How to be distinct on a name column and only display the highest ts_rank for that column PostgreSQL - postgresql

Question

I posted a question on this here but then I realized I am wanting more than just what I was asking.
I actually need to be DISTINCT on the name column by its highest ts_rank, So my code is,
SELECT name
,ts_rank(to_tsvector(name), query) + ts_rank(to_tsvector(content), query2) AS rank
FROM users
INNER JOIN microposts ON users.id = microposts.user_id
,plainto_tsquery('re') query
,plainto_tsquery('comics') query2
WHERE users.name ## query
OR microposts.content ## query2
ORDER BY rank DESC;
Gives
╔════════════════╤═════════════════════════════════════════╤═══════════╗
║ name │ content │ rank ║
╠════════════════╪═════════════════════════════════════════╪═══════════╣
║ Dawson Kreiger │ dc comics dc comics dc comics dc comics │ 0.0919062 ║
╟────────────────┼─────────────────────────────────────────┼───────────╢
║ Kaylin Green │ dc comics dc comics dc comics │ 0.0889769 ║
╟────────────────┼─────────────────────────────────────────┼───────────╢
║ Dawson Kreiger │ dc comics dc comics │ 0.0827456 ║
╟────────────────┼─────────────────────────────────────────┼───────────╢
║ Kaylin Green │ dc comics │ 0.0759909 ║
╟────────────────┼─────────────────────────────────────────┼───────────╢
║ Dawson Kreiger │ I went to the beach dc comics │ 0.0607927 ║
╟────────────────┼─────────────────────────────────────────┼───────────╢
║ Dawson Kreiger │ I went to the beach dc comics │ 0.0607927 ║
╟────────────────┼─────────────────────────────────────────┼───────────╢
║ Kaylin Green │ I went to the beach dc comics │ 0.0607927 ║
╟────────────────┼─────────────────────────────────────────┼───────────╢
║ Kaylin Green │ I went to the beach dc comics │ 0.0607927 ║
╚════════════════╧═════════════════════════════════════════╧═══════════╝
So I need the output to be this,
╔════════════════╤═════════════════════════════════════════╤═══════════╗
║ name │ content │ rank ║
╠════════════════╪═════════════════════════════════════════╪═══════════╣
║ Dawson Kreiger │ dc comics dc comics dc comics dc comics │ 0.0919062 ║
╟────────────────┼─────────────────────────────────────────┼───────────╢
║ Kaylin Green │ dc comics dc comics dc comics │ 0.0889769 ║
╚════════════════╧═════════════════════════════════════════╧═══════════╝
So I need to select a record that is distinct by name and has the highest rank. But how will the code know how to select the distinct user with the highest ts_rank?
EDIT
For instance if I do this
SELECT name
, ts_rank(to_tsvector(name), query) + ts_rank(to_tsvector(content), query2) AS rank
FROM
(
SELECT DISTINCT name FROM users WHERE rank = MAX(rank)
)
INNER JOIN microposts ON users.id=microposts.user_id
, plainto_tsquery('re') query
,plainto_tsquery('comics') query2
WHERE users.name ## query
OR microposts.content ## query2
ORDER BY rank DESC;
I get error: column "rank" does not exist

Answer 1

You could do a GROUP BY with a MAX.
SELECT name
,MAX(ts_rank(to_tsvector(name), query) + ts_rank(to_tsvector(content), query2)) AS rank
FROM users
INNER JOIN microposts ON users.id = microposts.user_id
,plainto_tsquery('re') query
,plainto_tsquery('comics') query2
WHERE users.name ## query
OR microposts.content ## query2
GROUP BY name
ORDER BY rank DESC;