I am transforming a xml into json using xml-to-json() function of xslt 3.0 using Saxon 9.8 HE. The problem I am getting is that my Number value is getting converted into exponent (scientific notation). I want output same what i pass in input xml.
xsltfiddle link
https://xsltfiddle.liberty-development.net/94hvTyT
input xml
<?xml version="1.0" encoding="UTF-8"?>
<map xmlns="http://www.w3.org/2005/xpath-functions">
<map key="Request">
<number key="price">1234567</number>
</map>
</map>
Note that this xml is also genrated using json-to-xml() funtion of xslt 3.0
XSLT
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="3.0">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:value-of select="xml-to-json(., map { 'indent' : true() })"/>
</xsl:template>
</xsl:stylesheet>
OUTPUT
{ "Request" :
{ "price" : 1.234567E6 }
}
Desired Output
{ "Request" :
{ "price" : 1234567 }
}
Any solution/suggestions on it would be great help for me.
The result is as specified in https://www.w3.org/TR/xpath-functions/#func-xml-to-json which says
An element $E named number results in the output of the string result
of xs:string(xs:double(fn:string($E)))
You would get the same result with other XPath/XQuery 3.1 implementations or XSLT 3.0 implementations.
So unless you are willing to change the <number key="price">1234567</number> to <string key="price">1234567</string> (could of course be done with an intermediary transformation step) I don't think you can prevent the exponential number format for large numbers with xml-to-json.
Related
I need to write a dynamic Attribute name instead of hardcode of Name attribute in dataweave 2.0 mulesoft 4 in anypointstudio
<?xml version="1.0" encoding="UTF-8"?>
<iGoApplicationData>
<UserData>
<Data Name="UpdateUserProfile">True</Data>
<Data Name="Action">??</Data>
</iGoApplicationData>
So in order to generate an XML like yours the DW structure will look like
{
iGoApplicationData: {
UserData: {
Data #(Name: payload.foo): "True",
Data #((var.attributeName): "Action"): "??"
}
}
}
So in this example I show how to specify a value in the attribute or a dynamic attribute name. For the dynamic attribute value just type the expression on the value side of the attribute (the part that goes after the :)
For dynamic attribute name you need to wrap the expression between parenthesis. When the name is wrapped between parenthesis it is considered dynamic. This applies to object keys and attributes names
When generating a XML file with BeanIO, the StreamBuilder name is used as root element. How to suppress this root element?
Example:
StreamBuilder builder = new StreamBuilder("builder_name")
.format("xml")
.parser(new XmlParserBuilder()).addRecord(Test.class);
The Test class:
#Record
public class Test {
#Field(at=0)
private String field1 = "ABC";
// Getters and Setters ...
}
The generated XML file:
<builder_name>
<Test>
<field1>ABC</field1>
</Test>
</builder_name>
I don't want builder_name to be showed as root element. I want Test element to be the root. How can I achieve that?
You need to set the xmlType property/attribute to XmlType.NONE on your stream configuration.
The answer is in Appendix A - XML Mapping file reference of the documentation.
xmlType - The XML node type mapped to the stream. If not specified or set to element, the stream is mapped to the root element of the XML document being marshalled or unmarshalled. If set to none, the XML input stream will be fully read and mapped to a child group or record.
The trick is now to translate that piece of information into the StreamBuilder API, which is:
xmlType(XmlType.NONE)
Your example then becomes:
StreamBuilder builder = new StreamBuilder("builder_name")
.format("xml")
.xmlType(XmlType.NONE)
.parser(new XmlParserBuilder())
.addRecord(Test.class);
Which produces this unformatted/unindented output:
<?xml version="1.0" encoding="utf-8"?><test><field1>ABC</field1></test>
To have the xml formatted (pretty print)/indented use:
StreamBuilder builder = new StreamBuilder("builder_name")
.format("xml")
.xmlType(XmlType.NONE)
.parser(new XmlParserBuilder()
.indent()
)
.addRecord(Test.class);
Note the change to the XmlParserBuilder, to produce this output:
<?xml version="1.0" encoding="utf-8"?>
<test>
<field1>ABC</field1>
</test>
I need to select the next node via next_sibling or first_elt. But I want to filter by node name (containing the string "TON")
first_elt ('HILTON[#method]' or 'SHERATON[#method]');
or
next_sibling ('HILTON[#method]' or 'SHERATON[#method]');
or
next_sibling ('TON[#method]');
Example I tried (not working):
#!/usr/bin/perl -w
use warnings;
use XML::Twig;
$t-> parsefile ('file.xml');
my $Y0=$t->first_elt('HILTON[#method]' or 'SHERATON[#method]');
it will just process for 'HILTON[#method]'
my $Y0=$t->first_elt('/*TON[#method]');
wrong navigation condition '/*TON[#method]' () at C:/strawberry/perl/site/lib/XML/Twig.pm line 3523
As this is outside of the XPath subset supported by XML::Twig, you have to use a custom filter, by passing code to first_elt:
$t->first_elt( sub { $_[0]->tag=~ m{TON$} && $_[0]->att( 'method') })
This returns the first element for which the sub returns a true value.
The need for such an expression is a bit troubling though. In your example you define a class of elements by the fact that their name ends in TON. What happens when you have a CARLTON element? Or when MARRIOTT elements need to be processed with SHERATON and HILTON? Do you need to rewrite your queries?
If you are the one designing the format of the data, I would suggest revising the format. HILTON and SHERATON should probably be attributes of a HOTEL, BRAND or OWNER tag. Maybe an additional attribute would be useful, to mark that both types should be processed similarly. This attribute would only make sense if it is a property intrinsic to the data.
If the data is what it is and you have no input on its format, then I would have a list of the tags to process and check on these:
my %TAGS_TO_PROCESS= map { $_ => 1 } qw( HILTON SHERATON);
my $elt= $t->first_elt( sub { $TAGS_TO_PROCESS{$_[0]->tag} && $_[0]->att( 'method') })
This way adding/substracting other tags is easy.
Use:
*[substring(name(), string-length(name()) - 2) = 'TON'][#method][1]
Explanation:
This expression uses an XPath 1.0 equevalent for the XPath 2.0 standard function ends-with():
The XPath 1.0 equivalent of the XPath 2.0 expression:
ends-with($s, $s2)
is:
substring($s, string-lenth() - string-length($s2) + 1) = $s2
In this last expression we substitute $s with name() and $s2 with 'TON'
XSLT - based verification:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/*">
<xsl:copy-of select=
"*[substring(name(), string-length(name()) - 2) = 'TON'][#method] "/>
==========
<xsl:copy-of select=
"*[substring(name(), string-length(name()) - 2) = 'TON'][#method][1] "/>
</xsl:template>
</xsl:stylesheet>
when applied on this XML document:
<t>
<HILTON method="buy"/>
<TON method="burn"/>
<TONIC method="drink"/>
<HILTON nomethod="yes"/>
<SHERATON/>
<SHERATON method="visit"/>
</t>
the transformation evaluates the two XPath expressions and the selected nodes are copied to the output:
<HILTON method="buy"/>
<TON method="burn"/>
<SHERATON method="visit"/>
==========
<HILTON method="buy"/>
The first expression selects all elements - children of the context node, whose name ends with "TON" and that also have a method attribute.
The second expression selects the first node from those, selected by the first expression.
This question is following on from Blaise's excellent answer here.
My question is, how do I use the JAXB #XmlSchema annotation from within Scala?
This is what I've come up with so far:
// File src/main/scala/co/orderly/prestasac/representations/wrappers.scala
package co.orderly.prestasac.representations
// JAXB
import javax.xml.bind.annotation._
#XmlSchema(xmlns = Array(#XmlNs(prefix = "xlink", namespaceURI = "http://www.w3.org/1999/xlink")))
package object wrappers {
}
Unfortunately this throws an error:
/home/alex/Development/Orderly/prestashop-scala-client/src/main/scala/co/orderly/prestasac/representations/wrappers/wrappers.scala:18: illegal start of simple expression
[error] #XmlSchema(xmlns=Array(#XmlNs(prefix = "xlink", namespaceURI = "http://www.w3.org/1999/xlink")))
[error] ^
In case there's a workaround which doesn't require #XmlSchema, I'll explain what I'm trying to do - basically I'm trying to unmarshall an XML representation which looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<prestashop xmlns:xlink="http://www.w3.org/1999/xlink">
<products>
<product id="11" xlink:href="http://www.myshop.com/api/products/11"/>
<product id="12" xlink:href="http://www.myshop.com/api/products/12"/>
...
</products>
</prestashop>
I believe I need to use #XmlSchema to define the "xlink"-prefixed namespace for the href links...
Hope I chose the correct forum.
I have a dataset object with one table that comes to me from a common custom component's GetDS method. I need to pass XML to another process (chunked as byte array). I have it all working but the XML is missing some attributes that the consuming process expects.
I create a dataset object and can control the name of the TableName (root element) and the row like this:
da.Fill(ds, "Foo")
ds.DataSetName = "FooUpload"
I use the GetXML method to serialize to XML that looks like the following:
<?xml version="1.0" standalone="yes" ?>
<FooUpload>
<Foo>
<FooMasterID>483</FooMasterID>
<Country>27</Country>
<PaymentCode>ANN</PaymentCode>
<Amount>132</Amount>
<PaidDate>2012-12-31 00:00:00</PaidDate>
<PaidBy>FooServices</PaidBy>
</Foo>
</FooUpload>
The calling process expects
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<FooUpload **ClientCode="FOOO" RecordCount="1" CreateDate="2008-12-09T15:02:18.920" CreateUser="valli"**>
<Foo>
<FooMasterID>483</FooMasterID>
<Country>27</Country>
<PaymentCode>ANN</PaymentCode>
<Amount>132</Amount>
<PaidDate>2012-12-31 00:00:00</PaidDate>
<PaidBy>FooServices</PaidBy>
</Foo>
</FooUpload>
Note the attributes on the FooUpload element. This node is the name of the DataTable in the DataSet.
I have searched for how to control the XMLSerializer and find lots of examples for custom objects. I even found examples of setting the column mapping to be MappingType.Attribute which is close but I need to do this with the root element which is actually the TableName for the dataset.
I feel that I am close and if I do not find a more elegant solution I will have to create a hack like looping and spitting out changed string plus rest of the XML.
You can feed the output of GetXML into a XmlDocument and add the attributes afterwards. For example:
XmlDocument xdoc = new XmlDocument();
xdoc.LoadXml(ds.GetXml());
XmlAttribute attr=xdoc.CreateAttribute("ClientCode");
attr.Value = "FOOOO";
xdoc.DocumentElement.Attributes.Append(attr);
Then you can save the xdoc into a file, or put it into a string, for example:
XmlTextWriter xw = new XmlTextWriter(new MemoryStream(),Encoding.UTF8);
xdoc.Save(xw);
xw.BaseStream.Position = 0;
StreamReader sr = new StreamReader(xw.BaseStream);
string result = sr.ReadToEnd();
This looks pretty much as what you are looking for.