How to show sum per day AND year postgresql - postgresql

Question

I want to get sum row values per day and per year, and showing on the same row.
The database that the first and second queries get results from from include a table like this (ltg_data):
time lon lat geom
2018-01-30 11:20:21 -105.4333 32.3444 01010....
And then some geometries that I'm joining to.
One query:
SELECT to_char(time, 'MM/DD/YYYY') as day, count(*) as strikes FROM counties JOIN ltg_data on ST_contains(counties.the_geom, ltg_data.ltg_geom) WHERE cwa = 'MFR' and time >= (now() at time zone 'utc') - interval '50500 hours' group by 1;
Results are like:
day strikes
01/28/2018 22
03/23/2018 15
12/19/2017 20
12/20/2017 12
Second query:
SELECT to_char(time, 'YYYY') as year, count(*) as strikes FROM counties JOIN ltg_data on ST_contains(counties.the_geom, ltg_data.ltg_geom) WHERE cwa = 'MFR' and time >= (now() at time zone 'utc') - interval '50500 hours' group by 1;
Results are like:
year strikes
2017 32
2018 37
What I'd like is:
day daily_strikes year yearly_strikes
01/28/2018 22 2018 37
03/23/2018 15 2018 37
12/19/2017 20 2017 32
12/20/2017 12 2017 32
I found that union all shows the year totals at the very bottom, but I'd like to have the results horizontally, even if there are repeat yearly totals. Thanks for any help!

Answer 1

You can try this kind of approach. It's not very optimal but at lease works:
I have a test table like this:
postgres=# select * from test;
d | v
------------+---
2001-02-16 | a
2002-02-16 | a
2002-02-17 | a
2002-02-17 | a
(4 wiersze)
And query:
select
q.year,
sum(q.countPerDay) over (partition by extract(year from q.day)),
q.day,
q.countPerDay
from (
select extract('year' from d) as year, date_trunc('day', d) as day, count(*) as countPerDay from test group by day, year
) as q
So the result looks like this:
2001 | 1 | 2001-02-16 00:00:001 | 1
2002 | 3 | 2002-02-16 00:00:001 | 1
2002 | 3 | 2002-02-17 00:00:001 | 2

Answer 2

create table strikes (game_date date,
strikes int
) ;
insert into strikes (game_date, strikes)
values ('01/28/2018', 22),
('03/23/2018', 15),
('12/19/2017', 20),
('12/20/2017', 12)
;
select * from strikes ;
select game_date, strikes, sum(strikes) over(partition by extract(year from game_date) ) as sum_stikes_by_year
from strikes ;
"2017-12-19" 20 "32"
"2017-12-20" 12 "32"
"2018-01-28" 22 "37"
"2018-03-23" 15 "37"
This application of aggregation is known as "windowing" functions or analytic functions:
PostgreSQL Docs
---- EDIT --- based on comments...
create table strikes_tally (strike_time timestamp,
lat varchar(10),
long varchar(10),
geom varchar(10)
) ;
insert into strikes_tally (strike_time, lat, long, geom)
values ('2018-01-01 12:43:00', '100.1', '50.8', '1234'),
('2018-01-01 12:44:00', '100.1', '50.8', '1234'),
('2018-01-01 12:45:00', '100.1', '50.8', '1234'),
('2018-01-02 20:01:00', '100.1', '50.8', '1234'),
('2018-01-02 20:02:00', '100.1', '50.8', '1234'),
('2018-01-02 22:03:00', '100.1', '50.8', '1234') ;
select to_char(strike_time, 'dd/mm/yyyy') as strike_date,
count(strike_time) over(partition by to_char(strike_time, 'dd/mm/yyyy')) as daily_strikes,
to_char(strike_time, 'yyyy') as year,
count(strike_time) over(partition by to_char(strike_time, 'yyyy') ) as yearly_strikes
from strikes_tally
;