of these two spheres (like the 3D part between the curved faces with red lines in the sample image above)
Maybe I could use the command 'surface' in MATLAB to draw out those two curved faces which make up the intersecting volume? I do not know how to do it....
Moreover, I also would like to draw these two spheres after erasing out those intersecting parts
That is, my goal: drawing out the intersecting and non-intersecting part of these two spheres individually.
Could anyone help me?
Thank you!
The answer is given in great detail at Wolfram. In brief, rather than copypaste all the equations:
1) calculate the circle of intersection of the two sphere's surfaces.
2) determine the location of that circle on each sphere.
3) Calculate the volume of each sphere's spherical cap for that circle and add the two volumes to get the "lens."
I am recommending this be moved to Math.SE because it is a math problem, and coding it in Matlab is trivial.

Techniques for differentiating between circle rectangle and triangle?

What coding techniques would allow me to to differentiate between circles, rectangles, and triangles in black and white image bitmaps?
You could train an Artificial Neural Network to classify the shapes :P
If noise is low enough to extract curves, approximations can be used: for each shape select parameters giving least error (he method of least squares may help here) and then compare these errors...
If the image is noisy, I would consider Hough transform - it may be used to detect shapes with small count of parameters, like circle (harder for rectangles and triangles).
just an idea off of the top of my head: scan the (pixel) image line-by-line, pixel-by-pixel. If you encounter the first white pixel (assuming it has a black background) you keep it's position as a starting point and look at the eight pixels surrounding it in every direction for the next white pixel. If you find an adjacent second pixel you can establish a directional vector between those two pixels.
Now repeat this until the direction of your vector changes (or the change is above a certain threshold). Keep the last point before the change as the endpoint of your first line and repeat the process for the next line.
Then calculate the angle between the two lines and store it. Now trace the third line. Calculate the angle between the 2nd and 3rd line as well.
If both angles are rectangular you probably found a rectangle, otherwise you probably found a triangle. If you can't find any straight line you could conclude that you found a circle.
I know the algorithm is a bit sketchy but I think (with some refinement) it could work if your image's quality is not too bad (too much noise, gaps in the lines etc.).
You are looking for the Hough Transform. For an implementation, try the AForge.NET framework. It includes circle and line hough transformations.