I have maven project with embedded jetty server.
I have already created apis using JAX-RS, which are working properly. Now I want to create swagger documentation for my apis.
To start with swagger I have added servlet configuration as describe below :
#WebServlet(name = "SwaggerConfig")
public class SwaggerServlet extends HttpServlet {
#Override
public void init(ServletConfig config) throws ServletException {
super.init(config);
System.out.println("init SwaggerServlet");
BeanConfig beanConfig = new BeanConfig();
beanConfig.setVersion("1.0.0");
beanConfig.setSchemes(new String[]{"http"});
beanConfig.setHost("localhost:8082");
beanConfig.setBasePath("/api");
beanConfig.setResourcePackage("com.myCompany.myApisResourcePackage");
beanConfig.setScan(true);
}
}
Also, in main method,
along with my jersey configuration I have added following code :
//swagger
ServletHolder swaggerServletHolder = new ServletHolder(SwaggerServlet.class);
swaggerServletHolder.setInitOrder(1);
swaggerServletHolder.setInitParameter("swagger.api.basepath", "http://localhost:8082");
context.addServlet(swaggerServletHolder, "/api/*");
//swagger end
So, the problem is, I am not able to find where swagger.json will be created.
In this case, swagger scans packages as server log says it, but swagger.json still not getting created.
Note: I am currently not adding swagger-ui as I think it is not mandatory for creating swagger.json
I got swagger json by hitting url "localhost:8082/swagger.json". I used same configuration as posted in my question.
Related
I have a basic SpringMVC Application which is running (and mapping) fine.
Now I wanted to set up my UnitTests with MockMvc to perform get requests and stuff.
But if I run the test there is an AssertionError "Status expected: <200> but was: <404>" and my console gives warning "No mapping found for HTTP request with URI [/] in DispatcherServlet with name ''".
I get the feeling my MockMvc cant communicate with my DispatcherServlet, so how do I define this connection?
Here is my short test class:
#RunWith(SpringJUnit4ClassRunner.class)
#WebAppConfiguration
#ContextConfiguration
public class HomeControllerTest {
private MockMvc mvc;
#Autowired
private WebApplicationContext wac;
#Before
public void setup() throws ServletException {
mvc = MockMvcBuilders.webAppContextSetup(wac).build();
}
#Test
public void testLandingPagePath() throws Exception {
mvc.perform(get("/")).andExpect(status().isOk());
}
}
So I expected MockMvc to get the location of my DispatcherServlet by default. But it actually doesn't call it for mapping.
I have my "web.xml" and "dispatcher-servlet.xml" located in "WEB-INF" folder and no extra configuration defined.
I got the feeling the problem is based on my project structure, but this is a basic eclipse "Dynamic Web Application", the tests are located in "src/test/java", parallel to "src/main/java".
I appreciate any help, since I spend last 2 hours on reading for solutions but not getting the trick.
After some more time I got things right now:
There is still no way for me to access the dispatcher-servlet.xml in WEB-INF folder. I added a new "config" package to my test-package in parallel to my "controller" test package and put a copy of the dispatcher-servlet.xml in there, called "test-dispatcher-servlet.xml".
Now my test class is able to access this with
#ContextConfiguration("../config/test-dispatcher-servlet.xml")
public class HomeControllerTest {
Hope this can help others who start with spring mvc testing :-)
I want to create a simple JAX-RS REST Service for Wildfly 10. My issue is that my REST Service is not found. Result in browser is 404 not found. I am not sure what exactly the issue is. I get no error or exception in wildfly log file. I am using eclipse neon 3 and wildfly 10. My project is using JAX-RS not resteasy.
Here my project setup and code:
I have created a Dynamic Web Project in Eclipse.
I have set JAX-RS(REST Service) support in the project facets. JAX-RS version is 2.0 (also tried with version 1.1)
I have create a subclass which extends Application (javax.ws.rs.core.Application)
I added the annotation #ApplicationPath("/yoshi-rest") to the class which extends Application.
I have created a class which contains my rest service method. The class itself has the #Path("/StatusService") annotation.
The affected method has the annotations #Get and #Path("/getStatus").
Due to I have the subclass of Application I didn't set the servlet mapping in web.xml.
Here the code:
Subclass of Application(RESTConfig):
#ApplicationPath("/yoshi-rest")
public class RESTConfig extends Application {
}
REST Service class(StatusService):
#Path("/StatusService")
public class StatusService {
#Get
#Path("/getStatus")
public String getStatus() {
return "Yoshi is up and running";
}
}
I can see during startup of wildfly that the subclass RESTConfig is deployed:
11:09:23,777 INFO [org.jboss.resteasy.resteasy_jaxrs.i18n] (ServerService Thread Pool -- 61) RESTEASY002225: Deploying javax.ws.rs.core.Application: class XXXX.yoshi.rest.services.RESTConfig
If I call the rest service url (http://localhost:8080/yoshi-rest/StatusService/getStatus) in browser, I get a '404 - Not found' as result.
Any idea what I am doing wrong?
You need to register service to connect to your RESTConfig:
#ApplicationPath("/yoshi-rest")
public class RESTConfig extends ResourceConfig {
public RESTConfig() {
register(StatusService.class);
}
See more on ResourceConfig configuration options
Standard JAX-RS uses an Application as its configuration class. ResourceConfig extends Application.
Putting the project name in the url solved the issue.
Thanks for help.
I wrote a REST web service using JAX-RS that knows nothing about the specific JAX-RS implementation I chose. I happen to be using TomEE which means my JAX-RS implementation is ApacheCXF.
I'd like to write unit tests for the web service that also know nothing about the JAX-RS implementation. Is this possible? So far every example I've found involves using classes from a specific JAX-RS implementation (JAXRSClientFactory for ApacheCXF, Jersey Test Framework, etc).
I've started experimenting with tomee-embedded and am able to test my EJB's but it doesn't seem to startup the REST services.
My solution was to use Arquillian paired with an Embedded TomEE. Arquillian provides a ton of functionality but I'm only using it to start/stop the Embedded TomEE. Therefore, all I needed to do was add this to my pom.xml:
<dependency>
<groupId>org.apache.openejb</groupId>
<artifactId>arquillian-tomee-embedded</artifactId>
<version>${tomee.version}</version>
<scope>test</scope>
</dependency>
Then I could write a JUnit test with a little extra Arquillian stuff and plain JAX-RS:
#RunWith(Arquillian.class)
public class MyServiceIT {
#ArquillianResource
private URL webappUrl;
#Deployment()
public static WebArchive createDeployment() {
return ShrinkWrap.create(WebArchive.class)
.addClasses(MyService.class)
.addAsWebInfResource("META-INF/persistence.xml") //Refers to src/main/resources/META-INF/persistence.xml
.addAsWebInfResource("test-resources.xml", "resources.xml") //Refers to src/test/resources/test-resources.xml
.addAsWebInfResource(EmptyAsset.INSTANCE, "beans.xml");
}
#Test
public void randomTest() throws URISyntaxException {
//Get data from the web service.
Client client = ClientBuilder.newClient();
WebTarget webTarget = client.target(webappUrl.toURI().resolve("myentity"));
Response response = webTarget.request(MediaType.APPLICATION_JSON).get();
int status = response.getStatus();
List<MyEntity> myEntities = response.readEntity(new GenericType<List<MyEntity>>() {});
//Perform some tests on the data
}
}
Have KIE Drools Workbench 6.2.0 Final installed inside a JBoss 7 Application Server local instance and Kie Server 6.2.0 Final inside a local Tomcat 7 instance.
Using the web based KIE Workbench strictly for evaluation purposes (am using it to code generate Java based Maven projects and am not using a particular IDE such as Eclipse or IntelliJ IDEA):
Created a new repository called testRepo
Created a new project called HelloWorld
Created a new Data Object called HelloWorld with a String property called message:
package demo;
/**
* This class was automatically generated by the data modeler tool.
*/
public class HelloWorld implements java.io.Serializable {
static final long serialVersionUID = 1L;
private java.lang.String message;
public HelloWorld()
{
}
public java.lang.String getMessage()
{
return this.message;
}
public void setMessage(java.lang.String message)
{
this.message = message;
}
public HelloWorld(java.lang.String message)
{
this.message = message;
}
}
Created a new DRL containing the following contents:
package demo;
import demo.HelloWorld;
rule "hello"
when
HelloWorld(message == "Joe");
then
System.out.println("Hello Joe!");
end
When I deploy it to my Kie Server under this URL:
http://localhost:8080/kie-server-6.2.0.Final-webc/services/rest/server/containers/helloworld
I get the following response when I copy and paste the above URL in Google Chrome:
<response type="SUCCESS" msg="Info for container hello">
<kie-container container-id="hello" status="STARTED">
<release-id>
<artifact-id>Hello</artifact-id>
<group-id>demo</group-id>
<version>1.0</version>
</release-id>
<resolved-release-id>
<artifact-id>Hello</artifact-id>
<group-id>demo</group-id>
<version>1.0</version>
</resolved-release-id>
<scanner status="DISPOSED"/>
</kie-container>
</response>
When I try to do a POST using the following payload (using Postman or SoapUI):
<batch-execution lookup="defaultKieSession">
<insert out-identifier="message" return-object="true" entrypoint="DEFAULT">
<demo.HelloWorld>
<message>Joe</message>
<demo.HelloWorld>
</insert>
Received the following:
HTTP Status 415 - Cannot consume content type
type Status report
message Cannot consume content type
description The server refused this request because the request entity is in a format not supported by the requested resource for the requested method.
What am I possibly doing wrong? I went to Deploy -> Rule Deployments and registered my kie-server along with creating a container called helloworld and as one can see from Step # 5, it worked. Perhaps I am not deploying it correctly?
Btw, I used the following Stack Overflow post as a basis (prior to asking this question)...
Most of the search results from Google just explain how to programmatically create Drools projects by setting up Maven based projects. Am evaluating KIE Drools Workbench to see how easily a non-technical person can use KIE Drools Workbench to generate Drools based rules and execute them.
Am I missing a step? Under Tomcat 7, it only contains the following directories under apache-tomcat-7.0.64/webapps/kie-server-6.2.0.Final-webc:
META-INF
WEB-INF
Thanks for taking the time to read this...
What content type are you using in your POST request header?
As far as I remember, that error message happened if you didn't provide a content-type: application/xml in your request's header.
Hope it helps,
are you ok?
The response of Esteban is right, but, you should add a another header, the header that you need to add is "Authorization", and the value of Authorization is the user that you registered to you application realm to your kie-server converted in base64. e.g.:
kieserver:system*01
converted to base64:
a2llc2VydmVyOnN5c3RlbSowMQ==
Anyway, the complete header of my request is like this:
Authorization : Basic a2llc2VydmVyOnN5c3RlbSowMQ==
Content-Type : application/xml
I hope it was helpful.
Sorry for my english! :)
I got it working with using Postman (Chrome app / plugin) with the Authorization tab selected to No Auth. Really cool response!
<response type="SUCCESS" msg="Container helloworld successfully called.">
<results>
<![CDATA[<execution-results>
<result identifier="message">
<demo.HelloWorld>
<message>Joe</message>
</demo.HelloWorld>
</result>
<fact-handle identifier="message" external-form="0:4:1864164041:1864164041:4:DEFAULT:NON_TRAIT"/>
</execution-results>]]>
</results>
</response>
I'm pretty new to JBoss and Seam. My project has a REST service of the style
#Path("/media")
#Name("mediaService")
public class MediaService {
#GET()
#Path("/test")
public Response getTest() throws Exception {
String result = "this works";
ResponseBuilder builder = Response.ok(result);
return builder.build();
}
}
I can reach this at http://localhost:8080/application/resource/rest/media/test. However, I don't like this URL at all and would prefer something much shorter like http://localhost:8080/application/test.
Can you please point me in the right direction on how to configure the application correctly? (Developing using Eclipse)
web.xml will contain seam resource servlet mapping , this should be modified to /*, and if you have more configuration to the path it will be in components.xml ,if it is resteasy seam is configured to use, it will look like the following
<resteasy:application resource-path-prefix="/rest"/>