I have a search input field in a ScalaJS app that fires off requests to a backend server whilst the user types in a city name. However, I need to implement a delay so that the request is not fired until after a certain delay (say 1000ms). Without such a delay, there is the chance that I'll get back false positives on the search (E.G. If the user wants to search for "paris", then there will be a false hit on "par" - a small town in Cornwall, England - when the third character is entered)
I've tried transcribing the JavaScript equivalent into Scala, but the setTimeout part doesn't seem to work.
import scala.scalajs.js.timers.{SetTimeoutHandle, clearTimeout, setTimeout}
private def delay = () => {
// Set initial timeout to do nothing after 0 ms
var handle: SetTimeoutHandle = setTimeout(0)(() => {})
(fn: Function0[Unit], ms: Double) => {
clearTimeout(handle)
handle = setTimeout(ms)(fn)
}
}
Then I'm handling the user input event using an Akka Actor
def receive = {
/************************************************
* Client event
* The user has typed something into the search field
*/
case evt: Event =>
delay()(handleInput, 1000.0)
}
Where handleInput is the zero parameter function that obtains the user's input and then fires off a request to the backend.
The anonymous inner function that clears and then resets the timeout is executed, but the handleInput function never gets called
Thanks
Chris W
The problem in your code is that you are giving a function of type () => Unit to setTimeout, but setTimeout takes a by-name parameter. In other words, the argument to setTimeout should be a statement to execute when the timeout expires. If you give it a function, then after the timeout that function value will be evaluated, but the function will not be called!
It is similar to mistakenly trying to do
val result = fn // result is the *function* itself, but does not call it
instead of
val result = fn() // fn is called, result is what it returns
You can fix your call to setTimeout by replacing fn by fn(). Also, it is typically more idiomatic, in those circumstances, to use {} instead of () for the parameter to setTimeout, which also gives a visual clue that it is a by-name parameter:
(fn: Function0[Unit], ms: Double) => {
clearTimeout(handle)
handle = setTimeout(ms) {
fn()
}
}
You should also adapt your first dummy setTimeout for consistency, although since it is a dummy anyway, that will not change the behavior:
// Set initial timeout to do nothing after 0 ms
var handle: SetTimeoutHandle = setTimeout(0) {}
Related
I will start mentioning I am very new to Scala but I have now to maintain a legacy code where some new feature are being tried to be include.
I have the following code:
Where a list is coming as a parameter where a new output needs to be processed. However it seems like code is not waiting for the response to the external service when processing.
def historyBet(jackpotListUser : List[JackpotBetHistory])(implicit MC: AppMarkerContext) : List[LegacyJackpotHistoryResponse] =
for {
bet <- jackpotListUser
prize = jackpotIntegratorService.findJackpotByJackpotHumanId(bet.jackpotHumanId) match {
case Some(jackpot : JackpotResponse) =>
...
extra code extracting price from jackpot : JackpotResponse
...
extra code generating result with prize
} yield result
How can I do a call to jackpotIntegratorService.findJackpotByJackpotHumanId to execute at that time. instead of returning something that F[Option....?
def findJackpotByJackpotHumanId(
jackpotHumanId: JackpotHumanId
)(implicit MC: AppMarkerContext): F[Option[JackpotResponse]] =
jackpotIntegratorRepo.findJackpotByJackpotHumanId(jackpotHumanId)
where it is finally implemented as:
override def findJackpotByJackpotHumanId(
jackpotHumanId: JackpotHumanId
)(implicit mc: AppMarkerContext): IO[Option[JackpotResponse]] =
... code calling an API which return the IO.
Thanks!
I thought I could do IO.await somewhere... but not sure where or how...
because in the "historyBet" function I got a F[] when it was an IO... so what is the syntax to be able to wait for the response and the continue?
Extra Comment:
The real issue we notice is that the method call is starting (the logs shows part of it) but the caller with in the maps continues too.
prize = jackpotIntegratorService.findJackpotByJackpotHumanId
this part of the code continues even when prize, which we want the final object JackpotResponse, not the IO or F.
So, if your method needs to call an IO then it must return an IO unless you unsafeRunSync them... but, as the name suggest, you should not do that.
So the return type is now: IO[List[LegacyJackpotHistoryResponse]
And can be implemented like this:
def historyBet(jackpotListUser: List[JackpotBetHistory])(implicit MC: AppMarkerContext): IO[List[LegacyJackpotHistoryResponse]] =
jackpotListUser.traverse { bet =>
jackpotIntegratorService.findJackpotByJackpotHumanId(bet.jackpotHumanId).map {
case Some(jackpot) =>
// ...
case None =>
// ...
}
}
I'm kinda new to akka typed and I was trying to send a message which requires an answer within a given time.
I found the request-response pattern with ask which seemed interesting but is there a way to implement it inside of an already defined Behaviours.receive?
Here the idea is to call nextPlayerTurn each time a player answers or after a timeout
override def refereeTurn(): Behavior[Msg] = Behaviors.receive {
case (_, msg: GuessMsg) =>
if(currentPlayer.isDefined && currentPlayer.get == msg.getSender) {
controller ! msg
} else {
println("Player tried to guess after Timeout")
}
Behaviors.same
case (context, msg: ReceivedResponseMsg) =>
if(currentPlayer.isDefined && currentPlayer.get == msg.getSender)
nextPlayerTurn(context)
Behaviors.same
...
}
...
/**
* Tells to a player to start his turn and sets a timer that defines time in which a player has to make a guess.
* If such guess isn't made, sends that user an end turn message, fails the promise of his turn and allows next
* player to play his turn
*/
override def nextPlayerTurn(ctx: ActorContext[Msg]): Unit = {
implicit val timeout: Timeout = Timeout.timeout
currentPlayer = Option(turnManager.nextPlayer)
ctx.ask[Msg,Msg](currentPlayer.get, ref => YourTurnMsg(ref)) {
case Success(msg: GuessMsg) => println("\n SUCCESS"); msg
case Failure(_) => println(currentPlayer.get +" didn't guess in time"); TurnEnd(currentPlayer.get)
case _ => TurnEnd(currentPlayer.get)
}
}
In this case after the YourTurnMsg is sent the player is supposed to respond with a GuessMsg which stops the timer, this never happens due to the case matching inside refereeTurn Begaviour being executed instead of the Success (which instead always gives a Failure after the Timeout).
Did i get the wrong idea about the ask patter and should just make a new Behaviour with a timer?
If you want to use the ask pattern then the code that handles the result needs to send a message to the main actor rather than trying to do any processing directly. You can send a different message based on the result or just send the raw result and process it in the actor, but you must not do anything that depends on actor state in that code because it could be run on a different thread.
But ask is not cheap so in this case it seems better to just set a timer and see which message comes back first.
I'm writing Selenium tests with ScalaTest's Selenium DSL and I'm running into timeouts I can't explain. To make matters more complicated, they only seem to happen some of the time.
The problem occurs whenever I access an Element after a page load or some Javascript rendering. It looks like this:
click on "editEmployee"
eventually {
textField(name("firstName")).value = "Steve"
}
My PatienceConfig is configured like this:
override implicit val patienceConfig: PatienceConfig =
PatienceConfig(timeout = Span(5, Seconds), interval = Span(50, Millis))
The test fails with the following error:
- should not display the old data after an employee was edited *** FAILED ***
The code passed to eventually never returned normally. Attempted 1 times over 10.023253653000001 seconds.
Last failure message: WebElement 'firstName' not found.. (EditOwnerTest.scala:24)
It makes sense that it doesn't succeed immediately, because the click causes some rendering, and the textfield may not be available right away. However, it shouldn't take 10 seconds to make an attempt to find it, right?
Also, I find it very interesting that the eventually block tried it only once, and that it took almost precisely 10 seconds. This smells like a timeout occurred somewhere, and it's not my PatienceConfig, because that was set to time out after 5 seconds.
With this workaround, it does work:
click on "editEmployee"
eventually {
find(name("firstName")).value // from ScalaTest's `OptionValues`
}
textField(name("firstName")).value = "Steve"
I did some digging in the ScalaTest source, and I've noticed that all calls that have this problem (it's not just textField), eventually call webElement at some point. The reason why the workaround works, is because it doesn't call webElement. webElement is defined like this:
def webElement(implicit driver: WebDriver, pos: source.Position = implicitly[source.Position]): WebElement = {
try {
driver.findElement(by)
}
catch {
case e: org.openqa.selenium.NoSuchElementException =>
// the following is avoid the suite instance to be bound/dragged into the messageFun, which can cause serialization problem.
val queryStringValue = queryString
throw new TestFailedException(
(_: StackDepthException) => Some("WebElement '" + queryStringValue + "' not found."),
Some(e),
pos
)
}
}
I've copied that code into my project and played around with it, and it looks like constructing and/or throwing the exception is where most of the 10 seconds are spent.
(EDIT Clarification: I've actually seen the code actually spend its 10 seconds inside the catch block. The implicit wait is set to 0, and besides, if I remove the catch block everything simply works as expected.)
So my question is, what can I do to avoid this strange behaviour? I don't want to have to insert superfluous calls to find all the time, because it's easily forgotten, especially since, as I said, the error occurs only some of the time. (I haven't been able to determine when the behaviour occurs and when it doesn't.)
It is clear that the textField(name("firstName")).value = "Steve" ends up calling the WebElement as you have found out.
Since the issue in the op is happening where ever web elements are involved (which in turn implies that webdriver is involved), I think it is safe to assume that the issue is related to the implicit wait on the Web driver.
implicitlyWait(Span(0, Seconds))
The above should ideally fix the issue. Also, making implicit wait to be 0 is a bad practice. Any web page might have some loading issues. The page load is handled by Selenium outside its wait conditions. But slow element load (may be due to ajax calls) could result in failure. I usually keep 10 seconds as my standard implicit wait. For scenarios which require more wait, explicit waits can be used.
def implicitlyWait(timeout: Span)(implicit driver: WebDriver): Unit = {
driver.manage.timeouts.implicitlyWait(timeout.totalNanos, TimeUnit.NANOSECONDS)
}
Execution Flow:
name("firstName") ends up having value as Query {Val by = By.className("firstName") }.
def name(elementName: String): NameQuery = new NameQuery(elementName)
case class NameQuery(queryString: String) extends Query { val by = By.name(queryString) }
Query is fed to the textField method which calls the Query.webElement as below.
def textField(query: Query)(implicit driver: WebDriver, pos: source.Position): TextField = new TextField(query.webElement)(pos)
sealed trait Query extends Product with Serializable {
val by: By
val queryString: String
def webElement(implicit driver: WebDriver, pos: source.Position = implicitly[source.Position]): WebElement = {
try {
driver.findElement(by)
}
catch {
case e: org.openqa.selenium.NoSuchElementException =>
// the following is avoid the suite instance to be bound/dragged into the messageFun, which can cause serialization problem.
val queryStringValue = queryString
throw new TestFailedException(
(_: StackDepthException) => Some("WebElement '" + queryStringValue + "' not found."),
Some(e),
pos
)
}
}
}
I don't know ScalaTest's specifics, but such strange timeouts usually occur when you're mixing up implicit and explicit waits together.
driver.findElement uses implicit waits internally. And depending on specified explicit waits timeout, you may face with summing both together.
Ideally, implicit waits should be set to 0 to avoid such issues.
Coming from a Java background, I have been trying to teach myself Scala for some time now. As part of that, I am doing a small pet project that exposes a HTTP endpoint that saves the registration numberof a vehicle against the owner and returns the status.
To give more context, I am using Slick as FRM which performs DB operations asynchronously and returns a Future.
Based on the output of this Future, I want to set the status variable to return back to the client.
Here, is the code
def addVehicleOwner(vehicle: Vehicle): String = {
var status = ""
val addFuture = db.run((vehicles returning vehicles.map(_.id)) += vehicle)
addFuture onComplete {
case Success(id) => {
BotLogger.info(LOGTAG, s"Vehicle registered at $id ")
status = String.format("Registration number - '%s' mapped to owner '%s' successfully", vehicle.registration,
vehicle.owner)
println(s"status inside success $status") //--------- (1)
}
case Failure(e: SQLException) if e.getMessage.contains("SQLITE_CONSTRAINT") => {
status = updateVehicleOwner(vehicle)
BotLogger.info(LOGTAG, s"Updated owner='${vehicle.owner}' for '${vehicle.registration}'")
}
case Failure(e) => {
BotLogger.error(LOGTAG, e)
status = "Sorry, unable to add now!"
}
}
exec(addFuture)
println(s"Status=$status") //--------- (2)
status
}
// Helper method for running a query in this example file:
def exec[T](sqlFuture: Future[T]):T = Await.result(sqlFuture, 1 seconds)
This was fairly simple in Java. With Scala, I am facing the following problems:
The expected value gets printed at (1), but (2) always prints empty string and same is what method returns. Can someone explain why?
I even tried marking the var status as #volatile var status, it still evaluates to empty string.
I know, that the above is not the functional way of doing things as I am muting state. What is the clean way of writing code for such cases.
Almost all the examples I could find described how to map the result of Success or handle Failure by doing a println. I want to do more than that.
What are some good references of small projects that I can refer to? Specially, that follow TDD.
Instead of relying on status to complete inside the closure, you can recover over the Future[T] which handle the exception if they occur, and always returns the result you want. This is taking advantage of the nature of expressions in Scala:
val addFuture =
db.run((vehicles returning vehicles.map(_.id)) += vehicle)
.recover {
case e: SQLException if e.getMessage.contains("SQLITE_CONSTRAINT") => {
val status = updateVehicleOwner(vehicle)
BotLogger.info(
LOGTAG,
s"Updated owner='${vehicle.owner}' for '${vehicle.registration}'"
)
status
}
case e => {
BotLogger.error(LOGTAG, e)
val status = "Sorry, unable to add now!"
status
}
}
val result: String = exec(addFuture)
println(s"Status = $result")
result
Note that Await.result should not be used in any production environment as it synchronously blocks on the Future, which is exactly the opposite of what you actually want. If you're already using a Future to delegate work, you want it to complete asynchronously. I'm assuming your exec method was simply for testing purposes.
I guess I need some type of promise chain, but the syntax eludes me...
Within the same component:
I'm calling:
this.somethingService.getSomethings().then(somethings => this.somethings = somethings);
Then I need to call:
this.otherService.getOthers(this.somethings).then(others => this.others = others);
In the second service call I'm using the result of the first to perform aggregate functions on its content, but its empty when the second call is made, thus the second service returns empty.
How can I get the second service to wait until the first promise has been resolved.
Thanx
Steve
You can chain promises this way:
this.somethingService.getSomethings().then(somethings => {
this.somethings = somethings;
return this.otherService.getOthers(somethings);
}).then(others => {
this.others = others;
});
The second callback will receive the result of the promise returns by the first callback.