I have huge problems creating a simple graph in Spark GraphX. I really don't understand anything so I try everything that I find but nothing works.
For example I try to reproduce the steps from here.
The following two were OK:
val flightsFromTo = df_1.select($"Origin",$"Dest")
val airportCodes = df_1.select($"Origin", $"Dest").flatMap(x => Iterable(x(0).toString, x(1).toString))
But after this I obtain an error:
val airportVertices: RDD[(VertexId, String)] = airportCodes.distinct().map(x => (MurmurHash.stringHash(x), x))
Error: missing Parameter type
Could You please tell me what is wrong?
And by the way, why MurmurHash? What is a purpose of it?
My guess is that you are working from a 3 year old tutorial with a recent Spark version.
The sqlContext read returns a Dataset instead of RDD.
If you want it like the tutorial use .rdd. instead
val airportVertices: RDD[(VertexId, String)] = airportCodes.rdd.distinct().map(x => (MurmurHash3.stringHash(x), x))
or change type of variable
val airportVertices: Dataset[(Int, String)] = airportCodes.distinct().map(x => (MurmurHash3.stringHash(x), x))
You could also checkout https://graphframes.github.io/ if you are interested in Graphs and Spark
Updated
To create a Graph you need vertices and edges
To make computation easier all vertices have to be identified by a VertexId (in essence a Long)
The MurmerHash is used to create very good unique hashes. More info here: MurmurHash - what is it?
Hashing is a best practise to distribute the data without skewing, but there is no technical reason why you couldn't use an incremental counter for each vertex
I've looked at the tutorial, but the only thing you have to change to make it work, is to add .rdd:
val flightsFromTo = df_1.select($"Origin",$"Dest").rdd
val airportCodes = df_1.select($"Origin", $"Dest").flatMap(x => Iterable(x(0).toString, x(1).toString)).rdd
Related
I have spark application and I implemented DataFrame extension -
def transform : Dataframe => Dataframe
,so app developer can pass custom transformations in my framework. Like
builder.load(path).transform(_.filter(col("sample") == lit(""))).
Now I want to track what was happened during spark execution:
Log:
val df = spark.read()
val df2 = df.filter(col("sample") == lit("")))
...
So, the idea is keep log of actions and pretty-print it at the end, but to do this I need somehow get the content of Dataframe => DataFrame function. Possibly, macros can help me, but I am not sure. I actually don't need the code(however will appreciate it), but just get the direction to go.
I am trying to build kd-trees from points in a pair RDD called "RDDofPoints" with type RDD[BoundingBox[Double],(Double,Double)]. All the points are assigned to a particular bounding box and my goal is to build a kd-tree for each of the Bounding Boxes.
I am trying to use reduceByKey for this purpose. However, I am stuck at how to call the buildtree function in this case.
The function declaration of buildtree is:
def buildtree(points: RDD[(Double, Double)], depth: Int = 0): Option[KdNodeforRDD]
And, I am trying to call it as:
val treefromPairRDD = RDDofPoints.reduceByKey((k,v) => buildtree(v))
This does not work obviously. I am fairly new to Scala and Spark, please suggest what could be the appropriate way to go about in this situation. I am not sure about using reduceByKey, if some other pair RDD function can be applied here, which one would it be?
Thank you.
I've been trying to learn/use Scala for machine learning and to do that I need to convert string variables to an index of dummies.
The way I've done it is with the StringIndexer in Scala. Before running I've used df.na.fill("missing") to replace missing values. Even after I run that I still get a NullPointerException.
Is there something else I should be doing or something else I should be checking? I used printSchema to filter only on the string columns to get the list of columns I needed to run StringIndexer on.
val newDf1 = reweight.na.fill("Missing")
val cat_cols = Array("highest_tier_nm", "day_of_week", "month",
"provided", "docsis", "dwelling_type_grp", "dwelling_type_cd", "market"
"bulk_flag")
val transformers: Array[org.apache.spark.ml.PipelineStage] = cat_cols
.map(cname => new StringIndexer()
.setInputCol(cname)
.setOutputCol(s"${cname}_index"))
val stages: Array[org.apache.spark.ml.PipelineStage] = transformers
val categorical = new Pipeline().setStages(stages)
val cat_reweight = categorical.fit(newDf)
Normally when using machine learning you would train the model with one part of the data and then test it with another part. Hence, there are two different methods to use to reflect this. You have only used fit() which is equivalent to training a model (or a pipeline).
This mean that your cat_reweight is not a dataframe, it is a PipelineModel. A PipelineModel have a function transform() that takes data with the same format as the one used for training and gives a dataframe as output. In other words, you should add .transform(newDf1) after fit(newDf1).
Another possible issue is that in your code you have used fit(newDf) instead of fit(newDf1). Make sure the correct dataframe is used for both the fit() and transform() methods, otherwise you will get a NullPointerException.
It works for me when running locally, however, if you still get an error you could try to cache() after replacing the nulls and then performing an action to make sure all transformations are done.
Hope it helps!
I want to convert a string column of a data frame to a list. What I can find from the Dataframe API is RDD, so I tried converting it back to RDD first, and then apply toArray function to the RDD. In this case, the length and SQL work just fine. However, the result I got from RDD has square brackets around every element like this [A00001]. I was wondering if there's an appropriate way to convert a column to a list or a way to remove the square brackets.
Any suggestions would be appreciated. Thank you!
This should return the collection containing single list:
dataFrame.select("YOUR_COLUMN_NAME").rdd.map(r => r(0)).collect()
Without the mapping, you just get a Row object, which contains every column from the database.
Keep in mind that this will probably get you a list of Any type. Ïf you want to specify the result type, you can use .asInstanceOf[YOUR_TYPE] in r => r(0).asInstanceOf[YOUR_TYPE] mapping
P.S. due to automatic conversion you can skip the .rdd part.
With Spark 2.x and Scala 2.11
I'd think of 3 possible ways to convert values of a specific column to a List.
Common code snippets for all the approaches
import org.apache.spark.sql.SparkSession
val spark = SparkSession.builder.getOrCreate
import spark.implicits._ // for .toDF() method
val df = Seq(
("first", 2.0),
("test", 1.5),
("choose", 8.0)
).toDF("id", "val")
Approach 1
df.select("id").collect().map(_(0)).toList
// res9: List[Any] = List(one, two, three)
What happens now? We are collecting data to Driver with collect() and picking element zero from each record.
This could not be an excellent way of doing it, Let's improve it with the next approach.
Approach 2
df.select("id").rdd.map(r => r(0)).collect.toList
//res10: List[Any] = List(one, two, three)
How is it better? We have distributed map transformation load among the workers rather than a single Driver.
I know rdd.map(r => r(0)) does not seems elegant you. So, let's address it in the next approach.
Approach 3
df.select("id").map(r => r.getString(0)).collect.toList
//res11: List[String] = List(one, two, three)
Here we are not converting DataFrame to RDD. Look at map it won't accept r => r(0)(or _(0)) as the previous approach due to encoder issues in DataFrame. So end up using r => r.getString(0) and it would be addressed in the next versions of Spark.
Conclusion
All the options give the same output but 2 and 3 are effective, finally 3rd one is effective and elegant(I'd think).
Databricks notebook
I know the answer given and asked for is assumed for Scala, so I am just providing a little snippet of Python code in case a PySpark user is curious. The syntax is similar to the given answer, but to properly pop the list out I actually have to reference the column name a second time in the mapping function and I do not need the select statement.
i.e. A DataFrame, containing a column named "Raw"
To get each row value in "Raw" combined as a list where each entry is a row value from "Raw" I simply use:
MyDataFrame.rdd.map(lambda x: x.Raw).collect()
In Scala and Spark 2+, try this (assuming your column name is "s"):
df.select('s').as[String].collect
sqlContext.sql(" select filename from tempTable").rdd.map(r => r(0)).collect.toList.foreach(out_streamfn.println) //remove brackets
it works perfectly
List<String> whatever_list = df.toJavaRDD().map(new Function<Row, String>() {
public String call(Row row) {
return row.getAs("column_name").toString();
}
}).collect();
logger.info(String.format("list is %s",whatever_list)); //verification
Since no one has given any solution in java(Real Programming Language)
Can thank me later
from pyspark.sql.functions import col
df.select(col("column_name")).collect()
here collect is functions which in turn convert it to list.
Be ware of using the list on the huge data set. It will decrease performance.
It is good to check the data.
Below is for Python-
df.select("col_name").rdd.flatMap(lambda x: x).collect()
An updated solution that gets you a list:
dataFrame.select("YOUR_COLUMN_NAME").map(r => r.getString(0)).collect.toList
This is java answer.
df.select("id").collectAsList();
I want to subtract an RDD from another RDD. I looked into the documentation and I found that subtract can do that. Actually, when I tested subtract, the final RDD remains the same and the values are not removed!
Is there any other function to do that? Or am I using subtract incorrectly?
Here is the code that I used:
val vertexRDD: org.apache.spark.rdd.RDD[(VertexId, Array[Int])]
val clusters = vertexRDD.takeSample(false, 3)
val clustersRDD: RDD[(VertexId, Array[Int])] = sc.parallelize(clusters)
val final = vertexRDD.subtract(clustersRDD)
final.collect().foreach(println(_))
Performing set operations like subtract with mutable types (Array in this example) is usually unsupported, or at least not recommended.
Try using a immutable type instead.
I believe WrappedArray is the relevant container for storing arrays in sets, but i'm not sure.
If your rdd is composed of mutables object it wont work... problem is it wont show an error either so this kind of problems are hard to identify, i had a similar one yesterday and i used a workaround.
rdd.keyBy( someImmutableValue ) -> do this using the same key value to
both your rdds
val resultRDD = rdd.subtractByKey(otherRDD).values
Recently I tried the subtract operation of 2 RDDs (of array List) and it is working. The important note is - the RDD val after .subtract method should be the list from where you're subtracting, not the other way around.
Correct: val result = theElementYouWantToSubtract.subtract(fromList)
Incorrrect: val reuslt = fromList.subtract(theElementYouWantToSubtract) (will not give any compile/runtime error message)